Django textarea form - python

i need to set rows and cols for a textarea in my HTML page from Django but it doesnt work.
I already put rows and cols in mine form
Views.py
class EditForm(forms.Form):
title = forms.CharField(widget=forms.TextInput(attrs={'name':'title'}))
body = forms.CharField(widget=forms.Textarea(attrs={'name':'body', 'rows':3, 'cols':5}))
def new(request):
return render(request,"encyclopedia/handlepage.html", {
"title": "CREATE NEW PAGE",
"edit": False,
"editpage": EditForm()
})
handlepage.html
{% extends "encyclopedia/layout.html" %}
{% block title %}
{{ title }}
{% endblock %}
{% block body %}
<h1>{{title}}</h1>
Markdown guides
{% if edit %}
//Useless right now
{% else %}
<form method="POST" action="{% url 'save' %}">
<input type="submit" value="SAVE ENTRY"><br>
{% csrf_token %}
{{ editpage }}
</form>
{% endif %}
{% endblock %}
Then my page should have a small text area but it have the same size independent by its row and cols like this

I had the exact same issue and I think we are working on the same project because the screenshots look the same: was this Project 1 for
CS50’s Web Programming with Python and JavaScript?
Anyway, I tried with
content = forms.CharField(widget=forms.Textarea(attrs={"rows":"5"}))
and it looked like it didn't work, but it was only because of a CSS property already applied that overrides the rows and columns attributes (as #AMG also suggested).
You can see this if you open your browser Inspector:
You just need to remove those two CSS properties for width and height to see the rows and columns attibutes apply.
I know that you have probably already solved this issue, but I'm posting this because I guess that fellow CS50 students may still need this answer in the future.

Does adding it in init work? I forget the reason I had to do it this way but it's what I've been using (I may be out of date though).
class EditForm(forms.Form):
body = forms.CharField(widget=forms.Textarea())
def __init__(self, *args, *kwargs):
super().__init__(*args, *kwargs)
self.fields['body'].widget.attrs['rows'] = 3
or alternatively in meta:
class EditForm(forms.Form):
# your fields defined here followed by Meta
class Meta:
fields = ['title', 'body' ]
widgets = {
'body': forms.Textarea(attrs={'rows': 3}),
}

Write those numbers in the quotes. And see if it works.
body = forms.CharField(widget=forms.Textarea(attrs={'name':'body', 'rows':'3', 'cols':'5'}))

What worked for me is changing the CSS style of the text-area.
class EditForm(forms.Form):
title = forms.CharField(widget=forms.TextInput(attrs={'name':'title'}))
body = forms.CharField(widget=forms.Textarea(attrs={'name':'body',
'style': 'height: 3em;'))
Hope it works for you!

I think I have found the answer.
in Project1\wiki\encyclopedia\static\encyclopedia.there is a CSS file called
style.CSS.
in this file determines the Style of textarea.
"
textarea {
height: 90vh;
width: 80%;
}
"
enter image description here
delete this and all come back.

