Develop Reference

MultiLine Message With Python Selenium for WhatsApp

I've found a solution (example at this link How to line break in WhatsApp with Selenium when sending a message?
But I've a problem sending Multiline Message with WhatsApp using Python and Selenium.
This is My code :
message = excel_data['Message'][msg]
# Locate search box through x_path
search_box = '//*[#id="side"]/div[1]/div/label/div/div[2]'
person_title = wait.until(lambda driver:driver.find_element_by_xpath(search_box))
# Clear search box if any contact number is written in it
person_title.clear()
# Send contact number in search box
person_title.send_keys(str(excel_data['Contact'][count]))
count = count + 1
msg=msg+1
# Wait for 2 seconds to search contact number
time.sleep(2)
try:
# Load error message in case unavailability of contact number
element = driver.find_element_by_xpath('//*[#id="pane-side"]/div[1]/div/span')
except NoSuchElementException:
# Format the message from excel sheet
message = message.replace('{customer_name}', column)
person_title.send_keys(Keys.ENTER)
actions = ActionChains(driver)
actions.send_keys(message)
actions.send_keys(Keys.ENTER)
actions.perform()
I've a file excel with 2 column : 1° Column Phone Number and 2° Column the message
All work well if message is a single message.
If message is on multi line doesn't work.
Ex.:
Message =
Hello
Gundam How are you?
I'm well
WhataApp send 3 message :
First with Hello
Second with Gundam How are you?
Third with I'well
I need all in One message in multiline
Could you help me modifying my code ?
I tried adding this but doesn't work:
ActionChains(driver).send_keys(message).perform()
ActionChains(driver).key_down(Keys.SHIFT).key_down(Keys.ENTER).key_up(Keys.SHIFT).key_up(Keys.ENTER).perform()
ActionChains(driver).send_keys(Keys.RETURN).perform()
Thanks a lot for your help

Use selenium Keys:
from selenium.webdriver.common.keys import Keys
Then:
val="text\text"
val =val.replace("\n",(Keys.SHIFT+Keys.ENTER))
just replace '\n' or '\r\n' with (Keys.SHIFT+Keys.ENTER)
so in your case:
First check what is the line end character
print((message).encode("unicode_escape"))
Then replace that with Keys.shift+enter
message=message.replace("\n",(Keys.SHIFT+Keys.ENTER))
You can directly use the unicode charactes:
elem.send_keys("first\ue008\ue007second")

following functions hopefully solve your purpose. Actually in whatsapp, pressing Enter Key will send the message immediately so won't work for multiline. for multiline shift + enter required to press at same time.
Selenium ActionChains method used to overcome the problem.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webd`enter code here`river.common.action_chains import ActionChains
def wa_msg_send(driver, msg):
messages = msg.split('\n')
for line in messages:
ActionChains(driver).send_keys(line).perform()
ActionChains(driver).key_down(Keys.SHIFT).key_down(Keys.ENTER).key_up(Keys.SHIFT).key_up(Keys.ENTER).perform()
else:
ActionChains(driver).send_keys(Keys.RETURN).perform()
functions argument driver can be created using following line & msg is your full multiline message.
driver = webdriver.Chrome(chrome_driver, options=chrome_options)
Please check and let me know if not worked.

In the whatsapp web '\n' works an 'Enter' key
And 'Enter' key works as send message on whatsapp web.
Because of that your multi-line message is getting send in mult-parts (or as multiple message)
For avoid it you can change '\n' with shift+Enter Key.
You can use the following way to send message with break line in a single message
from selenium.webdriver.common.keys import Keys
#You have to install selenium for keys or can choose any other library which be suitable for you.
br = (Keys.SHIFT)+(Keys.ENTER)+(Keys.SHIFT) # Assigning the keys for break line
## You can use any one way from the following.
message = f"Dear Student,{br}Please send your report{br}Thank you for your attention"
####################### Or #########################
# message = "Dear Student,{0}Please send your report{0}Thank you for your attention".format(br)
####################### Or #########################
# message = "Dear Student," + br + "Please send your report" + br + "Thank you for your attention"
Or, You can use escape character as following example
message = """Hello \
Gundam How are you? \
I'm well """
I have already explain multiple line breaking ways on a question.
You can check my Answer here.
Thank you

How do I read whatsapp messages from a contact using python?

