Allowing Python Script to run even on --help argument in argparse - python

I am using Argparse module in python for developing a Command Line Tool.
Here's the parser code:
from argparse import ArgumentParser
def arguments():
parser = ArgumentParser()
parser.add_argument('-c' , '--comms' , action = "store" , default = None , type = str , dest = "command",
help = 'Choosing a Command')
parser.add_argument( '-s' , '--search' , action = 'store' , default = None , type = str , dest = 'search_path' ,
help = 'Search for a command' )
parser.add_argument( '-f' , '--config' , action = 'store_true' ,
help = 'Show the present configuration')
parser.add_argument('--flush_details' , action = "store_false" ,
help = "Flushes the current commands buffer")
return parser.parse_args()
def main():
parser_results = arguments()
#More code comes here to analyze the results
However, when I run the code python foo.py --help, it never runs the script post parsing the arguments. Is there anything I can do to stop the behaviour. I want to analyse the parser results even if it is just asked for --help switch.
Would like to know what can I do to continue the script even after --help has been used

Remark: you should not do that, because it does not respect established usages and may disturb users. For the remaining of the answer I shall assume that you are aware of it and have serious reasons for not respecting common usages.
The only way I can imaging is to remove the standard -h|--help processing and install your own:
parser = ArgumentParser(add_help=False)
parser.add_argument('-h' , '--help', help = 'show this help', action='store_true')
...
Then in option processing, you just add:
parser_results = parser.parse_args()
if parser_results.help:
parser.print_help()

As user Thierry Lathuille has said in the comments, --help is meant to print the help and exit.
If for some reason you want to print the help and run the script, you can add your own argument like so:
import argparse
parser = argparse.ArgumentParser(description="This script prints Hello World!")
parser.add_argument("-rh", "--runhelp", action="store_true", help="Print help and run function")
if __name__ == "__main__":
args = parser.parse_args()
if args.runhelp:
parser.print_help()
print('Hello World!')
If the name of the script is main.py:
>>> python main.py -rh
usage: main.py [-h] [-rh]
This script prints Hello World!
optional arguments:
-h, --help show this help message and exit
-rh, --runhelp Print help and run function
Hello World!
EDIT:
If you insist on using --help instead of a custom argument:
import argparse
parser = argparse.ArgumentParser(description="This script prints Hello World!", add_help=False)
parser.add_argument("-h", "--help", action="store_true", help="Print help and run function")
if __name__ == "__main__":
args = parser.parse_args()
if args.help:
parser.print_help()
print('Hello World!')
If the name of the script is main.py:
>>> python main.py -h
usage: main.py [-h]
This script prints Hello World!
optional arguments:
-h, --help Print help and run function
Hello World!

Set the add_help parameter for argparse.ArgumentParser to False to disable -h and --help:
parser=argparse.ArgumentParser(add_help=False)
Then, add --help:
parser.add_argument('--help',action='store_true')

Related

How to get my argparse subparsers format be like in a list and not on one single line?

I have this code as the test
import argparse
def main():
parser = argparse.ArgumentParser("test", description="subparser help test")
commands = parser.add_subparsers(dest="command", title="Commands")
subparser_a = commands.add_parser("parser_a", description="description_of_parser_a")
subparser_a.add_argument("--foo")
subparser_a.add_argument("--bar")
subparser_b = commands.add_parser("parser_b", description="description_of_parser_b")
subparser_b.add_argument("--foo-b")
subparser_b.add_argument("--bar-b")
args = parser.parse_args()
if __name__ == '__main__':
main()
but when i run python test.py --help, it shows something like this
usage: test [-h] {parser_a,parser_b} ...
subparser help test
optional arguments:
-h, --help show this help message and exit
Commands:
{parser_a,parser_b}
but what i expect it to print is something like this
usage: test [-h] {parser_a,parser_b} ...
subparser help test
optional arguments:
-h, --help show this help message and exit
Commands:
parser_a description_of_parser_a
parser_b description_of_parser_b
is their any workaround or way to do that?
You have to change your code like below. description= -> help= in add_parser
import argparse
def main():
...
subparser_a = commands.add_parser("parser_a", help="description_of_parser_a")
...
subparser_b = commands.add_parser("parser_b", help="description_of_parser_b")
...
args = parser.parse_args()
if __name__ == '__main__':
main()

