How can I create form using this django model? - python

I am trying to create form using this model. I want to add data in this database model using form to perform CRUD operation. I am using MySQL database.
models.py
from django.db import models
from .managers import CategoryManager, SubCategoryManager
# this is my parent model
class Node(models.Model):
name = models.CharField(max_length=150)
parent = models.ForeignKey(
'self',
on_delete=models.CASCADE,
related_name='children',
null=True,
blank=True
)
def __str__(self):
return self.name
class Meta:
ordering = ('name',)
verbose_name_plural = 'Nodes'
class Category(Node):
object = CategoryManager()
class Meta:
proxy = True
verbose_name_plural = 'Categories'
class SubCategory(Node):
object = SubCategoryManager()
class Meta:
proxy = True
verbose_name_plural = 'SubCategories'
class Product(models.Model):
sub_category = models.ForeignKey(
SubCategory, on_delete=models.CASCADE
)
name = models.CharField(max_length=100)
description = models.TextField(blank=True)
def __str__(self):
return self.name

Try the Imagine smart compiler which allows automatic generating of code + tests for your CRUD APIs and Django models from a very simple config. Amongst other things, it generates code in the correct way to handle foreign key relationships in Django Views. You can also try a demo here imagine.ai/demo
PS: Something like this simple config will generate all the code for the CRUD API along with the tests!
Model Node {
id integer [primary-key]
name string [max-length 150]
}
Model Product {
id integer [primary-key]
name string [max-length 100]
description string [nullable]
}

Related

Use of foreignKey between app models in Django 1.10

I have a website built in Django 1.10. The site has 3 different apps: teams, members and news.
The first app, called teams has one model called Team.
This is the Team/models.py:
from django.db import models
from django.db.models.signals import pre_save
from django.utils.text import slugify
class Team(models.Model):
name = models.CharField(max_length=255)
description = models.TextField()
slug = models.CharField(max_length=255, default='team', editable=True)
class Meta:
ordering = ('name',)
def __unicode__(self):
return self.name
The second app, called members has one model called Member.
This is the Member/models.py:
from django.db import models
class Piloto(models.Model):
name = models.CharField(max_length=255)
biography = models.TextField()
slug = models.CharField(max_length=255, default='piloto', editable=True)
class Meta:
ordering = ('name',)
def __unicode__(self):
return self.name
What I want is include the name of the team inside the member profile, so I know it should be something like:
team_of_member = models.ForeignKey();
But I don't know what to put in the parenthesis or how to import the model of the team to the model of the member. I was following the documentation of Django 1.10 but it wasn't working, also I've tried this link but it doesn't work. Could you give a hand? Thanks
Edit:
I tried to do as #Bulva was suggesting, so my code is now like this:
from django.db import models
from equipos.models import Team
class Member(models.Model):
name = models.CharField(max_length=255)
team = models.ForeignKey('teams.Team', null=True)
biography = models.TextField()
slug = models.CharField(max_length=255, default='piloto', editable=True)
class Meta:
ordering = ('name',)
def __unicode__(self):
return self.name
What you want is to provide the teams the member is a member of. It all depends on your business logic. A team has many members by definition, but can a member be a part of many teams? If yes, you have a many-to-many relationship. If no, you have a one-to-many relationship.
Under one-to-many assumption, the foreignkey information has to be put in the referenced model. Then:
from django.db import models
from team.models import Team # Generally, apps are in all lower-case (assuming your app is called team)
class Member(models.Model):
name = models.CharField(max_length=255)
team = models.ForeignKey('team.Team', related_name = 'members', null=True) # Do not forget to put team.Team inside a pair of single-quotes.
biography = models.TextField()
slug = models.CharField(max_length=255, default='piloto', editable=True)
class Meta:
ordering = ('name',)
def __unicode__(self): # use def __str__(self): in Python 3+
return self.name
In your view, you can then say this:
albert_team = albert.team
albert_teammates = albert_team.members
Under Many-to-Many assumption, it is more natural to capture the relationship in the team model:
from django.db import models
from django.db.models.signals import pre_save
from django.utils.text import slugify
class Team(models.Model):
name = models.CharField(max_length=255)
description = models.TextField()
slug = models.CharField(max_length=255, default='team', editable=True)
members = models.ManyToManyField('team.Member', related_name = 'teams')
class Meta:
ordering = ('name',)
def __unicode__(self):
return self.name
In views.py:
albert_teams = albert.teams
all_albert_teammates = []
for team in albert_teams:
all_albert_teammates.append(team.members)
Try this:
from teams.models import Team
# in the member model field
team_of_member = models.ForeignKey(Team);
In order to do what you want (assuming the code provided is your full "problematic" code) you should:
In Member/models.py:
from django.db import models
from teams.models import Team # <--add this line
class Piloto(models.Model):
name = models.CharField(max_length=255)
team_of_member = models.ForeignKey(Team, on_delete=models.CASCADE); # <--add this line
biography = models.TextField()
slug = models.CharField(max_length=255, default='piloto', editable=True)
class Meta:
ordering = ('name',)
def __unicode__(self):
return self.name
After you do this, remember to:
python manage.py makemigrations
python manage.py migrate
to change your models state.
Good luck :)

