Trying to pull a random ".tif" image from folder and print image - python

I have created a definition that loads every image from a called folder. I am now trying to create a code that will either 1) load a specific image when indexed, and/or 2) load an image at random. I have attached two screenshots of my code and the error I am receiving.
https://i.stack.imgur.com/nQKrV.png
https://i.stack.imgur.com/toXkI.png

It looks like you need to concatenate the directory path with the file name:
with open(os.path.join(rat110_GF_path, random_filename)) as file
lines = file.readlines()

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Saving image of every python execution in a folder with a serial number as file name

I am a beginner in Python and would like to execute a code which saves an image into particular directory.
The thing is, I would like to save image with a serial number so that I can have many images(each execution gives one image) in the directory.
plt.savefig('Images/Imageplot.png') ## Image saved to particular folder
About the serial number, you can use the uuid library to generate a random and unique id for an image. See more here: https://www.geeksforgeeks.org/generating-random-ids-using-uuid-python/
To save images, it is a bit more complicated. It requires you to import the os library.
Here is an example:
import os
UPLOADED_FILE_DIR_PATH = os.path.join(os.path.dirname(__file__), "static", "uploaded-images")
my_file_path = os.path.join(UPLOADED_FILE_DIR_PATH, my_filename)
image_file.save(my_file_path)
This is a block of code I used previously for my website, so it may not apply for you, depending on your situation. I personnaly like that method, but if you are unsatisfied, take a look at this for more options: https://towardsdatascience.com/loading-and-saving-images-in-python-ba5a1f5058fb

Python/Opencv save multiple images to folder with different names

I am working on image processing, I have a folder with all of the images that needs to be processed, and I want to save all the processed images to another folder. How do I do that?
for img in glob.glob("Img/*.png"):
path = '/result'
image = cv2.imread(img)
angle, rotated = correct_skew(image)
print(angle)
cv2.imwrite(os.path.join(path , 'img.png'), rotated)
cv2.waitKey(1)
This code can read the image and process it, but I can't figure out how to save all the images with different names, like I want it to be img1.png, img2.png, etc.
Or is there anyway that I can save the images to another folder with the same names as before?
In order to save your processed images in a serial manner, you can use enumerate. When a loop is initiated using enumerate, a counter is also initiated. And each iteration yields an integer number.
In the following case i is the integer value which increments for each iteration. i is used as part of the file name to save the processed image
path = '/result'
for i, img in enumerate(glob.glob("Img/*.png"), 1):
image = cv2.imread(img)
angle, rotated = correct_skew(image)
print(angle)
cv2.imwrite(os.path.join(output_path, 'img_{}.png'.format(i)), rotated)
Save the last line as a variable wrapped in a string()
Then cv2.imwrite(variable)for the last line.
#My thought is to change the type to a string and then write the file as originally desired. When you save as a string you can change whatever type it is turning into inside the for statement.

How to use temporary file from form upload - Python Django

I have a form where users can upload up to 1,000 images at a time. I have changed my FILE_UPLOAD_MAX_MEMORY_SIZE in Django settings to 0 so all files uploaded via a form are written to a temp directory in my root folder.
I am then trying to process the images with OpenCV.
original_img = cv2.imread(temp_image.temporary_file_path())
gray = cv2.cvtColor(original_img,cv2.COLOR_BGR2GRAY)
temp_image.temporary_file_path()
This returns the absolute file path of the temp image in a string format
So I put that in the cv2.imread, however, it creates a NoneType instead of a numpy array like it should and then my program cannot run when it reaches
gray = cv2.cvtColor(original_img,cv2.COLOR_BGR2GRAY)
How do I read the temporary file into OpenCV?
Any help is much appreciated.
in your case save that file to another path in your system first
import os
os.rename(temp_image.temporary_file_path(), another_file_path_in_your_system)
original_img = cv2.imread(another_file_path_in_your_system)
gray = cv2.cvtColor(original_img,cv2.COLOR_BGR2GRAY)

ipython notebook - uploading from and saving to subdirectories?

Change IPython working directory
Inserting image into IPython notebook markdown
Hi, I've read the two above links, and the second link seems most relevant. what the person describes - simply calling the subdirectory - doesn't work for me. For instance, I have an image 'gephi.png' in '/Graphs/gephi.png'
But when I write the following
from IPython.display import Image
path = "/Graphs/gephi.png"
i = Image(path)
i
no image pops up - Yup. No error. Just nothing pops up besides an empty square box image.
Clarification:
When I move the image to the regular director, the image pops up fine.
My only code change is path = "gephi.png"
IPython's Image display object takes three kinds of arguments
The first is raw image data (e.g. the results of open(filename).read():
with open("Graphs/graph.png") as f:
data = f.read()
Image(data=data)
The second model is to load an image from a filename. This is functionally the same as above, but IPython does the reading from the file:
Image(filename="Graphs/graph.png")
The third form is passing URLs. External URLs can be used, but relative URIs will serve files relative to the notebook's own directory:
Image(url="Graphs/graph.png")
Where this can get confusing is if you don't tell IPython which one of these you are specifying, and you just pass the one argument positionally:
Image("Graphs/graph.png")
IPython tries to guess what you mean in this case:
if it looks like a path and points to an existing file, use it as a filename
if it looks like a URL, use it as a URL
otherwise, fallback on embedding the string as raw png data
That #3 is the source of the most confusion. If you pass it a filename that doesn't exist,
you will get a broken image:
Image("/Graphs/graph.png")
Note that URLs to local files must be relative. Absolute URLs will generally be wrong:
Image(url="/Graphs/graph.png")
An example notebook illustrating these things.

python PIL acces multiple images from a single image file

I have written a python script to Delta compress an image. The image file format is .tif which contains 8 images. When I use the normal code ...
org_Image = Image.open(image)
org_Data = org_Image.load()
... I can only access the first image. How do I go about accessing the other ones?
You use org_Image.seek(org_Image.tell() + 1) to get the next one.
In PIL seek moves you to a given frame, (with an IO_Error if it doesn't exist), and tell reports the current frame number.

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