How to create folders from a nested dictionary? - python

How to create folders with name of all dictionaries in nested dictionary?
The code should iterate through dictionary and create the directories structure like in nested dictionary with keeping all hierarchy.
dic = {
"root": {
'0_name': {
"0_name_a": {
"0_name_a_a": {
},
"0_name_a_b": {
"file": "file"
}
},
"0_name_b": {
}
},
"1_name": {
},
"2_name": {
},
"3_name": {
"3_name": {
},
}
}
}
Should make directories like:
root/0_name
root/0_name/0_name_a
root/0_name/0_name_a/0_name_a_a
root/0_name/0_name_a/0_name_a_b
root/0_name/0_name_b
root/1_name/1_name_a
root/2_name/
root/3_name/3_name(the same name)
The script needs to determine if the value is final, and create a folder with that path, then remove that value from a dictionary and start over. Also somehow to recognize "file" type and skip it. I couldn't determine a recursive way to iterate all values and add them to a path.
My approach (absolutely not working, just pasted it in to show something):
def rec(dic):
path = []
def nova(dic):
for k, v in dic.copy().items():
if isinstance(v, dict):
path.append(k)
if not v:
print(os.path.join(*path))
path.clear()
dic.pop(k)
nova(v)
if path == []:
nova(dic)

You're going to need a recursive program, and the value of "path" needs to be part of that recursion.
This isn't exactly what you want, but it's close.
def handle_problem(dic):
def one_directory(dic, path):
for name, info in dic.items():
next_path = path + "/" + name
if isinstance(info, dict):
print("Creating " + next_path) # actually use mkdir here!
one_directory(info, next_path)
one_directory(dic, '')

Related

Having an issue parsing through this json in python

I have created a var that is equal to t.json. The JSON file is a follows:
{
"groups": {
"customerduy": {
"nonprod": {
"name": "customerduynonprod",
"id": "529646781943",
"owner": "cloudops#coerce.com",
"manager_email": ""
},
"prod": {
"name": "phishing_duyaccountprod",
"id": "241683454720",
"owner": "cloudops#coerce.com",
"manager_email": ""
}
},
"customerduyprod": {
"nonprod": {
"name": "phishing_duyaccountnonprod",
"id": "638968214142",
"owner": "cloudops#coerce.com",
"manager_email": ""
}
},
"ciasuppliergenius": {
"prod": {
"name": "ciasuppliergeniusprod",
"id": "220753788760",
"owner": "cia_developers#coerce.com",
"manager_email": "jarks#coerce.com"
}
}
}
}
my goal was to pars this JSON file and get value for "owner" and output it to a new var. Example below:
t.json = group_map
group_id_aws = group(
group.upper(),
"accounts",
template,
owner = group_map['groups']['prod'],
manager_description = "Groups for teams to access their product accounts.",
The error I keep getting is: KeyError: 'prod'
Owner occurs 4 times, so here is how to get all of them.
import json
# read the json
with open("C:\\test\\test.json") as f:
data = json.load(f)
# get all 4 occurances
owner_1 = data['groups']['customerduy']['nonprod']['owner']
owner_2 = data['groups']['customerduy']['prod']['owner']
owner_3 = data['groups']['customerduyprod']['nonprod']['owner']
owner_4 = data['groups']['ciasuppliergenius']['prod']['owner']
# print results
print(owner_1)
print(owner_2)
print(owner_3)
print(owner_4)
the result:
cloudops#coerce.com
cloudops#coerce.com
cloudops#coerce.com
cia_developers#coerce.com
You get a key error since the key 'prod' is not in 'groups'
What you have is
group_map['groups']['customerduy']['prod']
group_map['groups']['ciasuppliergenius']['prod']
So you will have to extract the 'owner' from each element in the tree:
def s(d,t):
for k,v in d.items():
if t == k:
yield v
try:
for i in s(v,t):
yield i
except:
pass
print(','.join(s(j,'owner')))
If your JSON is loaded in variable data, you can use a recursive function
that deals with the two containers types (dict and list) that can occur
in a JSON file, recursively:
def find_all_values_for_key(d, key, result):
if isinstance(d, dict):
if key in d:
result.append(d[key])
return
for k, v in d.items():
find_all_values_for_key(v, key, result)
elif isinstance(d, list):
for elem in d:
find_all_values_for_key(elem, key, result)
owners = []
find_all_values_for_key(data, 'owner', owners)
print(f'{owners=}')
which gives:
owners=['cloudops#coerce.com', 'cloudops#coerce.com', 'cloudops#coerce.com', 'cia_developers#coerce.com']
This way you don't have to bother with the names of intermediate keys, or in general the structure of your JSON file.
You don't have any lists in your example, but it is trivial to recurse through
them to any dict with an owner key that might "lurk" somewhere nested
under a a list element, so it is better to deal with potential future changes
to the JSON.