I'm building a bot that logs into zoom at specified times and the links are being obtained from whatsapp. So i was wondering if it is was possible to retrieve those links from whatsapp directly instead of having to copy paste it into python. Google is filled with guides to send messages but is there any way to READ and RETRIEVE those messages and then manipulate it?

You can, at most, try to read WhatsApp messages with Python using Selenium WebDriver since I strongly doubt that you can access WhatsApp APIs.
Selenium is basically an automation tool that lets you automate tasks in your browser so, perhaps, you could write a Python script using Selenium that automatically opens WhatsApp and parses HTML information regarding your WhatsApp web client.
First of all, we mentioned Selenium, but we will use it only to automate the opening and closing of WhatsApp, now we have to find a way to read what's inside the WhatsApp client, and that's where the magic of Web Scraping comes is hand.
Web scraping is a process of extracting data from a website, in this case, the data is represented by the Zoom link you need to automatically obtain, while the web site is your WhatsApp client. To perform this process you need a way to extract (parse) information from the website, to do so I suggest you use Beautiful Soup, but I advise you that a minimum knowledge of how HTML works is required.
Sorry if this may not completely answer your question but this is all the knowledge I have on this specific topic.

You can open WhatsApp on browser using https://selenium-python.readthedocs.io/ in Python.
Selenium is basically an automation tool that lets you automate tasks in your browser so, perhaps, you could write a Python script using Selenium that automatically opens WhatsApp and parses HTML information regarding your WhatsApp web client.
I learn and use code from "https://towardsdatascience.com/complete-beginners-guide-to-processing-whatsapp-data-with-python-781c156b5f0b" this site. Go through the details written on mentioned link.
You have to install external python library "whatsapp-web" from this link --- "https://pypi.org/project/whatsapp-web/". Just type in command prompt / windows terminal by "python -m pip install whatsapp-web".
It will show result ---
python -m pip install whatsapp-web
Collecting whatsapp-web
Downloading whatsapp_web-0.0.1-py3-none-any.whl (21 kB)
Installing collected packages: whatsapp-web
Successfully installed whatsapp-web-0.0.1

You can read all the cookies from whatsapp web and add them to headers and use the requests module or you can also use selenium with that.

