Specify multiple file extensions with glob python [duplicate] - python

Is there a better way to use glob.glob in python to get a list of multiple file types such as .txt, .mdown, and .markdown? Right now I have something like this:
projectFiles1 = glob.glob( os.path.join(projectDir, '*.txt') )
projectFiles2 = glob.glob( os.path.join(projectDir, '*.mdown') )
projectFiles3 = glob.glob( os.path.join(projectDir, '*.markdown') )

Maybe there is a better way, but how about:
import glob
types = ('*.pdf', '*.cpp') # the tuple of file types
files_grabbed = []
for files in types:
files_grabbed.extend(glob.glob(files))
# files_grabbed is the list of pdf and cpp files
Perhaps there is another way, so wait in case someone else comes up with a better answer.

glob returns a list: why not just run it multiple times and concatenate the results?
from glob import glob
project_files = glob('*.txt') + glob('*.mdown') + glob('*.markdown')

So many answers that suggest globbing as many times as number of extensions, I'd prefer globbing just once instead:
from pathlib import Path
files = (p.resolve() for p in Path(path).glob("**/*") if p.suffix in {".c", ".cc", ".cpp", ".hxx", ".h"})

from glob import glob
files = glob('*.gif')
files.extend(glob('*.png'))
files.extend(glob('*.jpg'))
print(files)
If you need to specify a path, loop over match patterns and keep the join inside the loop for simplicity:
from os.path import join
from glob import glob
files = []
for ext in ('*.gif', '*.png', '*.jpg'):
files.extend(glob(join("path/to/dir", ext)))
print(files)

Chain the results:
import itertools as it, glob
def multiple_file_types(*patterns):
return it.chain.from_iterable(glob.iglob(pattern) for pattern in patterns)
Then:
for filename in multiple_file_types("*.txt", "*.sql", "*.log"):
# do stuff

For example, for *.mp3 and *.flac on multiple folders, you can do:
mask = r'music/*/*.[mf][pl][3a]*'
glob.glob(mask)
The idea can be extended to more file extensions, but you have to check that the combinations won't match any other unwanted file extension you may have on those folders. So, be careful with this.
To automatically combine an arbitrary list of extensions into a single glob pattern, you can do the following:
def multi_extension_glob_mask(mask_base, *extensions):
mask_ext = ['[{}]'.format(''.join(set(c))) for c in zip(*extensions)]
if not mask_ext or len(set(len(e) for e in extensions)) > 1:
mask_ext.append('*')
return mask_base + ''.join(mask_ext)
mask = multi_extension_glob_mask('music/*/*.', 'mp3', 'flac', 'wma')
print(mask) # music/*/*.[mfw][pml][a3]*

with glob it is not possible. you can use only:
* matches everything
? matches any single character
[seq] matches any character in seq
[!seq] matches any character not in seq
use os.listdir and a regexp to check patterns:
for x in os.listdir('.'):
if re.match('.*\.txt|.*\.sql', x):
print x

While Python's default glob doesn't really follow after Bash's glob, you can do this with other libraries. We can enable braces in wcmatch's glob.
>>> from wcmatch import glob
>>> glob.glob('*.{md,ini}', flags=glob.BRACE)
['LICENSE.md', 'README.md', 'tox.ini']
You can even use extended glob patterns if that is your preference:
from wcmatch import glob
>>> glob.glob('*.#(md|ini)', flags=glob.EXTGLOB)
['LICENSE.md', 'README.md', 'tox.ini']

Same answer as #BPL (which is computationally efficient) but which can handle any glob pattern rather than extension:
import os
from fnmatch import fnmatch
folder = "path/to/folder/"
patterns = ("*.txt", "*.md", "*.markdown")
files = [f.path for f in os.scandir(folder) if any(fnmatch(f, p) for p in patterns)]
This solution is both efficient and convenient. It also closely matches the behavior of glob (see the documentation).
Note that this is simpler with the built-in package pathlib:
from pathlib import Path
folder = Path("/path/to/folder")
patterns = ("*.txt", "*.md", "*.markdown")
files = [f for f in folder.iterdir() if any(f.match(p) for p in patterns)]