Related

Django-autocomplete-light showing empty dropdown instead of autocomplete widget

I am trying to implement django-autocomplete-light in my projects but cannot figure out why it does not show me the autocomplete widget, but keeps showing an empty dropdown.
I followed the tutorial: https://django-autocomplete-light.readthedocs.io/en/3.1.3/tutorial.html.
I found that this problem has occurred in other stackoverflow questions, but none of those answers have helped me so far.
I have the following model:
class Vilt(models.Model):
vilt_title = models.CharField(max_length=200, unique=True)
I created this autocomplete view:
class ViltAutocomplete(autocomplete.Select2QuerySetView):
def get_queryset(self):
# Don't forget to filter out results depending on the visitor !
# if not self.request.user.is_authenticated():
# return Vilt.objects.none()
qs = Vilt.objects.all().order_by('vilt_title')
if self.q:
qs = qs.filter(vilt_title__istartswith=self.q)
return qs
I use this ModelForm where I specify the widget.
from .models import Vilt
from dal import autocomplete
class ViltSearchForm(forms.ModelForm):
vilt_title = forms.ModelChoiceField(
queryset = Vilt.objects.all(),
widget = autocomplete.ModelSelect2(url='vilt-autocomplete')
)
class Meta:
model = Vilt
fields = ('vilt_title',)
from .views import (ViltAutocomplete,
)
urlpatterns = [
#other paths
path('vilt/autocomplete/', ViltAutocomplete.as_view(), name='vilt-autocomplete'),
#other paths
]
{% extends "bierviltje/base.html" %}
{% load static %}
{% load crispy_forms_tags %}
{% block content %}
<div class="container">
#other forms
<div>
<form action="" method="post">
{% csrf_token %}
{{ vilt_search_form|crispy }}
<input type="submit" />
</form>
</div>
#other forms
</div>
{% endblock content %}
{% block javascript %}
{{ vilt_search_form.media }}
{% endblock javascript %}
This is the Javascript that is loaded in before the javascript block in base.html:
<!-- jQuery first, then Popper.js, then Bootstrap JS -->
<script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js"></script>
{% block javascript %}
{% endblock javascript %}
It's been sometime since you posted your query. But in case you have not found the answer yet, here is the solution:
In your ModelForm "ViltSearchForm", please change the widget from:
widget = autocomplete.ModelSelect2(url='vilt-autocomplete')
to:
widget = autocomplete.ListSelect2(url='vilt-autocomplete')
However, if I may add here, I can't fathom the reason for using "autocomplete" on a stand alone model.
A feedback would be much appreciated.

How to get the current URL linkable within a Django template? [duplicate]