How to define custom relationships between legacy models in Django REST Framework

I am working with some legacy database models in a Django REST Framework application:
class Variable(models.Model):
var_id = models.AutoField(primary_key=True)
resource_type = models.CharField(max_length=1, blank=True, null=True)
resource_id = models.BigIntegerField(blank=True, null=True)
var_name = models.CharField(max_length=500, blank=True, null=True)
class Meta:
managed = False
db_table = 'variables'
class Project(models.Model):
project_id = models.AutoField(primary_key=True)
name = models.CharField(unique=True, max_length=100, blank=True, null=True)
class Meta:
managed = True
db_table = 'projects'
Project and Variable are related models such that when the resource_type of a Variable is 'P', then its resource_id represents the project_id of the Project it belongs to. If the resource_type is something other than 'P, then that Variable belongs to a different type of model. I unfortunately can not make significant changes to the database schema for these models.
Is there a way to define a custom relationship between these two models so that I can treat them as if Variable was defined with a ForeignKey to Project? Or as if Project has a ManyToManyField relationship to Variable? I'd ultimately like to be able to create a nested serializer relationship. Something like:
class Variable(serializers.ModelSerializer):
class Meta:
model = models.Variable
fields = ('var_id', 'resource_type', 'resource_id', 'var_name')
class ProjectSerializer(serializers.ModelSerializer):
variables = VariableSerializer(many=True)
class Meta:
model = models.Project
fields = ('project_id', 'name', 'variables')
Thanks!

Django admin form, field instead of object in foreign key

Im using a forigen key to reference another object from my parent object. However when i go to the drop down list created by django admin, i get the object name instead of the field value. how can i add the field value to the form instead?
admin.py
from django.contrib import admin
from .models import Maintenance
from .models import MaintenanceType
from .models import ServiceType
# Register your models here.
class MaintenanceAdmin(admin.ModelAdmin):
list_display = ('Title','Impact','Service','Description','StartTime','EndTime',)
list_editable = ('Title','Impact','Service','Description','StartTime','EndTime',)
admin.site.register(Maintenance, MaintenanceAdmin)
class MaintenanceTypeAdmin(admin.ModelAdmin):
list_display = ('Type',)
list_editable = ('Type',)
admin.site.register(MaintenanceType, MaintenanceTypeAdmin)
class ServiceTypeAdmin(admin.ModelAdmin):
list_display = ('Service','Service',)
list_editable = ('Service','Service',)
admin.site.register(ServiceType, ServiceTypeAdmin)
models.py
from django.db import models
# Create your models here.
class MaintenanceType(models.Model):
Type = models.CharField(max_length=200)
class Meta:
verbose_name = "Planned Maintenance Types"
verbose_name_plural = "Planned Maintenance Types"
class ServiceType(models.Model):
Service = models.CharField(max_length=200)
class Meta:
verbose_name = "Service Types"
verbose_name_plural = "Service Types"
class Maintenance(models.Model):
Title = models.CharField(max_length=200)
Impact = models.ForeignKey(MaintenanceType)
Service = models.ForeignKey(ServiceType)
Description = models.TextField()
StartTime = models.DateTimeField()
EndTime = models.DateTimeField()
class Meta:
verbose_name = "Planned IT Maintenance"
verbose_name_plural = "Planned IT Maintenance"
Implement __str__ in the MaintenanceType model, which should return a string in whatever formatting you wish to appear in the drop down (and anywhere else actually).
It appears that you simply need to return self.Type.
Python 2 only
You can specify what's returned by accessing an object by setting the unicode method to retun what you want it to be.
So I think your MaintenanceType should look like
class MaintenanceType(models.Model):
Type = models.CharField(max_length=200)
class Meta:
verbose_name = "Planned Maintenance Types"
verbose_name_plural = "Planned Maintenance Types"
def __unicode__(self):
return self.Type