collecting input files from command line in unix using argparse library

I'm trying to write a script that would take some flags and files as arguments and then execute other scripts, depend on the flag that the user chooses. For example, the command line should look like that:
main_script.py -flag1 -file_for_flag_1 another_file_for_flag_1
and
main_script.py -flag2 -file_for_flag_2
I tried to use the argparse library, but I don't know how to take the input files as arguments for the next steps and manipulate them as I want. I started with:
parser = argparse.ArgumentParser(description="Processing inputs")
parser.add_argument(
"-flat_map",
type=str,
nargs="+",
help="generates a flat addressmap from the given files",
)
parser.add_argument(
"-json_convert",
type=str,
nargs="+",
help="generates a flat addressmap from the given files",
)
args = parser.parse_args(args=["-flat_map"])
print(args)
I printed args in the end to see what I get from it but I got nothing I can work with.
Would like to have some guidance. Thanks.
You can convert the args to a dict (where the key is the arg option and the value is the arg value) if it's more convenient for you:
args_dict = {key: value for key, value in vars(parser.parse_args()).items() if value}
Using argparse you can use sub-commands to select sub-modules:
import argparse
def run_command(parser, args):
if args.command == 'command1':
# add code for command1 here
print(args)
elif args.command == 'command2':
# add code for command2 here
print(args)
parser = argparse.ArgumentParser(
prog='PROG',
epilog="See '<command> --help' to read about a specific sub-command."
)
subparsers = parser.add_subparsers(dest='command', help='Sub-commands')
A_parser = subparsers.add_parser('command1', help='Command 1')
A_parser.add_argument("--foo")
A_parser.add_argument('--bar')
A_parser.set_defaults(func=run_command)
B_parser = subparsers.add_parser('command2', help='Command 2')
B_parser.add_argument('--bar')
B_parser.add_argument('--baz')
B_parser.set_defaults(func=run_command)
args = parser.parse_args()
if args.command is not None:
args.func(parser, args)
else:
parser.print_help()
This generates a help page like so:
~ python args.py -h
usage: PROG [-h] {command1,command2} ...
positional arguments:
{command1,command2} Sub-commands
command1 Command 1
command2 Command 2
optional arguments:
-h, --help show this help message and exit
See '<command> --help' to read about a specific sub-command.
and help text for each sub-command:
~ python args.py B -h
arg.py command2 -h
usage: PROG command2 [-h] [--bar BAR] [--baz BAZ]
optional arguments:
-h, --help show this help message and exit
--bar BAR
--baz BAZ

Make argparse behave same way in python 2 and 3

So, I'm writing a program in python using argparse. But my problem is it behaves differently in python 2 and 3. Here's the code
import argparse,sys
class CustomParser(argparse.ArgumentParser):
def error(self, message):
sys.stderr.write('\033[91mError: %s\n\033[0m' % message)
self.print_help()
sys.exit(2)
parser = CustomParser(description='Short sample app')
subparsers = parser.add_subparsers(title='Available sub-commands', dest="choice", help="choose from one of these")
ana = subparsers.add_parser("test",
formatter_class=argparse.RawTextHelpFormatter,
description = 'test',
help ="test")
ana.add_argument("-testf", type=int, help="a test flag", required=True)
args = parser.parse_args()
in python 2 it gives output (just by typing python file.py no -h flag)
Error: too few arguments
usage: test.py [-h] {test} ...
Short sample app
optional arguments:
-h, --help show this help message and exit
Available sub-commands:
{test} choose from one of these
test test
But, if I run the same in python 3 (python3 file.py) it gives no out put. I know if I provide the -h flag then I can see the description. But I want the help description to appear just by typing python3 file.py just like the python 2. Also note, I don't want to make the subparser required.

