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I need to keep a certain character for my python project which and I don’t want to replace every unused character with ‘’ is there any way to do it?
You can use a function re.sub in re library
For example:
data = re.sub('0123456789abcdefghijklmnopqrstuvwxyzQWERTYUIOPASDFGHJKLZXCVBNNM+/-', '', data)
This will keep every character in the first parameter replace with the second parameter by using String from the third parameter
if you want to keep "d" in the string
origin = "abcdefghidx"
result = "".join([c for c in origin if c=="d"])
You can use str.replace('what to want to delete', 'what you want to add').
ex-
name = "stackoverflow"
newName = name.replace('o', '0')
newName becomes 'stack0verfl0w'
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How would I replace characters in a string for certain indices in Python?
For example, I have version = "00.00.00" and need to change each of the 0s to a different value, say 3, to look like "33.33.33". Also, would this be possible if I had a variable storing this value. If I have vnumber = "3", would I be able to get the same output by using the variable? I'm sure replace() is a good function to use for this, but I'm not sure about syntax.
From an interactive session, you could type:
>>> help(str.replace)
But to answer the question most directly:
vnumber = '3'
newversion = version.replace('0', vnumber)
Is probably what you want to do.
Your guess about str.replace was right. It takes to arguments, the first is the string to be found in the original string, and the second is the string to replace the found occurrences of the first argument with. Code could be like this:
vnumber = "3"
version = "00.00.00"
newversion = version.replace("0", vnumber)
print(newversion)
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I want to strip 0 from a given string.
The string contains either 1 or 0. I want to strip the zeroes if they appear at the ends.
I know i can do this using if condition, but i want to know if there is any function made to do this efficiently than using if-else.
Example-
String = 0100010101010
Output = 10001010101
Also, i don't think using regex is any more efficient, complexity wise.
Try this:
s = "0100010101010"
print(s.lstrip("0").rstrip("0"))
'10001010101'
This should work for the string s:
s = s.strip("0")
Make sure s is a string and not a number.
Can you try this , it will work
s = str(s).strip("0")
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Suppose I have string
exp='"\"OLS\".\"ORDER_ITEMS\".\"QUANTITY\" <50 and \"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston''
How can I find word before string \"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston' that is and in my case
result should be and
Here's one way (after fixing your string literal):
import re
exp='"OLS"."ORDER_ITEMS"."QUANTITY" <50 and "OLS"."PRODUCTS"."PRODUCT_NAME" = \'Kingston\''
search_for = '"OLS"."PRODUCTS"."PRODUCT_NAME"'
m = re.search(r'(\w+)\s+' + search_for, exp)
print(m.group(1))
Result:
and
Note that there's no reason to escape the double quote characters in your string, since you're defining the string with single quotes. For the same reason, you do have to escape the single quotes around Kingston.
This?
key = "\"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston'"
exp[:exp.index(key)].split()[-1]
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This is one of the string that I got:
str ='_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
what I want:
['Name', 'coordinates','CITIZENS','colonisation']
I'm trying to get word in string such as Name, coordinate, citizens, colonisation with their original case.
I tried split method to remove underscores and make them individual word.
,but it did not work well.
How can I do this?
Yo can use a regular expression for that:
import re
text ='_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
re.findall('_(\w*)_', text)
Note str is a built python function, don't use for variable names
A regex should do the trick:
import re
s = '_Name_ created _coordinates_ so that _CITIZENS_ would learn _colonisation_.'
result = re.findall('_(\w+)_', s)
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I have
filename = src_filename
print filename
somehow it is printing filename = 'apple' instead of just apple. Is there a way I can remove these single quotes.
The single quotes denote a string literal
>>> 'apple'
'apple'
If you print the string, it will not use the single quotes
>>> print('apple')
apple
So in your case you can simply
print(filename)
>>> print(filename.strip('"\''))