Develop Reference

How to use selenium for webscraping google flights?

I'm trying to pull the airline names and prices of a specific flight. I'm having trouble with the x.path and/or using the right html tags because when I run the code below, all I get back is 14 empty lists.
from selenium import webdriver
from lxml import html
from time import sleep
driver = webdriver.Chrome(r"C:\Users\14074\Python\chromedriver")
URL = 'https://www.google.com/travel/flights/searchtfs=CBwQAhopagwIAxIIL20vMHBseTASCjIwMjEtMTItMjNyDQgDEgkvbS8wMWYwOHIaKWoNCAMSCS9tLzAxZjA4chIKMjAyMS0xMi0yN3IMCAMSCC9tLzBwbHkwcAGCAQsI____________AUABSAGYAQE&tfu=EgYIAhAAGAA'
driver.get(URL)
sleep(1)
tree = html.fromstring(driver.page_source)
for flight_tree in tree.xpath('//div[#class="TQqf0e sSHqwe tPgKwe ogfYpf"]'):
title = flight_tree.xpath('.//*[#id="yDmH0d"]/c-wiz[2]/div/div[2]/div/c-wiz/div/c-wiz/div[2]/div[2]/div/div[2]/div[6]/div/div[2]/div/div[1]/div/div[1]/div/div[2]/div[2]/div[2]/span/text()')
price = flight_tree.xpath('.//span[contains(#data-gs, "CjR")]')
print(title, price)
#driver.close()
This is just the first part of my code but I can't really continue without getting this to work. If anyone has some ideas on what I'm doing wrong that would be amazing! It's been driving me crazy. Thank you!

I noticed a few issues with your code. First of all, I believe that when entering this page, first google will show you the "I agree to terms and conditions" popup before showing you the content of the page, therefore you need to first click on that button.
Also, you should use the find_elements_by_xpath function directly on driver instead of using the page content, as this also allows you to render the javascript content. You can find more info here: python tree.xpath return empty list
To get more info on how to scrape using selenium and python you could check out this guide: https://www.webscrapingapi.com/python-selenium-web-scraper/
I used the following code to scrape the titles. (I also changed the xpaths to do so, by extracting them directly from google chrome. You can do that by right clicking on an element -> inspect and in the elements tab where the element is, you can right click -> copy -> Copy xpath)
from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
# I used these for the code to work on my windows subsystem linux
option = webdriver.ChromeOptions()
option.add_argument('--no-sandbox')
option.add_argument('--disable-dev-sh-usage')
driver = webdriver.Chrome(ChromeDriverManager().install(), options=option)
URL = 'https://www.google.com/travel/flights/searchtfs=CBwQAhopagwIAxIIL20vMHBseTASCjIwMjEtMTItMjNyDQgDEgkvbS8wMWYwOHIaKWoNCAMSCS9tLzAxZjA4chIKMjAyMS0xMi0yN3IMCAMSCC9tLzBwbHkwcAGCAQsI____________AUABSAGYAQE&tfu=EgYIAhAAGAA'
driver.get(URL)
driver.find_element_by_xpath('//*[#id="yDmH0d"]/c-wiz/div/div/div/div[2]/div[1]/div[4]/form/div[1]/div/button/span').click() # this is necessary to pres the I agree button
elements = driver.find_elements_by_xpath('//*[#id="yDmH0d"]/c-wiz[2]/div/div[2]/div/c-wiz/div/c-wiz/div[2]/div[3]/div[3]/c-wiz/div/div[2]/div[1]/div/div/ol/li')
for flight_tree in elements:
title = flight_tree.find_element_by_xpath('.//*[#class="W6bZuc YMlIz"]').text
print(title)

I tried the below code, with screen maximized and having explicit waits and could successfully extract the information, please see below :
Sample code :
driver = webdriver.Chrome(driver_path)
driver.maximize_window()
driver.get("https://www.google.com/travel/flights/searchtfs=CBwQAhopagwIAxIIL20vMHBseTASCjIwMjEtMTItMjNyDQgDEgkvbS8wMWYwOHIaKWoNCAMSCS9tLzAxZjA4chIKMjAyMS0xMi0yN3IMCAMSCC9tLzBwbHkwcAGCAQsI____________AUABSAGYAQE&tfu=EgYIAhAAGAA")
wait = WebDriverWait(driver, 10)
titles = wait.until(EC.presence_of_all_elements_located((By.XPATH, "//div/descendant::h3")))
for name in titles:
print(name.text)
price = name.find_element(By.XPATH, "./../following-sibling::div/descendant::span[2]").text
print(price)
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Output :
Tokyo
₹38,473
Mumbai
₹3,515
Dubai
₹15,846

