How can below dictionary converted to expected dataframe like below?
{
"getArticleAttributesResponse": {
"attributes": [{
"articleId": {
"id": "2345",
"locale": "en_US"
},
"keyValuePairs": [{
"key": "tags",
"value": "[{\"displayName\": \"Nice\", \"englishName\": \"Pradeep\", \"refKey\": \"Key2\"}, {\"displayName\": \"Family Sharing\", \"englishName\": \"Sarvendra\", \"refKey\": \"Key1\", \"meta\": {\"customerDisplayable\": [false]}}}]"
}]
}]
}
}
Expected dataframe:
id displayName englistname refKey
2345 Nice Pradeep Key2
2345 Family Sharing Sarvendra Key1
df1 = pd.DataFrame(d['getDDResponse']['attributes']).explode('keyValuePairs')
df2 = pd.concat([df1[col].apply(pd.Series) for col in df1],1).assign(value = lambda x :x.value.apply(eval)).explode('value')
df = pd.concat([df2[col].apply(pd.Series) for col in df2],1)
OUTPUT:
0 0 display englishName reference source
0 1234 tags Unarchived Unarchived friend monster
Related
I am using Github's GraphQL API to fetch some issue details.
I used Python Requests to fetch the data locally.
This is how the output.json looks like
{
"data": {
"viewer": {
"login": "some_user"
},
"repository": {
"issues": {
"edges": [
{
"node": {
"id": "I_kwDOHQ63-s5auKbD",
"title": "test issue 1",
"number": 146,
"createdAt": "2023-01-06T06:39:54Z",
"closedAt": null,
"state": "OPEN",
"updatedAt": "2023-01-06T06:42:00Z",
"comments": {
"edges": [
{
"node": {
"id": "IC_kwDOHQ63-s5R2XCV",
"body": "comment 01"
}
},
{
"node": {
"id": "IC_kwDOHQ63-s5R2XC9",
"body": "comment 02"
}
}
]
},
"labels": {
"edges": []
}
},
"cursor": "Y3Vyc29yOnYyOpHOWrimww=="
},
{
"node": {
"id": "I_kwDOHQ63-s5auKm8",
"title": "test issue 2",
"number": 147,
"createdAt": "2023-01-06T06:40:34Z",
"closedAt": null,
"state": "OPEN",
"updatedAt": "2023-01-06T06:40:34Z",
"comments": {
"edges": []
},
"labels": {
"edges": [
{
"node": {
"name": "food"
}
},
{
"node": {
"name": "healthy"
}
}
]
}
},
"cursor": "Y3Vyc29yOnYyOpHOWripvA=="
}
]
}
}
}
}
The json was put inside a list using
result = response.json()["data"]["repository"]["issues"]["edges"]
And then this list was put inside a DataFrame
import pandas as pd
df = pd.DataFrame (result, columns = ['node', 'cursor'])
df
These are the contents of the data frame
id
title
number
createdAt
closedAt
state
updatedAt
comments
labels
I_kwDOHQ63-s5auKbD
test issue 1
146
2023-01-06T06:39:54Z
None
OPEN
2023-01-06T06:42:00Z
{'edges': [{'node': {'id': 'IC_kwDOHQ63-s5R2XCV","body": "comment 01"}},{'node': {'id': 'IC_kwDOHQ63-s5R2XC9","body": "comment 02"}}]}
{'edges': []}
I_kwDOHQ63-s5auKm8
test issue 2
147
2023-01-06T06:40:34Z
None
OPEN
2023-01-06T06:40:34Z
{'edges': []}
{'edges': [{'node': {'name': 'food"}},{'node': {'name': 'healthy"}}]}
I would like to split/explode the comments and labels columns.
The values in these columns are nested dictionaries
I would like there to be as many rows for a single issue, as there are comments & labels.
I would like to flatten out the data frame.
So this involves split/explode and concat.
There are several stackoverflow answers that delve on this topic. And I have tried the code from several of them.
