Subprocess command line argument with user defined .exe path - python

I'm learning python and I'm trying to use subprocess.run in Windows to pass a script via python to an external program using a command line argument that looks like
program -r script.
At the moment program is a variable defined by user input (that includes spaces) to allow for different versions. And script is also a path that will point to the temp script path. Eg:
program = C:\Program files\folder prog\folder\program.exe
script = C:\User\path\to script\script.txt
I tried this, but it involved manual input of escape characters and only the program argument works.
programm = "\"C:\\Program Files\\folder prog\\folder\\program.exe\""
script = "\"C:\\User\\path\\to script\\script.txt\""
process = subprocess.run([program, '-r', script],
stdout=subprocess.PIPE,
universal_newlines=True)
process
process.stdout
How do I use subprocess correctly to run this command line argument with the correct escape characters for the variable program and script path?

Related

Handling a command line executable within in Python 2X via subprocess

I am wanting to run an executable that would normally be run directly on the command line but ultimately via a Python script.
I used subprocess.Popen after reading through here and multiple Google results to achieve some limited success.
>>>import subprocess
>>>exe_path = sys.argv[1]
>>>dir_path_in = sys.argv[2]
>>>dir_path_out = sys.argv[3]
>>>subprocess.Popen([exe_path])
It then displays
<subprocess.Popen object at 0x021B7B30>
Followed by
>>>usage: <path to exe> [options] <dir_path> <dir_path_out>
But if I enter what you would normally expect to on the command line if used exclusively it returns:
>>>SyntaxError: invalid token
I have tested what is entered exclusively on the command line with the exe and it works fine just not via Python
I have had a look through StackOverFlow and the best kind of comparison I found was here How to handle an executable requiring interactive responses?
Ultimately the "usage" part will not even be required in the end as the declared sys.argvs will provide all the information the executable requires to run automatically.
The subprocess.call() achieved the desired result by declaring the argv variables and then concatenating the variables and using that final variable in a subprocess.call() as opposed to using shlex.split() which I first tried but it struggled with paths even with the '\' escaped for Windows
import subprocess
exe_path = sys.argv[1]
dir_path_in = sys.argv[2]
dir_path_out = sys.argv[3]
command = exe_path, dir_path_in, dir_path_out
p = subprocess.call(command)

python subprocess call failing while same command line call works fine

I am trying to replace a command line call by a Python script using subprocess:
path_to_executable = r'c:\UK\app\Debug\lll.exe'
x = subprocess.call([path_to_executable, args])
args is a string that looks like this:
-unemp Base -rate Base -scen_name Base -print_progress 0 -rate_date 1 -hpa Base -dealpath C:\data\ -nthread 4 -deallist C:\config\all.txt -outdir c:\outdir\Base
The call is working when run from the command line, however failing with the same arguments in subprocess with the following error:
FileIOException(Unable to open directory C:/.../hist.csv)
(The csv file is present - but it's a file, not a directory.)
My questions:
1. How could it be that it work through the command line but not subprocess?
2. Why might it be trying to open a csv file as a directory, when it's not doing the same thing on the command line?
Maybe subprocess is not able to locate the file/directory..Are you sure the file is present and the path to the file does not contain any special character (e.g. ~/) ?
Otherwise try using argument shell=True
from the subprocess doc:
subprocess.call(args, *, stdin=None, stdout=None, stderr=None, shell=False)

