I checked a few other posts and either they didn't contain the information I need or I didn't understand them. I want to make this program print the sentence for every entry in the nested dictionary, and maybe also make a function to do this as well (not familiar with these yet).
I know it will use a for loop but what I can't figure out is how to configure the keys(?).
people = {
1: {
'name': 'David Wallace',
'age': 50,
'occupation': 'CFO',
'ethnicity': 'American',
'location': 'New York'
},
2: {
'name': 'Michael',
'age': 42,
'occupation': 'Regional Manager',
'ethnicity': 'American',
'location': 'Scranton, Pennsylvania'
},
3: {
'name': 'Jim',
'age': 27,
'occupation': 'Sales Rep',
'ethnicity': 'American',
'location': 'Scranton, Pennsylvania'
}
}
print('{name} is a {age} year-old {ethnicity} {occupation} from {location}.'.format(**people))
You're really treating the top-level dict more like a list, so you can write a for loop traversing the top-level like so:
people = {
1: {
'name': 'David Wallace',
'age': 50,
'occupation': 'CFO',
'ethnicity': 'American',
'location': 'New York'
},
2: {
'name': 'Michael',
'age': 42,
'occupation': 'Regional Manager',
'ethnicity': 'American',
'location': 'Scranton, Pennsylvania'
},
3: {
'name': 'Jim',
'age': 27,
'occupation': 'Sales Rep',
'ethnicity': 'American',
'location': 'Scranton, Pennsylvania'
}
}
for person in people.values():
print('{name} is a {age} year-old {ethnicity} {occupation} from {location}.'.format(**person))
The full reference for Python dictionaries is here: https://docs.python.org/3/library/stdtypes.html#dict.items
Edit: Thanks to user Chris Charley for the suggestion to use people.values() instead of people.items()
Related
I want to convert input json to nested json defined, I am not able to think of any json library which help me achieve this
Input json
[{'Name': 'John', 'state': 'Boston', 'currency': 'USD', 'marks': 100},
{'Name': 'Rohan', 'state': 'Paris', 'currency': 'EUR', 'marks': 20},
{'Name': 'Rohan', 'state': 'Lyon', 'currency': 'EUR', 'marks': 11.4},
{'Name': 'Messi', 'state': 'Madrid', 'currency': 'EUR', 'marks': 9.9},
{'Name': 'Lampard', 'state': 'London', 'currency': 'GBP', 'marks': 12.2},
{'Name': 'Lampard', 'state': 'London', 'currency': 'FBP', 'marks': 10.9}]
output json
{
"USD": {
"John": {
"Boston": [
{
"Marks": 100
}
]
},
Current scenario based on value Currency,Name,state,marks
The nested json can be put upto n level if required such as Name and state and marks or it can be Name , curreny , state and marks or Name,curreny and marks
So you want currency > name > state > list of marks.
One solution would be to create the structure using defaultdicts, and then just add to it.
from collections import defaultdict
from functools import wraps
data = [...]
def ddmaker(type_):
#wraps(dict)
def caller():
return defaultdict(type_)
return caller
# create the structure of the output
output = defaultdict(ddmaker(ddmaker(list)))
# add to it
for item in data:
currency = item["currency"]
name = item["Name"]
state = item["state"]
mark = item["marks"]
output[currency][name][state].append({'Marks': mark})
I looked up "nested dict" and "nested list" but either method work.
I have a python object with the following structure:
[{
'id': 'productID1', 'name': 'productname A',
'option': {
'size': {
'type': 'list',
'name': 'size',
'choices': [
{'value': 'M'},
]}},
'variant': [{
'id': 'variantID1',
'choices':
{'size': 'M'},
'attributes':
{'currency': 'USD', 'price': 1}}]
}]
what i need to output is a csv file in the following, flattened structure:
id, productname, variantid, size, currency, price
productID1, productname A, variantID1, M, USD, 1
productID1, productname A, variantID2, L, USD, 2
productID2, productname A, variantID3, XL, USD, 3
i tried this solution: Python: Writing Nested Dictionary to CSV
or this one: From Nested Dictionary to CSV File
i got rid of the [] around and within the data and e.g. i used this code snippet from 2 and adapted it to my needs. IRL i can't get rid of the [] because that's simple the format i get when calling the API.
with open('productdata.csv', 'w', newline='', encoding='utf-8') as output:
writer = csv.writer(output, delimiter=';', quotechar = '"', quoting=csv.QUOTE_NONNUMERIC)
for key in sorted(data):
value = data[key]
if len(value) > 0:
writer.writerow([key, value])
else:
for i in value:
writer.writerow([key, i, value])
but the output is like this:
"id";"productID1"
"name";"productname A"
"option";"{'size': {'type': 'list', 'name': 'size', 'choices': {'value': 'M'}}}"
"variant";"{'id': 'variantID1', 'choices': {'size': 'M'}, 'attributes': {'currency': 'USD', 'price': 1}}"
anyone can help me out, please?
thanks in advance
list indices must be integers not strings
The following presents a visual example of a python list:
0 carrot.