Some solutions provided on doing a Google search for "Django breadcrumbs" include using templates and block.super, basically just extending the base blocks and adding the current page to it. http://www.martin-geber.com/thought/2007/10/25/breadcrumbs-django-templates/
http://www.djangosnippets.org/snippets/1289/ - provides a template tag but I'm not sure this would work if you don't have your urls.py properly declared.
I'm wondering what's the best way? And if you have implemented breadcrumbs before how did you do it?
--- Edit --
My question was meant to be: is there a general accepted method of doing breadcrumbs in Django, but from the answers I see there is not, and there are many different solutions, I'm not sure who to award the correct answer to, as I used a variation of using the block.super method, while all the below answers would work.
I guess then this is too much of a subjective question.
Note: I provide the full snippet below, since djangosnippets has been finicky lately.
Cool, someone actually found my snippet :-) The use of my template tag is rather simple.
To answer your question there is no "built-in" django mechanism for dealing with breadcrumbs, but it does provide us with the next best thing: custom template tags.
Imagine you want to have breadcrumbs like so:
Services -> Programming
Services -> Consulting
Then you will probably have a few named urls: "services", and "programming", "consulting":
(r'^services/$',
'core.views.services',
{},
'services'),
(r'^services/programming$',
'core.views.programming',
{},
'programming'),
(r'^services/consulting$',
'core.views.consulting',
{},
'consulting'),
Now inside your html template (lets just look at consulting page) all you have to put is:
//consulting.html
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Services' services %}
{% breadcrumb_url 'Consulting' consulting %}
{% endblock %}
If you want to use some kind of custom text within the breadcrumb, and don't want to link it, you can use breadcrumb tag instead.
//consulting.html
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Services' services %}
{% breadcrumb_url 'Consulting' consulting %}
{% breadcrumb 'We are great!' %}
{% endblock %}
There are more involved situations where you might want to include an id of a particular object, which is also easy to do. This is an example that is more realistic:
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Employees' employee_list %}
{% if employee.id %}
{% breadcrumb_url employee.company.name company_detail employee.company.id %}
{% breadcrumb_url employee.full_name employee_detail employee.id %}
{% breadcrumb 'Edit Employee ' %}
{% else %}
{% breadcrumb 'New Employee' %}
{% endif %}
{% endblock %}
DaGood breadcrumbs snippet
Provides two template tags to use in your HTML templates: breadcrumb and breadcrumb_url. The first allows creating of simple url, with the text portion and url portion. Or only unlinked text (as the last item in breadcrumb trail for example). The second, can actually take the named url with arguments! Additionally it takes a title as the first argument.
This is a templatetag file that should go into your /templatetags directory.
Just change the path of the image in the method create_crumb and you are good to go!
Don't forget to {% load breadcrumbs %} at the top of your html template!
from django import template
from django.template import loader, Node, Variable
from django.utils.encoding import smart_str, smart_unicode
from django.template.defaulttags import url
from django.template import VariableDoesNotExist
register = template.Library()
#register.tag
def breadcrumb(parser, token):
"""
Renders the breadcrumb.
Examples:
{% breadcrumb "Title of breadcrumb" url_var %}
{% breadcrumb context_var url_var %}
{% breadcrumb "Just the title" %}
{% breadcrumb just_context_var %}
Parameters:
-First parameter is the title of the crumb,
-Second (optional) parameter is the url variable to link to, produced by url tag, i.e.:
{% url person_detail object.id as person_url %}
then:
{% breadcrumb person.name person_url %}
#author Andriy Drozdyuk
"""
return BreadcrumbNode(token.split_contents()[1:])
#register.tag
def breadcrumb_url(parser, token):
"""
Same as breadcrumb
but instead of url context variable takes in all the
arguments URL tag takes.
{% breadcrumb "Title of breadcrumb" person_detail person.id %}
{% breadcrumb person.name person_detail person.id %}
"""
bits = token.split_contents()
if len(bits)==2:
return breadcrumb(parser, token)
# Extract our extra title parameter
title = bits.pop(1)
