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Cant replace spaces in a python variable

i tried to replace spaces in a variable in python but it returns me this error
AttributeError: 'HTTPHeaders' object has no attribute 'replace'
this is my code
for req in driver.requests:
print(req.headers)
d = req.headers
x = d.replace("""
""", "")

So, if you check out the class HTTPHeaders you'll see it has a __repr__ function and that it's an HTTPMessage object.
Depending on what you exactly want to achieve (which is still not clear to me!, i.e, for which header do you want to replace spaces?) you can go about this two ways. Use the methods on the HTTPMessage object (documented here) or use the string version of it by calling repr on the response. I recommend you use the first approach as it is much cleaner.
I'll give an example in which I remove spaces for all canary values in all of the requests:
for req in driver.requests:
canary = req.headers.get("canary")
canary = canary.replace(" ", "")
P.S., your question is nowhere near clear enough as it stands. Only after asking multiple times and linking your other question it becomes clear that you are using seleniumwire, for example. Ideally, the code you provide can be run by anyone with the installed packages and reproduces the issue you have. BUT, allright, the comments made it more clear.

How to remove automatically m. part from the URL with keeping the rest of the current link in full

How to automatically remove the m. from the URL, while keeping the rest of the current link in full, in order to switch from mobile mode to computer mode in Selenium by Python 3.8.2
https://m.facebook.com/*************
I have tried this code but failed
driver.get('https://m.facebook.com/***********').replace("https://m.", "")

You can do this by just using the replace() function of the str class:
link = 'https://m.facebook.com/whatever'
link = link.replace('/m.facebook', '/facebook')
EDIT: After seeing your updated answer, what you were doing wrong is that you were trying to call the replace() function on get(). You need to call it directly after the string.
driver.get('https://m.facebook.com/***********'.replace("https://m.", ""))

Some help understanding my own Python code

I'm starting to learn Python and I've written the following Python code (some of it omitted) and it works fine, but I'd like to understand it better. So I do the following:
html_doc = requests.get('[url here]')
Followed by:
if html_doc.status_code == 200:
soup = BeautifulSoup(html_doc.text, 'html.parser')
line = soup.find('a', class_="some_class")
value = re.search('[regex]', str(line))
print (value.group(0))
My questions are:
What does html_doc.text really do? I understand that it makes "text" (a string?) out of html_doc, but why isn't it text already? What is it? Bytes? Maybe a stupid question but why doesn't requests.get create a really long string containing the HTML code?
The only way that I could get the result of re.search was by value.group(0) but I have literally no idea what this does. Why can't I just look at value directly? I'm passing it a string, there's only one match, why is the resulting value not a string?

requests.get() return value, as stated in docs, is Response object.
re.search() return value, as stated in docs, is MatchObject object.
Both objects are introduced, because they contain much more information than simply response bytes (e.g. HTTP status code, response headers etc.) or simple found string value (e.g. it includes positions of first and last matched characters).
For more information you'll have to study docs.
FYI, to check type of returned value you may use built-in type function:
response = requests.get('[url here]')
print type(response) # <class 'requests.models.Response'>

Seems to me you are lacking some basic knowledge about Classes, Object and methods...etc, you need to read more about it here (for Python 2.7) and about requests module here.
Concerning what you asked, when you type html_doc = requests.get('url'), you are creating an instance of class requests.models.Response, you can check it by:
>>> type(html_doc)
<class 'requests.models.Response'>
Now, html_doc has methods, thus html_doc.text will return to you the server's response
Same goes for re module, each of its methods generates response object that are not simply int or string