1 broccoli.
2 asparagus.
3 cauliflower.
4 corn.
5 cucumber.
6 eggplant.
7 bell pepper
0, 1, 2 are all "indices".
"carrot", "broccoli", etc... are all said to be "values"
Essentially, a python list is a machine which has integer inputs and arbitrary outputs.
Think of a python list as a black-box:
A number, such as 5, goes into the box.
you turn a crank handle attached to the box.
Maybe the string "cucumber" comes out of the box
You got an error: TypeError: list indices must be integers or slices, not str
There are various solutions.
Convert Strings into Integers
Convert the string into an integer.
listy_the_list = ["carrot", "broccoli", "asparagus", "cauliflower"]
string_index = "2"
integer_index = int(string_index)
element = listy_the_list[integer_index]
so yeah.... that works as long as your string-indicies look like numbers (e.g. "456" or "7")
The integer class constructor, int(), is not very smart.
For example, x = int("3 ") will produce an error.
You can try x = int(strying.strip()) to get rid of leading and trailing white-space characters.
Use a Container which Allows Keys to be Strings
Long ago, before before electronic computers existed, there were various types of containers in the world:
cookie jars
muffin tins
carboard boxes
glass jars
steel cans.
back-packs
duffel bags
closets/wardrobes
brief-cases
In computer programming there are also various types of "containers"
You do not have to use a list as your container, if you do not want to.
There are containers where the keys (AKA indices) are allowed to be strings, instead of integers.
In python, the standard container which like a list, but where the keys/indices can be strings, is a dictionary
thisdict = {
"make": "Ford",
"model": "Mustang",
"year": 1964
}
thisdict["brand"] == "Ford"
If you want to index into a container using strings, instead of integers, then use a dict, instead of a list
The following is an example of a python dict which has state names as input and state abreviations as output:
us_state_abbrev = {
'Alabama': 'AL',
'Alaska': 'AK',
'American Samoa': 'AS',
'Arizona': 'AZ',
'Arkansas': 'AR',
'California': 'CA',
'Colorado': 'CO',
'Connecticut': 'CT',
'Delaware': 'DE',
'District of Columbia': 'DC',
'Florida': 'FL',
'Georgia': 'GA',
'Guam': 'GU',
'Hawaii': 'HI',
'Idaho': 'ID',
'Illinois': 'IL',
'Indiana': 'IN',
'Iowa': 'IA',
'Kansas': 'KS',
'Kentucky': 'KY',
'Louisiana': 'LA',
'Maine': 'ME',
'Maryland': 'MD',
'Massachusetts': 'MA',
'Michigan': 'MI',
'Minnesota': 'MN',
'Mississippi': 'MS',
'Missouri': 'MO',
'Montana': 'MT',
'Nebraska': 'NE',
'Nevada': 'NV',
'New Hampshire': 'NH',
'New Jersey': 'NJ',
'New Mexico': 'NM',
'New York': 'NY',
'North Carolina': 'NC',
'North Dakota': 'ND',
'Northern Mariana Islands':'MP',
'Ohio': 'OH',
'Oklahoma': 'OK',
'Oregon': 'OR',
'Pennsylvania': 'PA',
'Puerto Rico': 'PR',
'Rhode Island': 'RI',
'South Carolina': 'SC',
'South Dakota': 'SD',
'Tennessee': 'TN',
'Texas': 'TX',
'Utah': 'UT',
'Vermont': 'VT',
'Virgin Islands': 'VI',
'Virginia': 'VA',
'Washington': 'WA',
'West Virginia': 'WV',
'Wisconsin': 'WI',
'Wyoming': 'WY'
}
i could actually iterate this list and create my own sublist, e.g. e list of variants
data = [{
'id': 'productID1', 'name': 'productname A',
'option': {
'size': {
'type': 'list',
'name': 'size',
'choices': [
{'value': 'M'},
]}},
'variant': [{
'id': 'variantID1',
'choices':
{'size': 'M'},
'attributes':
{'currency': 'USD', 'price': 1}}]
},
{'id': 'productID2', 'name': 'productname B',
'option': {
'size': {
'type': 'list',
'name': 'size',
'choices': [
{'value': 'XL', 'salue':'XXL'},
]}},
'variant': [{
'id': 'variantID2',
'choices':
{'size': 'XL', 'size2':'XXL'},
'attributes':
{'currency': 'USD', 'price': 2}}]
}
]
new_list = {}
for item in data:
new_list.update(id=item['id'])
new_list.update (name=item['name'])
for variant in item['variant']:
new_list.update (varid=variant['id'])
for vchoice in variant['choices']:
new_list.update (vsize=variant['choices'][vchoice])
for attribute in variant['attributes']:
new_list.update (vprice=variant['attributes'][attribute])
for option in item['option']['size']['choices']:
new_list.update (osize=option['value'])
print (new_list)
but the output is always the last item of the iteration, because i always overwrite new_list with update().
