I´m lookiing for update one field, array in array
db.germain.updateOne({}, {$set: { "items.$[elem].sub_items.price" : 2}}, {arrayFilters: [ { "elem.sub_item_name": "my_item_two_one" } ] } )
I find one but it doesn´t update.
{
"_id" : ObjectId("4faaba123412d654fe83hg876"),
"user_id" : 123456,
"items" : [
{
"item_name" : "my_item_one",
"sub_items" : [
{
"sub_item_name" : "my_item_one_one",
"price" : 20
},
]
},
{
"item_name" : "my_item_two",
"sub_items" : [
{
"sub_item_name" : "my_item_two_one",
"price" : 30
},
{
"sub_item_name" : "my_item_two_two",
"price" : 50
},
]
}
]
}
Actually its nested array. So you need to specify which object in the parent array to be changed? and which object in the specified object of parent array to be changed.
db.collection.update({},
{
$set: {
"items.$[parent].sub_items.$[child].price": 2
}
},
{
arrayFilters: [
{ "parent.item_name": "my_item_two" },
{ "child.sub_item_name": "my_item_two_one" }
}
]
})
If you need o to change the whole object in parent array, simply you can use $ positional operator.
Related
I have a table in opensearch in which the format of every field is "text".
This is how my table looks like
Now the query(q1) which I am running in opensearch looks like this. i am not getting any output. But when I run query q2 then I get the output.
q1 = {"size":10,"query":{"bool":{"must":[{"multi_match":{"query":"cen","fields":["name","alias"],"fuzziness":"AUTO"}}],"filter":[{"match_phrase":{"category":"Specialty"}},{"match_phrase":{"prov_type":"A"}},{"match_phrase":{"prov_type":"C"}}]}}}
q2 = {"size":10,"query":{"bool":{"must":[{"multi_match":{"query":"cen","fields":["name","alias"],"fuzziness":"AUTO"}}],"filter":[{"match_phrase":{"category":"Specialty"}},{"match_phrase":{"prov_type":"A"}}]}}}
Now I want to apply multiple filtering on prov_type. I have tried using terms also with prov_type in list like ['A','B'].
Can anyone please answer this on how to apply multiple filters on value for single column in opensearch/elasticsearch. Datatype for every field is text.
Have already tried this - How to filter with multiple fields and values in elasticsearch?
Mapping for the index
GET index/_mapping
{
"spec_proc_comb_exp" : {
"mappings" : {
"properties" : {
"alias" : {
"type" : "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"ignore_above" : 256
}
}
},
"category" : {
"type" : "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"ignore_above" : 256
}
}
},
"name" : {
"type" : "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"ignore_above" : 256
}
}
},
"prov_type" : {
"type" : "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"ignore_above" : 256
}
}
},
"specialty_code" : {
"type" : "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"ignore_above" : 256
}
}
}
}
}
}
}
Please let me know in case you need anymore information
You can use the should query to filter your data with the OR condition.
Should: The clause (query) should appear in the matching document.
GET test_allergy/_search
{
"query": {
"bool": {
"should": [
{
"term": {
"prov_type": "A"
}
},
{
"term": {
"prov_type": "C"
}
}
],
"minimum_should_match": 1
}
}
}
Note: You can set minimum_should_match as a number or percentage.
