I am trying to make a Windows software using Tkinter from Python, the purpose of this app is to move specific types of files to a specified directory.
But the error comes here, it looks like that my move function ins't getting my entry text and also the extension text, so thats why I think there is the error, the code is here....
import tkinter.filedialog as filedialog
import tkinter as tk
import os
import shutil
def input_source():
input_path = tk.filedialog.askdirectory()
input_entry.delete(1, tk.END) # Remove current text in entry
input_entry.insert(0, input_path) # Insert the 'path'
def output():
output_path = tk.filedialog.askdirectory()
output_entry.delete(1, tk.END) # Remove current text in entry
output_entry.insert(0, output_path) # Insert the 'path'
def move():
files = os.listdir(input_entry.get())
for file in files: # for every file in the source directory
file_name, extension = os.path.splitext(file) # lets split the name of the file and its extension
if extension == f".{file_extension.get()}": # knowing what type of extension or type of file, lets just move
# those
# files to the new directory
shutil.move(f"{input_entry.get()}/{file}", output_entry.get())
else: # if there are any files with that extension, lets just pass\skip\terminate the process
pass
master = tk.Tk()
top_frame = tk.Frame(master)
bottom_frame = tk.Frame(master)
line = tk.Frame(master, height=1, width=400, bg="grey80", relief='groove')
# input path
input_path = tk.Label(top_frame, text="Input File Path:")
input_entry = tk.Entry(top_frame, text="", width=40)
browse1 = tk.Button(top_frame, text="Browse", command=input_source)
# output path
output_path = tk.Label(bottom_frame, text="Output File Path:")
output_entry = tk.Entry(bottom_frame, text="", width=40)
browse2 = tk.Button(bottom_frame, text="Browse", command=output)
# File extension
file_extension_ = tk.Label(bottom_frame, text="File type:")
file_extension = tk.Entry(bottom_frame, text="", width=40)
file_extension.insert(0, 'Type file extension: .')
move = tk.Button(bottom_frame, text='Move!', command=move)
top_frame.pack(side=tk.TOP)
line.pack(pady=10)
bottom_frame.pack(side=tk.BOTTOM)
input_path.pack(pady=5)
input_entry.pack(pady=5)
browse1.pack(pady=5)
output_path.pack(pady=5)
output_entry.pack(pady=5)
browse2.pack(pady=5)
file_extension.pack(pady=5)
file_extension.pack(pady=5)
move.pack(pady=20, fill=tk.X)
master.mainloop()
Simplify this and it should work. If you're just trying to move files to the typed path, why not do it this way?
from tkinter import *
import os
root = Tk()
root.title("File Mover")
def move_file():
firstpath = entry1.get()
secondpath = entry2.get()
os.replace(firstpath, secondpath)
label1 = Label(text="Enter File Directory to Move")
label2 = Label(text="Enter New File Directory")
entry1 = Entry(width=20, justify="center")
entry2 = Entry(width=20, justify="center")
button = Button(text="Move File", command=move_file)
label1.grid(row=0, column=0)
label2.grid(row=1,column=0)
entry1.grid(row=0,column=1)
entry2.grid(row=1, column=1)
button.grid(row=2,column=0)
root.mainloop()
this requires they include the name of the file in the path, but I guarantee that it will get the text, and that it works moving the files on my machine.
Related
I'm new to Tkinter and I'm trying to create a simple Button that opens a file dialog box, where the user chooses which CSV file to open. Under the button there is a label that should display the file path for the file that was opened.
When I click on the button once, everything works as expected. However, if I click on it a second time and select a different file, the new filepath overlaps with the previous one, instead of replacing it.
