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How to click on a webpage element with Python

Imgur Web Element
I want to write a line of code that clicks on the ellipsis on the webpage. I've attached the element description.
I can't share the webpage as it is password protected
Here's what I tried:
element = driver.find_element_by_css_selector('.fas.fa-ellipsis-v')
element.click()
I am expecting the ellipsis to pop open but i get the following error:
Message: no such element: Unable to locate element: {"method":"css selector","selector":".fas.fa-ellipsis-v"}

First of all, please, do not use images when your want a code review or help, it is more easier to help with raw code.
In that case:
Message: no such element: Unable to locate element: {"method":"css selector","selector":".fas.fa-ellipsis-v"}
Try to use this code below instead of driver.find_element_by_css_selector([...]) :
WebDriverWait(your_driver, your_timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, your_locator)))
or
WebDriverWait(your_driver, your_timeout).until(EC.visibility_of_element_located((By.CSS_SELECTOR, your_locator)))
After the WaitDriverWait, use your find and click code.
If you need more help locating elements by, try look the Selenium Docs.

It worked by using the following line:
driver.execute_script("arguments[0].click();", element)

I have "no such element: Unable to locate element" error although ID is 100% correct

I am trying to click on "OK" button on a pop up using selenium and Python but i face an error "no such element: Unable to locate element" although being sure that my id is 100% correct.
> <a class="dxm-content dxm-hasText dx dxalink" href="javascript:;" role="menuitem" id="Dialog_PAC_Menu_DXI0_T"><span class="dx-vam dxm-contentText">OK</span></a>
My python selenium code:
Export2 = driver.find_element(By.XPATH,'//a[#id="Dialog_PAC_Menu_DXI0_T"]')
Export2.click()
Where exactly did I go wrong, i also tried full Xpath, wait till clickable, time sleep. everything!
i would appreciate if someone can help me with it.

Well, it looks like you found the answer and that was because your element was inside an iFrame so I will just post an answer here so others can find an easy answer if they view your question.
tmpheader = driver.find_element(By.CSS_SELECTOR, "#modal > iframe")
driver.switch_to.frame(tmpheader)
Export2 = driver.find_element(By.XPATH,'//a[#id="Dialog_PAC_Menu_DXI0_T"]')
Export2.click()
This switches our current driver that we are looking for into the first iFrame element on the page. If there is more than one iFrame you would need to check for more attributes in the first line to make sure you are looking at the correct one

Actually that's how I solved my issue as my element was inside an iFrame as John Gordon suggested.
driver.switch_to.frame(driver.find_element(By.TAG_NAME,'iframe'))
slider = driver.find_element(By.XPATH,"//*[contains(#id,'_xaf_dviImportExportFormat_Edit_dropdown_DD_B-1Img')]").click()

Message: no such element: Unable to locate element python selenium

i have this error in selenium python
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"/html/body/div[24]/div[1]/div/div/div[3]/div[1]/div/button[1]"}
i want the element with this xpath:
driver.find_element_by_xpath("/html/body/div[24]/div[1]/div/div/div[3]/div[1]/div/button[1]").click()
if doesn't exist, then click other element with other xpath like:
driver.find_element_by_xpath("/html/body/div[24]/div[1]/div/div/div[3]/div[1]/div/button[2]").click()
everything is clear if element 1 doesn't exists to click, click to element 2
how can I do this in selenium python
thanks

NoSuchElementException generally occurs because of one the below reasons
Element locator is incorrect
Element is not rendered
Page is not rendered or loaded
Element is inside a frame
You can have a look, do a debug and based on that write your code. :)

This is not the exact solution, but this is the idea
if elem1.is_displayed():
elem1.click()
else:
elem2.click()

I'd suggest you using time.sleep(10) and a nested try block to catch your errors while it accomplishes what you want to do. For example:
time.sleep(10)
try:
driver.find_element_by_xpath("/html/body/div[24]/div[1]/div/div/div[3]/div[1]/div/button[1]").click()
except:
print("button1 could not be found... Now trying to retreive button2")
try:
driver.find_element_by_xpath("/html/body/div[24]/div[1]/div/div/div[3]/div[1]/div/button[2]").click()
except:
print("button1 nor button2 were not found...")
Note that the time.sleep(10) delays your code from executing anything after this line for 10 seconds, and this allows the page to load properly for elements to be located easier.

How do I click a button using Selenium in Python?

