Develop Reference

How to print text after the input prompt while input is still happening?

I am trying to get things to print after the input area in python so that I can get something like this:
-----------------------------------
> (this is where this input is)
-----------------------------------
This is my original snippet:
input("-----------------------------------\n > "); print("-----------------------------------")
I am asking if there is a way to get things to print before the user hits enter while input() is getting input.

How to add a line of inputted text next column over and over until the person prompts to quit on Python

My code works fine for the salesperson to enter the following criteria until the file is created with one list after being prompted to continue or quit writing the .txt file.
def write_text():
print("Welcome to a Costco Hotel Text Creator.")
print('-'*20) #This serves no purpose but to make the terminal look cleaner.
new_file = input("Enter a new file name: ")
while True: #In the loop where the sales person must enter the following criteria for the new text.
with open(new_file, "w") as f:
f.write(str(input("Enter a member's name: ")))
f.write(str(";")) #Makes it easier and logical to seperate the text by semicolon.
print("The members services are: ")
services = ['Conference','Dinner','Lodging','Membership Renewal']
for service in services:
print(f"{service.capitalize() : <14}") #Capitalizes the string, but not allowed to type exactly.
f.write(str(input("Enter the hotel services. Type exactly shown: ")))
f.write(str(";")) #Makes it easier and logical to seperate the text by semicolon.
f.write(str(input("Enter the price: ")))
f.write(str(";")) #Makes it easier and logical to seperate the text by semicolon.
f.write(str(input("Enter the full date (MM/DD/YYYY): ")))
print('-'*20) #This serves no purpose but to make the terminal look cleaner.
exit = input("Are you done writing the text file? If yes, please type 'yes' to exit")
if exit == 'yes': #If the person typed 'no' then it exits before entering the sales system.
print("Exiting the saved file.")
break
write_text()
My result:
Sammy;Conference;20.00;09/25/2022
Expected result:
Sammy;Conference;20.00;09/25/2022
Johnny;Conference;25.00;09/25/2022
Tony;Conference;30.00;09/25/2022
The list goes on until the user can enter 'yes' to quit. I already have the function that allows reading the text file to sum the revenue per category. Any help and advice is appreciated. Thank you!

When you use with open(...) as .. it closes the file as soon as you exit the code block, and since you are using the w file mode you are overwriting your previous entries every time your loop goes back to the top. You also don't need to wrap input statements with str(). The return value of input will always be a string.
One solution would be to simply put the while true loop inside of the the with open( ) block. You will also need to add a line break at the end of the loop.
def write_text():
print("Welcome to a Costco Hotel Text Creator.")
print('-'*20) # This serves no purpose but to make the terminal look cleaner.
new_file = input("Enter a new file name: ")
with open(new_file, "w") as f:
while True: # In the loop where the sales person must enter the
f.write(input("Enter a member's name: ") + ";")
print("The members services are: ")
services = ['Conference','Dinner','Lodging','Membership Renewal']
for service in services:
print(f"{service.capitalize() : <14}") # Capitalizes the string, but not allowed to type exactly.
f.write(input("Enter the hotel services. Type exactly shown: ") + ";")
f.write(input("Enter the price: ") + ";")
f.write(input("Enter the full date (MM/DD/YYYY): ") + "\n")
print('-'*20)
exit = input("Are you done writing the text file? If yes, please type 'yes' to exit")
if exit == 'yes': # If the person typed 'no' then it exits before entering the sales system.
print("Exiting the saved file.")
break
write_text()
You can also combine the ";" with the text from the input statement to cut back on calls to write. This also makes it look cleaner and more readable as well.
You could also just use the a/append file mode, but closing and reopening the file over and over again doesn't seem like the better option.
Update
If you want to verify that the user input matches a certain word you can do something like this, lets say you want to validate that the user input one of the listed services correctly
print("The members services are: ")
services = ['Conference','Dinner','Lodging','Membership Renewal']
for service in services:
print(f"{service.capitalize() : <14}") # Capitalizes the string, but not allowed to type exactly.
while True:
response = input("Enter the hotel services. Type exactly shown: ")
if response in services:
f.write(response + ';')
break
else:
print("Incorrect entry please try again.")
I would recommend taking this functionality and putting it into a separate function so that you can apply the logic to all of your input statements.