Get item in dictionary inside list from JSON - Python

I need to get the name information, inside the "object" list.
In this example I need this information (10.0.0.19)
"sourceNetworks":{
"objects":[
{
"type":"Host",
"overridable":false,
"id":"005056BF-7C6E-0ed3-0000-012884911113",
"name":"**10.0.0.19**"
}
]
}
I can get any information that is not in the "objects" lists with the command example_json[['metadata']['accessPolicy']['name']
and I get the "mb-test-01" information correctly from the json, but I don't know the syntax to get the items inside the "object" list.
to create this json I use in GET request this way
example_json = requests.get(f"https://{hostname}/api/fmc_config/v1/domain/{uuid}/policy/accesspolicies/{acp_id}/accessrules?expanded=true",headers=header_acp, verify=False).json()
follow the full json.
{
"metadata":{
"ruleIndex":1,
"section":"Mandatory",
"category":"--Undefined--",
"accessPolicy":{
"type":"AccessPolicy",
"name":"mb-test-01",
"id":"005056BF-7C6E-0ed3-0000-012884914323"
},
"timestamp":1635219651530,
"domain":{
"name":"Global",
"id":"e276abec-e0f2-11e3-8169-6d9ed49b625f",
"type":"Domain"
}
},
"links":{
"self":"https://fmcrestapisandbox.cisco.com/api/fmc_config/v1/domain/e276abec-e0f2-11e3-8169-6d9ed49b625f/policy/accesspolicies/005056BF-7C6E-0ed3-0000-012884914323/accessrules/005056BF-7C6E-0ed3-0000-000268434442"
},
"enabled":true,
"action":"ALLOW",
"type":"AccessRule",
"id":"005056BF-7C6E-0ed3-0000-000268434442",
"sourceNetworks":{
"objects":[
{
"type":"Host",
"overridable":false,
"id":"005056BF-7C6E-0ed3-0000-012884911113",
"name":"10.0.0.19"
}
]
},
"destinationNetworks":{
"objects":[
{
"type":"Host",
"overridable":false,
"id":"005056BF-7C6E-0ed3-0000-012884911491",
"name":"192.168.0.39"
}
]
},
"logBegin":false,
"logEnd":false,
"variableSet":{
"name":"Default-Set",
"id":"76fa83ea-c972-11e2-8be8-8e45bb1343c0",
"type":"VariableSet"
},
"logFiles":false,
"enableSyslog":false,
"vlanTags":{
},
"sendEventsToFMC":false,
"name":"rule-1"
}
Presumably you want to retrieve all "name"s under "objects" keys so you could use a recursive function:
def get_name(d):
for k,v in d.items():
if k=='objects':
for i in v:
yield i.get('name')
elif isinstance(v, dict):
yield from get_name(v)
names = list(get_name(data))
Output:
['10.0.0.19', '192.168.0.39']

How can I extend file paths for a dictionary

import plazy
txt_filter = lambda x : True if x.endswith('') else False
file_paths: list = plazy.list_files(root='/data/', filter_func=txt_filter, is_include_root=True)
print(file_paths)
output:
["/data/subdir1/subdir1_1/file1.txt","/data/subdir2/subdir2_1/file2.txt", "/data/subdir2/subdir2_1/file1.txt", "/data/subdir3/subdir3_1/subdir3_2/file1.txt"]
How can I extend these paths for a specific dictionary. I want it to look like this
{
"data":
"subdir1" : { "subdir1_1": ["file1.txt"]},
"subdir2" : { "subdir2_1": ["file1.txt", "file2.txt"]},
"subdir3" : { "subdir3_1":
{ "subdir3_2": ["file1.txt"]}
}
}
I think one way to address this is by using plazy.list_files in a limited depth first (to get top level dirs) and recurse manually, rather than letting it get the whole tree.
Some pseudo code to illustrate...
topdirs = getdirs(/root)
foreach dir
children = getdirs(/dir)
leaves = gettxtfiles(/dir/)
As your program recurses into the structure it builds it map the way you want it.
I took care of it without using Plazy.
path = '/data/'
import os
import pprint
def f(path):
if os.path.isdir(path):
d ,l = {}, []
for name in os.listdir(path):
if os.path.isdir(os.path.join(path, name)):
d[name] = f(os.path.join(path, name))
else:
l.append(name)
d = l
return d
pprint.pprint(f(path))
Output
{
"data":
"subdir1" : { "subdir1_1": ["file1.txt"]},
"subdir2" : { "subdir2_1": ["file1.txt", "file2.txt"]},
"subdir3" : { "subdir3_1":
{ "subdir3_2": ["file1.txt"]}
}
}

