I want to display a number inside a circle.
The number must be centered (x,y).
How to do it?
import pygame, sys
pygame.init()
screen= pygame.display.set_mode((0, 0))
black= (0,0,0)
white= (255,255,255)
red= (255,0,0)
number= "8"
bigfont = pygame.font.SysFont("arial", 50)
text = bigfont.render(number, True, white)
def draw():
pygame.draw.circle(screen, red, (300,300), 200)
screen.blit(text, (300,300))
pygame.display.update()
Get the bounding rectangle of the text and set the center of the rectangle by the center of the text. Use the rectangle to blit the text:
text_rect = text.get_rect()
text_rect.center = (300, 300)
screen.blit(text, text_rect)
The same with one line of code:
screen.blit(text, text.get_rect(center = (300, 300)))
Use this code in a function:
def draw_circle(x, y, text):
pygame.draw.circle(screen, red, (x, y), 200)
screen.blit(text, text.get_rect(center = (x, y)))
See pygame.Surface.blit:
[...] The dest argument can either be a pair of coordinates representing the position of the upper left corner of the blit or a Rect, where the upper left corner of the rectangle will be used as the position for the blit.
Minimal example:
import pygame
pygame.init()
window = pygame.display.set_mode((500, 500))
font = pygame.font.SysFont(None, 100)
clock = pygame.time.Clock()
text = font.render("Text", True, (255, 255, 0))
run = True
while run:
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window_center = window.get_rect().center
window.fill(0)
pygame.draw.circle(window, (255, 0, 0), window_center, 100)
window.blit(text, text.get_rect(center = window_center))
pygame.display.flip()
clock.tick(60)
pygame.quit()
exit()
To centre PyGame text around point x_pos, y_pos:
Get the dimensions of the text object: width, height = text.get_rect()[2:4]
When you render (screen.blit()) the image, shift the coordinates back by half the width and half the height: screen.blit(text, (x_pos - int(width / 2), y_pos - int(height / 2)))
Related
I'm trying to create this program in pygame to study code/math, but i don't know how to lock the mouse position around a circle in pygame, any help?
import pygame
pygame.init()
x = 250
y = 250
window = pygame.display.set_mode((500, 500))
pygame.display.set_caption("around circle")
#line to be created
def Lin(xref, yref):
lin = pygame.draw.line(window, (250, 250, 0), (x, y), (xref, yref), 1)
window_open = True
while window_open:
pygame.display.update()
window.fill((0, 0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
window_open = False
mousepos = pygame.mouse.get_pos()
xref = mousepos[0]
yref = mousepos[1]
# 2 circles to get only the border
cir0 = pygame.draw.circle(window, (250, 250, 250), (x, y), 100, 1)
cir1 = pygame.draw.circle(window, (250, 250, 250), (x, y), 99, 1)
Lin(xref, yref)
pygame.quit()
I would do something similar to Mike67 answer, but would take advantage of the features of pygame's Vector's (see docs here).
import pygame
pygame.init()
x = 250
y = 250
radius = 100
center = pygame.Vector2(x, y)
window = pygame.display.set_mode((500, 500))
pygame.display.set_caption("around circle")
#line to be created
def Lin(start_point, vector):
pygame.draw.line(window, (250, 250, 0), start_point, start_point+vector, 1)
window_open = True
while window_open:
pygame.display.update()
window.fill((0, 0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
window_open = False
mousepos = pygame.mouse.get_pos()
line_vector = pygame.Vector2(mousepos) - center
if line_vector.length() > radius:
line_vector.scale_to_length(radius)
# 2 circles to get only the border
cir0 = pygame.draw.circle(window, (250, 250, 250), (x, y), radius, 1)
cir1 = pygame.draw.circle(window, (250, 250, 250), (x, y), radius-1, 1)
Lin(center, line_vector)
pygame.quit()
I modified the Lin() function as well.
