Develop Reference

How to pause window to turn on another window?

I use tkinter and CTK:
I have created a page for login and I want to stop or use this page when the user is logged in, I want to show a new window and I want to resume the window when I want? How can I do that, I didn't know how to make it

I'll bite. Here's an example application that opens a second window when the user clicks a button on the main window, and disables interaction with the main window until the second window is closed.
Some configuration has been omitted for brevity, and I'm not using CTk here because I don't know how you've implemented it in your specific application - however, it should be easy enough to modify this example to work with CTk.
import tkinter as tk
from tkinter import ttk
class App(tk.Tk):
def __init__(self):
super().__init__()
self.open_button = ttk.Button(
self,
text='Open 2nd Window',
command=self.modal
)
self.open_button.pack()
def modal(self):
self.window = tk.Toplevel(self) # create new window
# bind a handler for when the user closes this window
self.window.protocol('WM_DELETE_WINDOW', self.on_close)
# disable interaction with the main (root) window
self.attributes('-disabled', True)
self.close_button = ttk.Button(
self.window,
text='Close Modal',
command=self.on_close
)
self.close_button.pack()
def on_close(self):
# re-enable interaction the root window
self.attributes('-disabled', False)
# close the modal window
self.window.destroy()
if __name__ == '__main__':
app = App()
app.mailoop() # run the app
In the future:
Provide code that shows you made a good-faith effort to solve the problem on your own
Don't post the same question multiple times within hours - if you need to make changes, edit the original question

If you mean you want to open up another window to do something before going back to the original window, you should consider using message box. Here is a link that goes over the types of messageboxes: https://docs.python.org/3/library/tkinter.messagebox.html.

Close window menu when clicking on root

I'm having trouble figuring out how to close a python tkinter window menu when clicking on the root of the menu, ie."File".
I was hoping there was just a command option available when instantiating the menu but it appears as though that is not the case. Also I know that there is an unpost method I can use to get rid of the menu but I don't know how I would trigger it on root menu click.
Edit:
Since Bryan said that my menus should be acting the same as any other menus in my os I decided to put together an example of how I'm doing menus. Maybe I am doing something wrong here but on ubuntu in every other program if I click on the root of the menu it will close it again. In this program it does not close when clicking on the root, only when clicking elsewhere on the screen does the menu close.
import tkinter as tk
import tkinter.messagebox
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
self.title("App Here")
self.window_menu = tk.Menu(self)
self.filemenu = tk.Menu(self.window_menu, tearoff=0)
self.build_window_menu()
self.config(menu=self.window_menu)
def build_window_menu(self):
self.window_menu.add_cascade(label="File", menu=self.filemenu)
self.filemenu.add_command(label='alert', command=self._handle_menualert)
def _handle_menualert(self):
tk.messagebox.showwarning(
"Menu Stuff",
"I am menu alert!"
)
if __name__ == '__main__':
app = App()
app.mainloop()

Efficient way to create a child window with access to main window disabled?

I'm looking for the most efficient way to create a child window and also forbid all access to the main window, in order that user will have to click on "OK" button inside the child window in order to recover the access to the main window.
Here is my code, using Toplevel class. It works, but is there a more efficient way to do ?
from tkinter import *
class MainWindow(Tk):
def __init__(self):
Tk.__init__(self)
def SetEnableStatus(self, status):
for w in self.winfo_children():
if status == False:
w.grab_set()
else:
w.grab_release()
def CreateChildWindow(self):
subWindow = Toplevel(self)
def quit_subwindow():
subWindow.destroy()
self.SetEnableStatus(True) # Enable all widgets of main window
Button(subWindow, text='Exit', command=quit_subwindow).pack()
self.SetEnableStatus(False) # Disable all widgets of main window

