Develop Reference

python-requests: What is different here between my python script and their curl command?

There is some api endpoint, which i try to send POST request with code like this
import requests
url = 'https://deviantart.com/api/v1/oauth2/collections/folders/create'
headers = {'Content-Type': 'application/json'}
data = {'folder': 'folder_name'}
params = {'access_token': '<authorization_code_flow_token>'}
r = requests.post(url=url,
headers=headers,
params=params,
json=data)
print(r.text)
But i get 400 response:
{
"error":"invalid_request",
"error_description":"Request field validation failed.",
"error_details":{"folder":"folder is required"},
"status":"error"
}
I don't understand why it fails, because their example with curl works fine.
curl https://www.deviantart.com/api/v1/oauth2/collections/folders/create \
-d "folder=Awesome Collection" \
-d access_token=Alph4num3r1ct0k3nv4lu3
And I was successful with post responses to get authenticated.
I tried to change content-type header(json and x-www-formurlencoded) and pass data-payload different ways(passing json string to data param, passing dict to json, passing paylod as query string). But It does not work. I dont have a clue what i am doing wrong. It seems like i send payload wrong or put wrong headers, but i tried a lot of "combinations" and still no effect.
For next hour you if you want try to help you can use access_token:
ba4550889c8c36c8d82093906145d9fd66775c959030d3d772

The following code will work.
import requests
url = "https://www.deviantart.com/api/v1/oauth2/collections/folders/create"
payload={'folder': 'Awesome Collection',
'access_token': 'ba4550889c8c36c8d82093906145d9fd66775c959030d3d772'}
files=[]
headers = {}
response = requests.request("POST", url, headers=headers, data=payload, files=files)
print(response.text)

CURL command in Python's requests

Can you please help me convert the following CURL command into a command for Python's requests library?
curl -F pdb_file[pathvar]=#/path/myfile.pdb -X POST https://proteins.plus/api/pdb_files_rest -H "Accept: application/json"
I've tried many things, like this:
import requests
file = open("3w32.pdb", "rb")
url = "https://proteins.plus/api/pdb_files_rest"
response = requests.post(url, data=file)
response.json()
or this:
import requests
file = open("3w32.pdb", "rb")
url = "https://proteins.plus/api/pdb_files_rest"
response = requests.post(url, data={"pdb_file[pathvar]": file}, json={"Accept": "application/json"})
response.json()
but I can't make it work. I either get an error from the server, or a JSONDecodeError in Python.

Try this answer https://stackoverflow.com/a/22567429/4252013
Instead of using "data" argument try with "file"

Ok, I managed to solve it at last.
The problem was that the 'pdb_file[pathvar]' part in the curl command should've been added to the request, like this:
import requests
file = open("3w32.pdb", "rb")
url = "https://proteins.plus/api/pdb_files_rest"
response = requests.post(url, files={'pdb_file[pathvar]':file})
response.json()
Now it works!

The problem in your code is that you have only opened the file and passed the pointer. you can pass the file contents by having file.read() in place.
Please refer this block of code:
import requests
file = open("3w32.pdb", "rb")
url = "https://proteins.plus/api/pdb_files_rest"
response = requests.post(url, data=file.read())
response.json()

How to write python code for the below curl request to send a post request and uploading an image as binary

curl --request POST -H "Content-Type: application/octet-stream" --data-binary "#/C:\\Users\\U6068366\\Downloads\\Koala.jpg" https://c6y09pww43.execute-api.us-east-1.amazonaws.com/p
--
App_Url = "https://p7a0km3l6k.execute-api.us-east-1.amazonaws.com/preprod/v1/images/trademark/metadata/providerPartition/{providerPartition}/providerPartitionId/{providerPartitionId}"
# f = open('C://Users//UX016491//PycharmProjects//DSSApi//data1.json')
# requests_json = json.loads(f.read())
files = {'media' : open('C:\\Users\\UX016491\\Desktop\\images\\image123.jpg','rb') }
response = requests.request("POST", App_Url, files = files, headers={"content-type": 'application/octet-stream'})
print(response)
if __name__ == '__main__':
test_createimage_data()

EDIT: I added url from python example because url in curl was incomplete. But it still need two values providerPartition and providerPartitionId
On https://curl.trillworks.com/ you can convert curl to python code. And mostly it works.
Here code from this page. But I can't test it.
import requests
# incompletet url from curl
#url = 'https://c6y09pww43.execute-api.us-east-1.amazonaws.com/p'
providerPartition = '??'
providerPartitionId = '??'
url = f'https://p7a0km3l6k.execute-api.us-east-1.amazonaws.com/preprod/v1/images/trademark/metadata/providerPartition/{providerPartition}/providerPartitionId/{providerPartitionId}'
headers = {
'Content-Type': 'application/octet-stream',
}
data = open('C:\\Users\\U6068366\\Downloads\\Koala.jpg', 'rb').read()
response = requests.post(url, headers=headers, data=data)
print(response.text)
You can also test both with url https://httpbin.org/post and it will send back what it get from you. And you can compare results from both requests. I tested curl and python code and I go the same information so they should give the same effect.

Python post request returns 500

I am using requests to make a POST request to create a user. The request succeeds with 201 created when I use curl, however fails with a 500 response when I use requests. My curl command is
curl --user administrator:password -H "Content-Type: application/json" https://localhost:8080/midpoint/ws/rest/users -d #user.json -v
And my python script is:
import requests
import json
headers = {
'Content-Type': 'application/json',
}
with open('user.json') as j:
data = json.load(j)
response = requests.post('https://localhost:8080/midpoint/ws/rest/users', headers=headers, data=str(data), auth=('Administrator', 'password'))
print(response)
Can anyone see a reason why my python script would be failing? I am at a loss.

str(data) returns the Python representation of data, not its JSON representation. These two forms can differ in things like ' vs. ", True vs. true, and None vs. null. To properly JSONify data, call json.dumps() on it:
response = requests.post(..., data=json.dumps(data))
or let requests do the JSONification:
response = requests.post(..., json=data)
or use the JSON as it appears in user.json directly:
with open('user.json') as j:
data = j.read()
response = requests.post(..., data=data)

How to convert a curl request to python?

I need to convert a curl statement to Python
curl -k -d 'id=id1' --data-urlencode 'username=user1' --data-urlencode 'password=pass1' https://aaaa.bbb.com:nnnn
I was able to use
import requests
data = [
('id', 'id1'),
]
response = requests.post('https://aaaa.bbb.com/:nnnn', data=data)
With this I get certificate_verify_failed. How can I include urlencode for the username and password

For bypassing certification check use (verify=False) :
response = requests.post('https://aaaa.bbb.com/:nnnn', data=data, verify=False)
and for ensuring to send data as url encoded :
response = requests.post('https://aaaa.bbb.com/:nnnn', data=data, verify=False, headers={'Content-Type':'application/x-www-form-urlencoded'})

The reason for certificate_verify_failed is perhaps because the client is trying to verify the server certificate and failing in doing so. You may disable the verification on the client side by using verify=False
import requests
url = "https://aaaa.bbb.com:nnnn"
headers = {}
data = {
"id": "id1"
}
response = requests.post(url, data=data, headers=headers, verify=False)