token.contents = ' '.join(bits)
url_node = url(parser, token)
return UrlBreadcrumbNode(title, url_node)
class BreadcrumbNode(Node):
def __init__(self, vars):
"""
First var is title, second var is url context variable
"""
self.vars = map(Variable,vars)
def render(self, context):
title = self.vars[0].var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.vars[0]
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_unicode(title)
url = None
if len(self.vars)>1:
val = self.vars[1]
try:
url = val.resolve(context)
except VariableDoesNotExist:
print 'URL does not exist', val
url = None
return create_crumb(title, url)
class UrlBreadcrumbNode(Node):
def __init__(self, title, url_node):
self.title = Variable(title)
self.url_node = url_node
def render(self, context):
title = self.title.var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.title
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_unicode(title)
url = self.url_node.render(context)
return create_crumb(title, url)
def create_crumb(title, url=None):
"""
Helper function
"""
crumb = """<span class="breadcrumbs-arrow">""" \
"""<img src="/media/images/arrow.gif" alt="Arrow">""" \
"""</span>"""
if url:
crumb = "%s<a href='%s'>%s</a>" % (crumb, url, title)
else:
crumb = "%s %s" % (crumb, title)
return crumb
The Django admin view modules have automatic breadcumbs, which are implemented like this:
{% block breadcrumbs %}
<div class="breadcrumbs">
{% trans 'Home' %}
{% block crumbs %}
{% if title %} › {{ title }}{% endif %}
{% endblock %}
</div>
{% endblock %}
So there is some kind of built-in support for this..
My view functions emit the breadcrumbs as a simple list.
Some information is kept in the user's session. Indirectly, however, it comes from the URL's.
Breadcrumbs are not a simple linear list of where they've been -- that's what browser history is for. A simple list of where they've been doesn't make a good breadcrumb trail because it doesn't reflect any meaning.
For most of our view functions, the navigation is pretty fixed, and based on template/view/URL design. In our cases, there's a lot of drilling into details, and the breadcrumbs reflect that narrowing -- we have a "realm", a "list", a "parent" and a "child". They form a simple hierarchy from general to specific.
In most cases, a well-defined URL can be trivially broken into a nice trail of breadcrumbs. Indeed, that's one test for good URL design -- the URL can be interpreted as breadcrumbs and displayed meaningfully to the users.
For a few view functions, where we present information that's part of a "many-to-many" join, for example, there are two candidate parents. The URL may say one thing, but the session's context stack says another.
For that reason, our view functions have to leave context clues in the session so we can emit breadcrumbs.
Try django-breadcrumbs — a pluggable middleware that add a breadcrumbs callable/iterable in your request object.
It supports simple views, generic views and Django FlatPages app.
I had the same issue and finally I've made simple django tempalate tag for it: https://github.com/prymitive/bootstrap-breadcrumbs
http://www.djangosnippets.org/snippets/1289/ - provides a template tag but i'm not sure this would work if you don't have your urls.py properly declared.
Nothing will work if you don't have your urls.py properly declared. Having said that, it doesn't look as though it imports from urls.py. In fact, it looks like to properly use that tag, you still have to pass the template some variables. Okay, that's not quite true: indirectly through the default url tag, which the breadcrumb tag calls. But as far as I can figure, it doesn't even actually call that tag; all occurrences of url are locally created variables.
But I'm no expert at parsing template tag definitions. So say somewhere else in the code it magically replicates the functionality of the url tag. The usage seems to be that you pass in arguments to a reverse lookup. Again, no matter what your project is, you urls.py should be configured so that any view can be reached with a reverse lookup. This is especially true with breadcrumbs. Think about it:
home > accounts > my account
Should accounts, ever hold an arbitrary, hardcoded url? Could "my account" ever hold an arbitrary, hardcoded url? Some way, somehow you're going to write breadcrumbs in such a way that your urls.py gets reversed. That's really only going to happen in one of two places: in your view, with a call to reverse, or in the template, with a call to a template tag that mimics the functionality of reverse. There may be reasons to prefer the former over the latter (into which the linked snippet locks you), but avoiding a logical configuration of your urls.py file is not one of them.
