Inheritance - Calling methods within methods - python

I know the super() function allows you to call a parent method from a child class. So in this example:
class Exam():
def __init__(self, a):
self.a = a
def show(self):
print("This is from parent method")
class Quiz(Exam):
def __init__(self, b, a):
super().__init__(a)
self.b = b
def show(self):
print("This is from child method")
super().show()
q = Quiz('b', 'a')
q.show()
>>> 'This is from child method'
>>> 'This is from parent method'
What if I added another method called get_score to both the parent and child class like here:
class Exam():
def __init__(self, a):
self.a = a
def show(self):
print("This is from parent method")
print (self.get_score())
def get_score(self):
return self.a
class Quiz(Exam):
def __init__(self, b, a):
super().__init__(a)
self.b = b
def show(self):
print("This is from child method")
super().show()
print (self.get_score())
def get_score(self):
return self.b
q = Quiz('b', 'a')
q.show()
>>> 'This is from child method'
>>> 'This is from parent method'
>>> 'b'
>>> 'b'
I can understand why calling super().show() in the child class would return 'b' since I am overwriting the get_score() method.
However, is there a way to maintain the integrity of the parent class so that when I do call super().show()
I get this instead?
>>> 'This is from child method'
>>> 'This is from parent method'
>>> 'a'
>>> 'b'
Sorry in advance if this is bad design. Let me know what other alternatives I can take, even if it means I should the name of the method to avoid this kind of collision.

Use name-mangling, which will prevent the name-collisions in the subclass
:
class Exam():
def __init__(self, a):
self.a = a
def show(self):
print("This is from parent method")
print (self.__get_score())
def __get_score(self):
return self.a
get_score = __get_score
class Quiz(Exam):
def __init__(self, b, a):
super().__init__(a)
self.b = b
def show(self):
print("This is from child method")
super().show()
print (self.__get_score())
def __get_score(self):
return self.b
get_score = __get_score
q = Quiz('b', 'a')
q.show()

Related

Default arguments in a child class and an inheritance (Python 3.10)

I want a child class to inherit from a parent class all methods and attributes with one small change - setting a default value for one argument in the child class shared with the parent class. How can I do it? With following code, I get an AttributeError when trying to call add method on the child class' instance.
https://pastebin.com/WFxmbyZD
def ParentClass():
"""An exemplary parent class."""
def __init__(self, a, b):
self.a = a
self.b = b
def adder(self):
return a + b
def ChildClass(ParentClass):
"""An exemplary child class."""
def __init__(self, a, b=3):
super().__init__(a, b)
child_class_instance = ChildClass(5)
print(child_class_instance.adder())
You have a mistake declaring the class.
I will show you examples here. The child class can have a different signature for the constructor and the methods.
class ParentClass:
"""An exemplary parent class."""
def __init__(self, a, b):
self.a = a
self.b = b
def adder(self):
return self.a + self.b
def adder_bis(self, c):
return self.a + self.b + c
class ChildClass(ParentClass):
"""An exemplary child class."""
def __init__(self, a, b=3):
super().__init__(a, b)
def adder_bis(self):
return super().adder_bis(self.a)
child_class_instance = ChildClass(5)
print(child_class_instance.adder())
print(child_class_instance.adder_bis())
I commented what I thought was wrong:
class ParentClass(): #class instead of def
"""An exemplary parent class."""
def __init__(self, a, b):
self.a = a
self.b = b
def adder(self):
return self.a + self.b #use self here
class ChildClass(ParentClass): #class instead of def
"""An exemplary child class."""
def __init__(self, a, b=3):
super().__init__(a, b)
child_class_instance = ChildClass(5)
print(child_class_instance.adder())
output:
8

How to inherit from pre-existing class instance in Python?