I can not paste the links to those questions, because stackoverflow marks my question as spam due to many links.
But these are the steps I have tried
df3 = df2['comments'].apply(pd.Series)
Drill down further
df4 = df3['edges'].apply(pd.Series)
df4
Drill down further
df5 = df4['node'].apply(pd.Series)
df5
The last statement above gives me the KeyError: 'node'
I understand, this is because node is not a key in the DataFrame.
But how else can i split this dictionary and concatenate all columns back to my issues row?
This is how I would like the output to look like
id
title
number
createdAt
closedAt
state
updatedAt
comments
labels
I_kwDOHQ63-s5auKbD
test issue 1
146
2023-01-06T06:39:54Z
None
OPEN
2023-01-06T06:42:00Z
comment 01
Null
I_kwDOHQ63-s5auKbD
test issue 1
146
2023-01-06T06:39:54Z
None
OPEN
2023-01-06T06:42:00Z
comment 02
Null
I_kwDOHQ63-s5auKm8
test issue 2
147
2023-01-06T06:40:34Z
None
OPEN
2023-01-06T06:40:34Z
Null
food
I_kwDOHQ63-s5auKm8
test issue 2
147
2023-01-06T06:40:34Z
None
OPEN
2023-01-06T06:40:34Z
Null
healthy
If dct is your dictionary from the question you can try:
df = pd.DataFrame(d['node'] for d in dct['data']['repository']['issues']['edges'])
df['comments'] = df['comments'].str['edges']
df = df.explode('comments')
df['comments'] = df['comments'].str['node'].str['body']
df['labels'] = df['labels'].str['edges']
df = df.explode('labels')
df['labels'] = df['labels'].str['node'].str['name']
print(df.to_markdown(index=False))
Prints:
id
title
number
createdAt
closedAt
state
updatedAt
comments
labels
I_kwDOHQ63-s5auKbD
test issue 1
146
2023-01-06T06:39:54Z
OPEN
2023-01-06T06:42:00Z
comment 01
nan
I_kwDOHQ63-s5auKbD
test issue 1
146
2023-01-06T06:39:54Z
OPEN
2023-01-06T06:42:00Z
comment 02
nan
I_kwDOHQ63-s5auKm8
test issue 2
147
2023-01-06T06:40:34Z
OPEN
2023-01-06T06:40:34Z
nan
food
I_kwDOHQ63-s5auKm8
test issue 2
147
2023-01-06T06:40:34Z
OPEN
2023-01-06T06:40:34Z
nan
healthy
#andrej-kesely has answered my question.
I have selected his response as the answer for this question.
I am now posting a consolidated script that includes my poor code and andrej's great code.
In this script i want to fetch details from Github's GraphQL API Server.
And put it inside pandas.
Primary source for this script is this gist.
And a major chunk of remaining code is an answer by #andrej-kesely.
Now onto the consolidated script.
First import the necessary packages and set headers
import requests
import json
import pandas as pd
headers = {"Authorization": "token <your_github_personal_access_token>"}
Now define the query that will fetch data from github.
In my particular case, I am fetching issue details form a particular repo
it can be something else for you.
query = """
{
viewer {
login
}
repository(name: "your_github_repo", owner: "your_github_user_name") {
issues(states: OPEN, last: 2) {
edges {
node {
id
title
number
createdAt
closedAt
state
updatedAt
comments(first: 10) {
edges {
node {
id
body
}
}
}
labels(orderBy: {field: NAME, direction: ASC}, first: 10) {
edges {
node {
name
}
}
}
comments(first: 10) {
edges {
node {
id
body
}
}
}
}
cursor
}
}
}
}
"""
Execute the query and save the response
def run_query(query):
request = requests.post('https://api.github.com/graphql', json={'query': query}, headers=headers)
if request.status_code == 200:
return request.json()
else:
raise Exception("Query failed to run by returning code of {}. {}".format(request.status_code, query))
result = run_query(query)
And now is the trickiest part.
In my query response, there are several nested dictionaries.