Here is the code for the implementation function (please let me know if you need more bits of code for context):
def open_csv_file():
global df
global filename
global initialdir
initialdir = r"C:\Users\stefa\Documents\final project models\Case A"
filename = filedialog.askopenfilename(initialdir=initialdir,
title='Select a file', filetypes = (("CSV files","*.csv"),("All files","*.*")))
df = pd.read_csv(os.path.join(initialdir,filename))
lbl_ok = tk.Label(tab2, text = ' ') #tab2 is a ttk.Notebook tab
lbl_ok.config(text='Opened file: ' + filename)
lbl_ok.grid(row=0,column=1)
Here is how to do it with .config(), create the label instance just once (can then grid as much as you want but probably just do that once too), then just configure the text:
from tkinter import Tk, Button, Label, filedialog
def open_file():
filename = filedialog.askopenfilename()
lbl.config(text=f'Opened file: {filename}')
root = Tk()
Button(root, text='Open File', command=open_file).grid()
lbl = Label(root)
lbl.grid()
root.mainloop()
You can use a StringVar for this. Here is an example that may help you:
from tkinter import *
from tkinter.filedialog import askopenfilename
root = Tk()
root.geometry('200x200')
def openCsv():
csvPath.set(askopenfilename())
csvPath = StringVar()
entry = Entry(root, text=csvPath)
entry.grid(column=0, row=0)
btnOpen = Button(root, text='Browse Folder', command=openCsv)
btnOpen.grid(column=1, row=0)
root.mainloop()
I want to convert the image formats of all images in a folder using tkinter. all extensions I want in a combobox but I don't know why this code doesn't work .no error is displayed.
from tkinter import filedialog, StringVar
from tkinter import ttk
root=tkinter.Tk()
root.geometry("800x600")
#defining functions
def get_folder():
global folder_path
folder_path = filedialog.askdirectory(initialdir='./', title="Select Folder")
print(folder_path)
def get_extension():
change_to = com.get()
change_from = "py"
files=os.listdir(folder_path)
for file in files:
if (".%s"%change_from) in file:
newfile=file.replace((".%s"%change_from),".%s"%change_to)
os.rename((folder_path+'/'+file),(folder_path+'/'+newfile))
#defining widgets for frames
folder_label = tkinter.Label(from_frame)
browse_button = tkinter.Button(from_frame, text="Browse", command=get_folder)
change_button = tkinter.Button(button_frame, text="Change Extension", command=get_extension)
change_button.pack()
#defining combobox
com = StringVar()
list_combo = ['.png','.jpg','.jpeg', '.svg', '.tif','.bmp','.gif','ppm']
combox = ttk.Combobox(root, width = 25, font = 'arial 19 bold', value = list_combo, state = 'r', textvariable = com)
combox.place(x= 190, y= 190)
combox.set('select type')
root.configure(bg = 'coral1')
root.mainloop()```
Is this what You want:
from tkinter import Tk, Button, Label, StringVar, Frame
from tkinter.ttk import Combobox
from tkinter.filedialog import askdirectory
import os
def convert_extensions():
path = dir_lbl.cget('text')
from_ = from_var.get()
to_ = to_var.get()
files_from = [f'{path}/{file}' for file in os.listdir(path) if file.split('.')[-1] == from_]
files_to = ['.'.join(file.split('.')[:-1]) + '.' + file.split('.')[-1].replace(from_, to_) for file in files_from]
for from_file, to_file in zip(files_from, files_to):
os.rename(from_file, to_file)
print(f'{"-" * 100}\n'
f'{"From:": <10} {from_file}\n'
f'{"To:": <10} {to_file}\n')
root = Tk()
root.geometry('500x200')
Button(root, text='Choose Directory', command=lambda: dir_lbl.config(text=askdirectory())).pack(pady=5)
dir_lbl = Label(root, text='')
dir_lbl.pack(pady=5)
options_frame = Frame(root)
options_frame.pack(pady=5)
from_var = StringVar(value='Convert from')
list_combo = ['png', 'jpg', 'jpeg', 'svg', 'tif', 'bmp', 'gif', 'ppm']
Combobox(options_frame, value=list_combo,
textvariable=from_var, state='r').pack(side='left', padx=5, pady=5)
to_var = StringVar(value='Convert to')
Combobox(options_frame, value=list_combo,
textvariable=to_var, state='r').pack(side='left', padx=5, pady=5)
Button(root, text='Convert', command=convert_extensions).pack(pady=5)
root.mainloop()
This however allows more control in that You can choose both the extension to convert and to which one convert.