I'm trying to crawl review data on an app from a Google Play website page using Python and Selenium. What I'm trying to do here is to click the "Full Review" button to see the entire text of each review.
But I keep running into these errors each time:
ElementNotInteractableException: Message: element not interactable
or
AttributeError: 'list' object has no attribute 'click'
or
NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":".LkLjZd ScJHi OzU4dc "}
The element for the button is this:
<button class="LkLjZd ScJHi OzU4dc " jsaction="click:TiglPc" jsname="gxjVle">Full Review</button>
The xpath for the button is this:
//*[#id="fcxH9b"]/div[4]/c-wiz/div/div[2]/div/div[1]/div/div/div[1]/div[2]/div/div[26]/div/div[2]/div[2]/span[1]/div/button
And this is the code I'm using for xpath:
full_review = driver.find_elements_by_xpath('//*[#id="fcxH9b"]/div[4]/c-wiz/div/div[2]/div/div[1]/div/div/div[1]/div[2]/div/div[26]/div/div[2]/div[2]/span[1]/div/button')
full_review.click()
I can't find the button by class name, xpath or anything.
Could anyone help me figure out this problem? In addition, is it possible to find the element by jsname?
I would really appreciate if you could help.

Avoid using xpath whenever possible, it's the most brittle selector.
id > CSS > Xpath
For your button, this css selector should work:
button[jsname='gxjVle']
You'll probably need to specify the child as that probably won't be unique

Your XPath selector is a little bit flaky, you can simplify it to be something like:
//button[text()='Full Review']
You're using the wrong function, if you're looking for a single unique element you should be using WebDriver.find_element_by_xpath one, mind that element, not elements
It's better to use Explicit Wait just in case element is not immediately available in DOM (for example if you're testing application built using AJAX technology)
Assuming all above:
full_review = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Full Review']")))

Unable to click on the Link Text, have tried Find_ELEMENT_BY_LINK_TEXT and quite a few other things , but its not working

SCREENSHOT OF THE HTML
Here is the screenshot of html code with which I am struggling , I want to click on the Smart Watches in the left-Nav and I am using the following code to click on it
driver.implicitly_wait(30)
driver.find_element_by_link_text('Smart Watches').click()
But I am getting the following error and I am clueless why i just cant find it on page
selenium.common.exceptions.NoSuchElementException: Message: no such
element: Unable to locate element: {"method":"link
text","selector":"Smart Watches"} (Session info:
chrome=60.0.3112.113) (Driver info: chromedriver=2.29.461591
(62ebf098771772160f391d75e589dc567915b233),platform=Windows NT
6.2.9200 x86_64)
I have also tried the explicit code and Expected conditions as follows -:
wait = WebDriverWait(driver, 20)
link = wait.until(expected_conditions.presence_of_element_located((By.LINK_TEXT,'"Smart Watches"')))
link.click()
But even its giving me Timeout exception
Here is the link of the page where I am stuck since morning
https://www.kogan.com/au/shop/phones/
I am very new to coding , any help would be helpful !! I just want to know why find_element_by_link_text is not working here , it looks weird to me!!
Thanks in advance

The problem is that when you use find_element_by_link_text(), it must be an exact match to the text contained in the link. In your HTML picture, you can see "Smart Watches" but what you aren't seeing is the SPAN just below but still inside the A is closed. Most likely if you expand it, you will see additional text that you must include if you are going to use find_element_by_link_text().
Another option is find_element_by_partial_link_text() which is more like a contains() instead of equals(). Depending on the page, it may find too many matches. You would have to try and see if it works.
Yet another option is using an XPath. There are a lot of different ways to create an XPath for this depending on exactly what you want.
This is the most general and thus most likely to find unwanted links but it may work. It's pretty much the same as find_element_by_partial_link_text()
//a[contains(.,'Smart Watches')
Other options include
//a[starts-with(.,'Smart Watches')
//li[#data-filter-facet='smart-watches']/a[contains(.,'Smart Watches')
//li[#data-filter-facet='smart-watches']/a[starts-with(.,'Smart Watches')
... and so on...

You can try this way...
Accessing text: find_element_by_xpath["//a[contains(text(), 'Smart Watches')]"].click()

Don't know why it is not wotks but partial link text works. Please see my java code for the same:
WebDriver driver=new FirefoxDriver();
driver.get("https://www.kogan.com/au/shop/phones/");
WebElement watch=driver.findElement(By.partialLinkText("Smart Watch"));
WebDriverWait waitElement=new WebDriverWait(driver, 30);
waitElement.until(ExpectedConditions.elementToBeClickable(watch));
watch.click();

You need to add double quotation marks, as it is in the html code:
driver.find_element_by_link_text('"Smart Watches"').click()

most of the time it might happen that link is taking some more time to load after your page has loaded. rather than using implicit wait use explicit wait.
wait = WebDriverWait(driver, 30)
link = wait.until(expected_conditions.presence_of_element_located((By.LINK_TEXT,"Smart Watches")))
link.click()
it could also be the case that link is inside another frame, in this case you will have to switch to this frame.