I would like to split them - more details in my question above.
This magic code from #andrej-kesely does that for you.
df = pd.DataFrame(d['node'] for d in result['data']['repository']['issues']['edges'])
df['comments'] = df['comments'].str['edges']
df = df.explode('comments')
df['comments'] = df['comments'].str['node'].str['body']
df['labels'] = df['labels'].str['edges']
df = df.explode('labels')
df['labels'] = df['labels'].str['node'].str['name']
print(df)
I have a json structured as this:
{
"data": [
{
"groups": {
"data": [
{
"group_name": "Wedding planning - places and bands (and others) to recommend!",
"date_joined": "2009-03-12 01:01:08.677427"
},
{
"group_name": "Harry Potter and the Deathly Hollows",
"date_joined": "2009-01-15 01:38:06.822220"
},
{
"group_name": "Xbox , Playstation, Wii - console fans",
"date_joined": "2010-04-02 04:02:58.078934"
}
]
},
"id": "0"
},
{
"groups": {
"data": [
{
"group_name": "Lost&Found (Strzegom)",
"date_joined": "2010-02-01 14:13:34.551920"
},
{
"group_name": "Tennis, Squash, Badminton, table tennis - looking for sparring partner (Strzegom)",
"date_joined": "2008-09-24 17:29:43.356992"
}
]
},
"id": "1"
}
]
}
How does one parse jsons in this form? Should i try building a class resembling this format? My desired output is a csv where index is an "id" and in the first column I have the most recently taken group, in the second column the second most recently taken group and so on.
Meaning the result of this would be:
most recent second most recent
0 Xbox , Playstation, Wii - console fans Wedding planning - places and bands (and others) to recommend!
1 Lost&Found (Strzegom) Tennis, Squash, Badminton, table tennis - looking for sparring partner (Strzegom)
solution could be like this:
data = json.load(f)
result = []
# it's max element in there for each id. Helping how many group_name here for this example [3,2]
max_element_group_name = [len(data['data'][i]['groups']['data']) for i in range(len(data['data']))]
max_element_group_name.sort()
for i in range(len(data['data'])):
# get id for each groups
id = data['data'][i]['id']
# sort data_joined in groups
sorted_groups_by_date = sorted(data['data'][i]['groups']['data'],key=lambda x : time.strptime(x['date_joined'],'%Y-%m-%d %H:%M:%S.%f'),reverse=True)
# get groups name using minumum value in max_element_group_name for this example [2]
group_names = [sorted_groups_by_date[j]['group_name'] for j in range(max_element_group_name[0])]
# add result list with id
result.append([id]+group_names)
# create df for list
df = pd.DataFrame(result, columns = ['id','most recent', 'second most recent'])
# it could be better.
I read csv file into a dataframe named df
Each rows contains str below.
'{"id":2140043003,"name":"Olallo Rubio",...}'
I would like to extract "name" and "id" from each row and make a new dataframe to store the str.