Accessing a nested node in a json dictionary with an attribute [duplicate]

I have a dictionary which contains the following json elements.
myjsonDictionary = \
{
"Teams": {
"TeamA": {
"#oid": "123.0.0.1",
"dataRequestList": {
"state": {
"#default": "0",
"#oid": "2"
}
},
"TeamSub": {
"#oid": "3",
"dataRequestList": {
"state": {
"#default": "0",
"#oid": "2"
}
}
}
},
# ....many nested layers
}
}
I have the following issue and am currently very confused on how to solve this problem.
I want to be able to parse this dictionary and get the concatenation of the "#oid" value and the respective "#oid" when I request the "key" such as "TeamA" or "TeamSub".
I have a function which takes in the gettheiDLevelConcatoid(myjsonDictionary, key).
I can call this function like this:
gettheiDLevelConcatoid(myjsonDictionary, key) where "key" is like "TeamA"
And the expected output should be "123.0.0.1.2". Note the 2 appended to the 123.0.0.1.
gettheiDLevelConcatoid(myjsonDictionary, key) where "key" is like TeamSub
Output is "123.0.0.1.3.2". Note the "3.2" added to the "123.0.0.1".
My current implementation:
def gettheiDLevelConcatoid(myjsonDictionary, key)
for item in myjsonDictionary:
if (item == key):
#not sure what to do
I am so lost on how to implement a generic method or approach for this.
With recursive traversal for specific keys:
def get_team_idlvel_oid_pair(d, search_key):
for k, v in d.items():
if k.startswith('Team'):
if k == search_key:
return '{}{}.{}'.format(d['#oid'] + '.' if '#oid' in d else '',
v['#oid'], v['dataRequestList']['state']['#oid'])
elif any(k.startswith('Team') for k_ in v):
return get_team_idlvel_oid_pair(v, search_key)
print(get_team_idlvel_oid_pair(myjsonDictionary['Teams'], 'TeamA'))
print(get_team_idlvel_oid_pair(myjsonDictionary['Teams'], 'TeamSub'))
Sample output:
123.0.0.1.2
123.0.0.1.3.2

python recursive dictionary converting to strings

I had a problem on converting dictionaries to strings which has recursive features.
I had a map of routing such as the following;
urls = {
'/' : 'BaseController.hello',
'/api' : {
'/auth' : {
'/me' : 'ApiController.hello',
'/login' : {
'/guest' : 'ApiController.guest_login',
'/member': 'ApiController.member_login'
}
}
}
}
What I need to do is to generate a dictionary from that into the following;
url_map = {
'/' : 'BaseController.hello',
'/api/auth/me' : 'ApiController.hello',
'/api/auth/login/guest' : 'ApiController.guest_login',
'/api/auth/login/member': 'ApiController.member_login',
}
This feature is called route grouping but I haven't been able to write a function to generate that. Any ideas ?
You can recursively do it like this
def flatten(current_dict, current_key, result_dict):
# For every key in the dictionary
for key in current_dict:
# If the value is of type `dict`, then recurse with the value
if isinstance(current_dict[key], dict):
flatten(current_dict[key], current_key + key, result_dict)
# Otherwise, add the element to the result
else:
result_dict[current_key + key] = current_dict[key]
return result_dict
print flatten(urls, "", {})
Output
{
'/api/auth/me': 'ApiController.hello',
'/api/auth/login/guest': 'ApiController.guest_login',
'/': 'BaseController.hello',
'/api/auth/login/member': 'ApiController.member_login'
}

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