Update :
Please change the xpath's class name of each section from the current time class name of WhatsApp web by using inspect element section in WhatsApp web to use the following code. Because WhatsApp have changed its element's class names.
I have tried that in creating a WhatsApp bot using python.
But there are still many bugs because of I am also beginner.
steps based on my research :
Open browser using selenium webdriver
Login on WhatsApp using qr code
If you know from which number you are going to received the meeting link then use this step otherwise check the following process mention after this process.
Find and open the chat room where you are going to received zoom meeting link.
For getting message from known chat room to perform action
#user_name = "Name of meeting link Sender as in your contact list"
Example :
user_name = "Anurag Kushwaha"
#In above variable at place of `Anurag Kushwaha` pass Name or number of Your Teacher
# who going to sent you zoom meeting link same as you have in your contact list.
user = webdriver.find_element_by_xpath('//span[#title="{}"]'.format(user_name))
user.click()
# For getting message to perform action
message = webdriver.find_elements_by_xpath("//span[#class='_3-8er selectable-text copyable-text']")
# In the above line Change the xpath's class name from the current time class name by inspecting span element
# which containing received text message of any chat room.
for i in message:
try:
if "zoom.us" in str(i.text):
# Here you can use you code to preform action according to your need
print("Perform Your Action")
except:
pass
If you do not know by which number you are going to received the link.
Then you can get div class of any unread contact block and get open all the chat room list which are containing that unread div class.
Then check all the unread messages of open chat and get the message from the div class.
When you don't know from whom you gonna received zoom meeting link.
# For getting unread chats you can use
unread_chats = webdriver.find_elements_by_xpath("// span[#class='_38M1B']")
# In the above line Change the xpath's class name from the current time class name by inspecting span element
# which containing the number of unread message showing the contact card inside a green circle before opening the chat room.
# Open each chat using loop and read message.
for chat in unread_chats:
chat.click()
# For getting message to perform action
message = webdriver.find_elements_by_xpath("//span[#class='_3-8er selectable-text copyable-text']")
# In the above line Change the xpath's class name from the current time class name by inspecting span element
# which containing received text message of any chat room.
for i in messge:
try:
if "zoom.us" in str(i.text):
# Here you can use you code to preform action according to your need
print("Perform Your Action")
except:
pass
Note : In the above code 'webdriver' is the driver by which you open web.whatsapp.com
Example :
from selenium import webdriver
webdriver = webdriver.Chrome("ChromePath/chromedriver.exe")
webdriver.get("https://web.whatsapp.com")
# This wendriver variable is used in above code.
# If you have used any other name then please rename in my code or you can assign your variable in that code variable name as following line.
webdriver = your_webdriver_variable
A complete code reference Example :
from selenium import webdriver
import time
webdriver = webdriver.Chrome("ChromePath/chromedriver.exe")
webdriver.get("https://web.whatsapp.com")
time.sleep(25) # For scan the qr code
# Plese make sure that you have done the qr code scan successful.
confirm = int(input("Press 1 to proceed if sucessfully login or press 0 for retry : "))
if confirm == 1:
print("Continuing...")
elif confirm == 0:
webdriver.close()
exit()
else:
print("Sorry Please Try again")
webdriver.close()
exit()
while True:
unread_chats = webdriver.find_elements_by_xpath("// span[#class='_38M1B']")
# In the above line Change the xpath's class name from the current time class name by inspecting span element
# which containing the number of unread message showing the contact card inside a green circle before opening the chat room.
# Open each chat using loop and read message.
for chat in unread_chats:
chat.click()
time.sleep(2)
# For getting message to perform action
message = webdriver.find_elements_by_xpath("//span[#class='_3-8er selectable-text copyable-text']")
# In the above line Change the xpath's class name from the current time class name by inspecting span element
# which containing received text message of any chat room.
for i in messge:
try:
if "zoom.us" in str(i.text):
# Here you can use you code to preform action according to your need
print("Perform Your Action")
except:
pass
Please make sure that the indentation is equal in code blocks if you are copying it.
Can read my another answer in following link for more info about WhatsApp web using python.
Line breaks in WhatsApp messages sent with Python
I am developing WhatsApp bot using python.
For contribution you can contact at : anurag.cse016#gmail.com
Please give a star on my https://github.com/4NUR46 If this Answer helps you.

Try This Its A bit of a hassle but it might work
import pyautogui
import pyperclip
import webbrowser
grouporcontact = pyautogui.locateOnScreen("#group/contact", confidence=.6) # Take a snip of the group or contact name/profile photo
link = pyperclip.paste()
def searchforgroup():
global link
time.sleep(5)
webbrowser.open("https://web.whatsapp.com")
time.sleep(30)#for you to scan the qr code if u have done it then u can edit it to like 10 or anything
grouporcontact = pyautogui.locateOnScreen("#group/contact", confidence=.6)
x = grouporcontact[0]
y = grouporcontact[1]
if grouporcontact == None:
#Do any other option in my case i just gave it my usual link as
link = "mymeetlink"
else:
pyautogui.moveTo(x,y, duration=1)
pyautogui.click()
# end of searching group
def findlink():
global link
meetlink = pyautogui.locateOnScreen("#", confidence=.6)#just take another snap of a meet link without the code after the "/"
f = meetlink[0]
v = meetlink[1]
if meetlink == None:
#Do any other option in my case i just gave it my usual link as
link = "mymeetlink"
else:
pyautogui.moveTo(f,v, duration=.6)
pyautogui.rightClick()
pyautogui.moveRel(0,0, duration=2) # You Have to play with this it basically is considered by your screen size so just edit that and edit it till it reaches the "Copy Link Address"
pyautogui.click()
link = pyperclip.paste()
webbrowser.open(link) # to test it out
So Now You Have It Have To Install pyautogui, pyperclip
and just follow the comments in the snippet and everything should work :)