I use the following codes to extract but it shows an error. Please let me know if there is any suggestions on how to solve this problem. Thanks
JSONDecodeError: Expecting ',' delimiter: line 1 column 32 (char 31)
text={
"id": 2140043003,
"name": "Olallo Rubio",
"is_registered": True,
"chosen_currency": 'Null',
"avatar": {
"thumb": "https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=40&h=40&fit=crop&v=1510685152&auto=format&q=92&s=653706657ccc49f68a27445ea37ad39a",
"small": "https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=160&h=160&fit=crop&v=1510685152&auto=format&q=92&s=0bd2f3cec5f12553e679153ba2b5d7fa",
"medium": "https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=160&h=160&fit=crop&v=1510685152&auto=format&q=92&s=0bd2f3cec5f12553e679153ba2b5d7fa"
},
"urls": {
"web": {
"user": "https://www.kickstarter.com/profile/2140043003"
},
"api": {
"user": "https://api.kickstarter.com/v1/users/2140043003?signature=1531480520.09df9a36f649d71a3a81eb14684ad0d3afc83e03"
}
}
}
def extract(text,*args):
list1=[]
for i in args:
list1.append(text[i])
return list1
print(extract(text,'name','id'))
# ['Olallo Rubio', 2140043003]
Here's what I came up with using pandas.json_normalize():
import pandas as pd
sample = [{
"id": 2140043003,
"name":"Olallo Rubio",
"is_registered": True,
"chosen_currency": None,
"avatar":{
"thumb":"https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=40&h=40&fit=crop&v=1510685152&auto=format&q=92&s=653706657ccc49f68a27445ea37ad39a",
"small":"https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=160&h=160&fit=crop&v=1510685152&auto=format&q=92&s=0bd2f3cec5f12553e679153ba2b5d7fa",
"medium":"https://ksr-ugc.imgix.net/assets/019/223/259/16513215a3869caaea2d35d43f3c0c5f_original.jpg?w=160&h=160&fit=crop&v=1510685152&auto=format&q=92&s=0bd2f3cec5f12553e679153ba2b5d7fa"
},
"urls":{
"web":{
"user":"https://www.kickstarter.com/profile/2140043003"
},
"api":{
"user":"https://api.kickstarter.com/v1/users/2140043003?signature=1531480520.09df9a36f649d71a3a81eb14684ad0d3afc83e03"
}
}
}]
# Create datafrane
df = pd.json_normalize(sample)
# Select columns into new dataframe.
df1 = df.loc[:, ["name", "id",]]
Check df1:
Input:
print(df1)
Output:
name id
0 Olallo Rubio 2140043003
I have a list
list1= ['{"bank_name": null, "country": null, "url": null, "type": "Debit", "scheme": "Visa", "bin": "789452"}\n',
'{"prepaid": "", "bin": "123457", "scheme": "Visa", "type": "Debit", "bank_name": "Ohio", "url": "www.u.org", "country": "UKs"}\n']
I passed it into a dataframe:
df = pd.DataFrame({'bincol':list1})
print(df)
bincol
0 {"bank_name": null, "country": null, "url": nu...
1 {"prepaid": "", "bin": "123457", "scheme": "Vi...
I am trying to split bincol columns into new columns using this function
def explode_col(df, column_value):
df = df.dropna(subset=[column_value])
if isinstance(df[str(column_value)].iloc[0], str):
df[column_value] = df[str(column_value)].apply(ast.literal_eval)
expanded_child_df = (pd.concat({i: json_normalize(x) for i, x in .pop(str(column_value)).items()}).reset_index(level=1,drop=True).join(df, how='right', lsuffix='_left', rsuffix='_right').reset_index(drop=True))
expanded_child_df.columns = map(str.lower, expanded_child_df.columns)
return expanded_child_df
df2 = explode_col(df,'bincol')
But i am getting this error, am i missing something here ?
raise ValueError(f'malformed node or string: {node!r}')
ValueError: malformed node or string: <_ast.Name object at 0x7fd3aa05c400>
For me working in your sample data json.loads for convert data to dictionaries, then is used json_normalize for DataFrame:
import json
df = pd.json_normalize(df['bincol'].apply(json.loads))
print(df)
bank_name country url type scheme bin prepaid
0 None None None Debit Visa 789452 NaN
1 Ohio UKs www.u.org Debit Visa 123457
I have a deeply nested JSON that I am trying to turn into a Pandas Dataframe using json_normalize.