Try django-mptt.
Utilities for implementing Modified Preorder Tree Traversal (MPTT) with your Django Model classes and working with trees of Model instances.
This answer is just the same as #Andriy Drozdyuk (link). I just want to edit something so it works in Django 3.2 (in my case) and good in bootstrap too.
for create_crumb function (Remove the ">" bug in the current code)
def create_crumb(title, url=None):
"""
Helper function
"""
if url:
crumb = '<li class="breadcrumb-item">{}</li>'.format(url, title)
else:
crumb = '<li class="breadcrumb-item active" aria-current="page">{}</li>'.format(title)
return crumb
And for __init__ in BreadcrumbNode, add list() to make it subscriptable. And change smart_unicode to smart_text in render method
from django.utils.encoding import smart_text
class BreadcrumbNode(Node):
def __init__(self, vars):
"""
First var is title, second var is url context variable
"""
self.vars = list(map(Variable, vars))
def render(self, context):
title = self.vars[0].var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.vars[0]
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_text(title)
And add this in base.html for the view for Bootstrap. Check the docs
<nav style="--bs-breadcrumb-divider: '>';" aria-label="breadcrumb">
<ol class="breadcrumb">
{% block breadcrumbs %}
{% endblock breadcrumbs %}
</ol>
</nav>
Obviously, no one best answer, but for practical reason I find that it is worth considering the naïve way. Just overwrite and rewrite the whole breadcrumb... (at least until the official django.contrib.breadcrumb released )
Without being too fancy, it is better to keep things simple. It helps the newcomer to understand. It is extremely customizable (e.g. permission checking, breadcrumb icon, separator characters, active breadcrumb, etc...)
Base Template
<!-- File: base.html -->
<html>
<body>
{% block breadcrumb %}
<ul class="breadcrumb">
<li>Dashboard</li>
</ul>
{% endblock breadcrumb %}
{% block content %}{% endblock content %}
</body>
</html>
Implementation Template
Later on each pages we rewrite and overwrite the whole breadcrumb block.
<!-- File: page.html -->
{% extends 'base.html' %}
{% block breadcrumb %}
<ul class="breadcrumb">
<li>Dashboard</li>
<li>Level 1</li>
<li class="active">Level 2</li>
</ul>
{% endblock breadcrumb %}
Practicallity
Realworld use cases:
Django Oscar: base template, simple bread
Django Admin: base template, simple bread, permission check breadcrumb
You could also reduce the boiler plate required to manage breadcrumbs using django-view-breadcrumbs, by adding a crumbs property to the view.
urls.py
urlpatterns = [
...
path('posts/<slug:slug>', views.PostDetail.as_view(), name='post_detail'),
...
]
views.py
from django.views.generic import DetailView
from view_breadcrumbs import DetailBreadcrumbMixin
class PostDetail(DetailBreadcrumbMixin, DetailView):
model = Post
template_name = 'app/post/detail.html'
base.html
{% load django_bootstrap_breadcrumbs %}
{% block breadcrumbs %}
{% render_breadcrumbs %}
{% endblock %}
Something like this may work for your situation:
Capture the entire URL in your view and make links from it. This will require modifying your urls.py, each view that needs to have breadcrumbs, and your templates.
First you would capture the entire URL in your urls.py file
original urls.py
...
(r'^myapp/$', 'myView'),
(r'^myapp/(?P<pk>.+)/$', 'myOtherView'),
...
new urls.py
...
(r'^(?P<whole_url>myapp/)$', 'myView'),
(r'^(?P<whole_url>myapp/(?P<pk>.+)/)$', 'myOtherView'),
...
Then in your view something like:
views.py
...
def myView(request, whole_url):
# dissect the url
slugs = whole_url.split('/')
# for each 'directory' in the url create a piece of bread
breadcrumbs = []
url = '/'
for slug in slugs:
if slug != '':
url = '%s%s/' % (url, slug)
breadcrumb = { 'slug':slug, 'url':url }
breadcrumbs.append(breadcrumb)
objects = {
'breadcrumbs': breadcrumbs,
}
return render_to_response('myTemplate.html', objects)
...
Which should be pulled out into a function that gets imported into the views that need it
Then in your template print out the breadcrumbs
myTemplate.html
...
<div class="breadcrumb-nav">
<ul>
{% for breadcrumb in breadcrumbs %}
<li>{{ breadcrumb.slug }}</li>
{% endfor %}
</ul>
</div>
...