Here is one-line list-comprehension variant of Pat's answer (which also includes that you wanted to glob in a specific project directory):
import os, glob
exts = ['*.txt', '*.mdown', '*.markdown']
files = [f for ext in exts for f in glob.glob(os.path.join(project_dir, ext))]
You loop over the extensions (for ext in exts), and then for each extension you take each file matching the glob pattern (for f in glob.glob(os.path.join(project_dir, ext)).
This solution is short, and without any unnecessary for-loops, nested list-comprehensions, or functions to clutter the code. Just pure, expressive, pythonic Zen.
This solution allows you to have a custom list of exts that can be changed without having to update your code. (This is always a good practice!)
The list-comprehension is the same used in Laurent's solution (which I've voted for). But I would argue that it is usually unnecessary to factor out a single line to a separate function, which is why I'm providing this as an alternative solution.
Bonus:
If you need to search not just a single directory, but also all sub-directories, you can pass recursive=True and use the multi-directory glob symbol ** 1:
files = [f for ext in exts
for f in glob.glob(os.path.join(project_dir, '**', ext), recursive=True)]
This will invoke glob.glob('<project_dir>/**/*.txt', recursive=True) and so on for each extension.
1 Technically, the ** glob symbol simply matches one or more characters including forward-slash / (unlike the singular * glob symbol). In practice, you just need to remember that as long as you surround ** with forward slashes (path separators), it matches zero or more directories.

Python 3
We can use pathlib; .glob still doesn't support globbing multiple arguments or within braces (as in POSIX shells) but we can easily filter the result.
For example, where you might ideally like to do:
# NOT VALID
Path(config_dir).glob("*.{ini,toml}")
# NOR IS
Path(config_dir).glob("*.ini", "*.toml")
you can do:
filter(lambda p: p.suffix in {".ini", ".toml"}, Path(config_dir).glob("*"))
which isn't too much worse.

A one-liner, Just for the hell of it..
folder = "C:\\multi_pattern_glob_one_liner"
files = [item for sublist in [glob.glob(folder + ext) for ext in ["/*.txt", "/*.bat"]] for item in sublist]
output:
['C:\\multi_pattern_glob_one_liner\\dummy_txt.txt', 'C:\\multi_pattern_glob_one_liner\\dummy_bat.bat']

files = glob.glob('*.txt')
files.extend(glob.glob('*.dat'))

By the results I've obtained from empirical tests, it turned out that glob.glob isn't the better way to filter out files by their extensions. Some of the reason are:
The globbing "language" does not allows perfect specification of multiple extension.
The former point results in obtaining incorrect results depending on file extensions.
The globbing method is empirically proven to be slower than most other methods.
Even if it's strange even other filesystems objects can have "extensions", folders too.
I've tested (for correcteness and efficiency in time) the following 4 different methods to filter out files by extensions and puts them in a list:
from glob import glob, iglob
from re import compile, findall
from os import walk
def glob_with_storage(args):
elements = ''.join([f'[{i}]' for i in args.extensions])
globs = f'{args.target}/**/*{elements}'
results = glob(globs, recursive=True)
return results
def glob_with_iteration(args):
elements = ''.join([f'[{i}]' for i in args.extensions])
globs = f'{args.target}/**/*{elements}'
results = [i for i in iglob(globs, recursive=True)]
return results
def walk_with_suffixes(args):
results = []
for r, d, f in walk(args.target):
for ff in f:
for e in args.extensions:
if ff.endswith(e):
results.append(path_join(r,ff))
break
return results
def walk_with_regs(args):
reg = compile('|'.join([f'{i}$' for i in args.extensions]))
results = []
for r, d, f in walk(args.target):
for ff in f:
if len(findall(reg,ff)):
results.append(path_join(r, ff))
return results
By running the code above on my laptop I obtained the following auto-explicative results.
Elapsed time for '7 times glob_with_storage()': 0.365023 seconds.
mean : 0.05214614
median : 0.051861
stdev : 0.001492152
min : 0.050864
max : 0.054853
Elapsed time for '7 times glob_with_iteration()': 0.360037 seconds.
mean : 0.05143386
median : 0.050864
stdev : 0.0007847381
min : 0.050864
max : 0.052859
Elapsed time for '7 times walk_with_suffixes()': 0.26529 seconds.
mean : 0.03789857
median : 0.037899
stdev : 0.0005759071
min : 0.036901
max : 0.038896
Elapsed time for '7 times walk_with_regs()': 0.290223 seconds.
mean : 0.04146043
median : 0.040891
stdev : 0.0007846776
min : 0.04089
max : 0.042885
Results sizes:
0 2451
1 2451
2 2446
3 2446
Differences between glob() and walk():
0 E:\x\y\z\venv\lib\python3.7\site-packages\Cython\Includes\numpy
1 E:\x\y\z\venv\lib\python3.7\site-packages\Cython\Utility\CppSupport.cpp
2 E:\x\y\z\venv\lib\python3.7\site-packages\future\moves\xmlrpc
3 E:\x\y\z\venv\lib\python3.7\site-packages\Cython\Includes\libcpp
4 E:\x\y\z\venv\lib\python3.7\site-packages\future\backports\xmlrpc
Elapsed time for 'main': 1.317424 seconds.
The fastest way to filter out files by extensions, happens even to be the ugliest one. Which is, nested for loops and string comparison using the endswith() method.
Moreover, as you can see, the globbing algorithms (with the pattern E:\x\y\z\**/*[py][pyc]) even with only 2 extension given (py and pyc) returns also incorrect results.