A generic sample of the JSON data I'm working with looks looks like this (I've added context of what I'm trying to do at the bottom of the post):
{
"per_page": 2,
"total": 1,
"data": [{
"total_time": 0,
"collection_mode": "default",
"href": "https://api.surveymonkey.com/v3/responses/5007154325",
"custom_variables": {
"custvar_1": "one",
"custvar_2": "two"
},
"custom_value": "custom identifier for the response",
"edit_url": "https://www.surveymonkey.com/r/",
"analyze_url": "https://www.surveymonkey.com/analyze/browse/",
"ip_address": "",
"pages": [
{
"id": "103332310",
"questions": [{
"answers": [{
"choice_id": "3057839051"
}
],
"id": "319352786"
}
]
},
{
"id": "44783164",
"questions": [{
"id": "153745381",
"answers": [{
"text": "some_name"
}
]
}
]
},
{
"id": "44783183",
"questions": [{
"id": "153745436",
"answers": [{
"col_id": "1087201352",
"choice_id": "1087201369",
"row_id": "1087201362"
}, {
"col_id": "1087201353",
"choice_id": "1087201373",
"row_id": "1087201362"
}
]
}
]
}
],
"date_modified": "1970-01-17T19:07:34+00:00",
"response_status": "completed",
"id": "5007154325",
"collector_id": "50253586",
"recipient_id": "0",
"date_created": "1970-01-17T19:07:34+00:00",
"survey_id": "105723396"
}
],
"page": 1,
"links": {
"self": "https://api.surveymonkey.com/v3/surveys/123456/responses/bulk?page=1&per_page=2"
}
}
I'd like to end up with a dataframe that contains the question_id, page_id, response_id, and response data like this:
choice_id col_id row_id text question_id page_id response_id
0 3057839051 NaN NaN NaN 319352786 103332310 5007154325
1 NaN NaN NaN some_name 153745381 44783164 5007154325
2 1087201369 1087201352 1087201362 NaN 153745436 44783183 5007154325
3 1087201373 1087201353 1087201362 NaN 153745436 44783183 5007154325
I can get close by running the following code (Python 3.6):
df = json_normalize(data=so_survey_responses['data'], record_path=['pages', 'questions'], meta='id', record_prefix ='question_')
print(df)
Which returns:
question_answers question_id id
0 [{'choice_id': '3057839051'}] 319352786 5007154325
1 [{'text': 'some_name'}] 153745381 5007154325
2 [{'col_id': '1087201352', 'choice_id': '108720... 153745436 5007154325
But if I try to run json_normalize at a deeper nest and keep the 'question_id' data from the above result, I can only get the page_id values to return, not true question_id values:
answers_df = json_normalize(data=so_survey_responses['data'], record_path=['pages', 'questions', 'answers'], meta=['id', ['questions', 'id'], ['pages', 'id']])
print(answers_df)
Returns:
choice_id col_id row_id text id questions.id pages.id
0 3057839051 NaN NaN NaN 5007154325 103332310 103332310
1 NaN NaN NaN some_name 5007154325 44783164 44783164
2 1087201369 1087201352 1087201362 NaN 5007154325 44783183 44783183
3 1087201373 1087201353 1087201362 NaN 5007154325 44783183 44783183
A complicating factor may be that all the above (question_id, page_id, response_id) are 'id:' in the JSON data.
I'm sure this is possible, but I can't get there. Any examples of how to do this?
Additional context:
I'm trying to create a dataframe of SurveyMonkey API response output.
My long term goal is to re-create the "all responses" excel sheet that their export service provides.
I plan to do this by getting the response dataframe set up (above), and then use .apply() to match responses with their survey structure API output.
I've found the SurveyMonkey API pretty lackluster at providing useful output, but I'm new to Pandas so it's probably on me.
You need to modify the meta parameter of your last option, and, if you want to rename columns to be exactly the way you want, you could do it with rename:
answers_df = json_normalize(data=so_survey_responses['data'],
record_path=['pages', 'questions', 'answers'],
meta=['id', ['pages', 'questions', 'id'], ['pages', 'id']])\
.rename(index=str,
columns={'id': 'response_id', 'pages.questions.id': 'question_id', 'pages.id': 'page_id'})
There is no way to do this in a completely generic way using json_normalize(). You can use the record_path and meta arguments to indicate how you want the JSON to be processed.
However, you can use the flatten package to flatten your deeply nested JSON and then convert that to a Pandas dataframe. The page has example usage of how to flatten a deeply-nested JSON and convert to a Pandas dataframe.