One shortcoming of doing it this way is that as it stands you can only show the 'directory' part of the url as the link text. One fix for this off the top of my head (probably not a good one) would be to keep a dictionary in the file that defines the breadcrumb function.
Anyways that's one way you could accomplish breadcrumbs, cheers :)
You might want to try django-headcrumbs (don’t worry, they are not going to eat your brains).
It’s very lightweight and absolutely straightforward to use, all you have to do is annotate your views (because defining crumbs structure in templates sounds crazy to me) with a decorator that explains how to get back from the given view.
Here is an example from the documentation:
from headcrumbs.decorators import crumb
from headcrumbs.util import name_from_pk
#crumb('Staff') # This is the root crumb -- it doesn’t have a parent
def index(request):
# In our example you’ll fetch the list of divisions (from a database)
# and output it.
#crumb(name_from_pk(Division), parent=index)
def division(request, slug):
# Here you find all employees from the given division
# and list them.
There are also some utility functions (e.g. name_from_pk you can see in the example) that automagically generate nice names for your crumbs without you having to wright lots of code.
I've created template filter for this.
Apply your custom filter (I've named it 'makebreadcrumbs') to the request.path like this:
{% with request.resolver_match.namespace as name_space %}
{{ request.path|makebreadcrumbs:name_space|safe }}
{% endwith %}
We need to pass url namespace as an arg to our filter.
Also use safe filter, because our filter will be returning string that needs to be resolved as html content.
Custom filter should look like this:
#register.filter
def makebreadcrumbs(value, arg):
my_crumbs = []
crumbs = value.split('/')[1:-1] # slice domain and last empty value
for index, c in enumerate(crumbs):
if c == arg and len(crumbs) != 1:
# check it is a index of the app. example: /users/user/change_password - /users/ is the index.
link = '{}'.format(reverse(c+':index'), c)
else:
if index == len(crumbs)-1:
link = '<span>{}</span>'.format(c)
# the current bread crumb should not be a link.
else:
link = '{}'.format(reverse(arg+':' + c), c)
my_crumbs.append(link)
return ' > '.join(my_crumbs)
# return whole list of crumbs joined by the right arrow special character.
Important:
splited parts of the 'value' in our filter should be equal to the namespace in the urls.py, so the reverse method can be called.
Hope it helped.
A generic way, to collect all callable paths of the current url could be resolved by the following code snippet:
from django.urls import resolve, Resolver404
path_items = request.path.split("/")
path_items.pop(0)
path_tmp = ""
breadcrumb_config = OrderedDict()
for path_item in path_items:
path_tmp += "/" + path_item
try:
resolve(path_tmp)
breadcrumb_config[path_item] = {'is_representative': True, 'current_path': path_tmp}
except Resolver404:
breadcrumb_config[path_item] = {'is_representative': False, 'current_path': path_tmp}
If the resolve function can't get a real path from any urlpattern, the Resolver404 exception will be thrown. For those items we set the is_representative flag to false. The OrderedDict breadcrumb_config holds after that the breadcrumb items with there configuration.
For bootstrap 4 breadcrumb for example, you can do something like the following in your template:
<nav aria-label="breadcrumb">
<ol class="breadcrumb">
{% for crumb, values in BREADCRUMB_CONFIG.items %}
<li class="breadcrumb-item {% if forloop.last or not values.is_representative %}active{% endif %}" {% if forloop.last %}aria-current="page"{% endif %}>
{% if values.is_representative %}
<a href="{{values.current_path}}">
{{crumb}}
</a>
{% else %}
{{crumb}}
{% endif %}
</li>
{% endfor %}
</ol>
</nav>
Only the links which won't raises a 404 are clickable.
I believe there is nothing simpler than that (django 3.2):
def list(request):
return render(request, 'list.html', {
'crumbs' : [
("Today", "https://www.python.org/"),
("Is", "https://www.python.org/"),
("Sunday", "https://www.djangoproject.com/"),
]
})
Breadcrumbs.html
<div class="page-title-right">
<ol class="breadcrumb m-0">
{% if crumbs %}
{% for c in crumbs %}
<li class="breadcrumb-item {{c.2}}">{{c.0}}</li>
{% endfor %}
{% endif %}
</ol>
</div>
css:
.m-0 {
margin: 0!important;
}
.breadcrumb {
display: flex;
flex-wrap: wrap;
padding: 0 0;
margin-bottom: 1rem;
list-style: none;
border-radius: .25rem;
}
dl, ol, ul {
margin-top: 0;
margin-bottom: 1rem;
}
ol, ul {
padding-left: 2rem;
}

