I keep running into 'Page not found' when trying to load http://localhost:8000/ . I have an empty path set to direct the page to my project_index page, but this is all I get:
I have checked and re-checked all of my urlpatters, but cannot figure out where the problem is.
Here are all my urls.py scripts that correspond to this project:
personal_portfolio/:
projects/:
blog/:
You don't have anything starting with
urlpatterns = [
path("", ..... ),
]
in your main urls.py.
like all the URLs you defined has a suffix thus Django can't find it,
either you need to do
urlpatterns = [
path("", include('project.urls') ),
]
or
urlpatterns = [
path("", include('blog.urls') ),
]
Related
I am trying to attach hobbieswithCSS.html file to my website, while using Django. I am a beginner when it comes to Django, so I have naturally came across some problems (in the title) like this.
I have this anchor tag on my homepage -
My Hobbies
I have this view in my views.py file -
def hobbieswithCSS(request):
return render(request,'basic_app/hobbieswithCSS.html')
I think, that the main problem will be with the urlpatterns in urls.py file, because I am not sure how to set it up. These are my urlpatterns -
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^admin/', admin.site.urls),
url(r'^basic_app/',include('basic_app.urls')),
url(r'^logout/$',views.user_logout,name='logout'),
url(r'^$', views.hobbieswithCSS, name='hobbieswithCSS'),
]
Could anybody please tell me, how could I change the code in order to make that hobbieswithCSS.html file display, when I am trying to run it on my server?
It must be:
My Hobbies
Without basic_app.
Also you have the same path for index and hobbies . You have to change your url path:
urlpatterns = [
url(r'^$', views.index, name='index'),
...
url(r'^hobbies/$', views.hobbieswithCSS, name='hobbieswithCSS'),
]
in your template update to
My Hobbies
I am learning Django. I build an app in which I am setting up the URL patterns but in all cases it's displaying the data for the index page.
appTwo urls.py File :
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^$', views.users, name='users'),
url(r'^$', views.help, name='help'),
]
MyProject urls.py file :
urlpatterns = [
url(r'^$', views.index, name='index'),
url('admin/', admin.site.urls),
url(r'^users/', include('appTwo.urls')),
url(r'^help/', include('appTwo.urls')),
]
If I call /users or /help, the browser display the data for index file only.
Is there something with a regex that I am doing wrong?
You're setting your urlpatterns in a wrong way. First of all, in you project's urls.py file you are saying that if a request is sent to /users or /help, then Django should look into your appTwo.urls. When Django gets there, it finds that the urlpatters are set so that everything that's empty after any of the aforementioned urls must be handled by the views.index, views.users and views.help. But as views.index is the first one in the list, then all the request end up being handled by that view.
By the way, if you're using Django >= 2.0 you no longer need to use the url() function, but the path() one instead, for which you can declare the paths as simple strings rather than regular expressions.
You should have something as follows:
MyProject/urls.py
from django.urls import path
urlpatterns = [
path('', include('appTwo.urls')),
path('admin/', admin.site.urls)
]
MyApp/urls.py
from django.urls import path
urlpatterns = [
path('', views.index, name='index'),
path('users/', views.users, name='users'),
path('help/', views.help, name='help'),
]
when django reaches here (in your apps url) while resolving the urls, see all three urls have empty regex as first param (so the first one will be selected), And as you see its index then you always show index page. You need to differentiate the urls. Something like this.
urlpatterns = [
url(r'^users/$', views.users, name='users'),
url(r'^help/$', views.help, name='help'),
url(r'^$', views.index, name='index'),
]
I think you also cant write url index with empty regex at top of other urls, otherwise it will always be selected.
I am new to Django and I am trying to create sample project in it. Please help me in resolving this error.
My Main URLs.py file
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^t20_predict/', include('PredictMatch.urls')),
]
My Apps URLs.py file
app_name = 'PredictMatch'
urlpatterns = [
# t20_predict/T20
url(r'^T20/$', views.t20index, name='t20index'),
]
becuase
url(r'^T20/$', views.t20index, name='t20index')
you are not expecting any id ,the url is just t20_predict/T20/ -> see here there is no id
if you want the url to receive id as well the url pattern should be
url(r'^T20/(?P<id>[0-9]+)/$', views.t20index, name='t20index')
I believe this is a simple question but I am having a hard time figuring out why this is not working.
I have a django project and I've added a second app (sales). Prior to the second app, my urls.py simply routed everything to the first app (chart) with the following:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('chart.urls')),
]
and it worked fine.
I have read the docs over and over a looked at many tutorials, so my impression is that I can simply amend the urls.py to include:
urlpatterns = [
path('admin/', admin.site.urls),
path('sales/', include('sales.urls')),
path('', include('chart.urls')),
]
and it should first look for a url with sales/ and if it finds that then it should route it to sales.urls, and if it doesn't find that then move on and route it to chart.urls. However, when I load this and type in 127.0.0.1:8000/sales, it returns the following error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/sales/
Raised by: chart.views.index
which tells me that it is not routing my sales/ url to sales.urls but to chart.urls. When I change path('', include('chart.urls')), to path('', include('sales.urls')), it does route it to sales.urls so I know that my sales.urls file is set up correctly.
I know this is probably an easy question but I cannot figure it out with anything I've read. Any help is appreciated.
chart.urls:
from django.urls import path, re_path
from . import views
urlpatterns = [
path('dashboard/', views.chart, name='dashboard'),
path('', views.index, name='index', kwargs={'pagename': ''}),
path('<str:pagename>/', views.index, name='index'),
]
sales.urls:
from django.urls import path
from . import views
urlpatterns = [
path('sales/', views.sales, name='Sales Dashboard'),
]
I think the correct url for the sales page in your case would be http://127.0.0.1:8000/sales/sales/.
This is because sales/ is then looking in the included sales.urls and not finding any urls at the root / (the only url included there is at sales/ (within sales/) so will be sales/sales/
Reply to an OLD question but may be useful for others...
from django.urls import path, include
dont for get to import include
Do this:
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('chart.urls')),
url(r'^sales/', include('sales.urls')),
]
you are not doing it properly since you are not telling your app where go once it is loaded .this r'^' to go directly to chart.url url(r'^', include('chart.urls')),
myproject/urls.py
urlpatterns = [
url(r'^$', include('website-app.urls', namespace='website')),
]
website-app/urls.py
urlpatterns = [
url(r'^$', views.somedef, name='somename')
]
I want to connect url domain.com/ to views.somedef which is not in myproject.
What domain.com/ means is just domain and end of address with /.
It is with No other parameters.
domain.com/other/parameters/ has other parameters (other/parameters/), so it is not what I want.
If I run django with that above code, django says
?: (urls.W001) Your URL pattern '^$' uses include with a regex ending with a '$'. Remove the dollar from the regex to avoid problems including URLs.
Is there any good way to use url domain.com/ in website-app/urls.py ,
Not in myproject/urls.py?
This should work
myproject/urls.py
urlpatterns = [
url(r'^', include('website-app.urls', namespace='website')),
]
website-app/urls.py
urlpatterns = [
url(r'$', views.somedef, name='somename')
]