I have a class Parent:
class Parent:
def __init__(self, foo):
self.foo = foo
I then have another class Child which extends Parent. But I want Child to take a pre-existing instance of parent and use this as the parent to inherit from (instead of creating a new instance of Parent with the same constructor parameters).
class Child(Parent):
def __init__(self, parent_instance):
""" Do something with parent_instance to set this as the parent instance """
def get_foo(self):
return self.foo
Then I would ideally be able to do:
p = Parent("bar")
c = Child(p)
print(c.get_foo()) # prints "bar"
You could copy the content of the parents's __dict__ to the child's. You can use vars() builtin function to do so, and the dictionary's update() method.
class Child(Parent):
def __init__(self, parent_instance):
vars(self).update(vars(parent_instance))
def get_foo(self):
return self.foo
p = Parent("bar")
c = Child(p)
print(c.get_foo())
# prints "bar"
You can use your own constructor - provide a classmethod that takes an instance of a parent.
class Parent:
def __init__(self, foo):
self.foo = foo
class Child(Parent):
def get_foo(self):
return self.foo
#classmethod
def from_parent(cls, parent_instance):
return cls(parent_instance.foo)
p = Parent('bar')
c = Child.from_parent(p)
c.get_foo()
I'm not sure inheritance is the right solution here as it breaks the LSP in the __init__ method.
Maybe parents and children just share a common interface.
I'd prefer something like (python3.8):
from typing import Protocol
class FoeAware(Protocol):
#property
def foe(self):
...
class Parent:
def __init__(self, foe):
self._foe = foe
#property
def foe(self):
return self._foe
class Child:
def __init__(self, parent: FoeAware):
self.parent = parent
#property
def foe(self):
return self.parent.foe
p = Parent("bar")
c = Child(p)
c.foe # bar
The key point is that it takes advantage of polymorphism with a common interface FoeAware, which is preferable to an inheritance tree.
Using getattr() to fetch the attribute from the parent instance
class Parent:
def __init__(self, foo):
self.foo = foo
class Child(Parent):
def __init__(self, parent_instance):
self.parent_instance = parent_instance
def get_foo(self):
return self.foo
def __getattr__(self, attr):
return getattr(self.parent_instance, attr)
par = Parent("bar")
ch = Child(par)
print(ch.get_foo())
#prints bar

How to call child constructor from parent?

In inheritance, most of the time we want to create child classes that inherit from the parent, and in the process of instantiation they have to call the parent constructor. In python we use super for this, and that's great.
I want to do somewhat the opposite: I have a parent class which is a template for a number of child classes. Then I want the child classes to each have a function that allows an instance to clone itself:
class Parent(object):
def __init__(self, ctype, a):
print('This is the parent constructor')
self._ctype = ctype
self._a = a
#property
def a(self):
return self._a
#property
def ctype(self):
return self._ctype
class ChildOne(Parent):
def __init__(self, a):
super(ChildOne, self).__init__('one', a)
print('This is the child One constructor')
self.one = 1
def clone(self):
return ChildOne(self._a)
class ChildTwo(Parent):
def __init__(self, a):
super(ChildTwo, self).__init__('two', a)
print('This is the child Two constructor')
self.two = 2
def clone(self):
return ChildTwo(self._a)
Now, if I create an instance of one of the children, I can clone it:
>>> k = ChildOne(42)
>>> k.ctype
'one'
>>> l = k.clone()
>>> l.a
42
>>> l is k
False
The problem is, the clone method is repeated- and nearly identical- in both sub-classes, except I need to specify explicitly which constructor to call. Is it possible to design a clone method that I define in the parent class, that correctly inherits to the children?
This can be done with:
Code:
class Parent(object):
def clone(self):
return type(self)(self._a)
Test Code:
class Parent(object):
def __init__(self, ctype, a):
print('This is the parent constructor')
self._ctype = ctype
self._a = a
#property
def a(self):
return self._a
#property
def ctype(self):
return self._ctype
def clone(self):
return type(self)(self._a)
class ChildOne(Parent):
def __init__(self, a):
super(ChildOne, self).__init__('one', a)
print('This is the child One constructor')
self.one = 1
class ChildTwo(Parent):
def __init__(self, a):
super(ChildTwo, self).__init__('two', a)
print('This is the child Two constructor')
self.two = 2
k = ChildOne(42)
print(k.ctype)
l = k.clone()
print(l.a)
print(type(l))
Results:
This is the parent constructor
This is the child One constructor
one
This is the parent constructor
This is the child One constructor
42
<class '__main__.ChildOne'>

