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How to split and access time in individual digits? [hh:mm:ss] [closed]

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I want to split the time into individual digits.
For Eg. We usually look at time in HH: MM: SS
I want to break it down and access both the H, M, and S separately. Like HH should be accessible as H1 [the first digit] and H2 [the second digit] and so on for minutes and seconds.
Please note I am looking for real-time values of the broken variables.

It is possible like this:
from datetime import datetime
# We get the current time.
d = datetime.now()
time_now = d.strftime("%H:%M:%S")
print("time:", time_now)
# We divide the received time into elements.
time_split = [int(t) for t in time_now if t != ":"]
print(time_split)
time: 17:08:39
[1, 7, 0, 8, 3, 9]
Where H1= time_split[0] etc.
Or you can create a dictionary with the variables you need:
var_list = ("h1", "h2", "", "m1", "m2", "", "s1", "s2")
time_dict = {v: int(t) for v, t in zip(var_list, time_now) if t != ":"}
print(time_dict)
{'h1': 1, 'h2': 7, 'm1': 0, 'm2': 8, 's1': 3, 's2': 9}

Creating dictionary from list of tuples giving only subset of key-value pairs [closed]

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I have a list of tuples of data and a datetime object.
..[(datetime.datetime(2020, 1, 3, 3, 22, 36), 43.988269794721404), (datetime.datetime(2020, 1, 3, 3, 22, 36), 43.988269794721404), (datetime.datetime(2020, 1, 3, 3, 22, 36), 43.988269794721404), (datetime.datetime(2020, 1, 3, 3, 22, 36),..
I am trying to create a dictionary from this list of tuples. So I call
d = dict(tuple_list)
BUT, the output is simply the last element in the list , {datetime.datetime(2020, 1, 3, 3, 22, 36): 43.988269794721404}.
What is going on here? I am using python 2.7. I also tried
new_dict = {k: v for k, v in zip(keys, values)} but that didn't work either! Thanks for the help!

First of all NO python 2.7
Your getting the last element because you list of tuples all have the same first value.
A dict MUST have unique keys.

python: how can i create a list of integers,to a number? [closed]

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I receive an input int that I don't previously know. How can I create a new list of integer from 0 to that int? An easy way please. Thank you in advance.
I mean that:
k = n
...
list = [0, ... , k]

numbers = list(range(k+1)) # For Python 2, it is just range(k+1).
Given an integer k, which you can get with input.
The range creates an iterator (in Python 3) with those numbers (k+1 because it is not inclusive, but you need it to be), then we make it into a list.
Demo:
>>> k = int(input())
16
>>> numbers = list(range(k+1))
>>> numbers
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]

A simple function would look like this, assuming you've got your input number n:
For python2.x:
def get_range(n):
return range(n + 1)
For python3.x:
def get_range(n):
return list(range(n + 1))
In either case:
int_list = get_range(10)
>>> print(int_list)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Python, Get element from list [closed]

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I have a list of lists with data like credit pays schedule:
[ [pay_number, pay_date, pay_amount], [pay_number, pay_date, pay_amount], e.t.c ]
how can I get next pay_date from it ?

You just need to iterate over the list:
thelist = [ [pay_number, pay_date, pay_amount], [pay_number, pay_date, pay_amount], ... ]
for sub_list in thelist:
current_pay_date = sub_list[1]
# do something with current_pay_date
If you want to access the next pay_date:
for i in range(len(thelist)):
sub_list = thelist[i]
current_pay_date = sub_list[1]
next_sub_list = thelist[i+1]
next_pay_date = next_sub_list[1]
Hope this was what you were looking for.

You can use the min function to get the element from your list which is the closest to today by using a custom key function:
>>> items = [[1, datetime.date(2014, 2, 28), 1], [2, datetime.date(2014, 2, 7), 2], [3, datetime.date(2014, 2, 14), 3]]
>>> min(items, key=lambda x: x[1] - datetime.date.today())
[2, datetime.date(2014, 2, 7), 2]

How to improve this python code? [closed]

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I am doing a problem in which i have to code about this problem-
>>> getNumbers(10)
[100, 64, 36, 16, 4, 0, 4, 16, 36, 64, 100]
>>> getNumbers(9)
[81, 49, 25, 9, 1, 1, 9, 25, 49, 81]
I am getting answers with my code but i am not satisfied with my code,please suggest some options to improve this code.
def getNumbers(num):
myList=[]
mylist=[]
if num%2==0:
for numbers in range(num,-2,-2):
myList.append(numbers**2)
for numbers in range(2,num+2,2):
mylist.append(numbers**2)
print myList+mylist
elif num%3==0:
for numbers in range(num,-1,-2):
myList.append(numbers**2)
for numbers in range(1,num+2,2):
mylist.append(numbers**2)
print myList+mylist
else:
print(mylist)
4 for loops!!! this is what teasing me here!!!

Like this?
def getNumbers(n):
return [i * i for i in range(-n, n + 1, 2)]