python argparse don't show correct help message

I have a python script using argparse. After typing in python script_name.py -h on the command line, it shows help message for another command but the code still works. The script can recognize options defined in it and run well. It looks like the script is packaged by something. I put argparse in a function and everything works well at the beginning. I just can't find out what causes the help message changed.
Here is the code:
#!/usr/bin/env python
import os
import sys
import json
import logging
import argparse
import handlers
HZZ_DIR = os.path.dirname(os.path.abspath(__file__))
ROOT_DIR = os.path.dirname(os.path.dirname(HZZ_DIR))
logger = logging.getLogger('hzz_logger')
logger.setLevel(logging.DEBUG)
console = logging.StreamHandler()
console.setLevel(logging.INFO)
logger.addHandler(console)
def parse_args():
arg_parser = argparse.ArgumentParser()
arg_parser.add_argument('job', choices=['ws','lm','np'],
help="ws: workspace; lm: limit; np: npranking")
arg_parser.add_argument('-a', '--action', nargs=1,
help="for Limit and NPranking: get/plot (limit/pull)")
arg_parser.add_argument('-b', '--blinded', action='store_true',
help="for Limit: true -- do expected only, false -- do observed as well.")
arg_parser.add_argument('-v', '--version', nargs=1, type=int,
help="input version")
arg_parser.add_argument('-t', '--tag', nargs=1,
help='workspace tag')
arg_parser.add_argument('-m', '--mass', nargs='+', type=int,
help='signal mass(es)')
arg_parser.add_argument('-c', '--config', nargs=1,
help='configure file')
arg_parser.add_argument('-u', '--update', action='store_true',
help="update default settings")
args = arg_parser.parse_args()
return args
def load_settings(args):
pass
def run_job(settings):
pass
def execute():
args = parse_args()
settings = load_settings(args)
run_job(settings)
if __name__ == '__main__':
execute()
The help message is pasted here, which is actually the help message a command not directly used in this code. The options for this command can also be recognized...
$ python hzz_handler.py -h
Usage: python [-l] [-b] [-n] [-q] [dir] [[file:]data.root] [file1.C ... fileN.C]
Options:
-b : run in batch mode without graphics
-x : exit on exception
-n : do not execute logon and logoff macros as specified in .rootrc
-q : exit after processing command line macro files
-l : do not show splash screen
dir : if dir is a valid directory cd to it before executing
-? : print usage
-h : print usage
--help : print usage
-config : print ./configure options
-memstat : run with memory usage monitoring
Wow, another anti-Pythonic ROOT mystery! Your question and the comments are really helpful. Why did not anybody post the answer with ROOT.PyConfig.IgnoreCommandLineOptions = True?
Here is a primitive work-around:
import argparse
# notice! ROOT takes over argv and prints its own help message when called from command line!
# instead I want the help message for my script
# therefore, check first if you are running from the command line
# and setup the argparser before ROOT cuts in
if __name__ == '__main__':
parser = argparse.ArgumentParser(
formatter_class = argparse.RawDescriptionHelpFormatter,
description = "my script",
epilog = "Example:\n$ python my_script.py -h"
)
parser.add_argument("param", type=str, help="a parameter")
parser.add_argument("-d", "--debug", action='store_true', help="DEBUG level of logging")
args = parser.parse_args()
if args.debug:
logging.basicConfig(level=logging.DEBUG)
else:
logging.basicConfig(level=logging.INFO)
logging.debug("parsed args: %s" % repr(args))
import ROOT
...
if __name__ == '__main__':
<do something with args>
In sort the answer is that always calls import ROOT after the argparse. Then ROOT won't take over the argparse and prints the required message that we want.