I have released Formic which implements multiple includes in a similar way to Apache Ant's FileSet and Globs.
The search can be implemented:
import formic
patterns = ["*.txt", "*.markdown", "*.mdown"]
fileset = formic.FileSet(directory=projectDir, include=patterns)
for file_name in fileset.qualified_files():
# Do something with file_name
Because the full Ant glob is implemented, you can include different directories with each pattern, so you could choose only those .txt files in one subdirectory, and the .markdown in another, for example:
patterns = [ "/unformatted/**/*.txt", "/formatted/**/*.mdown" ]
I hope this helps.

This is a Python 3.4+ pathlib solution:
exts = ".pdf", ".doc", ".xls", ".csv", ".ppt"
filelist = (str(i) for i in map(pathlib.Path, os.listdir(src)) if i.suffix.lower() in exts and not i.stem.startswith("~"))
Also it ignores all file names starting with ~.

After coming here for help, I made my own solution and wanted to share it. It's based on user2363986's answer, but I think this is more scalable. Meaning, that if you have 1000 extensions, the code will still look somewhat elegant.
from glob import glob
directoryPath = "C:\\temp\\*."
fileExtensions = [ "jpg", "jpeg", "png", "bmp", "gif" ]
listOfFiles = []
for extension in fileExtensions:
listOfFiles.extend( glob( directoryPath + extension ))
for file in listOfFiles:
print(file) # Or do other stuff

Not glob, but here's another way using a list comprehension:
extensions = 'txt mdown markdown'.split()
projectFiles = [f for f in os.listdir(projectDir)
if os.path.splitext(f)[1][1:] in extensions]

The following function _glob globs for multiple file extensions.
import glob
import os
def _glob(path, *exts):
"""Glob for multiple file extensions
Parameters
----------
path : str
A file name without extension, or directory name
exts : tuple
File extensions to glob for
Returns
-------
files : list
list of files matching extensions in exts in path
"""
path = os.path.join(path, "*") if os.path.isdir(path) else path + "*"
return [f for files in [glob.glob(path + ext) for ext in exts] for f in files]
files = _glob(projectDir, ".txt", ".mdown", ".markdown")

From previous answer
glob('*.jpg') + glob('*.png')
Here is a shorter one,
from glob import glob
extensions = ['jpg', 'png'] # to find these filename extensions
# Method 1: loop one by one and extend to the output list
output = []
[output.extend(glob(f'*.{name}')) for name in extensions]
print(output)
# Method 2: even shorter
# loop filename extension to glob() it and flatten it to a list
output = [p for p2 in [glob(f'*.{name}') for name in extensions] for p in p2]
print(output)

You can try to make a manual list comparing the extension of existing with those you require.
ext_list = ['gif','jpg','jpeg','png'];
file_list = []
for file in glob.glob('*.*'):
if file.rsplit('.',1)[1] in ext_list :
file_list.append(file)

import os
import glob
import operator
from functools import reduce
types = ('*.jpg', '*.png', '*.jpeg')
lazy_paths = (glob.glob(os.path.join('my_path', t)) for t in types)
paths = reduce(operator.add, lazy_paths, [])
https://docs.python.org/3.5/library/functools.html#functools.reduce
https://docs.python.org/3.5/library/operator.html#operator.add