Strange urllib2.urlopen() error with variable vs string

I am having some strange behavior while using urllib2 to open a URL and download a video.
I am trying to open a video resource and here is an example link:
https://zencoder-temp-storage-us-east-1.s3.amazonaws.com/o/20130723/b3ed92cc582885e27cb5c8d8b51b9956/b740dc57c2a44ea2dc2d940d93d772e2.mp4?AWSAccessKeyId=AKIAI456JQ76GBU7FECA&Signature=S3lvi9n9kHbarCw%2FUKOknfpkkkY%3D&Expires=1374639361
I have the following code:
mp4_url = ''
#response_body is a json response that I get the mp4_url from
if response_body['outputs'][0]['label'] == 'mp4':
mp4_url = response_body['outputs'][0]['url']
if mp4_url:
logging.info('this is the mp4_url')
logging.info(mp4_url)
#if I add the line directly below this then it works just fine
mp4_url = 'https://zencoder-temp-storage-us-east-1.s3.amazonaws.com/o/20130723/b3ed92cc582885e27cb5c8d8b51b9956/b740dc57c2a44ea2dc2d940d93d772e2.mp4?AWSAccessKeyId=AKIAI456JQ76GBU7FECA&Signature=S3lvi9n9kHbarCw%2FUKOknfpkkkY%3D&Expires=1374639361'
mp4_video = urllib2.urlopen(mp4_url)
logging.info('succesfully opened the url')
The code works when I add the designated line but it gives me a HTTP Error 403: Forbidden message when I don't which makes me think it is messing up the mp4_url somehow. But the confusing part is that when I check the logging line for mp4_url it is exactly what I hardcoded in there. What could the difference be? Are there some characters in there that may be disrupting it? I have tried converting it to a string by doing:
mp4_video = urllib2.urlopen(str(mp4_url))
But that didn't do anything. Any ideas?
UPDATE:
With the suggestion to use print repr(mp4_url) it is giving me:
u'https://zencoder-temp-storage-us-east-1.s3.amazonaws.com/o/20130723/b3ed92cc582885e27cb5c8d8b51b9956/b740dc57c2a44ea2dc2d940d93d772e2.mp4?AWSAccessKeyId=AKIAI456JQ76GBU7FECA&Signature=S3lvi9n9kHbarCw%2FUKOknfpkkkY%3D&Expires=1374639361'
And I suppose the difference is what is causing the error but what would be the best way to parse this?
UPDATE II:
It ended up that I did need to cast it to a string but also the source that I was getting the link (an encoded video) needed nearly a 60 second delay before it could serve that URL so that is why it kept working when I hardcoded it because it had that delay. Thanks for the help!

It would be better to simply dump the response obtained. This way you would be able to check what response_body['outputs'][0]['label'] evaluates to. In you case, you are initializing mp4_url to ''. This is not the same as None and hence the condition if mp4_url: will always be true.
You may want to check that the initial if statement where you check that response_body['outputs'][0]['label'] is correct.

Push a raw value to Firebase via REST API

I am trying to use the requests library in Python to push data (a raw value) to a firebase location.
Say, I have urladd (the url of the location with authentication token). At the location, I want to push a string, say International. Based on the answer here, I tried
data = {'.value': 'International'}
p = requests.post(urladd, data = sjson.dumps(data))
I get <Response [400]>. p.text gives me:
u'{\n "error" : "Invalid data; couldn\'t parse JSON object, array, or value. Perhaps you\'re using invalid characters in your key names."\n}\n'
It appears that they key .value is invalid. But that is what the answer linked above suggests. Any idea why this may not be working, or how I can do this through Python? There are no problems with connection or authentication because the following works. However, that pushes an object instead of a raw value.
data = {'name': 'International'}
p = requests.post(urladd, data = sjson.dumps(data))
Thanks for your help.

The answer you've linked is a special case for when you want to assign a priority to a value. In general, '.value' is an invalid name and will throw an error.
If you want to write just "International", you should write the stringified-JSON version of that data. I don't have a python example in front of me, but the curl command would be:
curl -X POST -d "\"International\"" https://...

Andrew's answer above works. In case someone else wants to know how to do this using the requests library in Python, I thought this would be helpful.
import simplejson as sjson
data = sjson.dumps("International")
p = requests.post(urladd, data = data)
For some reason I had thought that the data had to be in a dictionary format before it is converted to stringified JSON version. That is not the case, and a simple string can be used as an input to sjson.dumps().