I'm trying to download this image programmatically using python.
The code snippet below works perfectly fine for any other url (image source). However, for this specific image I'm downloading some kind of security check page rather than the wanted image.
requests.get(url, stream=True).content
Entering the linked URL in e.g. postman downloads the picture. What is the difference with the get request I'm sending through postman and the one I'm sending programmatically?
Thanks a lot!
Postman probably uses a different user-agent than requests.
You can add a common browser user-agent to your request. Then no Cloudflare page is displayed to me.
requests.get(
url,
stream=True,
headers={'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.77 Safari/537.36'}
).content
Related
I've been trying to make a code auto redeemer for a site theres a problem every time i send a request to the website the. The issue is a 403 error which means i haven't passed the right fooling methods like headers, cookies, CF. But I have so I'm lost I've tried everything the problem is 100% cloud flare having a strange verification I can't find a way to bypass it. I've passed auth headers with correct cookies aswell. I've tried with requests library and with cloudscrape and bs4
The site is
from bs4 import BeautifulSoup
import cloudscraper
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.132 Safari/537.36'
}
scraper = cloudscraper.create_scraper()
r = scraper.get('https://rblxwild.com/api/promo-code/redeem-code', headers=headers)
print(r) > 403
Someone too tell me how to bypass the cloudflare protection methods.
There's this site called https://coolors.co and I want to grab the color palettes they generate programmatically. In the browser, I just click the button "Start the generator!". The link the button is attached to is https://coolors.co/generate. If I go to that url in the browser, the color palette is generated. Notice, that the url is changed to https://coolors.co/092327-0b5351-00a9a5-4e8098-90c2e7 (that's an example - the last part of the url is just the hex codes). There is obviously a redirect.
But when I do this in Python with a get request, I am not redirected but stay on this intermediate site. When I look at r.text, it tells me "This domain doesn't exist and is for sale".
How do I fix this? How do I enable the redirect?
Here's the code:
url = 'https://coolors.co/generate'
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/96.0.4664.110 Safari/537.36'}
r = requests.get(url, headers=headers)
Thanks!
This website does not use an HTTP redirect.
It probably uses a Javascript form of redirection like changing window.location.href, requests is not a browser so it does not execute the javascript in the page you requested hence the absence of redirection.
I know that some of you already wrote about this problem, but after all atempts nothing works for me. So when I try to scrape web page (https://www.askgamblers.com/) I get 403 error. I already tried:
Changing to difrend request modes (GET, POST, HEAD)
Different User-Agent (I copy the same User-Agent that i found in dev console in Chrome)
Putting more params in header (i copy whole header that i found in dev console)
Using session
And still nothing works for me. What could try next. Did i miss something? What would you do in this case? You can also check my code with only user agent in header.
url = "https://www.askgamblers.com/"
page = requests.get(url, headers={'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/96.0.4664.45 Safari/537.36'})
print(page.status_code)
I am using the latest version of requests libary (2.26.0)
This is my first post, so be gentle on me :)
EDIT:
My problem was solved with this help: https://stackoverflow.com/a/61379638/17637402
I am using python requests to get the html page.
I am using the latest version of chrome in the user agent.
But the response tells that Please update your browser.
Here is my sample code.
import requests
url = 'https://www.choicehotels.com/alabama/mobile/quality-inn-hotels/al045/hotel-reviews/4'
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36', 'content-type': 'application/xhtml+xml', 'referer': url}
url_response = s.get(url, headers=headers, timeout=15)
print url_response.text
I am using python 2.7 in a windows server.
But when I ran the same code in my local I got the required output.
Please update your browser is the answer.
You cannot do https with old browser (and request in python2.7 could be old browser). There were a lot of security problems in https protocols, so it seems that servers doesn't allow to connect with unsecure encryptions and connection standards.
I am trying to get some data from a page. I open Chrome's development tools and successfully find the data I wanted. It's in XHR with GET method (sorry I don't know how to descript it).Then I copy the params, headers, and put all these to requests.get() method. The response I get is totally different to what I saw on the development tools.
Here is my code
import requests
queryList={
"category":"summary",
"subcategory":"all",
"statsAccumulationType":"0",
"isCurrent":"true",
"playerId":None,
"teamIds":"825",
"matchId":"1103063",
"stageId":None,
"tournamentOptions":None,
"sortBy":None,
"sortAscending":None,
"age":None,
"ageComparisonType":None,
"appearances":None,
"appearancesComparisonType":None,
"field":None,
"nationality":None,
"positionOptions":None,
"timeOfTheGameEnd":None,
"timeOfTheGameStart":None,
"isMinApp":None,
"page":None,
"includeZeroValues":None,
"numberOfPlayersToPick":None,
}
header={
'modei-last-mode':'JL7BrhwmeqKfQpbWy6CpG/eDlC0gPRS2BCvKvImVEts=',
'Referer':'https://www.whoscored.com/Matches/1103063/LiveStatistics/Spain-La-Liga-2016-2017-Leganes-Real-Madrid',
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.133 Safari/537.36',
"x-requested-with":"XMLHttpRequest",
}
url='https://www.whoscored.com/StatisticsFeed/1/GetMatchCentrePlayerStatistics'
test=requests.get(url=url,params=queryList,headers=header)
print(test.text)
I follow this post below but it's already 2 years ago and I believe the structure is changed.
XHR request URL says does not exist when attempting to parse it's content