Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
I am trying to rename a file in downloads folder and I get (I translate)
OSError: [WinError 123] Syntax of filename, catalog name or label is wrong: 'C:\\Users\\Miaoulis\\Downloads\\feed.xml' -> 'C:\\Users\\Miaoulis\\Downloads\\VECTOR_03-10-2020 16:49_new.xml'
using windows 10, Kaspersky Internet Security and the following
import os
src = 'C:\\Users\\Miaoulis\\Downloads\\feed.xml'
dst = 'C:\\Users\\Miaoulis\\Downloads\\VECTOR_'+str(file_date)+'_new.xml'
if os.path.isfile(src):
os.rename(src, dst)
thank you
The destination file name has a colon. Try renaming without colon.
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 17 days ago.
Improve this question
When I try to pickle a dataframe, I get an error:
df.to_pickle(r"C:\Users\TomCruise\workspace")
> [Errno 13] Permission denied: 'C:\\Users\\TomCruise\\workspace'
The folder called "workspace" is my current workspace. If I try df.to_excel("file name.xlsx") a file is correctly stored in the folder "workspace" with path C:\Users\TomCruise\Workspace.
Why does to_pickle return an error stating it does not have the permission to access the folder in the path, when to_excel works perfectly fine?
Try add the file extention
df.to_pickle(r"C:\Users\TomCruise\workspace\filename.pkl")
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
I have seen the answers/recommendations for this questions.
I promise that I do not have a random.py file named on my computer. I have searched it, tried to delete it will the send2trash module as well as os.unlink. I simply do not get it. I am unable to call the random.randit() because of this issue. Also when I call os.cwd() the file path does not exist on my computer. I again, have no idea how this is possible.
The code would be random.randint(), not random.randit()
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
import xlrd
path = input('enter the path')
data = xlrd.open_workbook(r'path)
The program doesn't work ,the reason is 'path' does not exist.
So what is the correct way to write the code?
import xlrd
path = input('enter path:')
data = xlrd.open_workbook(path)
This is supposed to work, your issue is you pass a string that just says 'path' instead of the path variable that has the path.
You can use a relative or absolute path.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 5 years ago.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Improve this question
I'm pretty new to Python and I'm trying to read a CSV file with Pandas. However I get the following error:
C:\Python\python.exe "C:/Users/Niels Hoogeveen/PycharmProjects/HelloWorld/HelloWorld.py"
C:\Python\python.exe: can't open file 'C:/Users/Niels Hoogeveen/PycharmProjects/HelloWorld/HelloWorld.py': [Errno 2] No such file or directory
I tried the absolute path, but I get the same error time and time again.
See the screenshot below.
What do I need to do?
screenshot of my code and error
Your file is called test.py instead of HelloWorld.py
By the way, it's possible that '/' must be replaced by '\'
Your Python file's name is not HelloWorld.py, it is test.py. :) Just change the name in the PyCharm terminal and it should start to work.
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
When I try to create and write to a text file only an empty file is created. Here is the code:
controlCheck = open("resources/controlType.txt", "w")
controlCheck.write("controller")
controlCheck.close()
Any idea what the problem is? Its driving me crazy.
Whenever python writes a file, it erases all former data.There are ways to get around it, such as using: what is talked about here: Opening a file for append