EDIT:
From your comment you indicated that you want it to always scale to the side of the circle. In that case just skip the test if line_vector.length() > radius and always scale it. You might be tempted to only scale it if length != radius, but when comparing floating point calculated numbers they are very unlikely to actually be the same (because of the decimal places involved) and you could see if the difference is less than a threshold and call them equal, but it really isn't worth the complication.
import pygame
pygame.init()
x = 250
y = 250
radius = 100
center = pygame.Vector2(x, y)
window = pygame.display.set_mode((500, 500))
pygame.display.set_caption("around circle")
#line to be created
def Lin(start_point, vector):
pygame.draw.line(window, (250, 250, 0), start_point, start_point+vector, 1)
window_open = True
while window_open:
pygame.display.update()
window.fill((0, 0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
window_open = False
mousepos = pygame.mouse.get_pos()
line_vector = pygame.Vector2(mousepos) - center
line_vector.scale_to_length(radius)
# 2 circles to get only the border
cir0 = pygame.draw.circle(window, (250, 250, 250), (x, y), radius, 1)
cir1 = pygame.draw.circle(window, (250, 250, 250), (x, y), radius-1, 1)
Lin(center, line_vector)
pygame.quit()
To keep the line in the circle, just adjust the mouse x/y coordinates relative to the mouse distance from the center.
Here is the updated code:
import pygame
import math
pygame.init()
x = 250
y = 250
window = pygame.display.set_mode((500, 500))
pygame.display.set_caption("around circle")
#line to be created
def Lin(xref, yref):
lin = pygame.draw.line(window, (250, 250, 0), (x, y), (xref, yref), 1)
window_open = True
while window_open:
pygame.display.update()
window.fill((0, 0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
window_open = False
mousepos = pygame.mouse.get_pos()
xref = mousepos[0]
yref = mousepos[1]
# get mouse distance from center
dist = math.sqrt((xref-x)**2 + (yref-y)**2)
if (dist > 100): # if mouse outside circle, adjust x/y proportionally
xref = x + (xref - x) * (100/dist)
yref = y + (yref - y) * (100/dist)
# 2 circles to get only the border
cir0 = pygame.draw.circle(window, (250, 250, 250), (x, y), 100, 1)
cir1 = pygame.draw.circle(window, (250, 250, 250), (x, y), 99, 1)
Lin(xref, yref)
pygame.quit()
I'm trying to just draw any text on to the screen in pygame but when I run the program it just runs normally but no text appears on the screen. Is there something I'm doing wrong?
import pygame, random, sys
from pygame.locals import *
pygame.init()
#set constants
WINDOWWIDTH = 600
WINDOWHEIGHT = 600
TEXTCOLOR = (255, 255, 255)
BACKGROUNDCOLOR = (0, 0, 255)
FPS = 40
BLACK = (0,0,0)
RED = (255, 0, 0)
WHITE = (255, 255, 255)
#set variables
rectY1 = 200
rectY2 = 200
Y1change = 0
Y2change = 0
ballX = 320
ballY = 240
ballXvel = 0
ballYvel = 0
paddle1 = pygame.Rect(18,rectY1,10,100)
paddle2 = pygame.Rect(620,rectY2,10,100)
ball = pygame.Rect(ballX,ballY,30,30)
font = pygame.font.SysFont(None, 48)
#create shapes
def drawshapes():
pygame.draw.rect(DISPLAY, WHITE, paddle1)
pygame.draw.rect(DISPLAY, WHITE, paddle2)
pygame.draw.rect(DISPLAY, WHITE, ball)
def drawText(text, font, surface, x, y):
textobj = font.render(text, 1, TEXTCOLOR)
textrect = textobj.get_rect()
textrect.topleft = (x, y)
surface.blit(textobj, textrect)
#set up display
DISPLAY = pygame.display.set_mode((640,480),0,32)
pygame.display.set_caption('Pong')
fpsClock = pygame.time.Clock()
drawText('bruh', font, DISPLAY, (200), (200))
pygame.display.update
idk if this really is the loop you are talking about but here it is:
running = True
while running:
# RGB - Red, Green, Blue
screen.fill((0, 0, 128 ))
#background Image
screen.blit(background, (0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
This question already has answers here:
Draw a transparent rectangles and polygons in pygame
(4 answers)
Closed 2 years ago.
How to make pygame.draw.circle transparent (add alpha level), as for "surface" "set_alpha"?
