I'm having trouble trying to
compute x * y using only addition, printing the intermediate result for each loop iteration, and
printing the final number. This is my
teacher's example of what the output should look like
I could really use some help figuring it out,, I don't really understand how to yet.
Edit: I am a first time coder so I'm not very skilled, I do know the basics though (Also very new to this website) Here's what my code looks like so far:
x = int(input("Input positive x: "))
y = int(input("Input positive y: "))
z = 0
w = 0
if x < 0:
exit("Please input a positive number for x")
if y < 0:
exit("Please input a positive number for y")
def multiplier(number, iterations):
for i in range(1, iterations):
number = number + 3
print(number) # 12
multiplier(number=3, iterations=4)
My answer. Little shorter than the others.
Ok, try thinking of multiplication as adding a number with itself by x times. Hence, 3*4 = 3+3+3+3 = 12, which is adding 3 by itself 4 times
Replicating this with a for loop:
#inputs
x = 3
y = 4
#output
iteration = 1
result = 0
for num in range(4):
result += x
print(f'Sum after iteration {iteration}: {result}')
iteration += 1 #iteration counter
The resulting output will be:
Sum after iteration 1: 3 Sum after iteration 2: 6 Sum after iteration
3: 9 Sum after iteration 4: 12
The code is simple and straightforward,Check which number is bigger and iterate according to that number.
x = 3
y = 4
out = 0
if x > y:
for v in range(0,x):
out += y
print("after iteration",v+1, ":", out)
if y > x:
for v in range(0,y):
out += x
print("after iteration",v+1, ":", out)
print(x,"*", y, "=", out)
Use print to print inside the loop to show each number after adding and the number of iteration occurs.
Here is a start. This assume both arguments are integers 0 or more:
def m(n1, n1a):
n1b = 0
while n1a > 0:
n1b += n1
n1a -= 1
return n1b
n = m(9, 8)
print(n == 72)
Related
This is my first time using Stack Overflow. I will try my best to be as clear as I can be. I need to write a code that returns my initial number, the number of even values, the number of odd values and the biggest value for each N I input. My issue with this is: I have at least two entries: N, number of values my program will receive, and X, the number itself (for N = 1, for example). When I finished my code, I noticed that for N > 1 the number of even and odd numbers are stacking, but the biggest number for each sequence is correct.
For N = 2, X = 9 and X = 15, the output is:
Initial value: 9
Even numbers: 13
Odd numbers: 7
Biggest number: 52
Initial value: 15
Even numbers: 25
Odd numbers: 13
Biggest number: 160
Any idea of why this is happening? Here is my code:
N = int(input())
EVEN = 0
ODD = 0
for i in range(N):
X = int(input())
print("Initial value: ", X)
MAX = X
while = True
if X % 2 == 0:
EVEN = EVEN + 1
X = X / 2
elif X == 1:
ODD = ODD + 1
break
elif X % 2 == 1:
ODD = ODD + 1
X = (3 * X) + 1
if X > MAX
MAX = X
print("Even numbers: ", EVEN)
print("Odd numbers: ", ODD)
print("Biggest number: ", MAX)
As mentioned in the comments, you forgot to reset the even/odd counters at every step of the for loop. It should work like this:
...
for i in range(N):
EVEN = 0
ODD = 0
X = int(input())
print("Initial value: ", X)
MAX = X
while True:
...
So basically I want python to first wait and let me input stuff and then do whatever it has to for every pair of inputs.
t = int(input())
E = 0
for i in range(0, t):
M, N = [int(M) for M in input(" ").split()]
if E in range(0, t):
if M > 0 and N > 0:
print("X")
if M > 0 and N == 0:
print("Y")
if M == 0 and N > 0:
print("Z")
i += 1
The terminal looks somewhat like this,
13 100
X
2 0
Y
I want the 2 0 to be before X but at the same time I want the code to calculate for 13 100 and output X but just after I input the 2nd pair of X, Y.
I also want to know how to remove the spaces before the '2 0' and the 'Y'.
Thanks.
Firstly, the reason you have spaces before 2 0 is because in the line:
M, N = [int(M) for M in input(" ").split()]
your input function has a space within the quotes, so you must remove it and just have an empty string:
M, N = [int(M) for M in input("").split()]
Next, the reason your code is asking for input then generating an output and so on is because the logical operators are within the for loop you have. To fix this you should have your loop to first gather the inputs then, have another loop to perform the logical operators on those inputs as so:
t = 2
E = 0
numList = []
for i in range(0, t):
M, N = [int(M) for M in input("").split()]
numList.append([M, N])
for val in numList:
if E in range(0, t):
if val[0] > 0 and val[1] > 0:
print("X")
if val[0] > 0 and val[1] == 0:
print("Y")
if val[0] == 0 and val[1] > 0:
print("Z")
To simplify things I set t = 2 since we are only talking about 2 pairs of numbers. Furthermore, I created a list to hold each pair of inputs (numList), in which the first for loop appends the values to it as an list. The next for loop looks at each item in numList and since numList is a list of lists I changed M and N to val[0] and val[1] which refer to the first number you inputed (M) and the second one you inputed (N).