{'id': 'productID2', 'name': 'productname B', 'varid': 'variantID2', 'vsize': 'XXL', 'vprice': 2, 'osize': 'XL'}
here's the final solution which worked for me:
data = [{
'id': 'productID1', 'name': 'productname A',
'variant': [{
'id': 'variantID1',
'choices':
{'size': 'M'},
'attributes':
{'currency': 'USD', 'price': 1}},
{'id':'variantID2',
'choices':
{'size': 'L'},
'attributes':
{'currency':'USD', 'price':2}}
]
},
{
'id': 'productID2', 'name': 'productname B',
'variant': [{
'id': 'variantID3',
'choices':
{'size': 'XL'},
'attributes':
{'currency': 'USD', 'price': 3}},
{'id':'variantID4',
'choices':
{'size': 'XXL'},
'attributes':
{'currency':'USD', 'price':4}}
]
}
]
for item in data:
for variant in item['variant']:
dic = {}
dic.update (ProductID=item['id'])
dic.update (Name=item['name'].title())
dic.update (ID=variant['id'])
dic.update (size=variant['choices']['size'])
dic.update (Price=variant['attributes']['price'])
products.append(dic)
keys = products[0].keys()
with open('productdata.csv', 'w', newline='', encoding='utf-8') as output_file:
dict_writer = csv.DictWriter(output_file, keys,delimiter=';', quotechar = '"', quoting=csv.QUOTE_NONNUMERIC)
dict_writer.writeheader()
dict_writer.writerows(products)
with the following output:
"ProductID";"Name";"ID";"size";"Price"
"productID1";"Productname A";"variantID1";"M";1
"productID1";"Productname A";"variantID2";"L";2
"productID2";"Productname B";"variantID3";"XL";3
"productID2";"Productname B";"variantID4";"XXL";4
which is exactly what i wanted.
I've been stuck on this for hours.. I want to retrieve only ONE individuals keys and values from a dictionary that is nested inside of a list.
GAMERS = [{
'name': 'Fatboi',
'parent': 'Dick Van Dyke',
'game': 'Dark Souls 3',
'weight': '420 lbs'
},
{
'name': 'Justin',
'parent': 'Heather Blueberry',
'game': 'Tetris',
'weight': '180 lbs'
},
{
'name': 'jerkhead',
'parent': 'none',
'games': 'Hello Kitty',
'weight': '240 lbs'
},{
'name': 'Tumor',
'parent': 'Jack Black',
'games': 'Trying to live',
'weight': '150 lbs'
}]
So for instance I want to get Justins information printed only, nobody elses. Any insights?
You can pass the key which you want and push it to separate list.
GAMERS = [{
'name': 'Fatboi',
'parent': 'Dick Van Dyke',
'game': 'Dark Souls 3',
'weight': '420 lbs'
},
{
'name': 'Justin',
'parent': 'Heather Blueberry',
'game': 'Tetris',
'weight': '180 lbs'
},{
'name': 'jerkhead',
'parent': 'none',
'games': 'Hello Kitty',
'weight': '240 lbs'
}]
def get_key_pair_list(input_dict, key):
new_list = []
for item in input_dict:
my_dict = {}
if key in item.keys():
my_dict[key] = item[key]
new_list.append(my_dict)
return new_list
print(get_key_pair_list(GAMERS, 'name'))
Output:
[{'name': 'Fatboi'}, {'name': 'Justin'}, {'name': 'jerkhead'}]
Comprehensive way:
key = 'name'
my_list = [{key, item[key]} for item in GAMERS if key in item.keys() ]
print(my_list)
output:
[{'name', 'Fatboi'}, {'name', 'Justin'}, {'name', 'jerkhead'}]
You want to filter the list and grab the first value that matches a predicate. Make sure to handle the case where the item doesnt exist!
