Develop Reference

Message: Unable to locate element - Follow Button Instagram Selenium Python

I'm trying to create a bot to hit a button in the browser, in another window hit the follow button instagram and go back to the first window. And It's ok to switch windows, but I can't did the bot press the follow button in instagam (I created a bot independent only for hit the follow button and ok but don't work in the new script). Where am I wrong? The code:
window_after = browser.window_handles[2]
time.sleep(10)
seguir = browser.find_elements_by_xpath('/html/body/div[1]/section/main/div/header/section/div[1]/div[1]/span/span[1]/button').click()
browser.switch_to.window(browser.window_handles[1])
The error:
Message: Unable to locate element: /html/body/div[1]/section/main/div/header/section/div[1]/div[1]/span/span[1]/button
I tried css selector but is the same error.

if you want to handle list of all follow buttons then you can usebelow xpath
//button[contains(text(),'Follow')]
Also you can handle speciific based on profile, so in that case you can use index
(//button[contains(text(),'Follow')])[index]
example:
WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"(//button[contains(text(),'Follow')])[1]"))).click()
Note : please add below imports to your solution
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait

HTML page seems to add iframe element when opening chrome by selenium in python

I am new to selenium and web automation tasks, and I am trying to code an application for automating papers search on PubMed, using chromedriver.
My aim is to click the top right "Sign in" button in the PubMed main page, https://www.ncbi.nlm.nih.gov/pubmed. So the problem is:
when I open PubMed main page manually, there are no iframes tags in the html source, and therefore the "Sign in" element should be simply accessible by its xpath "//*[#id="sign_in"]".
when same page is openened by selenium instead, I cannot find that "Sign in" element by its xpath, and if a try to inspect it, the html source seems to have embedded it in an <iframe> tag, so that it cannot be found anymore unless a driver._switch_to.frame method is executed. But if I open the html source code by Ctrl+Uand search for <iframe> element, there is still none of them. Here is the "Sign in" element inspection capture:
["Sign in" inspection][1]
I already got round this problem by:
bot = PubMedBot()
bot.driver.get('https://www.ncbi.nlm.nih.gov/pubmed')
sleep(2)
frames = bot.driver.find_elements_by_tag_name('iframe')
bot.driver._switch_to.frame(frames[0])
btn = bot.driver.find_element_by_xpath('/html/body/a')
btn.click()
But all I would like to understand is why the inspection code is different from the html source code, whether this <iframe> element is really appearing from nowhere, and if so why.
Thank you in advance.

You are facing issue due to synchronization .Kinddly find below solution to resolve your issue:
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium import webdriver
driver = webdriver.Chrome(executable_path=r"path ofchromedriver.exe")
driver.maximize_window()
wait = WebDriverWait(driver, 10)
driver.get("https://www.ncbi.nlm.nih.gov/pubmed")
iframe = wait.until(EC.presence_of_element_located((By.TAG_NAME, "iframe")))
driver.switch_to.frame(iframe)
wait.until(EC.element_to_be_clickable((By.XPATH, "//a[contains(text(), 'Sign in to NCBI')]"))).click()
Output:
Inspect element:

How can I "click" download button on selenium in python

I want to download user data on Google analytics by using crawler so I write some code using selenium. However, I cannot click the "export" button. It always shows the error "no such element". I tried to use find_element_by_xpath, by_name and by_id.
I upload inspect of GA page below.
I TRIED:
driver.find_element_by_xpath("//*[#class='download-link']").click()
driver.find_element_by_xpath('//*[#id="ID-activity-userActivityTable"]/div/div[2]/span[6]/button')
driver.find_element_by_xpath('//*[#class='_GAD.W_DECORATE_ELEMENT.C_USER_ACTIVITY_TABLE_CONTROL_ITEM_DOWNLOAD']')
Python Code:
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver = webdriver.Chrome('/Users/parkjunhong/Downloads/chromedriver')
driver.implicitly_wait(3)
usrid = '1021'
url = 'https://analytics.google.com/analytics/web/#/report/app-visitors-user-activity/a113876882w169675624p197020837/_u.date00=20190703&_u.date01=20190906&_r.userId='+usrid+'&_r.userListReportStates=%3F_u.date00=20190703%2526_u.date01=20190906%2526explorer-
table.plotKeys=%5B%5D%2526explorer-table.rowStart=0%2526explorer-
table.rowCount=1000&_r.userListReportId=app-visitors-user-id'
driver.get(url)
driver.find_element_by_name('identifier').send_keys('ID')
idlogin = driver.find_element_by_xpath('//*[#id="identifierNext"]/span/span')
idlogin.click()
driver.find_element_by_name('password').send_keys('PASSWD')
element = driver.find_element_by_id('passwordNext')
driver.execute_script("arguments[0].click();", element)
#login
driver.find_element_by_xpath("//*[#class='download-link']").click()
#click the download button
ERROR:
Message: no such element: Unable to locate element
inspection of GA