Simple argparse example wanted: 1 argument, 3 results

The documentation for the argparse python module, while excellent I'm sure, is too much for my tiny beginner brain to grasp right now. I don't need to do math on the command line or meddle with formatting lines on the screen or change option characters. All I want to do is "If arg is A, do this, if B do that, if none of the above show help and quit".
Here's the way I do it with argparse (with multiple args):
parser = argparse.ArgumentParser(description='Description of your program')
parser.add_argument('-f','--foo', help='Description for foo argument', required=True)
parser.add_argument('-b','--bar', help='Description for bar argument', required=True)
args = vars(parser.parse_args())
args will be a dictionary containing the arguments:
if args['foo'] == 'Hello':
# code here
if args['bar'] == 'World':
# code here
In your case simply add only one argument.
My understanding of the original question is two-fold. First, in terms of the simplest possible argparse example, I'm surprised that I haven't seen it here. Of course, to be dead-simple, it's also all overhead with little power, but it might get you started.
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("a")
args = parser.parse_args()
if args.a == 'magic.name':
print 'You nailed it!'
But this positional argument is now required. If you leave it out when invoking this program, you'll get an error about missing arguments. This leads me to the second part of the original question. Matt Wilkie seems to want a single optional argument without a named label (the --option labels). My suggestion would be to modify the code above as follows:
...
parser.add_argument("a", nargs='?', default="check_string_for_empty")
...
if args.a == 'check_string_for_empty':
print 'I can tell that no argument was given and I can deal with that here.'
elif args.a == 'magic.name':
print 'You nailed it!'
else:
print args.a
There may well be a more elegant solution, but this works and is minimalist.
The argparse documentation is reasonably good but leaves out a few useful details which might not be obvious. (#Diego Navarro already mentioned some of this but I'll try to expand on his answer slightly.) Basic usage is as follows:
parser = argparse.ArgumentParser()
parser.add_argument('-f', '--my-foo', default='foobar')
parser.add_argument('-b', '--bar-value', default=3.14)
args = parser.parse_args()
The object you get back from parse_args() is a 'Namespace' object: An object whose member variables are named after your command-line arguments. The Namespace object is how you access your arguments and the values associated with them:
args = parser.parse_args()
print (args.my_foo)
print (args.bar_value)
(Note that argparse replaces '-' in your argument names with underscores when naming the variables.)
In many situations you may wish to use arguments simply as flags which take no value. You can add those in argparse like this:
parser.add_argument('--foo', action='store_true')
parser.add_argument('--no-foo', action='store_false')
The above will create variables named 'foo' with value True, and 'no_foo' with value False, respectively:
if (args.foo):
print ("foo is true")
if (args.no_foo is False):
print ("nofoo is false")
Note also that you can use the "required" option when adding an argument:
parser.add_argument('-o', '--output', required=True)
That way if you omit this argument at the command line argparse will tell you it's missing and stop execution of your script.
Finally, note that it's possible to create a dict structure of your arguments using the vars function, if that makes life easier for you.
args = parser.parse_args()
argsdict = vars(args)
print (argsdict['my_foo'])
print (argsdict['bar_value'])
As you can see, vars returns a dict with your argument names as keys and their values as, er, values.
There are lots of other options and things you can do, but this should cover the most essential, common usage scenarios.
Matt is asking about positional parameters in argparse, and I agree that the Python documentation is lacking on this aspect. There's not a single, complete example in the ~20 odd pages that shows both parsing and using positional parameters.
None of the other answers here show a complete example of positional parameters, either, so here's a complete example:
# tested with python 2.7.1
import argparse
parser = argparse.ArgumentParser(description="An argparse example")
parser.add_argument('action', help='The action to take (e.g. install, remove, etc.)')
parser.add_argument('foo-bar', help='Hyphens are cumbersome in positional arguments')
args = parser.parse_args()
if args.action == "install":
print("You asked for installation")
else:
print("You asked for something other than installation")
# The following do not work:
# print(args.foo-bar)
# print(args.foo_bar)
# But this works:
print(getattr(args, 'foo-bar'))
The thing that threw me off is that argparse will convert the named argument "--foo-bar" into "foo_bar", but a positional parameter named "foo-bar" stays as "foo-bar", making it less obvious how to use it in your program.