Filename only in django form field

I have a model that contains a filefield and am using a modelform to add instances. When I come to modify an instance the form shows the current file and displays the file path ie library/filename.
Is there a way to show just the filename in the form?
Thanks
I got around this by using javascript.
I added the following to my model..
def filename(self):
return os.path.basename(self.file.name)
Then added this into my javascript in my template
{% block javascript %}
<script>
{% if part.file %}
$('[href="{{ part.file.url }}"]').html("{{ part.filename }}");
{% endif %}
</script>
{% endblock %}
This changed the link to show just the filename
A FileField will use by default the FileInput widget that produces a <input type="file"> HTML tag. I don't think you can change the default "display full path" behaviour from Django, check this post.
However, you can customise things in your ModelForm like that:
class YourForm(ModelForm):
class Meta:
...
widgets = {
'your_file_attribute': FileInput(attrs={'html_attribute': value}),
}

How do I access my own template variables from within a custom template tags template?

I am using Django to build a website.
I have a context processor setup that looks something like this:
TEMPLATE_CONTEXT_PROCESSORS = (
...
"mysite.context_processors.mystandardvariables"
)
This adds some standard variables that I like to use in templates, such as SITE_NAME and SITE_ROOT.
I have just created my first custom template tag and I find that I cannot access these standard variables.
I don't get any errors and my page displays ok, it's just that the variable that I want are not available.
To check which variables are available I already used {% debug %}.
My tag looks like this:
#register.inclusion_tag('search/search_snippet.html', takes_context = True)
def search(context):
form = forms.SearchForm()
return {'form': form }
The template for the tag looks like this:
<form action="{{ SITE_ROOT }}search" method="post">
{% csrf_token %}
<table>
{{ form.as_table }}
</table>
<input type="submit" value="Submit">
</form>
I am including the search tag in my home page like this:
{% extends "base.html" %}
{% load search_tags %}
{% block content %}
{% search %}
{% endblock %}
To answer my own question, I figured out a way to do what I want using a normal template tag rather than an inclusion tag.
#register.tag
def search(parser, token):
return SearchNode()
class SearchNode(template.Node):
def render(self, context):
return render_to_string('search/search_snippet.html',
{ 'form' : forms.FindForm() }, context)
Here I am passing the context through to the function that renders my template to a string.
I would have preferred to implement this as an inclusion tag as it seems like less work, but I wasn't sure how to get it to work.
If anyone knows how to get this working with an inclusion tag please answer and I'll mark your question as the right answer.

how to pass the variable from included template to the template where it is included?

In Django Views:-
if request.is_ajax():
t = get_template('bar-templates.html')
html = t.render(Context({'edit': True, 'user':'some-user' }))
return HttpResponse(html)
There is two templates:
Main template (foo-templates.html) which includes the template (bar-templates.html). In context edit and user is passed to the bar-templates.html But this variable is also used in foo-templates.html. In django we used to {{ edit }} to catch the variable. Since this variable comes in bar-templates.html. How can I use this to foo-templates.html.
foo-templates.html:
{% extends "base.html" %}
<div class="container">
{{ edit }} // Here I am not getting the edit value
{% if edit %} // I need this edit value. But this value is in context with `bar-templates.html`
do something
{% else %}
do something
{% endif %}
<div class="content">
{% include "bar-templates.html" %}
</div>
bar-templaes.html
{{ edit }} // Here It gives me the edit value
This is the templates which I am sending from views.
How to use the included template variable values to the template where it get included.
Using details from your other post, which you should edit to include into this one:
From what i can tell, you are trying to add a "selected" class to your sidebar menu. This won't work for you because as gcbirzan said, you aren't going to be able to get the context of your ajax response into your base template. On top of that you aren't going to re-render the base template so it wouldn't be changing anyways.
Using javascript you can extract the foo_id from your part.html. Since that code isn't shown, lets say you have your foo_id in a hidden div, <div id="foo_id" style="display:none;">foo_2</div>
Now you can change your ajax function to something like this:
$.ajax({
type:'GET',
cache: 'false',
url:"/foobar/",
success:function(data) {
$('#main-content').html(data);
var $foo_id = $('#foo_id').val();
$('#foo1>ul>li.selected').removeClass('selected');
$('#'+ foo_id).addClass('selected');
}
});
If you simply render foo:
t = get_template('foo-templates.html')
html = t.render(Context({'edit': True, 'user':'some-user' }))
then 'foo' and the included 'bar' both have the same value for 'edit'.
I don't completely understand your question, but have I answered it?

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