filtered_info = (
item for item in GAMERS if item['name'] == 'Justin'
)
justin_info = next(filtered_info, None)
if justin_info is not None:
print(justin_info)
This is my first question :)
I loop over a nested dictionary to print specific values. I am using the following code.
for i in lizzo_top_tracks['tracks']:
print('Track Name: ' + i['name'])
It works for string variables, but does not work for other variables. For example, when I use the following code for the date variable:
for i in lizzo_top_tracks['tracks']:
print('Album Release Date: ' + i['release_date'])
I receive a message like this KeyError: 'release_date'
What should I do?
Here is a sample of my nested dictionary:
{'tracks': [{'album': {'album_type': 'album',
'artists': [{'external_urls': {'spotify': 'https://open.spotify.com/artist/56oDRnqbIiwx4mymNEv7dS'},
'href': 'https://api.spotify.com/v1/artists/56oDRnqbIiwx4mymNEv7dS',
'id': '56oDRnqbIiwx4mymNEv7dS',
'name': 'Lizzo',
'type': 'artist',
'uri': 'spotify:artist:56oDRnqbIiwx4mymNEv7dS'}],
'external_urls': {'spotify': 'https://open.spotify.com/album/74gSdSHe71q7urGWMMn3qB'},
'href': 'https://api.spotify.com/v1/albums/74gSdSHe71q7urGWMMn3qB',
'id': '74gSdSHe71q7urGWMMn3qB',
'images': [{'height': 640,
'width': 640}],
'name': 'Cuz I Love You (Deluxe)',
'release_date': '2019-05-03',
'release_date_precision': 'day',
'total_tracks': 14,
'type': 'album',
'uri': 'spotify:album:74gSdSHe71q7urGWMMn3qB'}]}
The code you posted isn't syntactically correct; running it through a Python interpreter gives a syntax error on the last line. It looks like you lost a curly brace somewhere toward the end. :)
I went through it and fixed up the white space to make the structure easier to see; the way you had it formatted made it hard to see which keys were at which level of nesting, but with consistent indentation it becomes much clearer:
lizzo_top_tracks = {
'tracks': [{
'album': {
'album_type': 'album',
'artists': [{
'external_urls': {
'spotify': 'https://open.spotify.com/artist/56oDRnqbIiwx4mymNEv7dS'
},
'href': 'https://api.spotify.com/v1/artists/56oDRnqbIiwx4mymNEv7dS',
'id': '56oDRnqbIiwx4mymNEv7dS',
'name': 'Lizzo',
'type': 'artist',
'uri': 'spotify:artist:56oDRnqbIiwx4mymNEv7dS'
}],
'external_urls': {
'spotify': 'https://open.spotify.com/album/74gSdSHe71q7urGWMMn3qB'
},
'href': 'https://api.spotify.com/v1/albums/74gSdSHe71q7urGWMMn3qB',
'id': '74gSdSHe71q7urGWMMn3qB',
'images': [{'height': 640, 'width': 640}],
'name': 'Cuz I Love You (Deluxe)',
'release_date': '2019-05-03',
'release_date_precision': 'day',
'total_tracks': 14,
'type': 'album',
'uri': 'spotify:album:74gSdSHe71q7urGWMMn3qB'
}
}]
}
So the first (and only) value you get for i in lizzo_top_tracks['tracks'] is going to be this dictionary:
i = {
'album': {
'album_type': 'album',
'artists': [{
'external_urls': {
'spotify': 'https://open.spotify.com/artist/56oDRnqbIiwx4mymNEv7dS'
},
'href': 'https://api.spotify.com/v1/artists/56oDRnqbIiwx4mymNEv7dS',
'id': '56oDRnqbIiwx4mymNEv7dS',
'name': 'Lizzo',
'type': 'artist',
'uri': 'spotify:artist:56oDRnqbIiwx4mymNEv7dS'
}],
'external_urls': {
'spotify': 'https://open.spotify.com/album/74gSdSHe71q7urGWMMn3qB'
},
'href': 'https://api.spotify.com/v1/albums/74gSdSHe71q7urGWMMn3qB',
'id': '74gSdSHe71q7urGWMMn3qB',
'images': [{'height': 640, 'width': 640}],
'name': 'Cuz I Love You (Deluxe)',
'release_date': '2019-05-03',
'release_date_precision': 'day',
'total_tracks': 14,
'type': 'album',
'uri': 'spotify:album:74gSdSHe71q7urGWMMn3qB'
}
}
The only key in this dictionary is 'album', the value of which is another dictionary that contains all the other information. If you want to print, say, the album release date and a list of the artists' names, you'd do:
for track in lizzo_top_tracks['tracks']:
print('Album Release Date: ' + track['album']['release_date'])
print('Artists: ' + str([artist['name'] for artist in track['album']['artists']]))
If these are dictionaries that you're building yourself, you might want to remove some of the nesting layers where there's only a single key, since they just make it harder to navigate the structure without giving you any additional information. For example:
lizzo_top_albums = [{
'album_type': 'album',
'artists': [{
'external_urls': {
'spotify': 'https://open.spotify.com/artist/56oDRnqbIiwx4mymNEv7dS'
},
'href': 'https://api.spotify.com/v1/artists/56oDRnqbIiwx4mymNEv7dS',
'id': '56oDRnqbIiwx4mymNEv7dS',
'name': 'Lizzo',
'type': 'artist',
'uri': 'spotify:artist:56oDRnqbIiwx4mymNEv7dS'
}],
'external_urls': {
'spotify': 'https://open.spotify.com/album/74gSdSHe71q7urGWMMn3qB'
},
'href': 'https://api.spotify.com/v1/albums/74gSdSHe71q7urGWMMn3qB',
'id': '74gSdSHe71q7urGWMMn3qB',
'images': [{'height': 640, 'width': 640}],
'name': 'Cuz I Love You (Deluxe)',
'release_date': '2019-05-03',
'release_date_precision': 'day',
'total_tracks': 14,
'type': 'album',
'uri': 'spotify:album:74gSdSHe71q7urGWMMn3qB'
}]
This structure allows you to write the query the way you were originally trying to do it:
for album in lizzo_top_albums:
print('Album Release Date: ' + album['release_date'])
print('Artists: ' + str([artist['name'] for artist in album['artists']]))
Much simpler, right? :)
I know there must be a very simple solution to this question but I am new with Python and cannot figure out how to do it.
All I simply want to do is count how many times a particular value appears in this dictionary, for example, how many males there are.
people = {}
people['Applicant1'] = {'Name': 'David Brown',
'Gender': 'Male',
'Occupation': 'Office Manager',
'Age': '33'}
people['Applicant2'] = {'Name': 'Peter Parker',
'Gender': 'Male',
'Occupation': 'Postman',
'Age': '25'}
people['Applicant3'] = {'Name': 'Patricia M',
'Gender': 'Female',
'Occupation': 'Teacher',
'Age': '35'}
people['Applicant4'] = {'Name': 'Mark Smith',
'Gender': 'Male',
'Occupation': 'Unemployed',
'Age': '26'}
Any help is much appreciated!
For your example, you have applicants and their data. The data you are checking is their gender, so the below code will accomplish that.
amount = 0 # amount of people matching condition
for applicant in people.values(): # looping through all applicants
if applicant.get('Gender', False) == 'Male': # checks if applicant['Gender'] is 'Male'
# note it will return False if ['Gender'] wasn't set
amount += 1 # adds matching people to amount
This will get the amount of males in the applicant list.
I'd suggest refactoring your logic a bit to use a list of dicts.
people = [
{
'Name': 'David Brown',
'Gender': 'Male',
'Occupation': 'Office Manager',
'Age': '33'
},
{
'Name': 'Peter Parker',
'Gender': 'Male',
'Occupation': 'Postman',
'Age': '25'
},
{
'Name': 'Patricia M',
'Gender': 'Female',
'Occupation': 'Teacher',
'Age': '35'
},
{
'Name': 'Mark Smith',
'Gender': 'Male',
'Occupation': 'Unemployed',
'Age': '26'
}
]
Then you can use logic like
[applicant for applicant in people if applicant['Gender'] == 'Male']
Which will give you all of the males in the list
This is a function to count the number of occurrences of a given value inside a dictionary:
def count(dic, val):
sum = 0
for key,value in dic.items():
if value == val:
sum += 1
if type(value) is dict:
sum += count(dic[key], val)
return sum
Then you can use it as follow:
result = count(people, 'Male')