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Python Looping through urls in csv file returns \ufeffhttps://

I am new to python and I am trying to loop through the list of urls in a csv file and grab the website titleusing BeautifulSoup, which I would like then to save to a file Headlines.csv. But I am unable to grab the webpage title. If I use a variable with single url as follows:
url = 'https://www.space.com/japan-hayabusa2-asteroid-samples-landing-date.html'
resp = req.get(url)
soup = BeautifulSoup(resp.text, 'lxml')
print(soup.title.text)
It works just fine and I get the title Japanese capsule carrying pieces of asteroid Ryugu will land on Earth Dec. 6 | Space
But when I use the loop,
import csv
with open('urls_file2.csv', newline='', encoding='utf-8') as f:
reader = csv.reader(f)
for url in reader:
print(url)
resp = req.get(url)
soup = BeautifulSoup(resp.text, 'lxml')
print(soup.title.text)
I get the following
['\ufeffhttps://www.foxnews.com/us/this-day-in-history-july-16']
and an error message
InvalidSchema: No connection adapters were found for "['\\ufeffhttps://www.foxnews.com/us/this-day-in-history-july-16']"
I am not sure what am I doing wrong.

You have a byte order mark \\ufeff on the URL you parse from your file.
It looks like your file is a signature file and has encoding like utf-8-sig.
You need to read with the file with encoding='utf-8-sig'
Read more here.

As the previous answer has already mentioned about the "\ufeff", you would need to change the encoding.
The second issue is that when you read a CSV file, you will get a list containing all the columns for each row. The keyword here is list. You are passing the request a list instead of a string.
Based on the example you have given, I would assume that your urls are in the first column of the csv. Python lists starts with a index of 0 and not 1. So to extract out the url, you would need to extract the index of 0 which refers to the first column.
import csv
with open('urls_file2.csv', newline='', encoding='utf-8-sig') as f:
reader = csv.reader(f)
for url in reader:
print(url[0])
To read up more on lists, you can refer here.
You can add more columns to the CSV file and experiment to see how the results would appear.
If you would like to refer to the column name while reading each row, you can refer here.

How to input a list of URLs saved in a .txt to a Python program?

I have a list of URLs saved in a .txt file and I would like to feed them, one at a time, to a variable named url to which I apply methods from the newspaper3k python library. The program extracts the URL content, authors of the article, a summary of the text, etc, then prints the info to a new .txt file. The script works fine when you give it one URL as user input, but what should I do in order to read from a .txt with thousands of URLs?
I am only beginning with Python, as a matter of fact this is my first script, so I have tried to simply say url = (myfile.txt), but I realized this wouldn't work because I have to read the file one line at a time. So I have tried to apply read() and readlines() to it, but it wouldn't work properly because 'str' object has no attribute 'read' or 'readlines'. What should I use to read those URLs saved in a .txt file, each beginning in a new line, as the input of my simple script? Should I convert string to something else?
Extract from the code, lines 1-18:
from newspaper import Article
from newspaper import fulltext
import requests
url = input("Article URL: ")
a = Article(url, language='pt')
html = requests.get(url).text
text = fulltext(html)
download = a.download()
parse = a.parse()
nlp = a.nlp()
title = a.title
publish_date = a.publish_date
authors = a.authors
keywords = a.keywords
summary = a.summary
Later I have built some functions to display the info in a desired format and save it to a new .txt. I know this is a very basic one, but I am honestly stuck... I have read other similar questions here but I couldn't properly understand or apply the suggestions. So, what is the best way to read URLs from a .txt file in order to feed them, one at a time, to the url variable, to which other methods are them applied to extract its content?
This is my first question here and I understand the forum is aimed at more experienced programmers, but I would really appreciate some help. If I need to edit or clarify something in this post, please let me know and I will correct immediately.

Here is one way you could do it:
from newspaper import Article
from newspaper import fulltext
import requests
with open('myfile.txt',r) as f:
for line in f:
#do not forget to strip the trailing new line
url = line.rstrip("\n")
a = Article(url, language='pt')
html = requests.get(url).text
text = fulltext(html)
download = a.download()
parse = a.parse()
nlp = a.nlp()
title = a.title
publish_date = a.publish_date
authors = a.authors
keywords = a.keywords
summary = a.summary

This could help you:
url_file = open('myfile.txt','r')
for url in url_file.readlines():
print url
url_file.close()
You can apply it on your code as the following
from newspaper import Article
from newspaper import fulltext
import requests
url_file = open('myfile.txt','r')
for url in url_file.readlines():
a = Article(url, language='pt')
html = requests.get(url).text
text = fulltext(html)
download = a.download()
parse = a.parse()
nlp = a.nlp()
title = a.title
publish_date = a.publish_date
authors = a.authors
keywords = a.keywords
summary = a.summary
url_file.close()

Why does my Python program close after running the first loop?

I'm new to Python and scraping. I'm trying to run two loops. One goes and scrapes ids from one page. Then, using those ids, I call another API to get more info/properties.
But when I run this program, it just runs the first bit fine (gets the IDs), but then it closes and doesn't run the 2nd part. I feel I'm missing something really basic about control flow in Python here. Why does Python close after the first loop when I run it in Terminal?
import requests
import csv
import time
import json
from bs4 import BeautifulSoup, Tag
file = open('parcelids.csv','w')
writer = csv.writer(file)
writer.writerow(['parcelId'])
for x in range(1,10):
time.sleep(1) # slowing it down
url = 'http://apixyz/Parcel.aspx?Pid=' + str(x)
source = requests.get(url)
response = source.content
soup = BeautifulSoup(response, 'html.parser')
parcelId = soup.find("span", id="MainContent_lblMblu").text.strip()
writer.writerow([parcelId])
out = open('mapdata.csv','w')
with open('parcelIds.csv', 'r') as in1:
reader = csv.reader(in1)
writer = csv.writer(out)
next(reader, None) # skip header
for row in reader:
row = ''.join(row[0].split())[:-2].upper().replace('/','-') #formatting
url="https://api.io/api/properties/"
url1=url+row
time.sleep(1) # slowing it down
response = requests.get(url1)
resp_json_payload = response.json()
address = resp_json_payload['property']['address']
writer.writerow([address])

If you are running in windows (where filenames are not case sensitive), then the file you have open for writing (parcelids.csv) is still open when you reopen it to read from it.
Try closing the file before opening it to read from it.