This is pretty basic so if You have any questions, ask. I will probably add a detailed explanation later but for now this is all I can do. Oh and btw that three line print function is not necessary at all and it probably should be made to display that in tkinter window or sth but otherwise it can be removed.
How to Handle a Button Click Event in Python? I am New to python and trying to develop Zip Extractor tool.i've handled the Btn1 and Btn2 Properly but the 3'rd one is giving me errors.("name res1 is not defined") Here is the code
i've Wrote as follows: Plz Help Me as i am a noobie :| Thanks In Adv :)
from tkinter import *
from tkinter.filedialog import askdirectory
import os, zipfile
extension = ".zip"
PASSWORD = "virus007"
global res1
global res2
window = Tk()
window.title("Welcome Zip_Extractor_Utility")
window.geometry('640x260')
lbl1 = Label(window, text="Select Source Location:" ,font=("Arial Bold", 12))
lbl2 = Label(window, text="Select Destination Location:" ,font=("Arial Bold", 12))
lbl1.grid(column=0, row=7)
lbl2.grid(column=50, row=7)
def clicked1():
res1 = askdirectory()
print(res1)
return res1
btn1 = Button(window, text="Browse" , command=clicked1)
btn1.grid(column=1, row=7)
def clicked2():
res2 = askdirectory()
print(res2)
return res2
btn2 = Button(window, text="Browse" , command=clicked2)
btn2.grid(column=51, row=7)
##lbl3 = Label(window, text="Extract:" ,font=("Arial ", 12))
##lbl3.grid(column=70, row=7)
def clicked3():
os.chdir(res1) # change directory from working dir to dir with files
for item in os.listdir(res1): # loop through items in dir
if item.endswith(extension): # check for ".zip" extension
file_name = os.path.abspath(item) # get full path of files
zip_ref = zipfile.ZipFile(file_name) # create zipfile object
zip_ref.setpassword(PASSWORD)
zip_ref.extractall(res2) # extract file to dir
zip_ref.close() # close file
#os.remove(file_name) # delete zipped file
print('done')
btn3 = Button(window, text="Extract" , command=clicked3)
btn3.grid(column=71, row=7)
window.mainloop()
In your case, just check if res1 and res2 is defined in clicked3 function. Maybe with 'res1' in vars() and 'res2' in vars(). If it's not defined, warn users that they need to specify source and destination folder first.
With my current code, it does not matter whether I click on "Input Folder" - Change or "JukeBox" change the result always gets displayed in "JukeBox" entry. This is incorrect, using class and self how can I change the code to display result from "Input Folder" - Change in "Input Folder" entry and the result from "Jukbox" - Change in "Jukebox" entry?
Also, how can I save the selected folders to a file so that it is there on app exit and re open?