Dynamic element (Table) in page is not updated when i use Click() in selenium, so i couldn't retrive the new data

Page which i need to scrape data from: Digikey Search result
Issue
It is allowed to show only 100 row in each table, so i have to move between multiple tables using the NextPageButton.
As illustrated in the code below, I actually do though, but the results retrieves to me every time the first table results and doesn't move on to the next table results on my click action ActionChains(driver).click(element).perform().
Keep in mind that NO new pages is opened, click is going to be intercepted by some sort of JavaScript to do some rich UI stuff on the same page to load a new table of data
My Expectations
I am just trying to validate that I could move to the next table, then i will edit the code to loop through all of them.
This piece of code should return the data in the second table from results, BUT it actually returns the values from the first table which loaded initially with the URL. This means that the click action didn't occur or it actually occurred but the WebDriver driver content isn't being updated by interacting with dynamic JavaScript elements in the page.
I will appreciate any help, Thanks..
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support.expected_conditions import presence_of_element_located
from selenium.webdriver import ActionChains
import time
import sys
url = "https://www.digikey.com/en/products/filter/coaxial-connectors-rf-terminators/382?s=N4IgrCBcoA5QjAGhDOl4AYMF9tA"
chrome_driver_path = "..PATH\\chromedriver"
chrome_options = Options()
chrome_options.add_argument ("--headless")
webdriver = webdriver.Chrome(
executable_path= chrome_driver_path
,options= chrome_options
)
with webdriver as driver:
wait = WebDriverWait(driver, 10)
driver.get(url)
wait.until(presence_of_element_located((By.CSS_SELECTOR, "tbody")))
element = driver.find_element_by_css_selector("button[data-testid='btn-next-page']")
ActionChains(driver).click(element).perform()
time.sleep(10) #too much time i know, but to make sure it is not a waiting issue. something needs to be updated
results = driver.find_elements_by_css_selector("tbody")
for count in results:
countArr = count.text
print(countArr)
print()
driver.close()

Finally found a SOLUTION !
Source of the solution.
As expected the issue was in the clicking action itself. It is somehow not being done right or it's not being done at all as illustrated in the solution Source question.
the solution is to click the button using Javascript execution.
Change line 30
ActionChains(driver).click(element).perform()
to be as following:
driver.execute_script("arguments[0].click();",element)
That's it..

Having trouble referencing to a certain element on page with Selenium

I am having a terribly hard time referencing to a certain "next page" button on a website that I am trying to scrape links from [https://www.sreality.cz/adresar?strana=2]. If you scroll down you can see a red right arrow button that you can click to go to the next page and so the website load new dynamic content. Every approach seems to report the same exact error and I don't know how am I supposed to point to the element without running into it.
This is the code that I currently have :
from selenium import webdriver
chromedriver_path = "/home/user/Dokumenty/iCloud/RealityScraper/chromedriver"
driver = webdriver.Chrome(chromedriver_path)
print("WebDriver Successfully Initialized")
driver.get("https://www.sreality.cz/adresar?strana=2")
links = driver.find_elements_by_css_selector("h2.title a")
nextPage = driver.find_element_by_css_selector("li.paging-item a.btn-paging-pn.icof.icon-arr-right.paging-next")
for link in links:
print(link.get_attribute("href"))
nextPage.click()
The "nextPage" variable is holding a supposed value to be clicked on once the "links" variable search finishes scraping all the links from the company titles. However when I run this code I get an error :
selenium.common.exceptions.StaleElementReferenceException: Message:
stale element reference: element is not attached to the page document
I have been searching for various fixes online but none of them seemed to resolve the issue. I think that the issue at this point is not caused by the element not loading quickly enough but rather Selenium having trouble finding the element because of wrong reference.
Because of this I have tried using XPath to accurately point to the actual element and so I changed the "nextPage" variable to :
nextPage = driver.find_element_by_xpath("""/html/body/div[2]/div[1]/div[2]/div[2]/div[4]/div/div/div/div[2]/div/div[2]/ul[1]/li[12]/a""")
Which returns exactly the same error as stated above. I have been trying to find a solution to this for hours now and I can't understand where the issue lies. I would be grateful if anyone could explain to me what am I doing wrong. Thanks to anyone.

