I am given a string which is number example "44.87" or "44.8796". I want to extract everything after decimal (.). I tried to use regex in Python code but was not successful. I am new to Python 3.
import re
s = "44.123"
re.findall(".","44.86")
Something like s.split('.')[1] should work
If you would like to use regex try:
import re
s = "44.123"
regex_pattern = "(?<=\.).*"
matched_string = re.findall(regex_pattern, s)
?<= a negative look behind that returns everything after specified character
\. is an escaped period
.* means "match all items after the period
This online regex tool is a helpful way to test your regex as you build it. You can confirm this solution there! :)
Related
I'm trying to unescape the escaped regex pattern to apply it to a string.
It's actually dynamic I don't exactly know what it would look like, but throughout my testing I encountered one problem, the string with escaped regex pattern looks like this:
\\d{4}
I've written a simple regex which replaces every single combination of backslash and a character with just a character
And I'm applying it this way:
sub(r"\\(.)", "\\1", escaped_pattern)
But what it gives me afterwards is d{4} not \d{4} as I expect.
I've tried using raw strings for repl, escape\unescape it, it still doesnt return what I expect it to return. Would appreciate any help.
EDIT
escaped_pattern = settings.reg_exp
regexp = sub(r"\\(.)", "\\1", escaped_pattern)
search(regexp, string_to_regexp).group()[0]
Based on you update I'm pretty sure that you would get exactly your desired output if you just stopped trying to unescape it.
import re
s1 = "1234astring"
matches = re.search("\\d{4}", s1)
matches.group(0)
"1234"
matches.group()[0]
"1"
Try r"\\\\(.)" in search pattern and '\\\1' in substitution pattern.
works OK here: https://regex101.com/r/M3ikqj/1
I am not sure why this is not working. Perhaps I am missing something with Python regex.
Here is my regex and an example string of what I want it to match too:
PHONE_REGEX = "<(.*)>phone</\1>"
EXAMPLE = "<bar>phone</bar>"
I tested this match in isolation and it failed. I used an online regex tester and it matched. Am I simply missing something that is particular to Python regex?
Thanks!
You have to mark the string as a raw string, due to the \ in there, by putting an r in front of the regex:
m = re.match(r"<(.*)>phone</\1>", "<bar>phone</bar>")
Regex has never been my strong point. In python I'm attempting to build an expression which matches substrings such as this:
%MATCH%
%MATCH_1%
$THIS_IS_A_MATCH%
It would be extracted by a %MATCH% like this or %LIKE_THIS%
I ended up with this (logically, but does not seem to work): %[A-Z0-9_]*$%
So where am I going wrong on this?
You can use a simple regex like this:
[%$]\w+[%$] <-- Notice I put $ because of your sample
On the other hand, if you only want uppercase you can use:
[%$][A-Z_\d]+[%$]
If you only want to match content within %, you could also use:
%.+?%
Python code
import re
p = re.compile(ur'[%$]\w+[%$]')
test_str = u"%MATCH%\n\n%MATCH_1%\n\n$THIS_IS_A_MATCH%"
re.findall(p, test_str)
Btw, the problem with your regex is below:
%[A-Z0-9_]*$%
^--- Remove this dolar sign
I am trying to learn python and regex at the same time and I am having some trouble in finding how to match till end of string and make a replacement on the fly.
So, I have a string like so:
ss="this_is_my_awesome_string/mysuperid=687y98jhAlsji"
What I'd want is to first find 687y98jhAlsji (I do not know this content before hand) and then replace it to myreplacedstuff like so:
ss="this_is_my_awesome_string/mysuperid=myreplacedstuff"
Ideally, I'd want to do a regex and replace by first finding the contents after mysuperid= (till the end of string) and then perform a .replace or .sub if this makes sense.
I would appreciate any guidance on this.
You can try this:
re.sub(r'[^=]+$', 'myreplacedstuff', ss)
The idea is to use a character class that exclude the delimiter (here =) and to anchor the pattern with $
explanation:
[^=] is a character class and means all characters that are not =
[^=]+ one or more characters from this class
$ end of the string
Since the regex engine works from the left to the right, only characters that are not an = at the end of the string are matched.
You can use regular expressions:
>>> import re
>>> mymatch = re.search(r'mysuperid=(.*)', ss)
>>> ss.replace(mymatch.group(1), 'replacing_stuff')
'this_is_my_awesome_string/mysuperid=replacing_stuff'
You should probably use #Casimir's answer though. It looks cleaner, and I'm not that good at regex :p.
I am not sure why this is not working. Perhaps I am missing something with Python regex.
Here is my regex and an example string of what I want it to match too:
PHONE_REGEX = "<(.*)>phone</\1>"
EXAMPLE = "<bar>phone</bar>"
I tested this match in isolation and it failed. I used an online regex tester and it matched. Am I simply missing something that is particular to Python regex?
Thanks!
You have to mark the string as a raw string, due to the \ in there, by putting an r in front of the regex:
m = re.match(r"<(.*)>phone</\1>", "<bar>phone</bar>")