Argparse module with multiple command and arguments - python

I'm trying to parse commands with arguments using the python 3 Built-in argparse module.
I have read the argparse documentation partially, however, I could not find anything that meets my requirements.
I parse the arguments as input (I have my reasons).
I have multiple commands, for each, there are both essential and optional arguments.
For example:
restart --name (the name is replaced)
restart is the command and name is the essential argument.
Currently my code would count the "--" in the input and call the function with corresponding booleans (if --all given, is_all boolean parameter will be true)
I can also add an optional argument --all (all is not replaced).

Sounds like you are looking for something like this
def get_arguments():
parser = argparse.ArgumentParser()
parser.add_argument("--arg1", required=False, default=None)
parser.add_argument("--arg2", required=False, default=None)
return parser.parse_args()
args = get_arguments()
if args.arg1:
# do something
Really hard to answer this without seeing your code or example of what you want.

I'm assuming you're doing something like a shell of sorts. I'm going to also assume that each line entered has a command, each with their own arguments.
from argparse import ArgumentParser
def get_parser(cmd):
'''Returns a parser object for a given command'''
# Instantiate the parser object, add the appropriate arguments for the command
return parser # This is an example -- you need to instantiate it
def main():
while True:
try:
in_line = input('> ')
if not in_line.strip(): # Quit if empty
break
args = in_line.split()
parser = get_parser(args[0])
opts = parser.parser_args(args)
# Do stuff with opts depending on command
except EOFError:
break
except SystemExit:
pass # Prevent failures from killing the program by trapping sys.exit()

Related

How do I suppress an argument when nothing is input on command line?

#!/usr/bin/env python3
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('--selection', '-s')
parser.add_argument('--choice', '-c', default = argparse.SUPPRESS)
args = parser.parse_args()
def main(selection, choice):
print(selection)
print(choice)
if __name__=='__main__':
main(args.selection, args.choice)
The example provided is just to provide something simple and short that accurately articulates the actual problem I am facing in my project. My goal is to be able to ignore an argument within the code body when it is NOT typed into the terminal. I would like to be able to do this through passing the argument as a parameter for a function. I based my code off of searching 'suppress' in the following link: https://docs.python.org/3/library/argparse.html
When I run the code as is with the terminal input looking like so: python3 stackquestion.py -s cheese, I receive the following error on the line where the function is called:
AttributeError: 'Namespace' object has no attribute 'choice'
I've tried adding the following parameter into parser like so:
parser = argparse.ArgumentParser(argument_default=argparse.SUPPRESS)
I've also tried the above with
parser.add_argument('--choice', '-c')
But I get the same issue on the same line.
#Barmar answered this question in the comments. Using 'default = None' in parser.add_argument works fine; The code runs without any errors. I selected the anser from #BorrajaX because it's a simple solution to my problem.
According to the docs:
Providing default=argparse.SUPPRESS causes no attribute to be added if the command-line argument was not present:
But you're still assuming it will be there by using it in the call to main:
main(args.selection, args.choice)
A suppressed argument won't be there (i.e. there won't be an args.choice in the arguments) unless the caller specifically called your script adding --choice="something". If this doesn't happen, args.choice doesn't exist.
If you really want to use SUPPRESS, you're going to have to check whether the argument is in the args Namespace by doing if 'choice' in args: and operate accordingly.
Another option (probably more common) can be using a specific... thing (normally the value None, which is what argparse uses by default, anyway) to be used as a default, and if args.choice is None, then assume it hasn't been provided by the user.
Maybe you could look at this the other way around: You want to ensure selection is provided and leave choice as optional?
You can try to set up the arguments like this:
parser = argparse.ArgumentParser()
parser.add_argument('--selection', '-s', required=True)
parser.add_argument('--choice', '-c')
args = parser.parse_args()
if __name__ == '__main__':
if args.choice is None:
print("No choice provided")
else:
print(f"Oh, the user provided choice and it's: {args.choice}")
print(f"And selection HAS TO BE THERE, right? {args.selection}")