Accidentally calling an ovverriden method from base class's __init__

This program seems to do everything by the book, yet this issue cropped up: while a base class was being init'ed a member method was called that is overriden in the derived class and assumes that the derived class has been constructed.
Is there some best practice to protect against this?
#!/usr/bin/env python3
class A:
def __init__(self):
self.ax = 1
print(self)
def __repr__(self):
return "{} ax: {}".format(self.__class__.__name__, self.ax)
class B(A):
def __init__(self):
super().__init__()
self.bx = 10
def __repr__(self):
return super().__repr__() + " bx: {}".format(self.bx)
if __name__ == "__main__":
B()
And here's the error:
AttributeError: 'B' object has no attribute 'bx'
Generally, unless you really know what you are doing, you want to call the superclass initialization after everything your class needs to do is done. Same with this example, repr is trying to print self.bx before you initialize it. If you do
class B(A):
def __init__(self):
self.bx = 10
super().__init__()
def __repr__(self):
return super().__repr__() + " bx: {}".format(self.bx)
it works as expected
Edited:
Instead of doing computation on __init__, one idea may be to do that in a factory function/classmethod.
Example instead of doing:
class A:
def __init__(self, a, b):
self.a = a
self.b = b
self.initialize()
def initialize(self):
# do some things
Do:
class A:
def __init__(self, a, b):
self.a = a
self.b = b
#classmethod
def from_a_b(cls, a, b):
instance = cls(a, b)
instance.initialize()
return instance

