This question already has answers here:
Why does python use 'else' after for and while loops?
(24 answers)
Closed 2 years ago.
In the image attached, when i=3, why does the "break" take us to the final print("Out side the loop")? Why doesn't it jump to the part:
else:
print ("Loop terminates with success")?
I am struggling to understand this.
for...else loops only run the else when the loop terminates normally and a break is not encountered. So, it skips the else since the loop was ended early.
Related
This question already has answers here:
It is more efficient to use if-return-return or if-else-return?
(9 answers)
Closed 6 months ago.
I've always had the habit to put else statements but I'm wondering if there's any reason not to, if it works.
Here's an example:
def multiply_by_two(number, display_original_number=False):
result = number*2
if display_original_number is True:
return f'Multiplying {number}: {result}'
return f'{result}'
print(multiply_by_two(5, True))
print(multiply_by_two(5))
Output:
Multiplying 5: 10
10
If I put else: return f'{result}', it's bascially the same thing, right? Is there any reason I would want to put an else statement in such cases?
Within this use case there is no difference functionally. Personal preference would dictate this decision if you find it easier to read back your code using else: .
This question already has answers here:
Why is the purpose of the "else" clause following a "for" or "while" loop? [duplicate]
(2 answers)
Closed 2 years ago.
I am new to python programming. I am a little confused in the below code, how else statements work without corresponding if statement. Could anyone please explain to me the below code. Program is Prime number between two intervel.
start=int(input("Enter Number: "))
stop=int(input("Enter Second Number: "))
for i in range(start,stop):
if i>1:
for j in range(2,i//2+1):
if(i%j==0):
break
else:
print(i)
In Python, loops can have an else statement. However, think more of a try-except statement than a if clause.
An example:
for item in container:
if search_something(item):
# Found it!
break
else:
# Didn't find anything..
This question already has answers here:
How can I read inputs as numbers?
(10 answers)
What's the canonical way to check for type in Python?
(15 answers)
Closed 2 years ago.
I'm working on a script to take user input and write it into an Excel file
currently the script works but when trying to add in logic to reject non-integer answers, one of two things happen:
it gets stuck in an infinite loop after properly rejecting the first answer where it keeps asking for a new answer and never accepts it
it properly rejects the first answers, but then accepts the second no matter what it is
this is the code being used where it gets stuck in an infinite loop (I have tried a few other variations that do the same thing but this is the most recent)
true = True
x = input('What is the first marked distance?')
while true == True:
if x == int:
cl.value = x
break
else:
x = input('Please enter a whole number')
any advice on why this is looping and not working would be greatly appreciated
Use float(x)%1 == 0 instead of x == int
This question already has answers here:
How to run a script forever? [duplicate]
(8 answers)
Closed 3 years ago.
I do not know how to do code that is executing over and over again. I would like to achieve something like this:
(< stands for input, > stands for output)
message=input()
print('Write down the text.')
>Write down the text.
<qwerty
>qwerty
>Write down the text.
<asd
>asd
You can achieve this with a
while True:
// code you want to execute repeatedly here
The while loop will continue to execute until the condition becomes false (which it never will, in this case) so if/when you want to break out of the loop you'll need to have use a break statement
Do you mean like this?
while True:
message=input("Write down the text: ")
print(message)
This question already has answers here:
Asking the user for input until they give a valid response
(22 answers)
Closed 6 years ago.
Basically, I have a "raw_input" then an "if" statement and then many "elif" statements after it. If the user inputs invalid data I want the "else" to print a string, then restart the program so the user can try again. How can I do this?
Put your code in a loop:
while True:
# Code here
To exit the loop, use break, which will also quit the program.
while True:
# Code here
if running == False: # The condition for breaking is up to you, if you're using one
break