How to prevent writing into txt file the same words using open(text.txt,a)?

I have a question regarding appending to text file. I have written a script and what this script does is that it will read the URL in JSON format and extract the list of titles and write into the file "WordsInCategory.text".
As this code will be used in a loop thus I used f1 = open('WordsInCategory.text', 'a').
But I encountered a problem, that is it will add in already existing title into the file.
I am having trouble coming out with a solution to solve this problem and using 'w' will overwrite what it is written.
My code is as follows:
import urllib2
import json
url1 ='https://en.wikipedia.org/w/api.php?action=query&format=json&list=categorymembers&cmtype=page&cmtitle=Category:Geography&cmlimit=100'
json_obj = urllib2.urlopen(url1)
data1 = json.load(json_obj)
f1 = open('WordsInCategory.text', 'a')
for item in data1['query']:
for i in data1['query']['categorymembers']:
f1.write((i['title']).encode('utf8')+"\n")
Please advice on how I should modify my code.
Thank you.

I would suggest saving every title in an array, before writing to a file (and hence writing only once to the given file). You can modify your code this way :
import urllib2
import json
data = []
f1 = open('WordsInCategory.text', 'w')
url1 ='https://en.wikipedia.org/w/api.php?\
action=query&format=json&list=categorymembers\
&cmtype=page&cmtitle=Category:Geography&cmlimit=100'
json_obj = urllib2.urlopen(url1)
data1 = json.load(json_obj)
for item in data1['query']:
for i in data1['query']['categorymembers']:
data.append(i['title'].encode('utf8')+"\n")
# Do additional requests, and append the new titles to the data array
f1.write(''.join(set(data)))
f1.close()
set allows me to delete any duplicate entry.
If keeping the titles in memory is a problem, you can check if the title already exists before writing it to the file, but it may be awfully time consuming :
import urllib2
import json
data = []
url1 ='https://en.wikipedia.org/w/api.php?\
action=query&format=json&list=categorymembers\
&cmtype=page&cmtitle=Category:Geography&cmlimit=100'
json_obj = urllib2.urlopen(url1)
data1 = json.load(json_obj)
for item in data1['query']:
for i in data1['query']['categorymembers']:
title = (i['title'].encode('utf8')+"\n")
with open('WordsInCategory.text', 'r') as title_check:
if title not in title_check:
data.append(title)
with open('WordsInCategory.text', 'a') as f1:
f1.write(''.join(set(data)))
# Handle additional requests
Hope it'll be helpful.

You can track the titles you added.
titles = []
and then add each title to the list when writing
if title not in titles:
# write to file
titles += title

Python URLs in file Requests

I have a problem with my Python script in which I want to scrape the same content from every website. I have a file with a lot of URLs and I want Python to go over them to place them into the requests.get(url) object. After that I write the output to a file named 'somefile.txt'.
I have to the following Python script (version 2.7 - Windows 8):
from lxml import html
import requests
urls = ('URL1',
'URL2',
'URL3'
)
for url in urls:
page = requests.get(url)
tree = html.fromstring(page.text)
visitors = tree.xpath('//b["no-visitors"]/text()')
print 'Visitors: ', visitors
f = open('somefile.txt', 'a')
print >> f, 'Visitors:', visitors # or f.write('...\n')
f.close()
As you can see if have not included the file with the URLs in the script. I tried out many tutorials but failed. The filename would be 'urllist.txt'. In the current script I only get the data from URL3 - in an ideal case I want to get all data from urllist.txt.
Attempt for reading over the text file:
with open('urllist.txt', 'r') as f: #text file containing the URLS
for url in f:
page = requests.get(url)

You'll need to remove the newline from your lines:
with open('urllist.txt', 'r') as f: #text file containing the URLS
for url in f:
page = requests.get(url.strip())
The str.strip() call removes all whitespace (including tabs and newlines and carriage returns) from the line.
Do make sure you then process page in the loop; if you run your code to extract the data outside the loop all you'll get is the data from the last response you loaded. You may as well open the output file just once, in the with statement so Python closes it again:
with open('urllist.txt', 'r') as urls, open('somefile.txt', 'a') as output:
for url in urls:
page = requests.get(url.strip())
tree = html.fromstring(page.content)
visitors = tree.xpath('//b["no-visitors"]/text()')
print 'Visitors: ', visitors
print >> output, 'Visitors:', visitors

You should either save the each page in a seperate variable, or perform all the computation within the looping of the url list.
Based on your code, by the time your page parsing happens it will only contain the data for the last page get since you are overriding the page variable within each iteration.
Something like the following should append all the pages' info.
for url in urls:
page = requests.get(url)
tree = html.fromstring(page.text)
visitors = tree.xpath('//b["no-visitors"]/text()')
print 'Visitors: ', visitors
f = open('somefile.txt', 'a')
print >> f, 'Visitors:', visitors # or f.write('...\n')
f.close()