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a=("\nHello")
print(len(a))
The intended output is a new line with 5 printed but instead there is no new line and the length is coming out to be 6.
There is a new line printed, plus the 5 characters in 'Hello', that's 6 in total:
a = "\nHello"
print(a)
print("Total length is", len(a))
Output
<space>
Hello
Total length is 6
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This is a easy question but i need explanation.
In this code Why the output is 100:
x = 100.1205
y = str(x)[6]
print("{:.{}f}".format(x,y))
x = 100.1205
y = str(x)[6] ## This is turning x into a string and grabbing the 6th character which is 0
print("{:.{}f}".format(x,y)) # this is saying print x to the decimal place
#specified by the value of y (zeroth digit) which is 100
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i have a list
a=['invoice β invoice # 2018-33167-2 β date 03/21/2018 β total due $8,804.90']
i want to extract only digits from this list of the form
a=['2018-33167-2 03/21/2018 8,804.90']
i have used regex to extract
for i in a:
res = re.sub("\D", "", i)
but the result is
res=201833167203212018880490
Based on the expected output, you want more than just digits. The digits can have /, - and ,.
Maybe, perhaps, you wanted something that starts with and ends with a digit, but anything in the middle other than a space?
import re
a='invoice β invoice # 2018-33167-2 β date 03/21/2018 β total due $8,804.90'
print(re.findall(r'\d[^ ]+\d', a))
output
python3 test.py
['2018-33167-2', '03/21/2018', '8,804.90']
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I have a code like this.
print (' ', totalh, totalt, totalo)
and I want the integer of totalh to be 2 2 instead of 22 with a space in-between the integers. How do I go about doing it?
Convert it to a string which is an iterable and can be an argument to " ".join.
totalh = 22
print(" ".join(str(totalh)))
Output:
2 2
I suggest you this simple way: first convert totalh into a string with each digit being a character, then use " ".join() to insert a space between each digit:
totalh = 22
print(" ".join(str(totalh))) #2 2
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From:
25f207f28332c7da539dd2539230a7aad975f907a93d924b4b037abacde677f0f71f75cc250df2e4dd2be3e97a60f289
To:
0x7a60f289, 0xdd2be3e9, 0x250df2e4, 0xf71f75cc, 0xcde677f0, 0x4b037aba,
0xa93d924b, 0xd975f907, 0x9230a7aa, 0x539dd253, 0x8332c7da, 0x25f207f2
Just slice the string into chunks and reverse the order adding 0x with str.format:
s = "25f207f28332c7da539dd2539230a7aad975f907a93d924b4b037abacde677f0f71f75cc250df2e4dd2be3e97a60f289"
print(["0x{}".format(s[i-8:i]) for i in range(len(s), 0, -8) ])
['0x7a60f289', '0xdd2be3e9', '0x250df2e4', '0xf71f75cc', '0xcde677f0', '0x4b037aba', '0xa93d924b', '0xd975f907', '0x9230a7aa', '0x539dd253', '0x8332c7da', '0x25f207f2']
If you actually want decimals:
print([int("0x{}".format(s[i-8:i]),16) for i in range(len(s), 0, -8) ])
[2053173897, 3710641129, 621671140, 4146034124, 3454433264, 1258519226, 2839384651, 3648387335, 2452662186, 1402851923, 2201143258, 636618738]
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Two questions:
How to create a char+number random string. one char and 2 digit numbers
for example: U12 OR W82
How to create a random 5 digit number with no zero at the beginning: 02345 , 03243
1)
import random, string
"%c%02d" % (random.choice(string.uppercase), random.randint(0, 99))
2)
import random
random.randint(10000, 99999)