Image of the text file
Now what I want in this text file is the complete text written in a single line so that it looks like this one:What I want it to be like
How do I do this using python? I tried strip function ,replace function etc. It isnt just working.
You just need to read the file in, remove the new lines and write it again.
with open("./foo.txt", "r") as f:
formatted = ""
for line in f.readlines():
formatted += line.replace('\n', " ") # Removes the new lines, add spaces instead
formatted.replace(" ", " ") # Replace double space with one space
# Writes single line to textfile
with open("./bar.txt", "w") as out:
out.write(formatted)
Related
I'm trying to convert all white spaces to new line in a text file so I will have a list of all the words in the text in the end.
with open('keywords.txt', 'w+') as g:
replace = string.replace(" ","\n")
replace.writelines
This is not working for me sadly.
I'm open for any tips or ideas, I can't believe that I can't get something to work that requires 3-5 lines of code.
'w+' will empty your file and you never read in the current contents and string.replace does not work like that.
with open('keywords.txt', 'r+') as g:
s = g.read()
s = s.replace(" ", "\n")
g.seek(0)
g.truncate()
g.write(s)
I am trying to make a program that reads from a file and deletes one specific line inside of it and then puts all the data stored back to the file separated with a new line. The file uses this format:
Jones|20|20|00
bob|30|19|90
James|40|19|80
So I want to delete (backup contains this and is the line I want to delete)
bob|30|19|90
but the code that I am using takes away the new line and doesnt replace it but when I try to add \n to it the file doesn't want to read as it does this (adds 2 "\n"s):
Jones|20|20|00
James|40|19|80
I am using this code below:
def deleteccsaver(backup):
lockaccount =""
lockaccount = lockaccount.strip("\n")
with open('accounts_project.txt','r+') as f:
newline=[]
for line in f.readlines():
newline.append(line.replace(backup, lockaccount).strip("\n"))
with open('accounts_project.txt','w+') as f:
for line in newline:
f.writelines(line +"\n")
f.close()
resetlogin()
Please help as I dont know how to add the \n back without it appearing as "\n\n"
Without the "\n "it appears as:
Jones|20|20|00James|40|19|80
Any suggestions:
What I am doing here is reading the entire file at once, please don't do this if you have a very very big file. After reading all file contents at once, I am making a list out of it using "\n" as a delimiter. Read about split function in python to know more about it. Then from the list I am replacing the backup with lockaccount, as you have been doing the same, these are the names of variables that you are using, hope I did not confuse between them in this case. Then it will be saved to a new file after adding new line after each element of list, i.e. each line of the previous file. This will cause the result file to have all the contents as previous file, but removing what you wanted to remove. I see that lockaccount is itself an empty string, so adding it might create a newline in your file. In case you dont want lockaccount to replace the backup variable in the file, just remove the backup from the list using contents.remove(backup) instead of contents[contents.index(backup)] == lockaccount keeping the rest of the code same. Hope this explains better.
def deleteccsaver(backup):
lockaccount =""
lockaccount = lockaccount.strip("\n")
with open('accounts_project.txt','r+') as f:
contents = f.read().split("\n")
if backup in contents:
contents[contents.index(backup)] = lockaccount
new_contents = "\n".join(contents)
with open('accounts_project.txt','w+') as f:
f.write(new_contents)
resetlogin()
You are priting a newline character after each element in the list. So, if you replace a line with the empty string, well, you will get an empty line.
Try to simply skip over the line you want to delete:
if line == backup:
contiune
else:
lines.append(...)
PS. There is room for improvment in the code above, but I'm on the phone, I will get back with an edit later if nobody gets ahead of me
You can try to add newline = '\n'.join(newline) after your first for loop and then just write it into the accounts_project.txt file without a loop.
The code should then look like:
def deleteccsaver(backup):
lockaccount =""
lockaccount = lockaccount.strip("\n")
with open('accounts_project.txt','r+') as f:
newline=[]
for line in f.readlines():
newline.append(line.replace(backup, lockaccount).strip("\n"))
newline = '\n'.join(newline)
with open('accounts_project.txt','w+') as f:
f.write(newline)
f.close() # you don't necessarily need it inside a with statement
resetlogin()
Edit:
Above code still results in
Jones|20|20|00
James|40|19|80
as output.
That's because during the replacement loop an empty string will be appended to newline (like newline: ['Jones|20|20|00','','James|40|19|80']) and newline = '\n'.join(newline) will then result in 'Jones|20|20|00\n\nJames|40|19|80'.
A possible fix can be to replace:
for line in f.readlines():
newline.append(line.replace(backup, lockaccount).strip("\n"))
with
for line in f.readlines():
line = line.strip('\n')
if line != backup:
newline.append(line)
def deleteccsaver(backup):
lockaccount =""
lockaccount = lockaccount.strip("\n")
with open('accounts_project.txt','r+') as f:
contents = f.read().split("\n")
if backup in contents:
contents.remove(backup)
new_contents = "\n".join(contents)
with open('accounts_project.txt','w+') as f:
f.write(new_contents)
resetlogin()
I'm a huge python noob. Trying to write simple script that will split a line in a file where it see's a "?"
line in Input file (inputlog.log):
http://website.com/somejunk.jpg?uniqid&=123&an=1234=123
line in output file (outputlog.log):
http://website.com/somejunk.jpg uniqid&=123&an=1234=123
The goal here is to end up with a file that has 2 columns:
Here's my code it kinda works except it wont write to the 2nd file
"TypeError: expected a character buffer object"
import re
a = raw_input("what file do you want to open? ")
b = raw_input("what is the file you want to save to? ")
with open(a, 'r') as f1:
with open(b,'w') as f2:
data = f1.readlines()
print "This is the line: ", data #for testing
for line in data:
words= re.split("[?](.*)$",line)
print "Here is the Split: ", words #for testing
f2.write(words)
f1.close()
f2.close()
Your problem is that 'words' is a list. You cannot write that to your file. You need to convert it back to a string. Also, you need to pay attention when converting it back to make sure that you create the spacing/split you want between the string.