Run perl script from python

I know there are some topic on Stack Overflow about this. But none of these make any sense to me. I am new to both python and perl and trying my best to understand. I would like to run a perl script from a piece of python code.
executing the perl script in command prompt goes as following:
perl perlscript.pl input.bopt7 output.xml
I would like to run this command from my python code.
I have tried the following:
pipe = subprocess.Popen(["perlscript.pl" , "input.bopt7" , "output.xml"], stdout=subprocess.PIPE)
but this does not work. I get an error saying it is not a valid win32 ...
I need no input or output from this script. Just need to run it once.
You need to include the perl command itself when executing a perl script:
pipe = subprocess.Popen(["perl", "perlscript.pl" , "input.bopt7" , "output.xml"], stdout=subprocess.PIPE)
You did the same thing on the command line prompt; the Popen class cannot guess from the perlscript.pl file that you wanted to run this script with Perl. :-)
Did you try to add perl to Popen arguments (just as you do on the command line)?
pipe = subprocess.Popen(["perl", "perlscript.pl" , "input.bopt7" , "output.xml"], stdout=subprocess.PIPE)
In your example, Windows tries to execute "perlscript.pl" as a Win32 executable, since this is the first parameter you specified, and fails because it doesn't contain the proper binary header (since it is a text file).
The first argument should be perl.exe, if perl.exe is in your PATH; or the full path to the executable as all the rest are arguments to perl.exe.
Also make sure you put the full path for perlscript.pl and input.bopt7.

Run commands sequential from Python

I'm trying to build a LaTeX document using Python but am having problems getting the commands to run in sequence. For those familiar with LaTeX, you'll know that you usually have to run four commands, each completing before running the next, e.g.
pdflatex file
bibtex file
pdflatex file
pdflatex file
In Python, I'm therefore doing this to define the commands
commands = ['pdflatex','bibtex','pdflatex','pdflatex']
commands = [(element + ' ' + src_file) for element in commands]
but the problem is then running them.
I've tried to suss things out from this thread – e.g. using os.system() in a loop, subprocess stuff like map(call, commands) or Popen, and collapsing the list to a single string separated by & – but it seems like the commands all run as separate processes, without waiting for the previous one to complete.
For the record, I'm on Windows but would like a cross-platform solution.
EDIT
The problem was a bug in speciyfing the src_file variable; it's shouldn't have a ".tex". The following code now works:
test.py
import subprocess
commands = ['pdflatex','bibtex','pdflatex','pdflatex']
for command in commands:
subprocess.call((command, 'test'))
test.tex
\documentclass{article}
\usepackage{natbib}
\begin{document}
This is a test \citep{Body2000}.
\bibliographystyle{plainnat}
\bibliography{refs}
\end{document}
refs.bib
#book{Body2000,
author={N.E. Body},
title={Introductory Widgets},
publisher={Widgets International},
year={2000}
}
os.system shouldn't cause this, but subprocess.Popen should.
But I think using subprocess.call is the best choice:
commands = ['pdflatex','bibtex','pdflatex','pdflatex']
for command in commands:
subprocess.call((command, src_file))

How to use python in windows to open javascript, have it interpreted by WScript, and pass it the command line arguments

I have a format holding paths to files and command line arguments to pass to those files when they are opened in Windows.
For example I might have a path to a javascript file and a list of command line arguments to pass it, in such a case I want to open the javascript file in the same way you might with os.startfile and pass it the command line arguments - since the arguments are saved as a string I would like to pass it as a string but I can also pass it as a list if need be.
I am not quite sure what I should be using for this since a .js is not an executable, and thus will raise errors in Popen while startfile only takes verbs as its second command.
This problem can be extended to an arbitrary number of file extensions that need to be opened, and passed command line arguments, but will be interpreted by a true executable when opening.
If windows has registered the .js extension to open with wscript, you can do this, by leaving that decision up to the windows shell.
You can just use os.system() to do the same thing as you would do when you type it at the command prompt, for example:
import os
os.system('example.js arg1 arg2')
You can also use the start command:
os.system('start example.js arg1 arg2')
If you need more power, for example to get results, you can use subprocess.Popen(), but make sure to use shell=True (so that the shell can call the right application):
from subprocess import Popen
p = Popen('example.js arg1 arg2', shell=True)
# you can also do pass the filename and arguments separately:
# p = Popen(['example.js', 'arg1', 'arg2'], shell=True)
stdoutdata, stderrdata = p.communicate()
(Although this would probably require cscript instead of wscript)
If Windows doesn't have any default application to open the file with (or if it's not the one you want), well, you're on your own of course...

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