To glob multiple file types, you need to call glob() function several times in a loop. Since this function returns a list, you need to concatenate the lists.
For instance, this function do the job:
import glob
import os
def glob_filetypes(root_dir, *patterns):
return [path
for pattern in patterns
for path in glob.glob(os.path.join(root_dir, pattern))]
Simple usage:
project_dir = "path/to/project/dir"
for path in sorted(glob_filetypes(project_dir, '*.txt', '*.mdown', '*.markdown')):
print(path)
You can also use glob.iglob() to have an iterator:
Return an iterator which yields the same values as glob() without actually storing them all simultaneously.
def iglob_filetypes(root_dir, *patterns):
return (path
for pattern in patterns
for path in glob.iglob(os.path.join(root_dir, pattern)))

One glob, many extensions... but imperfect solution (might match other files).
filetypes = ['tif', 'jpg']
filetypes = zip(*[list(ft) for ft in filetypes])
filetypes = ["".join(ch) for ch in filetypes]
filetypes = ["[%s]" % ch for ch in filetypes]
filetypes = "".join(filetypes) + "*"
print(filetypes)
# => [tj][ip][fg]*
glob.glob("/path/to/*.%s" % filetypes)

I had the same issue and this is what I came up with
import os, sys, re
#without glob
src_dir = '/mnt/mypics/'
src_pics = []
ext = re.compile('.*\.(|{}|)$'.format('|'.join(['png', 'jpeg', 'jpg']).encode('utf-8')))
for root, dirnames, filenames in os.walk(src_dir):
for filename in filter(lambda name:ext.search(name),filenames):
src_pics.append(os.path.join(root, filename))

Use a list of extension and iterate through
from os.path import join
from glob import glob
files = []
extensions = ['*.gif', '*.png', '*.jpg']
for ext in extensions:
files.extend(glob(join("path/to/dir", ext)))
print(files)

You could use filter:
import os
import glob
projectFiles = filter(
lambda x: os.path.splitext(x)[1] in [".txt", ".mdown", ".markdown"]
glob.glob(os.path.join(projectDir, "*"))
)

You could also use reduce() like so:
import glob
file_types = ['*.txt', '*.mdown', '*.markdown']
project_files = reduce(lambda list1, list2: list1 + list2, (glob.glob(t) for t in file_types))
this creates a list from glob.glob() for each pattern and reduces them to a single list.

Yet another solution (use glob to get paths using multiple match patterns and combine all paths into a single list using reduce and add):
import functools, glob, operator
paths = functools.reduce(operator.add, [glob.glob(pattern) for pattern in [
"path1/*.ext1",
"path2/*.ext2"]])

If you use pathlib try this:
import pathlib
extensions = ['.py', '.txt']
root_dir = './test/'
files = filter(lambda p: p.suffix in extensions, pathlib.Path(root_dir).glob('**/*'))
print(list(files))

Related

Python: how to search for specific "string" in directory name (not individual file names)