It should be enough to call grab_set on the Toplevel object, and when you are done with it, you can simply destroy it, and call grab_set on self (but I am not 100% sure, even if the resulting program below confirms it).
In fact, if you create a button on your Tk root window and if you associate with this button for example a lambda function that prints something, then nothing will be printed, after "setting the grab" on the child window.
See the following example where basically all events are redirected to the Toplevel window, instead of to the Tk root window:
from tkinter import *
class MainWindow(Tk):
def __init__(self):
Tk.__init__(self)
Entry(self).pack(side="left")
Button(self, text="whoami", command=lambda : print("A Tk root window.")).pack(side="left")
def CreateChildWindow(self):
subWindow = Toplevel(self)
def quit_subwindow():
subWindow.destroy()
self.grab_set()
Button(subWindow, text="whoami", command=lambda : print("A Toplevel child window.")).pack()
Button(subWindow, text='Exit', command=quit_subwindow).pack()
subWindow.grab_set()
win = MainWindow()
win.CreateChildWindow()
win.mainloop()
Check out the following article at effbot.org to know more about how to create dialogs:
http://effbot.org/tkinterbook/tkinter-dialog-windows.htm

tkinter messagebox without buttons

In my program I just need to notify user to not press a physical button om a system with no keyboad or mouse,
want to popup a Wait message that disapears when the system is again ready

There are two reasons you don't want a message box here.
First, the whole point of a message box is that it's a modal dialog with some standardized buttons, and you don't want those buttons.
Second, the whole point of a modal dialog is that it's modal—it runs its own event loop, and doesn't return until the dialog is dismissed. This means (unless you're using background threads) your app can't do anything while displaying it.
The first problem is easy to solve. tkMessageBox is just a simple wrapper around tkCommonDialog.Dialog. It's worth looking at the source to see just how simple it is to construct a dialog box that does what you want. But tkSimpleDialog.Dialog is even simpler than tkCommonDialog (hence the name). For example:
class WaitDialog(tkSimpleDialog.Dialog):
def __init__(self, parent, title, message):
self.message = message
Dialog.__init__(self, parent, title=title, message=message)
def body(self, master):
Label(self, text=self.message).pack()
def buttonbox(self):
pass
def wait(message):
WaitDialog(root, title='Wait', message=message)
That's all it takes to create a modal dialog with no buttons. Dialog Windows and the source to tkSimpleDialog have more details.
The second problem is even easier to solve: If you don't want a modal dialog, then all you want is a plain old Toplevel. You may want it to be transient, so it stays on top of the master, hides with it, doesn't show up on the taskbar, etc., and you may want to configure all kinds of other things. But basically, it's this simple:
def wait(message):
win = Toplevel(root)
win.transient()
win.title('Wait')
Label(win, text=message).pack()
return win
Now you can call wait() and continue to run:
def wait_a_sec():
win = wait('Just one second...')
root.after(1000, win.destroy)
root = Tk()
button = Button(root, text='do something', command=wait_a_sec)
root.mainloop()

How to create child window and communicate with parent in TkInter

I'm creating some dialogs using TkInter and need to be able to open a child sub-window (modal or modeless) on clicking a button in the parent. The child would then allow a data record to be created and this data (either the record or if the operation was cancelled) needs to be communicated back to the parent window. So far I have:
import sel_company_dlg
from Tkinter import Tk
def main():
root = Tk()
myCmp = sel_company_dlg.SelCompanyDlg(root)
root.mainloop()
if __name__ == '__main__':
main()
This invokes the top level dialog which allows the user to select a company. The company selection dialog looks like this:
class SelCompanyDlg(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
self.parent_ = parent
self.frame_ = Frame( self.parent_ )
// .. more init stuff ..
self.btNew_ = Button( self.frame_, text="New ...", command=self.onNew )
def onNew(self):
root = Toplevel()
myCmp = company_dlg.CompanyDlg(root)
On clicking the New ... button, a Create Company dialog is displayed which allows the user to fill in company details and click on create or cancel. Here's the opening bit of that:
class CompanyDlg(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
// etc.
I'm struggling with the best way of invoking the child dialog in onNew() - what I have works but I'm not convinced it's the best approach and also, I can't see how to communicate the details to and from the child dialog.
I've tried looking at online tutorials / references but what I've found is either too simplistic or focuses on things like tkMessageBox.showinfo() which iss not what I want.