Notice the two lines near the end of my example -- neither of those will work to get the value of the foo-bar positional param. The first one is obviously wrong (it's an arithmetic expression args.foo minus bar), but the second one doesn't work either:
AttributeError: 'Namespace' object has no attribute 'foo_bar'
If you want to use the foo-bar attribute, you must use getattr, as seen in the last line of my example. What's crazy is that if you tried to use dest=foo_bar to change the property name to something that's easier to access, you'd get a really bizarre error message:
ValueError: dest supplied twice for positional argument
Here's how the example above runs:
$ python test.py
usage: test.py [-h] action foo-bar
test.py: error: too few arguments
$ python test.py -h
usage: test.py [-h] action foo-bar
An argparse example
positional arguments:
action The action to take (e.g. install, remove, etc.)
foo-bar Hyphens are cumbersome in positional arguments
optional arguments:
-h, --help show this help message and exit
$ python test.py install foo
You asked for installation
foo
Yet another summary introduction, inspired by this post.
import argparse
# define functions, classes, etc.
# executes when your script is called from the command-line
if __name__ == "__main__":
parser = argparse.ArgumentParser()
#
# define each option with: parser.add_argument
#
args = parser.parse_args() # automatically looks at sys.argv
#
# access results with: args.argumentName
#
Arguments are defined with combinations of the following:
parser.add_argument( 'name', options... ) # positional argument
parser.add_argument( '-x', options... ) # single-char flag
parser.add_argument( '-x', '--long-name', options... ) # flag with long name
Common options are:
help: description for this arg when --help is used.
default: default value if the arg is omitted.
type: if you expect a float or int (otherwise is str).
dest: give a different name to a flag (e.g. '-x', '--long-name', dest='longName'). Note: by default --long-name is accessed with args.long_name
action: for special handling of certain arguments
store_true, store_false: for boolean args '--foo', action='store_true' => args.foo == True
store_const: to be used with option const '--foo', action='store_const', const=42 => args.foo == 42
count: for repeated options, as in ./myscript.py -vv '-v', action='count' => args.v == 2
append: for repeated options, as in ./myscript.py --foo 1 --foo 2 '--foo', action='append' => args.foo == ['1', '2']
required: if a flag is required, or a positional argument is not.
nargs: for a flag to capture N args ./myscript.py --foo a b => args.foo = ['a', 'b']
choices: to restrict possible inputs (specify as list of strings, or ints if type=int).
Note the Argparse Tutorial in Python HOWTOs. It starts from most basic examples, like this one:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("square", type=int,
help="display a square of a given number")
args = parser.parse_args()
print(args.square**2)
and progresses to less basic ones.
There is an example with predefined choice for an option, like what is asked:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("square", type=int,
help="display a square of a given number")
parser.add_argument("-v", "--verbosity", type=int, choices=[0, 1, 2],
help="increase output verbosity")
args = parser.parse_args()
answer = args.square**2
if args.verbosity == 2:
print("the square of {} equals {}".format(args.square, answer))
elif args.verbosity == 1:
print("{}^2 == {}".format(args.square, answer))
else:
print(answer)
Here's what I came up with in my learning project thanks mainly to #DMH...
Demo code:
import argparse
def main():
parser = argparse.ArgumentParser()
parser.add_argument('-f', '--flag', action='store_true', default=False) # can 'store_false' for no-xxx flags
parser.add_argument('-r', '--reqd', required=True)
parser.add_argument('-o', '--opt', default='fallback')
parser.add_argument('arg', nargs='*') # use '+' for 1 or more args (instead of 0 or more)
parsed = parser.parse_args()
# NOTE: args with '-' have it replaced with '_'
print('Result:', vars(parsed))
print('parsed.reqd:', parsed.reqd)
if __name__ == "__main__":
main()
This may have evolved and is available online: command-line.py
Script to give this code a workout: command-line-demo.sh
code file: argparseDemo.py
Simple: common case
name(abbr, full), with help
import argparse
argParser = argparse.ArgumentParser()
argParser.add_argument("-n", "--name", help="your name")
args = argParser.parse_args()
print("args=%s" % args)
print("args.name=%s" % args.name)
call
python argparseDemo.py -n Crifan
python argparseDemo.py --name Crifan
output: args=Namespace(name='Crifan') and args.name=Crifan
type
argParser.add_argument("-a", "--age", type=int, help="your current age")
print("type(args.age)=%s" % type(args.age))
call: python argparseDemo.py --age 30
output: type(args.age)=<class 'int'> and args.age=30
required
argParser.add_argument("-a", "--age", required=True, type=int, help="your current age")
call: python argparseDemo.py
output: error argparseDemo.py: error: the following arguments are required: -a/--age
default
argParser.add_argument("-a", "--age", type=int, default=20, help="your current age. Default is 20")
call: python argparseDemo.py
output: args.age=20
choices