your click element is in an iFrame (iFrame id="galaxyIframe" ...). Therefore, you need to tell the driver to switch from the "main" page to said iFrame. If you add this line of code after your #login it should work:
driver.switch_to.frame(galaxyIframe)
(If the frame did not have a name, you would use: iframe = driver.find_element_by_xpath("xpath-to-frame") and then driver.switch_to.frame(iframe)
To get back to your default frame, use:
driver.switch_to.default_content()
Crawling GA is generally a pain. Not just because you have these iFrames everywhere.
Apart from that, I would recommend looking into puppeteer, the new kid on the crawler block. Even though the prospect of switching to javascript from python may be daunting, it is worth it! Once you get into it, selenium will have felt super clunky.

You can try with the text:
If you want to click on 'Export'-
//button[contains(text(),'Export')]

How to click on the element with text as LOGIN as per the website through Selenium and Python?

Windows 10Home x64 /
Python 3.7.0 win64 /
Selenium 3.14.0 /
Geckodriver 3.14.0 /
Firefox 61.0.2.
I'm trying to click on the login button, even though I have copied and pasted the full XPath I am not able to click the Login button.
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://library.yonsei.ac.kr/')
linkElem = driver.find_element_by_link_text('LOGIN').click()
username = driver.find_element_by_id('id')
username.send_keys('myuserAbc')
password = driver.find_element_by_id('password')
password.send_keys('mypass123')
linkElem = driver.find_element_by_xpath("/html/body/div[2]/div[2]/div/div[2]/form/fieldset/div[2]/p[#class='loginBtn']/input[#type='submit']").click()
Thank you for your help.
Update1: The script works up to the point of localizing the login button, I don't have problems with Marionette or having the latest Firefox version.
Update2: I added p[#class='loginBtn']/input[#type='submit'] in an effort to make it more specific but still doesn't work.

In my experience i have found that the button click might not work some times on form buttons with type set to action. The best possible way to work through this one will be to use the submit() method.
so something like this should work on your login form
from time import sleep
time.sleep(20)
driver.find_element_by_class_name('loginBtn').submit()
This will submit the form to the server and you will be able to go through the login process.
if that doesn't work you could also try the follwoing
driver.find_element_by_class_name('loginBtn).send_keys(Keys.ENTER)
Now, why Button.click(); not working here could have following
reasons.
1.The button is visible but not enabled.
2.Driver is finding the 2 instances of Button element
.More discussion about this can be found here
Selenium: submit() works fine, but click() does not

As per the HTML you have shared to invoke click() on the element with text as LOGIN you need to induce WebDriverWait for the desired element to be clickable and you can use either of the following solutions:
CSS_SELECTOR:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a[title='Login']>span"))).click()
XPATH:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//a[#title='Login']/span"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Selenium can't locate the element, a search button using xpath

I can't find a solution how this element cannot be found by using a selenium xpath. Other button on other websites always working just fine. Usually what I would normally do is, just open up a page and inspect the element and I would right click it and copy the xpath. Done.
But this website, www.gsc.com.my (a malaysian cinema booking site). Seems not able to find the button. Is it protected by another security layer?
Lets see the code below,
from selenium import webdriver
chromedriver_path = './chromedriver.exe'
driver = webdriver.Chrome(chromedriver_path)
driver.get('https://www.gsc.com.my')
driver.find_element_by_xpath("""//*[#id="btnNext"]""").click()
The error Message:
no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="btnNext"]"}

Button is located inside an iframe, so you need to switch to that frame before clicking the button:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
driver.switch_to.frame('getQuickFilter_ctrl_ifrBox')
wait(driver, 10).until(EC.element_to_be_clickable((By.ID, "btnNext"))).click()

Because there are two elements with id btnNext, you'll have to specify which of them using an index, 1 for the first, 2 for the second.
driver.find_element_by_xpath("""//*[#id="btnNext"][1]""").click()

You can try with this css selector :
div.container input#btnNext
Note that you will need to switch to iframe first , cause the check button is in a iframe.
For switching to iframe :
driver.switch_to.frame(driver.find_element_by_id("getQuickFilter_ctrl_ifrBox"))
and for clicking on check Button
wait = WebDriverWait(driver, 10)
check_button = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.container input#btnNext")))
check_button.click()