Multiprocessing, python - sharing the same webdriver pointer

I couldn't find a proper response so I post this question.
The fastest way to understand the question is the goal:
There is a main process and a subprocess (the one I want to create). The main process inspects several websites via webdriver, but sometimes it got stuck at low selenium level and don't want to change the official code. So.. I manually inspect sometimes the monitor to the check whether the process got stuck, and if so, then I change manually the url in the browser and it works again smooth. I don't want to be a human checker.. so i'd like to automate the task with a subprocess that shares the same webdriver and inspects the url by webdriver.current_url and do the work for me.
Here is my try in the minimal representative example form in which the sub-process only detects a change in the url of the webdriver
def test_sub(driver):
str_site0 = driver.current_url # get the site0 url
time.sleep(4) # give some time to the main-process to change to site1
str_site1 = driver.current_url # get the site1 url (changed by main-process)
if str_site0 == str_site1:
print('sub: no change detected')
else:
print('sub: change detected')
#endif
#enddef sub
def test_main():
""" main process changes from site0 (stackoverflow) to site1 (youtube)
sub process detects this change of url of the webdriver object (same pointer) by using
".current_url" method
"""
# init driver
pat_webdriver = r"E:\WPy64-3680\python-3.6.8.amd64\Lib\site-packages\selenium\v83_chromedriver\chromedriver.exe"
driver = webdriver.Chrome(executable_path= pat_webdriver)
time.sleep(2)
# open initial site
str_site0 = 'https://stackoverflow.com'
driver.get(str_site0)
time.sleep(2)
# init sub and try to pass the webdriver object
p = multiprocessing.Process(target=test_sub, args=(driver,)) # PROBLEM HERE! PYTHON UNCAPABLE
p.daemon = False
p.start()
# change site
time.sleep(0.5) # give some time sub query webdriver with site0
str_site1 = 'https://youtube.com' # site 1 (this needs to be detected by sub)
driver.get(str_site1)
# wait the sub to detect the change in url. and kill process (non-daemon insufficient don't know why..)
time.sleep(3)
p.terminate()
#enddef test_main
# init the program (main-process)
test_main()
the corresponding error by executing $python test_multithread.py (it's the name of the test script..) is the following one:

Python Selenium Webpage fill: To download data from links

I've compiled this code to perform an iteration of downloads from a webpage which has multiple download links. Once the download link is clicked, the webpage produces a webform which has to be filled and submitted for the download to start. I've tried running the code and face issue in 'try'& 'except' block code (Error: Too broad exception clause) and towards the end there is an error associated with the 'submit' (Error: method submit maybe static) both of these subsequently result in 'SyntaxError: invalid syntax '. Any suggestions / help will be much appreciated. Thank you.
import os
from selenium import webdriver
fp = webdriver.FirefoxProfile()
fp.set_preference("browser.download.folderList",2)
fp.set_preference("browser.download.manager.showWhenStarting",False)
fp.set_preference("browser.download.dir", os.getcwd())
fp.set_preference("browser.helperApps.neverAsk.saveToDisk", "application/x-msdos-program")
driver = webdriver.Firefox(firefox_profile=fp)
driver.get('http://def.com/catalog/attribute')
#This is to find the download links in the webpage one by one
i=0
while i<1:
try:
driver.find_element_by_xpath('//*[#title="xml (Open in a new window)"]').click()
except:
i=1
#Once the download link is clicked this has to fill the form for submission which fill download the file
class FormPage(object):
def fill_form(self, data):
driver.find_element_by_xpath('//input[#type = "radio" and #value = "Non-commercial"]').click()
driver.find_element_by_xpath('//input[#type = "checkbox" and #value = "R&D"]').click()
driver.find_element_by_xpath('//input[#name = "name_d"]').send_keys(data['name_d'])
driver.find_element_by_xpath('//input[#name = "mail_d"]').send_keys(data['mail_d'])
return self
def submit(self):
driver.find_element_by_xpath('//input[#value = "Submit"]').click()
data = {
'name_d': 'abc',
'mail_d': 'xyz#gmail.com',
}
FormPage().fill_form(data).submit()
driver.quit()