argParser.add_argument("-f", "--love-fruit", choices=['apple', 'orange', 'banana'], help="your love fruits")
call: python argparseDemo.py -f apple
output: args=Namespace(love_fruit='apple') and args.love_fruit=apple
multi args
argParser.add_argument("-f", "--love-fruit", nargs=2, help="your love fruits")
call: python argparseDemo.py -f apple orange
output: args.love_fruit=['apple', 'orange']
Detail
most simple: -x
code:
import argparse
argParser = argparse.ArgumentParser()
argParser.add_argument("-a") # most simple -> got args.a, type is `str`
args = argParser.parse_args()
print("args.a=%s" % args.a)
usage = run in command line
python argparseDemo.py -a 30
or: ./argparseDemo.py -a 30
makesure argparseDemo.py is executable
if not, add it: chmod +x argparseDemo.py
output
args.a=30
Note
default type is str
argParser.add_argument("-a") == argParser.add_argument("-a", type=str)
print("type(args.a)=%s" % type(args.a)) -> type(args.a)=<class 'str'>
args type is Namespace
print("type(args)=%s" % type(args)) -> type(args)=<class 'argparse.Namespace'>
args value is Namespace(a='30')
print("args=%s" % args) -> args=Namespace(a='30')
so we can call/use args.a
parameter name
full parameter name: --xxx
code
argParser.add_argument("-a", "--age")
usage
python argparseDemo.py -a 30
or: python argparseDemo.py --age 30
get parsed value: args.age
Note: NOT args.a, and NOT exist args.a
full parameter name with multiple words: --xxx-yyy
code
argParser.add_argument("-a", "--current-age")
get parsed value: args.current_age
add help description: help
code
argParser.add_argument("-a", help="your age") # with help
output
use --help can see description
 python argparseDemo.py --help
usage: argparseDemo.py [-h] [-a A]
optional arguments:
-h, --help show this help message and exit
-a A your age
designate parameter type: type
code
argParser.add_argument("-a", type=int) # parsed arg is `int`, not default `str`
output
print("type(args.a)=%s" % type(args.a)) -> type(args.a)=<class 'int'>
print("args=%s" % args) -> args=Namespace(a=30)
add default value: default
code
argParser.add_argument("-a", type=int, default=20) # if not pass a, a use default value: 20
effect
usage: python argparseDemo.py
output: print("args.age=%s" % args.age) -> args=Namespace(a=20)
You could also use plac (a wrapper around argparse).
As a bonus it generates neat help instructions - see below.
Example script:
#!/usr/bin/env python3
def main(
arg: ('Argument with two possible values', 'positional', None, None, ['A', 'B'])
):
"""General help for application"""
if arg == 'A':
print("Argument has value A")
elif arg == 'B':
print("Argument has value B")
if __name__ == '__main__':
import plac
plac.call(main)
Example output:
No arguments supplied - example.py:
usage: example.py [-h] {A,B}
example.py: error: the following arguments are required: arg
Unexpected argument supplied - example.py C:
usage: example.py [-h] {A,B}
example.py: error: argument arg: invalid choice: 'C' (choose from 'A', 'B')
Correct argument supplied - example.py A :
Argument has value A
Full help menu (generated automatically) - example.py -h:
usage: example.py [-h] {A,B}
General help for application
positional arguments:
{A,B} Argument with two possible values
optional arguments:
-h, --help show this help message and exit
Short explanation:
The name of the argument usually equals the parameter name (arg).
The tuple annotation after arg parameter has the following meaning:
Description (Argument with two possible values)
Type of argument - one of 'flag', 'option' or 'positional' (positional)
Abbreviation (None)
Type of argument value - eg. float, string (None)
Restricted set of choices (['A', 'B'])
Documentation:
To learn more about using plac check out its great documentation:
Plac: Parsing the Command Line the Easy Way
To add to what others have stated:
I usually like to use the 'dest' parameter to specify a variable name and then use 'globals().update()' to put those variables in the global namespace.
Usage:
$ python script.py -i "Hello, World!"
Code:
...
parser.add_argument('-i', '--input', ..., dest='inputted_variable',...)
globals().update(vars(parser.parse_args()))
...
print(inputted_variable) # Prints "Hello, World!"
New to this, but combining Python with Powershell and using this template, being inspired by an in-depth and great Python Command Line Arguments – Real Python
There is a lot you can do within the init_argparse() and I am covering just the most simple scenario here.
import argparse
use if __name__ == "__main__": main() pattern to execute from terminal
parse arguments within the main() function that has no parameters as all
define a init_argparse() function
create a parser object by calling argparse.ArgumentParser()
declare one or more argumnent with parser.add_argument("--<long_param_name>")
return parser
parse args by creating an args object by calling parser.parse_args()
define a function proper with param1, param2, ...
call function_proper with params being assigned as attributes of an args object
e.g. function_proper(param1=args.param1, param2=args.param2)
within a shell call the module with named arguments:
e.g. python foobar.py --param1="foo" --param2=="bar"
#file: foobar.py
import argparse
def function_proper(param1, param2):
#CODE...
