I am trying to get all surnames from xml file, but if I am trying to use find, It throws an exception
TypeError: 'NoneType' object is not iterable
This is my code:
import xml.etree.ElementTree as ET
tree = ET.parse('test.xml')
root = tree.getroot()
for elem in root:
for subelem in elem:
for subsubelem in subelem.find('surname'):
print(subsubelem.text)
When I remove the find('surname') from code, It returning all texts from subsubelements.
This is xml:
<?xml version="1.0" encoding="UTF-8"?>
<pp:card xmlns:pp="http://xmlns.page.com/path/subpath">
<pp:id>1</pp:id>
<pp:customers>
<pp:customer>
<pp:name>John</pp:name>
<pp:surname>Walker</pp:surname>
<pp:adress>
<pp:street>Walker street</pp:street>
<pp:number>1/1</pp:number>
<pp:state>England</pp:state>
</pp:adress>
<pp:created>2021-03-08Z</pp:created>
</pp:customer>
<pp:customer>
<pp:name>Michael</pp:name>
<pp:surname>Jordan</pp:surname>
<pp:adress>
<pp:street>Jordan street</pp:street>
<pp:number>28</pp:number>
<pp:state>USA</pp:state>
</pp:adress>
<pp:created>2021-03-09Z</pp:created>
</pp:customer>
</pp:customers>
</pp:card>
How should I fix it?
Not really a python person, but should the "find" statement include the "pp:" in its search, such as,
find('pp:surname')
Neither the opening nor closing tags actually match "surname".
Use the namespace when you call findall
import xml.etree.ElementTree as ET
xml = '''<?xml version="1.0" encoding="UTF-8"?>
<pp:card xmlns:pp="http://xmlns.page.com/path/subpath">
<pp:id>1</pp:id>
<pp:customers>
<pp:customer>
<pp:name>John</pp:name>
<pp:surname>Walker</pp:surname>
<pp:adress>
<pp:street>Walker street</pp:street>
<pp:number>1/1</pp:number>
<pp:state>England</pp:state>
</pp:adress>
<pp:created>2021-03-08Z</pp:created>
</pp:customer>
<pp:customer>
<pp:name>Michael</pp:name>
<pp:surname>Jordan</pp:surname>
<pp:adress>
<pp:street>Jordan street</pp:street>
<pp:number>28</pp:number>
<pp:state>USA</pp:state>
</pp:adress>
<pp:created>2021-03-09Z</pp:created>
</pp:customer>
</pp:customers>
</pp:card>'''
ns = {'pp': 'http://xmlns.page.com/path/subpath'}
root = ET.fromstring(xml)
names = [sn.text for sn in root.findall('.//pp:surname', ns)]
print(names)
output
['Walker', 'Jordan']
Related
Context:
I want to obtain information from an xml file. when doing print
"<Element 'vocation' at 0x000001C9C7849040>" I do not want that message to appear but the value
Original file XML:
<?xml version="1.0"?>
<spells>
<instant name="spell 1">
<vocation name="men 50"/>
<vocation name="men 100"/>
</instant>
<instant name="spells 2">
<vocation name="woman 50"/>
<vocation name="woman 100"/>
</instant>
</spells>
python code proposition
import xml.etree.ElementTree as ET
tree = ET.parse('D:\\desktop\\Archivos\\compilaciones\\1.5\\800\\data\\spells\\spells.xml')
root = tree.getroot()
for i in root.findall('instant'):
name_spells = i.get('name')
value_name_vocation = i.find('.//vocation[last()]')
print(name_spells, value_name_vocation)
Output Problem(<Element 'vocation' at 0x000001C9C7849040>)
spells1 <Element 'vocation' at 0x000001C9C7AB9810>
spells2 <Element 'vocation' at 0x000001C9C7849040>
desirable output
spells1 men 100
spells2 woman 100
I was searching and some functions don't work.
.text -> AttributeError: 'NoneType' object has no attribute 'text'
->'NoneType' object has no attribute 'iter'
I am open to using other libraries
Since you have the element object already you just need to get its name from within it. Like you already do with your counter variable i.
import xml.etree.ElementTree as ET
tree = ET.parse('D:\\desktop\\Archivos\\compilaciones\\1.5\\800\\data\\spells\\spells.xml')
root = tree.getroot()
for i in root.findall('instant'):
name_spells = i.get('name')
value_name_vocation = i.find('.//vocation[last()]')
print(name_spells, value_name_vocation.get('name'))
hi I am trying to parse xml with namespace and attribute.