I'm a total beginner in PyMongo. I'm trying to find activities that are registered multiple times. This code is returning an empty list. Could you please help me in finding the mistake:
rows = self.db.Activity.aggregate( [
{ '$group':{
"_id":
{
"user_id": "$user_id",
"transportation_mode": "$transportation_mode",
"start_date_time": "$start_date_time",
"end_date_time": "$end_date_time"
},
"count": {'$sum':1}
}
},
{'$match':
{ "count": { '$gt': 1 } }
},
{'$project':
{"_id":0,
"user_id":"_id.user_id",
"transportation_mode":"_id.transportation_mode",
"start_date_time":"_id.start_date_time",
"end_date_time":"_id.end_date_time",
"count": 1
}
}
]
)
5 rows from db:
{ "_id" : 0, "user_id" : "000", "start_date_time" : "2008-10-23 02:53:04", "end_date_time" : "2008-10-23 11:11:12" }
{ "_id" : 1, "user_id" : "000", "start_date_time" : "2008-10-24 02:09:59", "end_date_time" : "2008-10-24 02:47:06" }
{ "_id" : 2, "user_id" : "000", "start_date_time" : "2008-10-26 13:44:07", "end_date_time" : "2008-10-26 15:04:07" }
{ "_id" : 3, "user_id" : "000", "start_date_time" : "2008-10-27 11:54:49", "end_date_time" : "2008-10-27 12:05:54" }
{ "_id" : 4, "user_id" : "000", "start_date_time" : "2008-10-28 00:38:26", "end_date_time" : "2008-10-28 05:03:42" }
Thank you
When you pass _id: 0 in the $project stage, it will not project the sub-objects even if they are projected in the follow up, since the rule is overwritten.
Try the below $project stage.
{
'$project': {
"user_id":"_id.user_id",
"transportation_mode":"_id.transportation_mode",
"start_date_time":"_id.start_date_time",
"end_date_time":"_id.end_date_time",
"count": 1
}
}
rows = self.db.Activity.aggregate( [
{
'$group':{
"_id": {
"user_id": "$user_id",
"transportation_mode": "$transportation_mode",
"start_date_time": "$start_date_time",
"end_date_time": "$end_date_time"
},
"count": {'$sum':1}
}
},
{
'$match':{
"count": { '$gt': 1 }
}
},
{
'$project': {
"user_id":"_id.user_id",
"transportation_mode":"_id.transportation_mode",
"start_date_time":"_id.start_date_time",
"end_date_time":"_id.end_date_time",
"count": 1,
}
}
])
Your group criteria is likely too narrow.
The $group stage will create a separate output document for each distinct value of the _id field. The pipeline in the question will only include two input documents in the same group if they have exactly the same value in all four of those fields.
In order for a count to be greater than 1, there must exist 2 documents with the same user, mode, and exactly the same start and end.
In the same data you show, there are no two documents that would be in the same group, so all of the output documents from the $group stage would have a count of 1, and therefore none of them satisfy the $match, and the return is an empty list.
I need to get all objects inside "posts" that have "published: true"
with pymongo. I've tried already so many variants but all I can do:
for elt in db[collection].find({}, {"posts"}):
print(elt)
And it'll show all "posts". I've tried smth like this:
for elt in db[collection].find({}, {"posts", {"published": {"$eq": True}}}):
print(elt)
But it doesn't work. Help, I'm trying for 3 days already =\
What you want to be doing is to use the aggregate $filter like so:
db[collection].aggregate([
{
"$match": { // only fetch documents with such posts
"posts.published": {"$eq": True}
}
},
{
"$project": {
"posts": {
"$filter": {
"input": "$posts",
"as": "post",
"cond": {"$eq": ["$$post.published", True]}
}
}
}
}
])
Note that the currenct structure returned will be:
[
{posts: [post1, post2]},
{posts: [post3, post4]}
]
If you want to retrieve it as a list of posts you'll need to add an $unwind stage to flatten the array.
The query options are quite limited you can do it with $elemMatch (projection) or with the $ operator but both of these return only the first post that matches the condition which is not what you want.