def init_argparse() -> argparse.ArgumentParser:
parser = argparse.ArgumentParser()
parser.add_argument("--param1")
parser.add_argument("--param2")
return parser
def main() -> None:
parser = init_argparse()
args = parser.parse_args()
function_proper(param1=args.param1, param2=args.param2)
if __name__ == "__main__":
main()
>>> python .\foobar.py --param1="foo" --param2=="bar"
I went through all the examples and answers and in a way or another they didn't address my need. So I will list her a scenario that I need more help and I hope this can explain the idea more.
Initial Problem
I need to develop a tool which is getting a file to process it and it needs some optional configuration file to be used to configure the tool.
so what I need is something like the following
mytool.py file.text -config config-file.json
The solution
Here is the solution code
import argparse
def main():
parser = argparse.ArgumentParser(description='This example for a tool to process a file and configure the tool using a config file.')
parser.add_argument('filename', help="Input file either text, image or video")
# parser.add_argument('config_file', help="a JSON file to load the initial configuration ")
# parser.add_argument('-c', '--config_file', help="a JSON file to load the initial configuration ", default='configFile.json', required=False)
parser.add_argument('-c', '--config', default='configFile.json', dest='config_file', help="a JSON file to load the initial configuration " )
parser.add_argument('-d', '--debug', action="store_true", help="Enable the debug mode for logging debug statements." )
args = parser.parse_args()
filename = args.filename
configfile = args.config_file
print("The file to be processed is", filename)
print("The config file is", configfile)
if args.debug:
print("Debug mode enabled")
else:
print("Debug mode disabled")
print("and all arguments are: ", args)
if __name__ == '__main__':
main()
I will show the solution in multiple enhancements to show the idea
First Round: List the arguments
List all input as mandatory inputs so second argument will be
parser.add_argument('config_file', help="a JSON file to load the initial configuration ")
When we get the help command for this tool we find the following outcome
(base) > python .\argparser_example.py -h
usage: argparser_example.py [-h] filename config_file
This example for a tool to process a file and configure the tool using a config file.
positional arguments:
filename Input file either text, image or video
config_file a JSON file to load the initial configuration
optional arguments:
-h, --help show this help message and exit
and when I execute it as the following
(base) > python .\argparser_example.py filename.txt configfile.json
the outcome will be
The file to be processed is filename.txt
The config file is configfile.json
and all arguments are: Namespace(config_file='configfile.json', filename='filename.txt')
But the config file should be optional, I removed it from the arguments
(base) > python .\argparser_example.py filename.txt
The outcome will be is:
usage: argparser_example.py [-h] filename config_file
argparser_example.py: error: the following arguments are required: c
Which means we have a problem in the tool
Second Round : Make it optimal
So to make it optional I modified the program as follows
parser.add_argument('-c', '--config', help="a JSON file to load the initial configuration ", default='configFile.json', required=False)
The help outcome should be
usage: argparser_example.py [-h] [-c CONFIG] filename
This example for a tool to process a file and configure the tool using a config file.
positional arguments:
filename Input file either text, image or video
optional arguments:
-h, --help show this help message and exit
-c CONFIG, --config CONFIG
a JSON file to load the initial configuration
so when I execute the program
(base) > python .\argparser_example.py filename.txt
the outcome will be
The file to be processed is filename.txt
The config file is configFile.json
and all arguments are: Namespace(config_file='configFile.json', filename='filename.txt')
with arguments like
(base) > python .\argparser_example.py filename.txt --config_file anotherConfig.json
The outcome will be
The file to be processed is filename.txt
The config file is anotherConfig.json
and all arguments are: Namespace(config_file='anotherConfig.json', filename='filename.txt')
Round 3: Enhancements
to change the flag name from --config_file to --config while we keep the variable name as is we modify the code to include dest='config_file' as the following:
parser.add_argument('-c', '--config', help="a JSON file to load the initial configuration ", default='configFile.json', dest='config_file')
and the command will be
(base) > python .\argparser_example.py filename.txt --config anotherConfig.json
To add the support for having a debug mode flag, we need to add a flag in the arguments to support a boolean debug flag. To implement it i added the following:
parser.add_argument('-d', '--debug', action="store_true", help="Enable the debug mode for logging debug statements." )
the tool command will be:
(carnd-term1-38) > python .\argparser_example.py image.jpg -c imageConfig,json --debug
the outcome will be
The file to be processed is image.jpg