Python : How to "merge" two class

I want to add some attributes and methods into various class. The methods and attributes that I have to add are the same but not the class to assign them, so I want to construct a class who assign new methods and attributes for a class given in argument.
I try this but it's not working:
(I know that is a very wrong way to try to assign something to self, it's just to show what I want to do)
class A:
def __init__(self):
self.a = 'a'
def getattA(self):
return self.a
class B:
def __init__(self, parent) :
self = parent
# This is working :
print self.getattA()
def getattB(self):
return self.getattA()
insta = A()
instb = B(insta)
# This is not working :
print instb.getattB()
The result is :
a
Traceback (most recent call last):
File "D:\Documents and settings\Bureau\merge.py", line 22, in <module>
print instb.getattB()
File "D:\Documents and settings\Bureau\merge.py", line 16, in getattB
return self.getattA()
AttributeError: B instance has no attribute 'getattA'
And I expected to got 'a' for the call of instb.gettattB()
To resume I want to inherit class B from class A giving class A in argument of class B because my class B will be a subclass of various class, not always A.
The Best answer is in the comments, it was useful for me so I decided to show it in an answer (thank to sr2222):
The way to dynamicaly declare inherance in Python is the type() built-in function.
For my example :
class A(object) :
def __init__(self, args):
self.a = 'a'
self.args = args
def getattA(self):
return self.a, self.args
class B(object) :
b = 'b'
def __init__(self, args) :
self.b_init = args
def getattB(self):
return self.b
C = type('C', (A,B), dict(c='c'))
instc = C('args')
print 'attributes :', instc.a, instc.args, instc.b, instc.c
print 'methodes :', instc.getattA(), instc.getattB()
print instc.b_init
The code return :
attributes : a args b c
methodes : ('a', 'args') b
Traceback (most recent call last):
File "D:\Documents and settings\Bureau\merge2.py", line 24, in <module>
print instc.b_init
AttributeError: 'C' object has no attribute 'b_init'
My class C inerhite attributes and methods of class A and class B and we add c attribute. With the instanciation of C (instc = C('args')) The init for A is call but not for B.
Very useful for me because I have to add some attributes and methodes (the same) on different class.
I was having trouble with calling different constructors, using super doesn't necessarily make sense in a case like this, I opted to inherit and call each constructor on the current object manually:
class Foo(object):
def __init__(self, foonum):
super(Foo, self).__init__()
self.foonum = foonum
class Bar(object):
def __init__(self, barnum):
super(Bar, self).__init__()
self.barnum = barnum
class DiamondProblem(Foo, Bar):
# Arg order don't matter, since we call the `__init__`'s ourself.
def __init__(self, barnum, mynum, foonum):
Foo.__init__(self, foonum)
Bar.__init__(self, barnum)
self.mynum = mynum
How about this?
class A:
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B:
def __init__(self, parent) :
self.parent = parent
def __getattr__(self, attr):
return getattr(self.parent, attr)
def getattB(self):
return self.parent.getatt()
insta = A()
instb = B(insta)
print instb.getattB()
print instb.getatt()
But method in class A can not access attr in class B.
Another way:
import functools
class A:
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B:
def __init__(self, parent):
for attr, val in parent.__dict__.iteritems():
if attr.startswith("__"): continue
self.__dict__[attr] = val
for attr, val in parent.__class__.__dict__.iteritems():
if attr.startswith("__"): continue
if not callable(val): continue
self.__dict__[attr] = functools.partial(val, self)
def getattB(self):
return self.getatt()
insta = A()
instb = B(insta)
print instb.__dict__
print instb.getattB()
print instb.getatt()
Slow with init but call fast.
Since B is not a subclass of A, there is no path in B to getatt() in A
I guess i have a easier method
class fruit1:
def __init__(self):
self.name = "apple"
self.color = "blue"
class fruit2:
def __init__(self):
self.name = "banana"
self.size = 100
def merge(ob1, ob2):
ob1.__dict__.update(ob2.__dict__)
return ob1
f1 = fruit1()
f2 = fruit2()
fruit = merge(f1, f2)
print("name:",fruit.name," color:",fruit.color, " size:",fruit.size)
#output: name: banana color: blue size: 100
I'm not certain what you are trying to do, but the code below is giving my the output I think you are expecting. notice:
a is initialized outside the constructor in A
B is declared as a subclass of A
Code:
class A:
a='' #Initialize a
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B(A): #Declare B as subclass
def __init__(self, parent) :
self = parent
print self.getatt()
def getattB(self):
return self.getatt()
insta = A()
instb = B(insta)
print instb.getattB()
Helper function below conducts the merge of the dataclass instances, the attributes orders is derived from *args order:
from dataclasses import dataclass
#dataclass
class A:
foo: str
bar: str
def merge_dataclasses(*args):
if len({e.__class__.__name__ for e in args}) > 1:
raise NotImplementedError('Merge of non-homogeneous entries no allowed.')
data = {}
for entry in args[::-1]:
data.update(vars(entry))
return entry.__class__(**data)
print(merge_dataclasses(A(foo='f', bar='bar'), A(foo='b_foo', bar='b_bar')))
One easy way to merge two or more classes is through the tool set dyndesign:
from dyndesign import mergeclasses
class Base:
def __init__(self, init_value):
self.param = init_value
def m1(self):
print(f"Method `m1` of class `Base`, and {self.param=}")
def m2(self):
print(f"Method `m2` of class `Base`")
class Ext:
def m1(self):
print(f"Method `m1` of class `Ext`, and {self.param=}")
MergedClass = mergeclasses(Base, Ext)
merged_instance = MergedClass("INITIAL VALUE")
merged_instance.m1()
# Method `m1` of class `Ext`, and self.param='INITIAL VALUE'
merged_instance.m2()
# Method `m2` of class `Base`
Emphasizing ThorSummoner's's answer and Hong's comment; this method appears to be cleaner than the excepted answer. Notice Hong's use of super().init(self) in all but the last object added to the merge class.
class Foo(object):
def __init__(self, foonum):
super(Foo, self).__init__(self)
self.foonum = foonum
class Bar(object):
def __init__(self, barnum):
super(Bar, self).__init__(self)
self.barnum = barnum
class Oops(object):
def __init__(self, oopsnum):
super(Oops, self).__init__()
self.oopsnum = oopsnum
class DiamondProblem(Foo, Bar, Oops):
def __init__(self, mynum, foonum, barnum, oopsnum):
Foo.__init__(self, foonum)
Bar.__init__(self, barnum)
Oops.__init__(self, oopsnum)
self.mynum = mynum
def main():
dia = DiamondProblem(1, 10, 20, 30)
print(f"mynum: {dia.mynum}")
print(f"foonum: {dia.foonum}")
print(f"barnum: {dia.barnum}")
print(f"oopsnum: {dia.oopsnum}")

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