I want to create a list of all the filepath names that match a specific string e.g. "04_DEM" so I can do further processing on the files inside those directories?
e.g.
INPUT
C:\directory\NewZealand\04DEM\DEM_CD23_1232.tif
C:\directory\Australia\04DEM\DEM_CD23_1233.tif
C:\directory\NewZealand\05DSM\DSM_CD23_1232.tif
C:\directory\Australia\05DSM\DSM_CD23_1232.tif
WANTED OUTPUT
C:\directory\NewZealand\04DEM\
C:\directory\Australia\04DEM\
This makes sure that only those files are processed, as some other files in the directories also have the same string "DEM" included in their filename, which I do not want to modify.
This is my bad attempt due to being a rookie with Py code
import os
for dirnames in os.walk('D:\Canterbury_2017Copy'):
print dirnames
if dirnames=='04_DEM' > listofdirectoriestoprocess.txt
print "DONE CHECK TEXT FILE"
You can use os.path for this:
import os
lst = [r'C:\directory\NewZealand\04DEM\DEM_CD23_1232.tif',
r'C:\directory\Australia\04DEM\DEM_CD23_1233.tif',
r'C:\directory\NewZealand\05DSM\DSM_CD23_1232.tif',
r'C:\directory\Australia\05DSM\DSM_CD23_1232.tif']
def filter_paths(lst, x):
return [os.path.split(i)[0] for i in lst if os.path.normpath(i).split(os.sep)[3] == x]
res = list(filter_paths(lst, '04DEM'))
# ['C:\\directory\\NewZealand\\04DEM',
# 'C:\\directory\\Australia\\04DEM']
Use in to check if a required string is in another string.
This is one quick way:
new_list = []
for path in path_list:
if '04DEM' in path:
new_list.append(path)
Demo:
s = 'C:/directory/NewZealand/04DEM/DEM_CD23_1232.tif'
if '04DEM' in s:
print(True)
# True
Make sure you use / or \\ as directory separator instead of \ because the latter escapes characters.
First, you select via regex using re, and then use pathlib:
import re
import pathlib
pattern = re.compile('04DEM')
# You use pattern.search() if s is IN the string
# You use pattern.match() if s COMPLETELY matches the string.
# Apply the correct function to your use case.
files = [s in list_of_files if pattern.search(s)]
all_pruned_paths = set()
for p in files:
total = ""
for d in pathlib.Path(p):
total = os.path.join(total, d)
if pattern.search(s):
break
all_pruned_paths.add(total)
result = list(all_pruned_paths)
This is more robust than using in because you might need to form more complicated queries in the future.

How to perform a case-insensitive search for files of a given suffix?

I'm looking for the equivalent of find $DIR -iname '*.mp3', and I don't want to do the kooky ['mp3', 'Mp3', MP3', etc] thing. But I can't figure out how to combine the re*.IGNORECASE stuff with the simple endswith() approach. My goal is to not miss a single file, and I'd like to eventually expand this to other media/file types/suffixes.
import os
import re
suffix = ".mp3"
mp3_count = 0
for root, dirs, files in os.walk("/Volumes/audio"):
for file in files:
# if file.endswith(suffix):
if re.findall('mp3', suffix, flags=re.IGNORECASE):
mp3_count += 1
print(mp3_count)
TIA for any feedback
Don't bother with os.walk. Learn to use the easier, awesome pathlib.Path instead. Like so:
from pathlib import Path
suffix = ".mp3"
mp3_count = 0
p = Path('Volumes')/'audio': # note the easy path creation syntax
# OR even:
p = Path()/'Volumes'/'audio':
for subp in p.rglob('*'): # recursively iterate all items matching the glob pattern
# .suffix property refers to .ext extension
ext = subp.suffix
# use the .lower() method to get lowercase version of extension
if ext.lower() == suffix:
mp3_count += 1
print(mp3_count)
"One-liner", if you're into that sort of thing (multiple lines for clarity):
sum(1 for subp in (Path('Volumes')/'audio').rglob('*')
if subp.suffix.lower() == suffix)
You can try this :)
import os
# import re
suffix = "mp3"
mp3_count = 0
for root, dirs, files in os.walk("/Volumes/audio"):
for file in files:
# if file.endswith(suffix):
if file.split('.')[-1].lower() == suffix:
mp3_count += 1
print(mp3_count)
Python's string.split() will separate the string into a list, depending on what parameter is given, and you can access the suffix by [-1], the last element in the list
The regex equivalent of .endswith is the $ sign.
To use your example above, you could do this;
re.findall('mp3$', suffix, flags=re.IGNORECASE):
Though it might be more accurate to do this;
re.findall(r'\.mp3$', suffix, flags=re.IGNORECASE):
which makes sure that the filename ends with .mp3 rather than picking up files such as test.amp3.
This is a pretty good example of a situation that doesn't really require regex - so while you're welcome to learn from these examples, it's worth considering the alternatives provided by other answerers.

How to get a list of filenames(without extension) in directory in python?

