I'm solving a problem that involves a sparse matrix. It has the three main diagonals, and a bunch of other subdiagonals. The full size of the matrix is (2048000, 2048000), but as it is quite sparse, it has only 525312000 stored elements, corresponding to about 4 GB of memory for double precision. When I create this matrix, Activity Monitor and top on my Mac both report a memory use of about 4 GB, as expected.
Next, I create an incomplete LU factorisation, to use as a preconditioner when solving the matrix system with BiCGStab. I use the following code:
from scipy.sparse.linalg import spilu
ILU = spilu(csc_matrix(L+Lr))
here, Lr is the matrix I mentioned above, L is another sparse diagonal matrix that is purely tridiagonal, and thus much smaller.
The variable ILU is of type SuperLU, and according to ILU.nnz it contains only 20384063 stored elements, which means it should take about 150 MB of memory, yet Activity Monitor and top both claim that I am now using about 8 GB of memory, where previously I was using about 4 GB. So what happened to all of that memory?
Not a particularly satisfying answer, but I posted an issue at the SciPy repo, and from the discussion it seems this is an issue on Mac only, and that there isn't much to be done about it.
https://github.com/scipy/scipy/issues/13827
Related
I use a Scipy CSR representation of a 800,000x350,000 Matrix, let's say its M. I want to calculate the dot product M * M[0:x].T. Now depending on the value of x the memory consumption grows. x=1 is not noticeable but if x=2000 the multiplication process takes around 8 gigabyte of RAM.
I wonder what happens when i calculate this product and why it takes so much memory in comparison to storing the sparse Matrix (around 30Mb). Is the matrix expanded for the multiplication?
By investigating the results and memory consumption over time and after each operation I found out that the reason is the result of the sparse matrix multiplication. Indeed there are many zero-values in M. But the result of M*M.T is a matrix containing only 50% zeros. Thus the result consumes a lot memory.
Example: Let's assume each row vector of M has a none-zero field at the same index but other than that is sparse. Then the result of M*M.T would not be sparse at all (no zero-values).
Nonetheless, thanks for helping.
The compile core of csr matrix multiplication is found at
https://github.com/scipy/scipy/blob/0cff7a5fe6226668729fc2551105692ce114c2b3/scipy/sparse/sparsetools/csr.h
starting around line 500, the csr_matmat... function. It includes a reference to a math paper that it is based on.
The Python code called with A*B is __mul__. Look at the version for your csr matrix to make sure that it is calling self._mul_sparse_matrix, which you will see ends up calling self.format + '_matmat_pass1' (and pass2).
Assuming it isn't resorting to the dense versions, you'll have to study the underlying algorithm to understand whether this memory use is realistic or not.
I am trying to implement spectral clustering algorithm for a community detection in graph problem.
I have very huge matrix to calculates its Eigenvectors, matrix of > 1Mx1M.
Numpy and Scipy needs the matrix to be on memory to calculate it, which is impossible in my case.
Is there any other lib or package that calculates Eigenvectors and values on disk instead of memory (just like HDF5 allows us to store and manipulate data on disk)?
Or is there any solution you can suggest?
Increase the size of your swap file.
See:
What is virtual memory?
Creating a swap space
Using a swap space
Also systems typically report on in real time in the resource monitor.
For Ubuntu
[]
I need to multiply two big matrices and sort their columns.
import numpy
a= numpy.random.rand(1000000, 100)
b= numpy.random.rand(300000,100)
c= numpy.dot(b,a.T)
sorted = [argsort(j)[:10] for j in c.T]
This process takes a lot of time and memory. Is there a way to fasten this process? If not how can I calculate RAM needed to do this operation? I currently have an EC2 box with 4GB RAM and no swap.
I was wondering if this operation can be serialized and I dont have to store everything in the memory.
One thing that you can do to speed things up is compile numpy with an optimized BLAS library like e.g. ATLAS, GOTO blas or Intel's proprietary MKL.
To calculate the memory needed, you need to monitor Python's Resident Set Size ("RSS"). The following commands were run on a UNIX system (FreeBSD to be precise, on a 64-bit machine).
> ipython
In [1]: import numpy as np
In [2]: a = np.random.rand(1000, 1000)
In [3]: a.dtype
Out[3]: dtype('float64')
In [4]: del(a)
To get the RSS I ran:
ps -xao comm,rss | grep python
[Edit: See the ps manual page for a complete explanation of the options, but basically these ps options make it show only the command and resident set size of all processes. The equivalent format for Linux's ps would be ps -xao c,r, I believe.]
The results are;
After starting the interpreter: 24880 kiB
After importing numpy: 34364 kiB
After creating a: 42200 kiB
After deleting a: 34368 kiB
Calculating the size;
In [4]: (42200 - 34364) * 1024
Out[4]: 8024064
In [5]: 8024064/(1000*1000)
Out[5]: 8.024064
As you can see, the calculated size matches the 8 bytes for the default datatype float64 quite well. The difference is internal overhead.
The size of your original arrays in MiB will be approximately;
In [11]: 8*1000000*100/1024**2
Out[11]: 762.939453125
In [12]: 8*300000*100/1024**2
Out[12]: 228.8818359375
That's not too bad. However, the dot product will be way too large:
In [19]: 8*1000000*300000/1024**3
Out[19]: 2235.1741790771484
That's 2235 GiB!
What you can do is split up the problem and perfrom the dot operation in pieces;
load b as an ndarray
load every row from a as an ndarray in turn.
multiply the row by every column of b and write the result to a file.
del() the row and load the next row.
This wil not make it faster, but it would make it use less memory!
Edit: In this case I would suggest writing the output file in binary format (e.g. using struct or ndarray.tofile). That would make it much easier to read a column from the file with e.g. a numpy.memmap.
