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How to convert dict containing tuple values to string [closed]

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How to convert the following Input to the desired output using python.
Input:
{'Id': (34,), 'user': ('a.t#gmail.com',), 'createdOn': ('12 Oct',), 'status': (False,), 'message': ('Hello',)}
Output:
{'Id': 34, 'user': 'a.t#gmail.com', 'createdOn':'12 Oct', 'status': False, 'message': 'Hello'}

Just take first index for each value :
your_dict = {'Id': (34,), 'user': ('a.t#gmail.com',), 'createdOn': ('12 Oct',), 'status': (False,), 'message': ('Hello',)}
your_dict = {key:val[0] for key, val in your_dict.items()}

Why are the values in a tuple to begin with?
old_dict = {'Id': (34,), 'user': ('a.t#gmail.com',), 'createdOn': ('12 Oct',), 'status': (False,), 'message': ('Hello',)}
new_dict = {k:v[0] for k,v in old_dict.items()}
print(new_dict)

Python: TypeError: string indices must be integers [closed]

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This is a similar problem posted here lots of time but I am unable to get my head around it.
import json
str2 ="""[{'cta': [], 'ctr': 2880509, 'client_id': '229132', 'exchange': 'NSE_EQ', 'token': '3063', 'product': 'CO', 'order_type': 'M', 'duration': 'DAY', 'price': '0', 'trigger_price': '149.10', 'quantity': 1, 'disclosed_quantity': 0, 'side': 'S', 'avg_price': '148.10', 'traded_quantity': 1, 'pending_quantity': 0, 'message': '', 'exchange_order_id': '1300000006005800', 'syom_order_id': 'NA', 'order_number': '191101000336718', 'timestamp': '01/11/2019,12:19:45', 'exchange_timestamp': '01-Nov-2019 12:19:45', 'status': 'complete', 'time_in_micro': '1572590985928000', 'is_amo': False, 'order_complexity': 'CO', 'request_id': '1', 'valid_date': '--', 'tag': 'JWEB|TB1', 'comments': 'PLACE ORDER :: 229132|NSE_EQ|3063|EQ|I|0|1|S|CO|WEB|IP-172-31-4-125|1572590985897', 'fill_id': '', 'original_message': '', '_amo': False}]"""
str2 = (json.dumps(str2))
print(str2)
print(str2['client_id'])
Why this doesn't work? It says -
print(str2['client_id'])
TypeError: string indices must be integers
Note that str2 is output from someplace and my goal is to fetch the client_id or any other variable.
So what I am seeking is what is the possible way to parse it?

There are mutliple problems here. You don't seem to be thinking this through.
You start with a string. Calling json.dumps on a string just gives you another string. But you couldn't have called json.loads on the original string either, because it is not JSON; it appears to be a string representation of a Python object.
But then, even if you had correctly parsed it, it still wouldn't work, because it represents a list of dictionaries, not a single dict.
It seems unlikely that this is actually the output from your external system. If you want further help, you will need to explain exactly how you got that string.

how to prevent a for loop from overwriting a dictionary? [closed]

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I am creating a dictionary for a JSON file, through the use of a for loop.
However my for loop overwrites the entries
second_dict={}
third_dict={}
name=['suzen','lilly','sara']
hobbies=['chess','reading','dancing']
age=[13,14,15]
for i in range(len(name)):
second_dict["hobbies"]=hobbies[i]
second_dict["age"]=age[i]
third_dict[name[i]]=second_dict
print(third_dict)
I am getting this output
{'suzen': {'hobbies': 'chess', 'age': 13},
'lilly': {'hobbies': 'chess', 'age': 13},
'sara': {'hobbies': 'chess', 'age': 13}}
Instead of getting this one
{'suzen': {'hobbies': 'chess', 'age': 13},
'lilly': {'hobbies': 'reading', 'age': 14},
'sara': {'hobbies': 'dancing', 'age': 15}}
can anyone please point out my mistake?
thank you

new_dict={}
name=['suzen','lilly','sara']
hobbies=['chess','reading','dancing']
age=[13,14,15]
x = zip(name, hobbies, age)
for n,h,a in x:
new_dict[n]={'hobbies': h, 'age': a}
print(new_dict)
third_dict={}
name=['suzen','lilly','sara']
hobbies=['chess','reading','dancing']
age=[13,14,15]
for i in range(len(name)):
second_dict={}
second_dict["hobbies"]=hobbies[i]
second_dict["age"]=age[i]
third_dict[name[i]]=second_dict
print(third_dict)
As pointed in comments, you should create a new object for each second_dict, there are 3 second_dict.