How to correlate a selection from a list of options with the associated command?

So basically, what I'm trying to do is to create a menu that allows me to modify the contents of a text file. It's supposed to look like this:
Question 1
I think I already know how to create the menu, as shown here:
print("User Management")
print("1.Add new record")
print("2.View all record")
print("3.Search record")
print("4.Exit")
option = int(input("Enter your choice: "))
if option == 1 :
The problem I have I have no idea how to correlate the options to the commands. For example, if I wanted to correlate this:
name = input("Please enter your name:")
email = input("Please enter your email address:")
f = open("user.txt","a")
f.write("\n"+name+","+email)
f.close()
print("Record added."))
to 1 so whenever I input 1 in the "Enter your choice" it allows me to add a name and email address to the text file, etc. Here's an example I can find:
Example
I have been told that using the if and elseif functions allows me to do that, but I have no idea how. I'm quite new to Python, so forgive me if I seem ignorant. Any help will be appreciated.

You're right in that using a conditional (the fancy technical term for if/elseif/else) is the way to do that. Assuming that the text you have included in your question is accurate, it's likely that you haven't indented the code that is meant to be in the if block.
Python uses indentation (that is, spaces or tabs) to indicate what code is within each control structure. So in your example, if you want to only execute the second block of text if option == 1 you would want:
print("User Management")
print("1.Add new record")
print("2.View all record")
print("3.Search record")
print("4.Exit")
option = int(input("Enter your choice: "))
if option == 1 :
name = input("Please enter your name:")
email = input("Please enter your email address:")
f = open("user.txt","a")
f.write("\n"+name+","+email)
f.close()
print("Record added."))
For more on using if and other control flow, see the tutorial here.

Make python repeat a string until Yes or yes is inputted

Yes I know that there is already a post covering this, but when I read it, it didn't help so please don't mark this as a duplicate.
I want to write a program that asks the user if they want advice and if they input "No" or "no" I want it to repeat the question and if they input "Yes" or "yes" I want it to print the advice. I want it to include a while loop
I have tried to write it myself but I can't get it to work correctly.
Anyone know?
Code from the comment for 3.4 -
def doQuestion(question, advice):
reply = ("no")
while reply == "no":
print (question)
reply = input("Do you need some advice? ").lower()
if (reply == "yes"):
print ("Always listen to your IT teachers")
doQuestion("Do you want some advice?","Always listen to your IT teachers")

The following will keep on checking up on the user to see whether or not they need advice regarding a question:
def doTheyNeedAdvice(advice):
while raw_input("Do you need advice? ").lower() == "no":
pass
print (advice)
print "How old am I?"
doTheyNeedAdvice("I am old enough")

Python checking users input

So, basically, this is my code:
import random
import os
answer = input('What is the problem with your mobile phone? Please do not enter more than one sentence.')
print('The program has detected that you have entered a query regarding: '
if 'wet' or 'water' or 'liquid' or 'mobile' in answer:
print('Put your mobile phone inside of a fridge, it sounds stupid but it should work!')
What I want to know is, say for example if the user enters the keywords 'wet' and 'mobile' as their input, how do I feed back to them knowing that my program has recognised their query.
So by saying something like 'The program has detected that you have entered a query regarding:' how do I filter their keywords into this sentence, say, if they entered 'My mobile phone has gotten wet recently', I want to pick out 'mobile' and 'wet' without saying:
print('The program has detected that you have entered wet')
Because that sounds stupid IMO.
Thanks

If I understand your question correctly, this should solve your problem. Just put the print statement inside the if condition! Very simple, I guess :)
import random
import os
answer = input('What is the problem with your mobile phone? Please do not enter more than one sentence.')
if 'wet' or 'water' or 'liquid' or 'mobile' in answer:
print('The program has detected that you have entered a query regarding: water') # or anything else wet or whatever
print('Put your mobile phone inside of a fridge, it sounds stupid but it should work!')

You can do that with a tuple, a list and any function:
SEND_REPORT_TUPLE = ('wet', 'water', 'liquid', 'mobile')
#make a list from the input
input_list = answer.split(" ")
#And then the use any function with comprehension list
if any(e in SEND_REPORT_TUPLE for e in input_list):
print("The program has detected a query...")