What DrV and Roland Smith said are good answers; they should be listened to. My answer does nothing more than present an option to make your data sparse, a complete game-changer.
Sparsity can be extremely powerful. It would transform your O(100 * 300000 * 1000000) operation into an O(k) operation with k non-zero elements (sparsity only means that the matrix is largely zero). I know sparsity has been mentioned by DrV and disregarded as not applicable but I would guess it is.
All that needs to be done is to find a sparse representation for computing this transform (and interpreting the results is another ball game). Easy (and fast) methods include the Fourier transform or wavelet transform (both rely on similarity between matrix elements) but this problem is generalizable through several different algorithms.
Having experience with problems like this, this smells like a relatively common problem that is typically solved through some clever trick. When in a field like machine learning where these types of problems are classified as "simple," that's often the case.
YOu have a problem in any case. As Roland Smith shows you in his answer, the amount of data and number of calculations is enormous. You may not be very familiar with linear algebra, so a few words of explanation might help in understanding (and then hopefully solving) the problem.
Your arrays are both a collection of vectors with length 100. One of the arrays has 300 000 vectors, the other one 1 000 000 vectors. The dot product between these arrays means that you calculate the dot product of each possible pair of vectors. There are 300 000 000 000 such pairs, so the resulting matrix is either 1.2 TB or 2.4 TB depending on whether you use 32 or 64-bit floats.
On my computer dot multiplying a (300,100) array with a (100,1000) array takes approximately 1 ms. Extrapolating from that, you are looking at a 1000 s calculation time (depending on the number of cores).
The nice thing about taking a dot product is that you can do it piecewise. Keeping the output is then another problem.
If you were running it on your own computer, calculating the resulting matrix could be done in the following way:
create an output array as a np.memmap array onto the disk
calculate the results one row at a time (as explained by Roland Smith)
This would result in a linear file write with a largish (2.4 TB) file.
This does not require too many lines of code. However, make sure everything is transposed in a suitable way; transposing the input arrays is cheap, transposing the output is extremely expensive. Accessing the resulting huge array is cheap if you can access elements close to each other, expensive, if you access elements far away from each other.
Sorting a huge memmapped array has to be done carefully. You should use in-place sort algorithms which operate on contiguous chunks of data. The data is stored in 4 KiB chunks (512 or 1024 floats), and the fewer chunks you need to read, the better.
Now that you are not running the code in our own machine but on a cloud platform, things change a lot. Usually the cloud SSD storage is very fast with random accesses, but IO is expensive (also in terms of money). Probably the least expensive option is to calculate suitable chunks of data and send them to S3 storage for further use. The "suitable chunk" part depends on how you intend to use the data. If you need to process individual columns, then you send one or a few columns at a time to the cloud object storage.
However, a lot depends on your sorting needs. Your code looks as if you are finally only looking at a few first items of each column. If this is the case, then you should only calculate the first few items and not the full output matrix. That way you can do everything in memory.
Maybe if you tell a bit more about your sorting needs, there can be a viable way to do what you want.
Oh, one important thing: Are your matrices dense or sparse? (Sparse means they mostly contain 0's.) If your expect your output matrix to be mostly zero, that may change the game completely.
I am implementing a PCA algorithm in python with the standard svd function, i.e.,
u, s, v = svd(sigma)
The original space has 4800 dimensions, i.e., sigma is a 4800*4800 matrix.
The dimension seems not too large, but I always come across ``Memory Error'' in svd function. My computer is 32-bit windows 7.
So what is the problem? And what is the typical feature dimensions that the svd algorithm can solve?
Thanks!
You state standard svd function - but from where there is not one by standard in python you could be using one from numpy, scipy or several other places, (this is why "namespaces are a honking good idea").
From basic principles 4800*4800=23,040,000 i.e. 23 million entries, if each of those entries is a single byte, (which I doubt), then you will be using 23MB for each matrix and it looks like you are getting back 3 results so with the original that is 23*4 = 92MB but you are almost certain to be using float or double which will multiply that by 4 or 8 to give up to 1GB without any intermediate results... Win7/32 has a max memory map of just under 3 GB, (if you have that much or more fitted), to fit OS, Drivers, Graphics, etc. You will find that some implementations are more efficient than others and more tolerant of needing to use virtual memory.
As python can be run on a lot of platforms from tiny, e.g. RaspberryPi or embedded solution through various PC configurations, e.g. 512 MB DOS machine or Linux 64 bit with 32 GB of ram to a single supercomputer or a cluster of machines working as a supercomputing cluster so you are unlikely to find a simple "this works for matrices up to NxM" figure.
I am using scipy.sparse.linalg.eigsh to solve the generalized eigen value problem for a very sparse matrix and running into memory problems. The matrix is a square matrix with 1 million rows/columns, but each row has only about 25 non-zero entries. Is there a way to solve the problem without reading the entire matrix into memory, i.e. working with only blocks of the matrix in memory at a time?
It's ok if the solution involves using a different library in python or in java.
For ARPACK, you only need to code up a routine that computes certain matrix-vector products. This can be implemented in any way you like, for instance reading the matrix from the disk.
from scipy.sparse.linalg import LinearOperator
def my_matvec(x):
y = compute matrix-vector product A x
return y
A = LinearOperator(matvec=my_matvec, shape=(1000000, 1000000))
scipy.sparse.linalg.eigsh(A)
Check the scipy.sparse.linalg.eigsh documentation for what is needed in the generalized eigenvalue problem case.
The Scipy ARPACK interface exposes more or less the complete ARPACK interface, so I doubt you will gain much by switching to FORTRAN or some other way to access Arpack.