Assume my folder structure to be
+Data
-abc.jpg
-db.jpg
-ap.jpg
Input is 'path/to/Data'
Expected output is ['abc','db','ap']
I saw many similar questions but did not get what exactly I wanted.
I prefer to use os module in python.
simply try this,
l=os.listdir('path')
li=[x.split('.')[0] for x in l]
First list your directory files
split file by. and take first argument.
import os
files_no_ext = [".".join(f.split(".")[:-1]) for f in os.listdir() if os.path.isfile(f)]
print(files_no_ext)
import glob
from Pathlib import Path
for f in glob.glob("*.*"):
print(Path(f).stem)
import os
filenames=next(os.walk(os.getcwd()))[2]
efn=[f.split('.')[0] for f in filenames]
os.getcwd() #for get current directory path
You can use os.listdir which take path as argument and return a list of files and directories in it.
>>> list_ = os.listdir("path/to/Data")
>>> list_
>>> ['abc.jpg', 'dn.jpg', 'ap.jpg']
With that list, you only have to do a comprehension list which split each element on '.' (dot), take all the elements except the last one an join them with '.' (dot) and check if the element is a file using os.path.file().
>>> list_ = ['.'.join(x.split('.')[:-1]) for x in os.listdir("path/to/Data") if os.path.isfile(os.path.join('path/to/Data', x))]
>>> list_
>>> ['abc', 'dn', 'ap']
import os
from os import listdir
from os.path import isfile, join
def filesMinusExtension(path):
# os.path.splitext(f)[0] map with filename without extension with checking if file exists.
files = [os.path.splitext(f)[0] for f in listdir(path) if isfile(join(path, f))];
return files;

Rename files in a folder based on names in a different folder

I have 2 folders, each with the same number of files. I want to rename the files in folder 2 based on the names of the files in folder 1. So in folder 1there might be three files titled:
Landsat_1,
Landsat_2,
Landsat_3
and in folder 2 these files are called:
1,
2,
3
and I want to rename them based on folder 1 names. I thought about turning the item names of each folder into a a .txt file and then turning the .txt file in a list and then renaming but I'm not sure if this is the best way to do it. Any suggestions?
Edit:
I have simplified the file names above, so just appending with Landsat_ wil not work for me.
The real file names in folder 1 are more like LT503002011_band1, LT5040300201_band1, LT50402312_band4. In folder 2 they are extract1, extract2, extract3. There are 500 files in total and in folder 2 it is just a running count of extract and a number for each file.
As someone said, "sort each list and zip them together in order to rename".
Notes:
the key() function extracts all of the numbers so that sorted() can sort the lists numerically based on the embedded numbers.
we sort both lists: os.listdir() returns files in arbitrary order.
The for loop is a common way to use zip: for itemA, itemB in zip(listA, listB):
os.path.join() provides portability: no worries about / or \
A typical invocation on Windows: python doit.py c:\data\lt c:\data\extract, assuming those are directories you have described.
A typical invocation on *nix: : python doit.py ./lt ./extract
import sys
import re
import os
assert len(sys.argv) == 3, "Usage: %s LT-dir extract-dir"%sys.argv[0]
_, ltdir, exdir = sys.argv
def key(x):
return [int(y) for y in re.findall('\d+', x)]
ltfiles = sorted(os.listdir(ltdir), key=key)
exfiles = sorted(os.listdir(exdir), key=key)
for exfile,ltfile in zip(exfiles, ltfiles):
os.rename(os.path.join(exdir,exfile), os.path.join(exdir,ltfile))
You might want to use the glob package which takes a filename pattern and outputs it into a list. For example, in that directory
glob.glob('*')
gives you
['Landsat_1', 'Landsat_2', 'Landsat_3']
Then you can loop over the filenames in the list and change the filenames accordingly:
import glob
import os
folderlist = glob.glob('*')
for folder in folderlist:
filelist = glob.glob(folder + '*')
for fil in filelist:
os.rename(fil, folder + fil)
Hope this helps
I went for more completeness :D.
# WARNING: BACKUP your data before running this code. I've checked to
# see that it mostly works, but I would want to test this very well
# against my actual data before I trusted it with that data! Especially
# if you're going to be modifying anything in the directories while this
# is running. Also, make sure you understand what this code is expecting
# to find in each directory.
import os
import re
main_dir_demo = 'main_dir_path'
extract_dir_demo = 'extract_dir_path'
def generate_paths(directory, filenames, target_names):
for filename, target_name in zip(filenames, target_names):
yield (os.path.join(directory, filename),
os.path.join(directory, target_name))
def sync_filenames(main_dir, main_regex, other_dir, other_regex, key=None):
main_files = [f for f in os.listdir(main_dir) if main_regex.match(f)]
other_files = [f for f in os.listdir(other_dir) if other_regex.match(f)]
# Do not proceed if there aren't the same number of things in each
# directory; better safe than sorry.
assert len(main_files) == len(other_files)
main_files.sort(key=key)
other_files.sort(key=key)
path_pairs = generate_paths(other_dir, other_files, main_files)
for other_path, target_path in path_pairs:
os.rename(other_path, target_path)
def demo_key(item):
"""Sort by the numbers in a string ONLY; not the letters."""
return [int(y) for y in re.findall('\d+', item)]
def main(main_dir, extract_dir, key=None):
main_regex = re.compile('LT\d+_band\d')
other_regex = re.compile('extract\d+')
sync_filenames(main_dir, main_regex, extract_dir, other_regex, key=key)
if __name__ == '__main__':
main(main_dir_demo, extract_dir_demo, key=demo_key)

