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Python. How to sum each element with multi times in loop? [closed]

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Example:
import numpy
a = [1,2,3,4,5]
b = []
for i in range(len(a)):
b.append(a[i]+1)
Here, I have b = [2,3,4,5,6].
But I want sum multi times...(maybe I want to sum with 3 times). I expected after three times sum I have b = [4,5,6,7,8].
So, how I can get b=[4,5,6,7,8] from a=[1,2,3,4,5] with 3 times add 1 with loop?

Add 3 to each element using a list comprehension;
b = [i+3 for i in a]
or as a function, where you can change the value added to the list easily;
def add_k_to_list(k, a_list):
return [i+k for i in a_list]
To repeatedly apply as per your comment;
def add_k_to_list(k, a_list):
for _ in range(k):
a_list = [i+1 for i in a_list]
return(a_list)

Compare tow list order and return the result [closed]

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l = [1,2,3,4,5]
l1 = [2,5]
l2 = [5,1]
compare(l1,l)
result = PASS
compare(l2,l)
result - FAIL
I have a main list called l. I need to compare the order of the list - If l1 is in the order of l then the result is "PASS", then comparing l2 is in the order of l the it is not in the order of l then "FAIL"

def compare(tested, base):
indexes = [base.index(t) for t in tested]
return {True: "PASS", False: "FAIL"}[indexes == sorted(indexes)]
print(compare(l1, l))

Finding symbols in a list [closed]

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I have a list e.g. ["1","2","n","5","n","x","0","v","-","a","l","4","1","v","m","z","o","5","%","d",";","a","m","6"]
I want to print out the elements that are a letter or special symbol.
how do I do this?

Python comes with an isnumeric() method that returns true when a string is a number. In the case you listed you could try:
string_list = ["1","2","n","5","n","x","0","v","-","a","l","4","1","v","m","z","o","5","%","d",";","a","m","6"]
for value in string_list:
if not value.isnumeric():
print(value)
...which would output
n
n
x
v
-
a
l
v
m
z
o
%
d
;
a
m

You can use isdigit(). Like so:
some_str = "12a"
for i in some_str:
print(i.isdigit())
# outputs
True
True
False

How Values are assigned in Anonymous function? [closed]

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I don't understand whether 15 is sent to x or n
def func_compute(n):
return lambda x : x * n
result = func_compute(2)
print("Double the number of 15 =", result(15))

Assume a function f(x, n) = xn. Now you want to have this function for a fixed n, i.e., f_n(x) = xn. This is what func_compute(n) does, it returns f_n(x), a function, for the given n.
result(15) is then f_2(15) = f(15, 2) = 30.

append all Integers of an integer in a list in python using recursive function [closed]

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I need an example of a recursive function that will append all integer elements of a number into a list using python and doing this with the most basic algorithm.
For example if n = 1234, list will be [1,2,3,4].

Try this?
def numberToList(number):
# base case
if number == 0:
return []
# recurse
return numberToList(number / 10) + [ number % 10 ]
Run it like this:
>>> numberToList(1234)
[4, 3, 2, 1]