Actually you have two warnings and a error:
1 - "Too broad exception" this is a warning telling you that you should except espefic errors, not all of them. In your "except" line should be something like except [TheExceptionYouAreTreating]: an example would be except ValueError:. However this should not stop your code from running
2 - "Error: method submit maybe static" this is warning telling you that the method submit is a static method (bassically is a method that don't use the self attribute) to supress this warning you can use the decorator #staticmethod like this
#staticmethod
def submit():
...
3 - "SyntaxError: invalid syntax" this is what is stopping your code from running. This is a error telling you that something is written wrong in your code. I think that may be the indentation on your class. Try this:
i=0
while i<1:
try:
driver.find_element_by_xpath('//*[#title="xml (Open in a new window)"]').click()
except:
i=1
#Once the download link is clicked this has to fill the form for submission which fill download the file
class FormPage(object):
def fill_form(self, data):
driver.find_element_by_xpath('//input[#type = "radio" and #value = "Non-commercial"]').click()
driver.find_element_by_xpath('//input[#type = "checkbox" and #value = "R&D"]').click()
driver.find_element_by_xpath('//input[#name = "name_d"]').send_keys(data['name_d'])
driver.find_element_by_xpath('//input[#name = "mail_d"]').send_keys(data['mail_d'])
return self
def submit(self):
driver.find_element_by_xpath('//input[#value = "Submit"]').click()
data = {
'name_d': 'abc',
'mail_d': 'xyz#gmail.com',
}
FormPage().fill_form(data).submit()
driver.quit()
One more thing. Those are really simple errors and warnings, you should be able to fix them by yourself by carefully reading what the error has to say. I also reccomend you reading about Exceptions

Python Selenium: Unable to Find Element After First Refresh

I've seen a few instances of this question, but I was not sure how to apply the changes to my particular situation. I have code that monitors a webpage for changes and refreshes every 30 seconds, as follows:
import sys
import ctypes
from time import sleep
from Checker import Checker
USERNAME = sys.argv[1]
PASSWORD = sys.argv[2]
def main():
crawler = Checker()
crawler.login(USERNAME, PASSWORD)
crawler.click_data()
crawler.view_page()
while crawler.check_page():
crawler.wait_for_table()
crawler.refresh()
ctypes.windll.user32.MessageBoxW(0, "A change has been made!", "Attention", 1)
if __name__ == "__main__":
main()
The problem is that Selenium will always show an error stating it is unable to locate the element after the first refresh has been made. The element in question, I suspect, is a table from which I retrieve data using the following function:
def get_data_cells(self):
contents = []
table_id = "table.datadisplaytable:nth-child(4)"
table = self.driver.find_element(By.CSS_SELECTOR, table_id)
cells = table.find_elements_by_tag_name('td')
for cell in cells:
contents.append(cell.text)
return contents
I can't tell if the issue is in the above function or in the main(). What's an easy way to get Selenium to refresh the page without returning such an error?
Update:
I've added a wait function and adjusted the main() function accordinly:
def wait_for_table(self):
table_selector = "table.datadisplaytable:nth-child(4)"
delay = 60
try:
wait = ui.WebDriverWait(self.driver, delay)
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, table_selector)))
except TimeoutError:
print("Operation timeout! The requested element never loaded.")
Since the same error is still occurring, either my timing function is not working properly or it is not a timing issue.

I've run into the same issue while doing web scraping before and found that re-sending the GET request (instead of refreshing) seemed to eliminate it.
It's not very elegant, but it worked for me.

I appear to have fixed my own problem.
My refresh() function was written as follows:
def refresh():
self.driver.refresh()
All I did was switch frames right after the refresh() call. That is:
def refresh():
self.driver.refresh()
self.driver.switch_to.frame("content")
This took care of it. I can see that the page is now refreshing without issues.