------- EDIT --------
Realizing posts is actually an object and not an array, you'll have to turn the object to an array, iterate over to filter and then restore the structure like so:
db.collection.aggregate([
{
$project: {
"posts": {
"$arrayToObject": {
$filter: {
input: {
"$objectToArray": "$posts"
},
as: "post",
cond: {
$eq: [
"$$post.v.published",
true
]
}
}
}
}
}
}
])
Mongo Playground
What I assumed that your document looks like this,
{
"_id" : ObjectId("5f8570f8afdefd2cfe7473a7"),
"posts" : {
"a" : {
"p" : false,
"name" : "abhishek"
},
"k" : {
"p" : true,
"name" : "jack"
},
"c" : {
"p" : true,
"name" : "abhinav"
}
}}
You can try the following query but the result format will be a bit different, adding that for clarification,
db.getCollection('temp2').aggregate([
{
$project: {
subPost: { $objectToArray: "$posts" }
}
},
{
'$unwind' : '$subPost'
},
{
'$match' : {'subPost.v.p':true}
},
{
'$group': {_id:'$_id', subPosts: { $push: { subPost: "$subPost"} }}
}
])
result format,
{
"_id" : ObjectId("5f8570f8afdefd2cfe7473a7"),
"subPosts" : [
{
"subPost" : {
"k" : "k",
"v" : {
"p" : true,
"name" : "jack"
}
}
},
{
"subPost" : {
"k" : "c",
"v" : {
"p" : true,
"name" : "abhinav"
}
}
}
]
}
I have a DB in MongoDB that has 3 levels, and I want to get the value form last level. The structure is the following:
{
"_id" : "10000",
"Values" : [
{
"Value1" : "Article 1",
"Value2" : [
{
"Value2_1" : 1,
"Value2_2" : 2,
}
]
}
]
}
I need to get the value form the label "Value2_1".
So far my code is the following:
for row in collection.find({"_id":1, "Values.Value2.Value2_1":1})
print(row)
The output is always "None".
Any ideas about how to make the correct query?
Thanks!
By using dot (.) notation you can get your expected result.
db.collection.find({"Values.Value2.Value2_1" : 100})
The above query will select all documents where the Values array has Values2 array and Values2 has Values2_1 whose value is equal 100
Output:
{
"_id" : ObjectId("5b86bd1172876096c7a9d6cf"),
"Values" : [
{
"Value1" : "Article 1",
"Value2" : [
{
"Value2_1" : 100.0,
"Value2_2" : 200.0
},
{
"Value2_1" : 15.0,
"Value2_2" : 25.0
}
]
}
]
}
And if you try to search with _id then you don't need to use your
second condition because by definition _id is always unique.
This following query will also show the same result as above.
db.collection.find({"_id" : ObjectId("5b86bd1172876096c7a9d6cf")})
If you want to specifically get only those items from inner array which have fulfill your inner conditions, you can aggregate the query
PS - My 2 cents - I do not know if you require this, as i could not get it that clear from your question, i just thought you may be asking this.
db.coll.aggregate([{
$unwind: '$Values'
}, {
$project: {
'Values_F': {
$filter: {
input: "$Values.Value2",
as: "value2",
cond: {
$eq: ["$$value2.Value2_1", 1]
}
}
}
}
}, {
$project: {
'Values_F': 1,
'total': {
$size: '$Values_F'
}
}
}, {
$match: {
total: {
$gte: 1
}
}
}
])
MongoDB noob here...
So, I'm trying to print out the minimum value score inside a collection that looks like this...
> db.students.find({'_id': 1}).pretty()
{
"_id" : 1,
"name" : "Aurelia Menendez",
"scores" : [
{
"type" : "exam",
"score" : 60.06045071030959
},
{
"type" : "quiz",
"score" : 52.79790691903873
},
{
"type" : "homework",
"score" : 71.76133439165544
},
{
"type" : "homework",
"score" : 34.85718117893772
}
]
}
The incantation I'm using is as such...
db.students.aggregate(
// Initial document match (uses index, if a suitable one is available)
{ $match: {
_id : 1
}},
// Expand the scores array into a stream of documents
{ $unwind: '$scores' },
// Filter to 'homework' scores
{ $match: {
'scores.type': 'homework'
}},
// grab the minimum value score
{ $match: {
'scores.min.score': 1
}}
)
the output i'm getting is this...
{ "result" : [ ], "ok" : 1 }
What am I doing wrong?
You've got the right idea, but in the last step of the aggregation what you want to do is group all the scores by student and find the $min value.
Change the last pipeline operation to:
{ $group: {
_id: "$_id",
minScore: {$min: "$scores.score"}
}}
> db.students.aggregate(
{ $unwind: "$scores" },`
{ $match:{"scores.type":"homework"} },
{ $group: {
_id : "$_id",
maxScore : { $max : "$scores.score"},
minScore: { $min:"$scores.score"}
}
});
how to aggregate on each item in collection in mongoDB