The config file is imageConfig,json
Debug mode enabled
and all arguments are: Namespace(config_file='imageConfig,json', debug=True, filename='image.jpg')
A really simple way to use argparse and amend the '-h'/ '--help' switches to display your own personal code help instructions is to set the default help to False, you can also add as many additional .add_arguments as you like:
import argparse
parser = argparse.ArgumentParser(add_help=False)
parser.add_argument('-h', '--help', action='help',
help='To run this script please provide two arguments')
parser.parse_args()
Run: python test.py -h
Output:
usage: test.py [-h]
optional arguments:
-h, --help To run this script please provide two arguments
As an addition to existing answers, if you are lazy enough, it is possible to use code generation tool called protoargs. It generates arguments parser from the configuration. For python it uses argparse.
Configuration with optional A and B:
syntax = "proto2";
message protoargs
{
optional string A = 1; // A param description
optional string B = 2; // B param description
}//protoargs
Configuration with required A and B:
syntax = "proto2";
message protoargs
{
required string A = 1; // A param description
required string B = 2; // B param description
}//protoargs
Configuration with positional A and B:
syntax = "proto2";
message protoargs
{
required string A = 1; // A param description
required string B = 2; // B param description
}//protoargs
message protoargs_links
{
}//protoargs_links
Now all you should run is:
python ./protoargs.py -i test.proto -o . --py
And use it (it is possible to take other examples here):
import sys
import test_pa
class ArgsParser:
program = "test"
description = "Simple A and B parser test."
def parse(self, argv):
self.config = test_pa.parse(self.program, self.description, argv)
def usage(self):
return test_pa.usage(self.program, self.description)
if __name__ == "__main__":
parser = ArgsParser()
if len(sys.argv) == 1:
print(parser.usage())
else:
parser.parse(sys.argv[1:])
if parser.config.A:
print(parser.config.A)
if parser.config.B:
print(parser.config.B)
If you want more - change configuration, regenerate parser, use an updated parser.config.
UPD: As mentioned in rules, I must specify that this is my own project
code:
import argparse
parser=argparse.ArgumentParser()
parser.add_argument('-A', default=False, action='store_true')
parser.add_argument('-B', default=False, action='store_true')
args=parser.parse_args()
if args.A:
print('do this')
elif args.B:
print('do that')
else:
print('help')
running result:
$ python3 test.py
help
$ python3 test.py -A
do this
$ python3 test.py -B
do that
$ python3 test.py -C
usage: test.py [-h] [-A] [-B]
test.py: error: unrecognized arguments: -C
As for the original request (if A ....), I would use argv to solve it, not using argparse at all:
import sys
if len(sys.argv)==2:
if sys.argv[1] == 'A':
print('do this')
elif sys.argv[1] == 'B':
print('do that')
else:
print('help')
else:
print('help')
Since you have not clarified wheather the arguments 'A' and 'B' are positional or optional, I'll make a mix of both.
Positional arguments are required by default. If not giving one will throw 'Few arguments given' which is not the case for the optional arguments going by their name. This program will take a number and return its square by default, if the cube option is used it shall return its cube.
import argparse
parser = argparse.ArgumentParser('number-game')
parser.add_argument(
"number",
type=int,
help="enter a number"
)
parser.add_argument(
"-c", "--choice",
choices=['square','cube'],
help="choose what you need to do with the number"
)
# all the results will be parsed by the parser and stored in args
args = parser.parse_args()
# if square is selected return the square, same for cube
if args.c == 'square':
print("{} is the result".format(args.number**2))
elif args.c == 'cube':
print("{} is the result".format(args.number**3))
else:
print("{} is not changed".format(args.number))
usage
$python3 script.py 4 -c square
16
Here the optional arguments are taking value, if you just wanted to use it like a flag you can too. So by using -s for square and -c for cube we change the behaviour, by adding action = "store_true". It is changed to true only when used.
parser.add_argument(
"-s", "--square",
help="returns the square of number",
action="store_true"
)
parser.add_argument(
"-c", "--cube",
help="returns the cube of number",
action="store_true"
)
so the conditional block can be changed to,
if args.s:
print("{} is the result".format(args.number**2))
elif args.c:
print("{} is the result".format(args.number**3))
else:
print("{} is not changed".format(args.number))
usage
$python3 script.py 4 -c
64
The simplest answer!
P.S. the one who wrote the document of argparse is foolish
python code:
import argparse
parser = argparse.ArgumentParser(description='')
parser.add_argument('--o_dct_fname',type=str)
parser.add_argument('--tp',type=str)
parser.add_argument('--new_res_set',type=int)
args = parser.parse_args()
o_dct_fname = args.o_dct_fname
tp = args.tp
new_res_set = args.new_res_set
running code
python produce_result.py --o_dct_fname o_dct --tp father_child --new_res_set 1

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