I am almost close by using root.findall() and .get()
However still struggling to get the accurate values from xml file.
How to get the xml attribute values ?
Input:
<?xml version="1.0" encoding="UTF-8"?><message:GenericData
xmlns:message="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/message"
xmlns:common="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/common"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:generic="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic"
xsi:schemaLocation="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/message https://sdw-
wsrest.ecb.europa.eu:443/vocabulary/sdmx/2_1/SDMXMessage.xsd
http://www.sdmx.org/resources/sdmxml/schemas/v2_1/common https://sdw-
wsrest.ecb.europa.eu:443/vocabulary/sdmx/2_1/SDMXCommon.xsd
http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic https://sdw-
wsrest.ecb.europa.eu:443/vocabulary/sdmx/2_1/SDMXDataGeneric.xsd">
<generic:Obs>
<generic:ObsDimension value="1999-01"/>
<generic:ObsValue value="0.7029125"/>
</generic:Obs>
<generic:Obs>
<generic:ObsDimension value="1999-02"/>
<generic:ObsValue value="0.688505"/>
</generic:Obs>
Code:
import xml.etree.ElementTree as ET
tree = ET.parse("file.xml")
root = tree.getroot()
for x in root.findall('.//'):
print(x.tag, " ", x.get('value'))
Output:
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}Obs None
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}ObsDimension 1999-01
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}ObsValue 0.7029125
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}Obs None
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}ObsDimension 1999-02
{http://www.sdmx.org/resources/sdmxml/schemas/v2_1/data/generic}ObsValue 0.688505
Expected_Output:
1999-01 0.7029125
1999-02 0.688505
How about this:
for parent in root:
print(' '.join([child.get('value', "") for child in parent]))
I have the following XML that I would like to extract a portion of the child if name matches "Adam"
<data>
<a:config version="1.0" xmlns:a="uri:abc.com/a" xmlns:b="uri:abc.com/b">
<a:xxx config="ABC">
<set>option_on</set>
<location>/123/123</location>
<data>123</data>
</a:xxx>
<a:xxx name="Adam">
<a:yyy value="5555-5555">
<log>true</log>
</a:yyy>
</a:xxx>
<a:xxx name="Lisa">
<a:yyy value="2222-2222">
<log>false</log>
</a:yyy>
</a:xxx>
</a:config>
</data>
I manage to extract the section but it doesn't output the original namespace rather it is showing ns0 and ns1. Below is my code
import xml.etree.ElementTree as ET
tree2 = ET.parse("mycode.xml")
root2= tree2.getroot()
for elem in tree2.iter(tag='{uri:abc.com/a}xxx'):
match = elem.get('name')
if match == "Adam":
bla = ET.dump(elem)
Output as follows: -
<ns0:xxx xmlns:ns0="uri:abc.com/a" name="Adam">
<ns0:yyy value="5555-5555">
<log>true</log>
</ns0:yyy>
</ns0:xxx>
I am hoping to get exactly as what the original document is:-
<a:xxx name="Adam">
<a:yyy value="5555-5555">
<log>true</log>
</a:yyy>
</a:xxx>
Use the register_namespace function.
import xml.etree.ElementTree as ET
tree2 = ET.parse("mycode.xml")
root2 = tree2.getroot()
# Register the 'a' prefix to be used when serializing
ET.register_namespace("a", "uri:abc.com/a")
for elem in tree2.iter(tag='{uri:abc.com/a}xxx'):
match = elem.get('name')
if match == "Adam":
bla = ET.dump(elem)
Output:
<a:xxx xmlns:a="uri:abc.com/a" name="Adam">
<a:yyy value="5555-5555">
<log>true</log>
</a:yyy>
</a:xxx>
This is not the exact output that you asked for. You cannot force ElementTree to omit the namespace declaration (because doing so would make the output ill-formed).
I need to filter an XML file for certain values, if the node contains this value, the node should be removed.
