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For example, when I tried to get the user's username, this happens: Hello, [{'users': 'username'}]
How can I remove the rest, and get only the username?
appreciate the help!
Your question isn't clear
So, in order to get the username. First we need to iterate. Like this:
val = [{'users': 'username'}]
for values in val:
print(values["users"])
So this prints the 'username' in the dictionary.
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spam = ['cat','dog','bat']
spam.insert(0,'poo')
spam
this is my code, why is there nothing showing after I run this program?
Use
print(spam)
to show the content of "spam". Writing "spam" won't change anything.
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My questions refers to a "concatenation" of a Python dictionary. For example: I have a dictionary di = {1:'AB', 2:'BC',3:'CD'}, and I want with one command print(____) to get the output 'ABCD'.
Any suggestions?
Try This One.
print(''.join(str(e) for e in list(sorted(set(di[1]+di[2]+di[3]))))
Hope that this is what you wanted
di = {1:'AB', 2:'BC',3:'CD'}
print((di[1]+di[2]+di[3]).replace((di[2]),''))
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I have a passage. Is there a way from which I could scramble the words from the passage?
First, create a list with all the words of the passage.
If you have the text in another file, use "readlines" and "for" to iterate over it.
Then, use something like:
import random
List_Of_Words = ["these","are","the","words"]
random.shuffle(List_Of_Words)
Hope this helps !
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How to find and replace given string from list elements?
Enumerate the list and reassign each element to be itself but with the string in question replaced by nothing.
for idx,item in enumerate(my_list):
my_list[idx] = my_list[idx].replace(removed_string, '')
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I would need something like
{"a"=1,"b"=2,"c"=3,"d"=4}
but python is not able to decode it, it gives me an error message. is there a way around that?
thank you
Replacing the "=" with ":" should work...