How to build array from json input file in python 3? [closed]

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I am trying to build an array from the information comming from a local json file.
The desired output array format is:
output = [
'elementa-element2-element3',
'elementa-element2-element3',
]
The input from json is:
import json
with open('/Users/user/test.json', 'r') as f:
array = json.load(f)
print (array)
{'responseHeader': {'zkConnected': True, 'status': 0, 'QTime': 2, 'params': {'q': 'facet_gender:man', 'start': '0', 'fq': 'lang:de', 'rows': '10000', 'wt': 'json', 'facet': 'true'}}, 'response': {'numFound': 1005, 'start': 0, 'docs': [
{'rmc': 'm228238-0042', 'title': 'Day-Date 40', 'family': 'Day-Date', 'familyCode': 'day-date', 'facet_case_title': ['Oyster, 40 mm, Gelbgold']},
{'rmc': 'm326935-0007', 'title': 'Sky-Dweller', 'family': 'Sky-Dweller', 'familyCode': 'sky-dweller', 'facet_case_title': ['Oyster, 42 mm, Everose-Gold']}, ...
How can I acess the rows and build my array from all rows?
output = array
while i < len(array)
output[i] = array['response']['docs'][i]['familyCode']+'/'+array['response']['docs'][i]['rmc']

The json.load() will return a dictionary. This dictionary can be nested, if the json file contains nested elements. This is the case in your example, too.
If you format your json a little bit, it will be more clear:
{
'responseHeader': {
'zkConnected': True,
'status': 0,
'QTime': 2,
'params': {
'q': 'facet_gender:man',
'start': '0',
'fq': 'lang:de',
'rows': '10000',
'wt': 'json',
'facet':
'true'
}
},
'response': {
'numFound': 1005,
'start': 0,
'docs': [
{'rmc': 'm228238-0042', 'title': 'Day-Date 40', 'family': 'Day-Date', 'familyCode': 'day-date', 'facet_case_title': ['Oyster, 40 mm, Gelbgold']},
{'rmc': 'm326935-0007', 'title': 'Sky-Dweller', 'family': 'Sky-Dweller', 'familyCode': 'sky-dweller', 'facet_case_title': ['Oyster, 42 mm, Everose-Gold']},
...
]
}
}
If you want to retrieve the "docs", you actually need this:
array["response"]["docs"]
In your example, it is a list, and it can be used as you would normally do.
Example 1: get the first element of the list
documents = array["response"]["docs"] # Create new variable "documents".
print(documents[0]) # Print out first element of "docs" variable.
Example 2: Iterate over every element:
documents = array["response"]["docs"]
for document in documents:
print(document)

How can I turn integers into strings in a dict using Python? [closed]

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I'm creating a dictionary from the college scorecard API, but I'm having trouble joining integer queries to my dictionary (ie. "2015.student.size"). How would I do that in my code? I've tried "str() for f in", but that doesn't seem to work.
This is what I've written in Python so far:
import requests
import json
def main():
url = 'https://api.data.gov/ed/collegescorecard/v1/schools.json'
payload = {
'api_key': "api_key_here",
'_fields': ','.join([
'school.name',
'school.school_url',
'school.city',
'school.state',
'school.zip',
]),
'school.operating': '1',
'2015.academics.program_available.assoc_or_bachelors': 'true',
'2015.student.size__range': '1..',
'school.degrees_awarded.predominant__range': '1..3',
'school.degrees_awarded.highest__range': '2..4',
'id': '240444',
}
data = requests.get(url, params=payload).json()
for result in data['results']:
print(','.join(result.values()))
main()
What happens when I run the program:
vagrant#vagrant:/vagrant/scripts$ python test.py
Madison,www.wisc.edu,University of Wisconsin-Madison,WI,53706-1380
When I add "print data":
{u'results': [{u'school.city': u'Madison', u'school.school_url': u'ww
w.wisc.edu', u'school.name': u'University of Wisconsin-Madison', u'sc
hool.state': u'WI', u'school.zip': u'53706-1380'}], u'metadata': {u'p
er_page': 20, u'total': 1, u'page': 0}}

I think you are making this more difficult than necessary. Instead of the for loop, you can do
print(data)
Or if you want each dictionary from the list to be on its own line, instead of
print(','.join(result.values()))
Just do
print(result)