I found a solution only in changing the color of pygame.draw.circle to less bright
You've to use a pygame.Surface. Create a Surface with a per pixel alpha image format. e.g:
radius = 100
circle = pygame.Surface((radius*2, radius*2), pygame.SRCALPHA)
And draw a transparent circle on it. The color of the circle has to have an alpha channel < 255 (e.g. 128):
pygame.draw.circle(circle, (255, 0, 0, 128), (radius, radius), radius)
blit() the Surface to the window. e.g.:
window.blit(circle, (100, 100))
Example:
import pygame
pygame.init()
wndsize = (400, 400)
window = pygame.display.set_mode(wndsize)
clock = pygame.time.Clock()
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window.fill(0)
pygame.draw.rect(window, (0, 0, 255), (0, 0, 200, 400))
radius = 100
circle = pygame.Surface((radius*2, radius*2), pygame.SRCALPHA)
pygame.draw.circle(circle, (255, 0, 0, 128), (radius, radius), radius)
window.blit(circle, (100, 100))
pygame.display.flip()
You can create surface with alpha channel
surface1 = screen.convert_alpha()
fill it with transparent color -
surface1.fill([0,0,0,0])
draw circle using color [R,G,B,Alpha]
pygame.draw.circle(surface1, (255, 0, 0, 128), (300, 300), 200)
and blit it on screen
screen.blit(surface1, (0,0))
But alpha always mix object color with background color so it makes it less bright.
import pygame
pygame.init()
screen = pygame.display.set_mode((800,600))#, depth=32)
surface1 = screen.convert_alpha()
surface1.fill([0,0,0,0])
pygame.draw.circle(surface1, (255, 0, 0, 128), (325, 250), 100)
surface2 = screen.convert_alpha()
surface2.fill([0,0,0,0])
pygame.draw.circle(surface2, (0, 255, 0, 128), (475, 250), 100)
surface3 = screen.convert_alpha()
surface3.fill([0,0,0,0])
pygame.draw.circle(surface3, (0, 0, 255, 128), (400, 350), 100)
screen.fill([255,255,255]) # white background
screen.blit(surface1, (0,0))
screen.blit(surface2, (0,0))
screen.blit(surface3, (0,0))
pygame.display.flip()
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_ESCAPE:
running = False
pygame.quit()
Example on GitHub: furas/python-examples/pygame/transparency
I have a rectangle, say, rect1 . I have another rectangle called rect2. I want to blit 'rect2' such that the center of rect2 is same as that of rect1?
Just assign the center coordinates of rect1 to the center of rect2.
import pygame as pg
pg.init()
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
BG_COLOR = pg.Color('gray12')
rect1 = pg.Rect(200, 100, 161, 100)
rect2 = pg.Rect(0, 0, 120, 74)
rect2.center = rect1.center
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
screen.fill(BG_COLOR)
pg.draw.rect(screen, (0, 100, 255), rect1, 2)
pg.draw.rect(screen, (255, 128, 0), rect2, 2)
pg.display.flip()
clock.tick(60)
I am programming in Python with the pygame library. I want to know how to make a rectangle variable, something like:
import ...
rect1 = #RECT VARIABLE
rect2 = #RECT VARIABLE
Just do
pygame.Rect(left, top, width, height)
this will return you a Rect object in pygame
Perhaps something like this will work?
import pygame
# your whole code until you need a rectangle
rect1 = pygame.draw.rect( (x_coordinate, y_coordinate), (#a rgb color), (#size of rect in pixels) )
If you want a red rectangle with 100x150 size in 0x50 position, it will be:
rect1 = pygame.draw.rect( (0, 50), (255, 0, 0), (100, 150) )
To insert it into the screen you use:
pygame.screen_you_have_created.blit(rect1, 0, 50)
For rectangle draw pattern is : pygame.Rect(left, top, width, height)
You can modify this code according to your need.
import pygame, sys
from pygame.locals import *
pygame.init()
windowSurface = pygame.display.set_mode((500, 400), 0, 32)
pygame.display.set_caption('Title')
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
BLUE = (0, 0, 255)
basicFont = pygame.font.SysFont(None, 48)
message = 'Hello '
text = basicFont.render(message, False, WHITE, BLUE)
textRect = text.get_rect()
textRect.centerx = windowSurface.get_rect().centerx
textRect.centery = windowSurface.get_rect().centery
windowSurface.fill(WHITE)
pixArray = pygame.PixelArray(windowSurface)
pixArray[480][380] = BLACK
del pixArray
windowSurface.blit(text, textRect)
pygame.display.update()
while True:
for event in pygame.event.get():
if event.type == K_ESCAPE:
pygame.quit()
sys.exit()