Get user input with arguments in Python

TL;DR I need to get a user input that contains an argument in order to do something, I need my own script that gets user input, and acts like it's its own interpreter.
My goal is to make my own CLI with my own commands.
What I need now is to get user input within a python script. The grammar for my CLI is below: (The thing I don't know how to do)
COMMAND + ARGUMENT1 + ARGUMENT2 + ARGUMENT3
Example of what I want to do:
say "hi this is a test"
hi this is a test
I have a plan for how I can make the commands with arguments,
I make a folder named 'bin' and I put python scripts in them.
Inside the python scripts are functions.
Depending on the command type, either I call the functions do do something, or it prints a output.
But for now, I need to know HOW to get user input with ARGUMENTS
The built-in argparse module as #ToTheMax said can create complex command line interfaces.
By default argparse.ArgumentParser.parse_args() will read the command line arguments to your utility from sys.argv, but if you pass in an array, it will use it instead.
You can lex (split into an array of "words") a string just like the shell is using shlex.split() which is also built in. If you use quotation marks like in your example, the words between them won't be split apart, just as in the shell.
Here's a complete example. Refer to the documentation, because this is a bit of an advance usage of argparse. There is a section that talks about "subcommands" which is what this example is based on.
import argparse
import shlex
def do_say(args):
print(args.what)
parser = argparse.ArgumentParser()
subparsers = parser.add_subparsers()
say_command = subparsers.add_parser('say')
say_command.add_argument('what')
say_command.set_defaults(func=do_say)
command = 'say "hi this is a test"'
args = parser.parse_args(shlex.split(command))
args.func(args)
The cmd module is another built-in way to make a command prompt, but it doesn't do the parsing for you, so you'd maybe combine it with argparse and shlex.
I realize I already have a question that is answered.
You can find it here:
How do you have an input statement with multiple arguments that are stored into a variable?
Here is the correct code:
def command_split(text:str) -> (str,str):
"""Split a string in a command and any optional arugments"""
text = text.strip() # basic sanitize input
space = text.find(' ')
if space > 0:
return text[:space],text[space+1:]
return text,None
x = input(":>")
command,args = command_split(x)
# print (f'command: "{command:}", args: "{args}"')
if command == 'echo':
if args == None:
raise SyntaxError
print (args)
A more simple way:
x = input(":>")
if x.split(" ")[0] == 'echo':
echoreturn = ' '.join(x.split(" ")[1:])
print(echoreturn)
My version to #rgov 's post: (Thank you!)
import argparse
import shlex
def do_say(args):
print(args.what)
parser = argparse.ArgumentParser()
subparsers = parser.add_subparsers()
say_command = subparsers.add_parser('say')
say_command.add_argument('what')
say_command.set_defaults(func=do_say)
while True:
try:
command = input(":>")
args = parser.parse_args(shlex.split(command))
args.func(args)
except SyntaxError:
print("Syntax Error")
except ValueError:
print("Value Error")
except:
print("")

Argparse and mutually exclusive command line arguments

I have created a pastebin terminal client in python. It can take some command line arguments, like -o to open a file, -n to set a paste name etc. It also has option -l which lists the pastes and allows you to delete or view pastes. The problem is that I don't know how to do it in a nice way (using argparse) - it should not allow to use -l with any other options.
I added a simple logic:
if args.name:
if args.list:
print('The -l should be used alone. Check "pb -h" for help.')
sys.exit()
Can it be done using just argparse?
I know about mutually exclusive groups, I even have one (to set paste privacy) but I haven't figured this one yet.
Full code is available here: https://github.com/lkorba/pbstc/blob/master/pb
I don't think you can use argparse to achieve your goal in "a nice way" as you say.
I see 2 options here:
1) The simpler solution as I get it would be to just check your arguments after parsing them. Nothing fancy just:
args = parser.parse_args()
if args.list is not None:
if not (args.name is None and args.open is None and
args.public is None and args.format is None and args.exp is None):
parser.error('Cannot use list with name, open, public, format or exp argument')
2) On the other hand you could revise a bit your program and use
subparsers like:
subparsers = parser.add_subparsers(title="commands", dest="command")
parser_a = subparsers.add_parser('list', help='list help')
parser_b = subparsers.add_parser('action', help='Any action here')
parser_b.add_argument('-f', action="store", help='Choose paste format/syntax: text=None, '
'mysql=MYSQL, perl=Perl, python=Python etc...')
parser_b.add_argument('-n', '--name', action="store")
parser_b.add_argument('-o', '--open', action="store", help='Open file')
...
args = parser.parse_args()
if args.command == 'list':
...
elif args.command == 'action':
...
So, for example if you pass list -n='Name' as arguments in the latter case you will get an error:
usage: subparser_example.py [-h] {list,action} ...
subparser_example.py: error: unrecognized arguments: -n='Name'
Of course you also get (as overhead) one extra parameter action here...