You should do something like this.
words = ' '.join(words)
Pay close attention to the space inside the single quotes. That indicates it will put a space between your strings.
Finally, you then make your call to:
f2.write(words)
Upon making that change, I tested your code and it successfully split and wrote them to the file per your specification.
I am trying to write a jython code for deleting spaces from Text file.I have a following scenario.
I have a text file like
STARTBUR001 20120416
20120416MES201667 20120320000000000201203210000000002012032200000000020120323000000000201203240000000002012032600000000020120327000000000201203280000000002012032900000000020120330000000000
20120416MES202566 2012030500000000020120306000000000201203070000000002012030800000000020120309000000000201203100000000002012031100000000020120312000000000201203130000000002012031400000000020
20120416MES275921 20120305000000000201203060000000002012030700000000020120308000000000201203090000000002012031000000000020120311000000000201203120000000002012031300000000020120314000000000
END 0000000202
Here all lines are single lines.
But what i want is like
STARTBUR001 20120416
20120416MES201667 20120320000000000201203210000000002012032200000000020120323000000000201203240000000002012032600000000020120327000000000201203280000000002012032900000000020120330000000000
20120416MES202566 2012030500000000020120306000000000201203070000000002012030800000000020120309000000000201203100000000002012031100000000020120312000000000201203130000000002012031400000000020
20120416MES275921 20120305000000000201203060000000002012030700000000020120308000000000201203090000000002012031000000000020120311000000000201203120000000002012031300000000020120314000000000
END 0000000202
So in all i want to start checking from second line till i encounter END and delete all spaces at tyhe end of each line.
Can someone guide me for writing this code??
tried like:
srcfile=open('d:/BUR001.txt','r')
trgtfile=open('d:/BUR002.txt','w')
readfile=srcfile.readline()
while readfile:
trgtfile.write(readfile.replace('\s',''))
readfile=srcfile.readline()
srcfile.close()
trgtfile.close()
Thanks,
Mahesh
You can use fact that those special lines starts with special values:
line = srcfile.readline()
while line:
line2 = line
if not line2.startswith('START') and not line2.startswith('END'):
line2 = line2.replace(' ','')
trgtfile.write(line2)
line = srcfile.readline()
Also note that with readline() result strings ends with \n (or are empty at end of input file), and this code removes all spaces from the line, not only those at end of the line.
If I understood your example all you want is to remove empty lines, so instead of reading file line by line read it at once:
content = srcfile.read()
and then remove empty lines from content:
while '\n\n' in content:
content = content.replace('\n\n', '\n')
I have a text file which is about 400,000 lines long. I need to import this text file into a program which only accepts text files which are delimited with spaces or tabs, but this text file is delimited with semi-colons. There is no option in the program I am exporting the text file from (Arcmap) to change the delimination and doing find and replace in the text file itself will literally take 2 days.
I have searched for a script to do this but they all seem to replace the whole LINE of the word file with a space, instead of individually replacing each semi-colon, Leaving me with an empty text file.
Here is a sample of my text file:
"OID_";"POINTID";"GRID_CODE";"POINT_X";"POINT_Y"
;1;-56.000000;200900.250122;514999.750122
;2;-56.000000;200900.750122;514999.750122
;3;-56.000000;200901.250122;514999.750122
;4;-57.000000;200901.750122;514999.750122
;5;-57.000000;200902.250122;514999.750122
;6;-57.000000;200902.750122;514999.750122
;7;-57.000000;200903.250122;514999.750122
;8;-57.000000;200903.750122;514999.750122
;9;-57.000000;200904.250122;514999.750122
;10;-57.000000;200904.750122;514999.750122
I need it to look something like this:
1 -56.000000 200900.250122 514999.750122
2 -56.000000 200900.750122 514999.750122
How about this:
sed -i 's/;/ /g' yourBigFile.txt
This is not a Python solution. You have to start this in a shell. But if you use Notepad, I guess you are on Windows. So here a Python solution:
f1 = open('yourBigFile.txt', 'r')
f2 = open('yourBigFile.txt.tmp', 'w')
for line in f1:
f2.write(line.replace(';', ' '))
f1.close()
f2.close()
with Python, you can use fileinput.
import fileinput
for line in fileinput.FileInput("file",inplace=1):
line = line.replace(";"," ")
print line,
this will replace all your ";" to spaces in place.
Python 3.2 has added ability to use this as context manager, so that the files that fail during processing for some reason will always get closed:
import fileinput
def main():
with fileinput.input(inplace=True) as f:
for line in f:
line = line.replace(";", " ")
print(line, end='')
(inspiration)
Use it by supplying it with the text file you want to process.