My code:
import os
from tkinter import *
from tkinter import filedialog
inPut_dir = ''
jukeBox_dir = ''
def inPut():
opendir = filedialog.askdirectory(parent=root,initialdir="/",title='Input Folder')
inPut_dir = StringVar()
inPut_dir = os.path.abspath(opendir)
entry.delete(0, END)
entry.insert(0, inPut_dir)
def jukeBox():
opendir = filedialog.askdirectory(parent=root,initialdir="/",title='JukeBox')
jukeBox_dir = StringVar()
jukeBox_dir = os.path.abspath(opendir)
entry.delete(0, END)
entry.insert(0, jukeBox_dir)
root = Tk()
root.geometry("640x240")
root.title("Settings")
frametop = Frame(root)
framebottom = Frame(root)
frameright = Frame(framebottom)
text = Label(frametop, text="Input Folder").grid(row=5, column=2)
entry = Entry(frametop, width=50, textvariable=inPut_dir)
entry.grid(row=5,column=4,padx=2,pady=2,sticky='we',columnspan=20)
text = Label(frametop, text="JukeBox").grid(row=6, column=2)
entry = Entry(frametop, width=50, textvariable=jukeBox_dir)
entry.grid(row=6,column=4,padx=2,pady=2,sticky='we',columnspan=20)
ButtonA = Button(frametop, text="Change", command=inPut).grid(row=5, column=28)
ButtonB = Button(frametop, text="Change", command=jukeBox).grid(row=6, column=28)
ButtonC = Button(frameright, text="OK").grid(row=5, column=20, padx=10)
ButtonD = Button(frameright, text="Cancel").grid(row=5, column=15)
frametop.pack(side=TOP, fill=BOTH, expand=1)
framebottom.pack(side=BOTTOM, fill=BOTH, expand=1)
frameright.pack(side=RIGHT)
root.mainloop()
See attached image:enter image description here
Your code has both:
entry = Entry(frametop, width=50, textvariable=inPut_dir)
entry.grid(row=5,column=4,padx=2,pady=2,sticky='we',columnspan=20)
and
entry = Entry(frametop, width=50, textvariable=jukeBox_dir)
entry.grid(row=6,column=4,padx=2,pady=2,sticky='we',columnspan=20)
with jukeBox_dir/row 6 overriding inPut_dir/row 5
Therefore, in def input:
where you have:
entry.insert(0, inPut_dir)
You'll get the result in row 5 (jukebox_dir)
I'm just starting to use tkinter and it is a little difficult to handle it. Check this sample :
#!/usr/bin/env python
#-*- coding: utf-8 -*-
import Tkinter as tk
import tkFileDialog
def openfile():
filename = tkFileDialog.askopenfilename(title="Open file")
return filename
window = tk.Tk()
tk.Button(window, text='Browse', command=openfile).pack()
window.mainloop()
I juste created a browse button which keep the file path in the variable "filename" in the function openfile(). How can i put the content of "filename" in a variable out of the function ?
For example I want to put it in the variable P and print it in a terminal
def openfile():
filename = tkFileDialog.askopenfilename(title="Open file")
return filename
window = tk.Tk()
tk.Button(window, text='Browse', command=openfile).pack()
window.mainloop()
P = "the file path in filename"
print P
I also also want to put the file path in a widget Entry(), and as same as below, get the text in the Entry widget in another global variable.
If someone knows, it would be nice.
There are at least two different ways of doing it:
1) Bundle your whole app in a class like this:
import Tkinter as tk
import tkFileDialog
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self) # create window
self.filename = "" # variable to store filename
tk.Button(self, text='Browse', command=self.openfile).pack()
tk.Button(self, text='Print filename', command=self.printfile).pack()
self.spinbox = tk.Spinbox(self, from_=0, to=10)
self.spinbox.pack(pady=10)
tk.Button(self, text='Print spinbox value', command=self.printspinbox).pack()
self.mainloop()
def printspinbox(self):
print(self.spinbox.get())
def openfile(self):
self.filename = tkFileDialog.askopenfilename(title="Open file")
def printfile(self):
print(self.filename)
if __name__ == '__main__':
App()
In this case, filename is an attribute of the App, so it is accessible from any function inside the class.
2) Use a global variable:
import Tkinter as tk
import tkFileDialog
def openfile():
global filename
filename = tkFileDialog.askopenfilename(title="Open file")
def printfile():
print(filename)
def printspinbox():
print(spinbox.get())
window = tk.Tk()
filename = "" # global variable
tk.Button(window, text='Browse', command=openfile).pack()
tk.Button(window, text='Print filename', command=printfile).pack()
spinbox = tk.Spinbox(window, from_=0, to=10)
spinbox.pack(pady=10)
tk.Button(window, text='Print spinbox value', command=printspinbox).pack()
window.mainloop()