select files from path

I have files in particular path and need to select one by one base on namefile (yyyymmdd.faifb1p16m2.nc) where yyyy is year, mm is month, and dd is date. I made code like this :
results=[]
base_dir = 'C:/DATA2013'
os.chdir(base_dir)
files = os.listdir('C:/DATA2013')
for f in files:
results += [each for each in os.listdir('C:/DATA2013')
if each.endswith('.faifb1p16m2.nc')]
What should I do next if I only select files for January, and then February, and so on. Thank you.
You can do :
x = [i for i in results if i[4:6] == '01']
It will list all file names for January.
Assuming that your all files of same format as you have described in the question.
Two regexes:
\d{4}(?:\d?|\d{2})(?:\d?|\d{2})\.faifb1p16m2\.nc
\d{8}\.faifb1p16m2\.nc
Sample data:
20140131.faifb1p16m2.nc
2014131.faifb1p16m2.nc
201412.faifb1p16m2.nc
201411.faifb1p16m2.nc
20141212.faifb1p16m2.nc
2014121.faifb1p16m2.nc
201411.faifb1p16m2.nc
The first regex will match all 7 of those entries. The second regex will match only 1, and 5. I probably made the regexes way more complicated than I needed to.
You're going to want the second regex, but I'm just listing the first as an example.
from glob import glob
import re
re1 = r'\d{4}(?:\d?|\d{2})(?:\d?|\d{2})\.faifb1p16m2\.nc'
re2 = r'\d{8}\.faifb1p16m2\.nc'
l = [f for f in glob('*.faifb1p16m2.nc') if re.search(re1, f)]
m = [f for f in glob('*.faifb1p16m2.nc') if re.search(re2, f)]
print l
print
print m
#Then, suppose you want to filter and select everything with '12' in the list m
print filter(lambda x: x[4:6] == '12', m)
As another similar solution shows you can ditch glob for os.listdir(), so:
l = [f for f in glob('*.faifb1p16m2.nc') if re.search(re1, f)]`
Becomes:
l = [f for f in os.listdir() if re.search(re1, f)]
And then the rest of the code is great. One of the great things about using glob is that you can use iglob which is just like glob, but as an iterator, which can help with performance when going through a directory with lots of files.
One more thing, here's another stackoverflow post with an overview of python's infamous lambda feature. It's often used for the functions map, reduce, filter, and so on.
To validate filenames, you could use datetime.strptime() method:
#!/usr/bin/env python
import os
from datetime import datetime
from glob import glob
suffix = '.faifb1p16m2.nc'
def parse_date(path):
try:
return datetime.strptime(os.path.basename(path), '%Y%m%d' + suffix)
except ValueError:
return None # failed to parse
paths_by_month = [[] for _ in range(12 + 1)]
for path in glob(r'C:\DATA2013\*' + suffix): # for each nc-file in the directory
date = parse_date(path)
paths_by_month[date and date.month or 0].append(path)
print(paths_by_month[2]) # February paths
print(paths_by_month[0]) # paths with unrecognized date
try this:
from os import *
results = []
base_dir = 'C://local'
chdir(base_dir)
files = listdir(base_dir)
for f in files:
if '.faifb1p16m2.nc' in f and f[4:6] == '01': #describe the month in this string
print f

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