<?xml version="1.0" encoding="utf-8" ?>
<ogr:FeatureCollection
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://ogr.maptools.org/ TZwards.xsd"
xmlns:ogr="http://ogr.maptools.org/"
xmlns:gml="http://www.opengis.net/gml">
<gml:boundedBy></gml:boundedBy>
<gml:featureMember>
<ogr:TZwards fid="F0">
<ogr:Region_Nam>TARGET</ogr:Region_Nam>
<ogr:District_N>Kondoa</ogr:District_N>
<ogr:Ward_Name>Bumbuta</ogr:Ward_Name>
</ogr:TZwards>
</gml:featureMember>
<gml:featureMember>
<ogr:TZwards fid="F1">
<ogr:Region_Nam>REMOVE</ogr:Region_Nam>
<ogr:District_N>Kondoa</ogr:District_N>
<ogr:Ward_Name>Pahi</ogr:Ward_Name>
</ogr:TZwards>
</gml:featureMember>
</ogr:FeatureCollection>
The Python script should keep the <gml:featureMember> node if the <ogr:Region_Nam> contains TARGET and remove all other nodes.
from xml.dom import minidom
import xml.etree.ElementTree as ET
tree = ET.parse('input.xml').getroot()
removeList = list()
for child in tree.iter('gml:featureMember'):
if child.tag == 'ogr:TZwards':
name = child.find('ogr:Region_Nam').text
if (name == 'TARGET'):
removeList.append(child)
for tag in removeList:
parent = tree.find('ogr:TZwards')
parent.remove(tag)
out = ET.ElementTree(tree)
out.write(outputfilepath)
Desired output:
<?xml version="1.0" encoding="utf-8" ?>
<ogr:FeatureCollection>
<gml:boundedBy></gml:boundedBy>
<gml:featureMember>
<ogr:TZwards fid="F0">
<ogr:Region_Nam>TARGET</ogr:Region_Nam>
<ogr:District_N>Kondoa</ogr:District_N>
<ogr:Ward_Name>Bumbuta</ogr:Ward_Name>
</ogr:TZwards>
</gml:featureMember>
</ogr:FeatureCollection>
My output still contains all nodes..
You need to declare the namespaces in the python code:
from xml.dom import minidom
import xml.etree.ElementTree as ET
tree = ET.parse('/tmp/input.xml').getroot()
namespaces = {'gml': 'http://www.opengis.net/gml', 'ogr':'http://ogr.maptools.org/'}
for child in tree.findall('gml:featureMember', namespaces=namespaces):
if len(child.find('ogr:TZwards', namespaces=namespaces)):
name = child.find('ogr:TZwards', namespaces=namespaces).find('ogr:Region_Nam', namespaces=namespaces).text
if name != 'TARGET':
tree.remove(child)
out = ET.ElementTree(tree)
out.write("/tmp/out.xml")
I have code in a XML file, which I parse using et.parse:
<VIAFCluster xmlns="http://viaf.org/viaf/terms#" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:void="http://rdfs.org/ns/void#" xmlns:foaf="http://xmlns.com/foaf/0.1/">
<viafID>15</viafID>
<nameType>Personal</nameType>
</VIAFCluster>
<mainHeadings>
<data>
<text>
Gondrin de Pardaillan de Montespan, Louis-Antoine de, 1665-1736
</text>
</data>
</mainHeadings>
and I want to parse it as:
[15, "Personal", "Gondrin etc."]
I can't seem to print any of the string information with:
import xml.etree.ElementTree as ET
tree = ET.parse('/Users/user/Documents/work/oneline.xml')
root = tree.getroot()
for node in tree.iter():
name = node.find('nameType')
print(name)
as it appears as 'None' ... what am I doing wrong?
I'm still not sure exactly what you are wanting to do, but hopefully if you run the code below, it will help get you on your way. Using the getiterator function to iter through the elements will let you see what's going on. You can pick up the stuff you want as you come to them:
import xml.etree.ElementTree as et
xml = '''
<VIAFCluster xmlns="http://viaf.org/viaf/terms#"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:void="http://rdfs.org/ns/void#"
xmlns:foaf="http://xmlns.com/foaf/0.1/">
<viafID>15</viafID>
<nameType>Personal</nameType>
<mainHeadings>
<data>
<text>
Gondrin de Pardaillan de Montespan, Louis-Antoine de, 1665-1736
</text>
</data>
</mainHeadings>
</VIAFCluster>
'''
tree = et.fromstring(xml)
lst = []
for i in tree.getiterator():
t = i.text.strip()
if t:
lst.append(t)
print i.tag
print t
You will end up with a list as you wanted. I had to clean up your xml because you had more than one top level element, which is a no-no. Maybe that was your problem all along.
good luck, Mike