Finally,
for i in range(0, t):
should look like:
for i in range(t):
Since the range function automatically just counts from 0 to t and "i += 1" at the end of the loop is also unnecessary and redundant.
My final output:
[1]: https://i.stack.imgur.com/1Bo9U.png
Put all the inputs in a 2-dimensional list before the loop that processes them.
t = int(input())
E = 0
all_inputs = [[int(M) for M in input(" ").split()] for _ in range(t)]
for M, N in all_inputs:
if E in range(0, t):
if M > 0 and N > 0:
print("X")
if M > 0 and N == 0:
print("Y")
if M == 0 and N > 0:
print("Z")
i += 1
The space before the 2 0 is the prompt " " in your input(" ") call. If you don't want that, use input() with no prompt.
I don't see any reason for the space before Y.
Hope this help. Its a little cleaned up:
iterations = int(input("How many times? "))
values = []
for i in range(iterations):
values.append([int(M) for M in input(f"{i+1}. Enter two numbers: ").split()])
for M, N in values:
print(M, N, end=' -> ')
if M > 0 and N > 0:
print("X")
if M > 0 and N == 0:
print("Y")
if M == 0 and N > 0:
print("Z")
I have some code where I must find the multiples of number 3 and then summarize them
I have done the first job, I mean I found all the multiples of number 3 with for loop but I can't summarize all the numbers which I found.
I have tried so many times and tried to find the solution on google, but could not find
x = 3
for number in range(1000):
if number%x == 0:
print(number)
I need now the sum of all the numbers which indicates on this code, when you run this code you can see that there is publishing only the numbers that can divide by 3 now I need the sum of them
It's easier than you think:
sum(range(0, 1000, 3))
Explanation:
range is defined as such: range([start], end[, step]) so range(0, 1000, 3) means go from 0 to 1000 in steps of 3
The sum function will sum over any iterable (which includes range)
You need a variable to hold the sum (If you are in learning stage):
x = 3
total = 0
for number in range(1000):
if number % x == 0:
print(number)
total += number # equivalent to: total = total + number
print(total)
Edit:
To answer your comment use condition or condition:
x = 3
y = 5
total = 0
for number in range(10):
if number % x == 0 or number % y == 0:
print(number)
total += number # equivalent to: total = total + number
print(total)
You could create a result variable to which you can keep adding:
result = 0
x = 3
for number in range(1000):
if number%x == 0:
result += number
print(result)
The best way is using filter and sum:
# any iterable variable
iterable_var = range(100)
res = sum(filter(lambda x: x % 3 == 0, iterable_var), 0)
I made this prime number generator but it just prints every number (1, 2, 3...).
I am aware that there are other questions about this but I don't understand any of them. Here is what I have so far:
x = 1
y = 1
while x >= y:
if x % y == 0:
print(x)
x = x + 1
y = 1
else:
y = y + 1
y = 1
From your question, I think, it would be better try this way :
n = 10
i = 2
while i < n :
prime = 1 # reset the `prime` variable before the inner loop
for a in range(2, i):
if i%a == 0:
prime = 0
break
if prime:
print (i)
i += 1
Output :
2
3
5
7
There's something called a rubber ducky test where you explain your code, step by step, to a rubber duck. It forces you to walk through every step and you'll often find the error. In this case, think about what y is when you do x%y. You'll see that y=1 the first time this is called. So it will iterate through the loop incrementing x by 1 and y will remain set it 1. And x%y when y=1 will always be...
I made a program that looks like:
n = eval(input("enter a whole number: "))
x = 1
print (x)
while x != n:
x = x + 1
print (x)
This code produces a list from 1 to the given whole number n.
What would i do to be able to interact with this list making a second column that gave the square of the adjacent number?
something like
1 1
2 4
3 9
If you want to be able to show the square of 1, you need to initialize x as 0 and delete print(x) from your third line
this should do it:
n = eval(input("enter a whole number: "))
x = 0
while x != n:
x = x + 1
print (x, " ", x**2)
This code prints x and x**2 (the value of 'x ^ 2') separated by a space.
Here is what you are looking for:
n = eval(input("enter a whole number: "))
x = 1
print (x)
while x != n:
x = x + 1
p = x * x
print (x, p)
I would urge caution on using eval() so lightly though, you can use the int() function to run a string as an integer. Here is how I would write that code:
n = int(input("enter a whole number: "))
x = 0
while x != n:
x = x + 1
p = x * x
print (x, p)
EDIT: Updated code
Well, you could use a list of lists. Using a generator expression,
nums = [[n, n**2] for n in range(1,int(input("Enter a number"))]
So if you input 10, nums[1,1] will be 2.
So to print this out,
for i in nums:
print(i[0] + " " + i[1])
This is by far the simplest way to go.