There are at least a couple ways to solve your problem. Either your dialog can directly send information to the main application, or your dialog can generate an event that tells the main application that data is really to be pulled from the dialog. If the dialog simply changes the appearance of something (for example, a font dialog) I usually generate an event. If the dialog creates or deletes data I typically have it push information back to the application.
I typically have an application object that acts as the controller for the GUI as a whole. Often this is the same class as the main window, or it can be a separate class or even defined as a mixin. This application object has methods that dialogs can call to feed data to the application.
For example:
class ChildDialog(tk.Toplevel):
def __init__(self, parent, app, ...)
self.app = app
...
self.ok_button = tk.Button(parent, ..., command=self.on_ok)
...
def on_ok(self):
# send the data to the parent
self.app.new_data(... data from this dialog ...)
class MainApplication(tk.Tk):
...
def on_show_dialog(self):
dialog = ChildDialog(self)
dialog.show()
def new_data(self, data):
... process data that was passed in from a dialog ...
When creating the dialog, you pass in a reference to the application object. The dialog then knows to call a specific method on this object to send data back to the application.
If you're not into the whole model/view/controller thing you can just as easily pass in a function rather than an object, effectively telling the dialog "call this function when you want to give me data".

In one of my projects I was trying to check within a child tk.Toplevel window (child1) of my root window (self), if a tk.Toplevel window (child2) was created by the user from within the root window, and if this window (child2) is present at the users screen at the moment.
If this wouldn't be the case, the new tk.Toplevel window should gets created by the child window (child1) of the root window, instead of the root window itself. And if it was already created by the root window and is currently present at the users screen, it should get focus() instead of getting reinitialized by "child1".
The root window was wrapped inside a class called App() and both "children" windows were created by methods inside the root class App().
I had to initialize "child2" in a quiet mode if an argument given to the method was True. I suppose that was the entangled mistake. The problem occurred on Windows 7 64 bit, if that's significant.
I tried this (example):
import tkinter as tk
from tkinter import ttk
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
top = self.winfo_toplevel()
self.menuBar = tk.Menu(top)
top['menu'] = self.menuBar
self.menuBar.add_command(label='Child1', command=self.__create_child1)
self.menuBar.add_command(label='Child2', command=lambda: self.__create_child2(True))
self.TestLabel = ttk.Label(self, text='Use the buttons from the toplevel menu.')
self.TestLabel.pack()
self.__create_child2(False)
def __create_child1(self):
self.Child1Window = tk.Toplevel(master=self, width=100, height=100)
self.Child1WindowButton = ttk.Button(self.Child1Window, text='Focus Child2 window else create Child2 window', command=self.CheckForChild2)
self.Child1WindowButton.pack()
def __create_child2(self, givenarg):
self.Child2Window = tk.Toplevel(master=self, width=100, height=100)
if givenarg == False:
self.Child2Window.withdraw()
# Init some vars or widgets
self.Child2Window = None
else:
self.Child2Window.TestLabel = ttk.Label(self.Child2Window, text='This is Child 2')
self.Child2Window.TestLabel.pack()
def CheckForChild2(self):
if self.Child2Window:
if self.Child2Window.winfo_exists():
self.Child2Window.focus()
else:
self.__create_child2(True)
else:
self.__create_child2(True)
if __name__ == '__main__':
App().mainloop()
Here comes the problem:
I wasn't able to check if "child2" is already present. Got error: _tkinter.TclError: bad window path name
Solution:
The only way to get the right 'window path name' was, instead of calling the winfo_exists() method directly onto the "child2" window, calling the master of the "child1" window and adding the according attributes followed by the attributes of the master window you want to use.
Example (edit of the method CheckForChild2):
def CheckForChild2(self):
if self.Child2Window:
if self.Child1Window.master.Child2Window.winfo_exists():
self.Child1Window.master.Child2Window.focus()
else:
self.__create_child2(True)
else:
self.__create_child2(True)