Python argparse: command-line argument that can be either named or positional

I am trying to make a Python program that uses the argparse module to parse command-line options.
I want to make an optional argument that can either be named or positional. For example, I want myScript --username=batman to do the same thing as myScript batman. I also want myScript without a username to be valid. Is this possible? If so, how can it be done?
I tried various things similar to the code below without any success.
parser = argparse.ArgumentParser()
group = parser.add_mutually_exclusive_group()
group.add_argument("-u", "--user-name", default="admin")
group.add_argument("user-name", default="admin")
args = parser.parse_args()
EDIT: The above code throws an exception saying ValueError: mutually exclusive arguments must be optional.
I am using Python 2.7.2 on OS X 10.8.4.
EDIT: I tried Gabriel Jacobsohn's suggestion but I couldn't get it working correctly in all cases.
I tried this:
parser = argparse.ArgumentParser()
group = parser.add_mutually_exclusive_group()
group.add_argument("-u", "--user-name", default="admin", nargs="?")
group.add_argument("user_name", default="admin", nargs="?")
args = parser.parse_args()
print(args)
and running myScript batman would print Namespace(user_name='batman'), but myScript -u batman and myScript --user-name=batman would print Namespace(user_name='admin').
I tried changing the name user-name to user_name in the 1st add_argument line and that sometimes resulted in both batman and admin in the namespace or an error, depending on how I ran the program.
I tried changing the name user_name to user-name in the 2nd add_argument line but that would print either Namespace(user-name='batman', user_name='admin') or Namespace(user-name='admin', user_name='batman'), depending on how I ran the program.
The way the ArgumentParser works, it always checks for any trailing positional arguments after it has parsed the optional arguments. So if you have a positional argument with the same name as an optional argument, and it doesn't appear anywhere on the command line, it's guaranteed to override the optional argument (either with its default value or None).
Frankly this seems like a bug to me, at least when used in a mutually exclusive group, since if you had specified the parameter explicitly it would have been an error.
That said, my suggested solution, is to give the positional argument a different name.
parser = argparse.ArgumentParser()
group = parser.add_mutually_exclusive_group()
group.add_argument('-u','--username')
group.add_argument('static_username',nargs='?',default='admin')
Then when parsing, you use the optional username if present, otherwise fallback to the positional static_username.
results = parser.parse_args()
username = results.username or results.static_username
I realise this isn't a particularly neat solution, but I don't think any of the answers will be.
Here is a solution that I think does everything you want:
import argparse
if __name__ == '__main__':
parser = argparse.ArgumentParser()
parser.add_argument("-u", "--user-name", default="admin")
# Gather all extra args into a list named "args.extra"
parser.add_argument("extra", nargs='*')
args = parser.parse_args()
# Set args.user_name to first extra arg if it is not given and len(args.extra) > 0
if args.user_name == parser.get_default("user_name") and args.extra:
args.user_name = args.extra.pop(0)
print args
If you run myScript -u batman or myScript --user-name=batman, args.user_name is set to 'batman'. If you do myScript batman, args.user_name is again set to 'batman'. And finally, if you just do myScript, args.user_name is set to 'admin'.
Also, as an added bonus, you now have all of the extra arguments that were passed to the script stored in args.extra. Hope this helps.
Try to use the "nargs" parameter of the add_argument method.
This way it works for me.
Now you can add the username twice,
so you have to check it and raise an error, if you want.
import argparse
if __name__ == '__main__':
parser = argparse.ArgumentParser()
parser.add_argument("-u", "--user-name", default="admin")
parser.add_argument("user_name", default="admin", nargs="?")
args = parser.parse_args()
print(args)

Python command line parameters

I am just starting with python so I am struggling with a quite simple example. Basically I want pass the name of an executable plus its input via the command line arguments, e.g.:
python myprogram refprogram.exe refinput.txt
That means when executing myprogram, it executes refprogram.exe and passes to it as argument refinput. I tried to do it the following way:
import sys, string, os
print sys.argv
res = os.system(sys.argv(1)) sys.argv(2)
print res
The error message that I get is:
res = os.system(sys.argv(1)) sys.argv(2)
^
SyntaxError: invalid syntax
Anyone an idea what I am doing wrong?
I am running Python 2.7
This line
res = os.system(sys.argv(1)) sys.argv(2)
Is wrong in a couple of ways.
First, sys.argv is a list, so you use square brackets to access its contents:
sys.argv[1]
sys.argv[2]
Second, you close out your parentheses on os.system too soon, and sys.argv(2) is left hanging off of the end of it. You want to move the closing parenthesis out to the very end of the line, after all of the arguments.
Third, you need to separate the arguments with commas, a simple space won't do.
Your final line should look like this:
res = os.system(sys.argv[1], sys.argv[2])
A far, far better way to do this is with the argparse library. The envoy wrapper library makes subprocess easier to work with as well.
A simple example:
import argparse
import envoy
def main(**kwargs):
for key, value in kwargs.iteritems():
print key, value
cmd = '{0} {1}'.format(kwargs['program'], ' '.join(kwargs['infiles']))
r = envoy.run(cmd)
print r.std_out
print r.std_err
if __name__ == '__main__':
parser = argparse.ArgumentParser(description='Get a program and run it with input', version='%(prog)s 1.0')
parser.add_argument('program', type=str, help='Program name')
parser.add_argument('infiles', nargs='+', type=str, help='Input text files')
parser.add_argument('--out', type=str, default='temp.txt', help='name of output file')
args = parser.parse_args()
main(**vars(args))
This reads in the arguments, parses them, then sends them to the main method as a dictionary of keywords and values. That lets you test your main method independently from your argument code, by passing in a preconstructed dictionary.
The main method prints out the keywords and values. Then it creates a command string, and passes that to envoy to run. Finally, it prints the output from the command.
If you have pip installed, envoy can be installed with pip install envoy. The easiest way to get pip is with the pip-installer.
sys.argv is a list, and is indexed using square brackets, e.g. sys.argv[1]. You may want to check len(sys.argv) before indexing it as well.
Also, if you wanted to pass parameters to os.system(), you might want something like os.system(' '.join(sys.argv[1:])), but this won't work for arguments with spaces. You're better off using the subprocess module.
sys.argv is a list
import sys, string, os
print sys.argv
res = os.system(sys.argv[1]) sys.argv[2]
print res
If you are running Python 2.7 it is recommended to use the new subprocess module.
In this case you would write
import sys, subprocess
result = subprocess.check_output(sys.argv[1], sys.argv[2])

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