How can I create Django ModelForm for an abstract Model?

I have an abstract model that all my other models inherit from, it looks like this.
class SupremeModel(models.Model):
creator = models.ForeignKey(User, related_name="%(class)s_creator")
created = models.DateTimeField(null=True, blank=True)
deleted = models.BooleanField(default=False)
modified = models.DateTimeField(null=True,blank=True)
class Meta:
abstract = True
I then have a bunch of other models that inherit from this model, with something along these lines...
class ExampleModel(SupremeModel):
name = models.TextField(null=False, blank=False)
description = models.TextField(null=False, blank=False)
class AnotherModel(SupremeModel):
title = models.TextField(null=False, blank=False)
location = models.TextField(null=False, blank=False)
I want to create a Django model form for nearly all of my custom models that look similar to ExampleModel, but I always want the fields in SupremeModel to be excluded in the form...
How can I create a ModelForm that can be used to inherit the exclude parameters that will hide creator,created,deleted, and modified but show all of the other fields (in this case name and description or title and location).
you may try this
class ExcludedModelForm(ModelForm):
class Meta:
exclude = ['creator', 'created', 'deleted', 'modified']
class ExampleModelForm(ExcludedModelForm):
class Meta(ExcludedModelForm.Meta):
model = ExampleModel

How can I use the automatically created implicit through model class in Django in a ForeignKey field?

In Django I have the following models.
In the Supervisor model I have a many-to-many field without an explicitly defined through table. In the ForeignKey field of the Topic model I would like to refer to the automatically created intermediate model (created by the many-to-many field in the Supervisor model), but I don't know what is the name of the intermediate model (therefore I wrote '???' there, instead of the name).
Django documentation tells that "If you don’t specify an explicit through model, there is still an implicit through model class you can use to directly access the table created to hold the association."
How can I use the automatically created implicit through model class in Django in a ForeignKey field?
import re
from django.db import models
class TopicGroup(models.Model):
title = models.CharField(max_length=500, unique='True')
def __unicode__(self):
return re.sub(r'^(.{75}).*$', '\g<1>...', self.title)
class Meta:
ordering = ['title']
class Supervisor(models.Model):
name = models.CharField(max_length=100)
neptun_code = models.CharField(max_length=6)
max_student = models.IntegerField()
topicgroups = models.ManyToManyField(TopicGroup, blank=True, null=True)
def __unicode__(self):
return u'%s (%s)' % (self.name, self.neptun_code)
class Meta:
ordering = ['name']
unique_together = ('name', 'neptun_code')
class Topic(models.Model):
title = models.CharField(max_length=500, unique='True')
foreign_lang_requirements = models.CharField(max_length=500, blank=True)
note = models.CharField(max_length=500, blank=True)
supervisor_topicgroup = models.ForeignKey(???, blank=True, null=True)
def __unicode__(self):
return u'%s --- %s' % (self.supervisor_topicgroup, re.sub(r'^(.{75}).*$', '\g<1>...', self.title))
class Meta:
ordering = ['supervisor_topicgroup', 'title']
It's just called through - so in your case, Supervisor.topicgroups.through.
Although I think that if you're going to be referring to it explicitly in your Topic model, you might as well declare it directly as a model.

Categories

Resources