If you want to get all the ng-href tags from every page. Or you could look into their api.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from time import sleep
driver.get("https://www.sreality.cz/adresar?strana=2")
wait = WebDriverWait(driver, 10)
while True:
try:
links = wait.until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, "h2.title > a")))
#print(len(links))
for link in links:
print(link.get_attribute("ng-href"))
nextPage = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a.btn-paging-pn.icof.icon-arr-right.paging-next")))
nextPage.click()
time.sleep(10)
except Exception as e:
print(e)
break

First of all never use the absolute xpath it will breakdown easily, Use the relative xpath.
Secondly, i think the error you are getting is because after clicking "Next" button for the first time it loads a new page. Which has a different DOM structure and that's why you are not able to find that element.
You can try searching for the element after every new page load (after clicking "Next" button everytime.)
// imports
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver import ActionChains
from selenium.webdriver.common.by import By
// initialize
driver = webdriver.Chrome()
wait = WebDriverWait(driver, 20)
action = ActionChains(driver)
// Try to use the below code and see if it works.
Next_btn = wait.until(EC.presence_of_element_located((By.XPATH, '(//li[#class="paging-item"])[2]')))
action.move_to_element(Next_btn).click().perform()

Python Selenium - Webdriver interacts with data from previous page

I am trying to create a piece of code that takes an input from the user and searches for that input in his gmail account and then checks all the boxes from the sender which is the same as the input.
Here is my code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from bs4 import BeautifulSoup
from selenium.webdriver import Remote
from selenium.webdriver.support.ui import WebDriverWait
import urllib
driver = webdriver.Chrome('D:/chromedriver_win32/chromedriver.exe')
driver.get("http://www.gmail.com")
elem = driver.find_element_by_id('Email')
elem.send_keys("****************")
elem2 = driver.find_element_by_id('next')
elem2.send_keys(Keys.ENTER)
driver.maximize_window()
driver.implicitly_wait(20)
elem3 = driver.find_element_by_name('Passwd')
elem3.send_keys("*************")
driver.find_element_by_id('signIn').send_keys(Keys.ENTER)
driver.implicitly_wait(20)
inp = 'randominput'
driver.find_element_by_name('q').send_keys(inp)
driver.find_element_by_css_selector('button.gbqfb').send_keys(Keys.ENTER)
x = driver.current_url
for i in driver.find_elements_by_css_selector('.zA.zE'):
print(i.find_element_by_class_name('zF').get_attribute('name'))
if(i.find_element_by_class_name('zF').get_attribute('name') == inp):
i.find_element_by_css_selector('.oZ-jc.T-Jo.J-J5-Ji').click()
This main problem is that although the webdriver shows the new page where it has searched for the query but when the code interacts with the page it interacts with the previous one.
I have tried putting implicit wait. And when I check for the current url it shows the new url.

The problem is that this is a single page app so selenium isn't going to wait for new data to load. You need to figure out a way to wait for the search results to come back. Whether it be based off of the 'Loading...' that appears at the top or even just waiting for the first result to change.

Grab an element off of the first page and wait for it to go stale. That will tell you that the page is loading. Then wait for the element you want. This is about the only way to ensure that the page has reloaded and you aren't referencing the original page with a dynamic page.
To wait for stale, see staleness_of on http://selenium-python.readthedocs.io/waits.html.

How to check if some text is present on a web page using selenium 2?

Hi I am using selenium to automate test on web pages.
I am using selenium 2 and python and would like to have answers in this framework only.
SO how do I check whether some text is present or not? I have tried asset equals but it is not working?
assertEquals(driver.getPageSource().contains("email"), true);

For those of you who are still interested:
Generic Solution
if text in driver.page_source:
# text exists in page
unittest:
assertTrue(text in driver.page_source)
pytest:
assert text in driver.page_source

You can use driver.page_source and a simple regular expression to check if the text exists:
import re
src = driver.page_source
text_found = re.search(r'text_to_search', src)
self.assertNotEqual(text_found, None)

You can try something like
browser = webdriver.Firefox()
browser.get(url)
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.LINK_TEXT, 'some link text')))
Essentially the above lines launch Firefox, navigate to the specified url, cause the browser to hold for 10 seconds, for some url to load then look for a specific link text, if no link text is found, a TimeoutException is triggered.
Please note the number of brackets used, you will run into errors if the number of brackets does not correspond like the above.
To be able to run the above statement, the following must have been declared
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
This uses "element_to_be_clickable" - a full list of wait-conditions can be found here: Selenium Python: Waits