I try to click on dropdown options using selenium and python. The problem is that the dropdown values are different each time I open the browser therefore, i can not use the HTML tags from the webpage.
I'm wondering if there's any way of clicking the values?
I tried to use this line of code using answered provided by Sers in this case as an example How to select/click in a dropdown content using selenium chromewebdriver / python but I'm not sure how should I change/compose the class here.
att4 = WebDriverWait(driver, 2).until(ec.visibility_of_element_located((
By.CLASS_NAME, f"div.awsui-select-option awsui-select-option-selectable[title='{l}']"))).click()
l is for each option in my dropdown, I need to click on each of them
You are using a wrong, non-stable locator.
Try this:
att4 = WebDriverWait(driver, 2).until(ec.visibility_of_element_located((By.XPATH, "//div[#data-value='Bambino']"))).click()
Or
att4 = WebDriverWait(driver, 2).until(ec.visibility_of_element_located((By.XPATH, "//div[#title='Bambino']"))).click()
Related
I'm kinda of a newbie in Selenium, started learning it for my job some time ago. Right now I'm working with a code that will open the browser, enter the specified website, put the products ID in the search box, search, and them open it. Once it opens the product, it needs to extract its name and price and write it in a CSV file. I'm kinda struggling with it a bit.
The main problem right now is that Selenium is unable to open the product after searching it. I've tried by ID, name and class and it still didn't work.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import csv
driver = webdriver.Firefox()
driver.get("https://www.madeiramadeira.com.br/")
assert "Madeira" in driver.title
elem = driver.find_element_by_id("input-autocomplete")
elem.clear()
elem.send_keys("525119")
elem.send_keys(Keys.RETURN)
product_link = driver.find_element_by_id('variant-url').click()
The error I get is usually this:
NoSuchElementException: Message: Unable to locate element: [id="variant-url"]
There are multiple elements with the id="variant-url", So you could use the index to click on the desired element, Also you need to handle I think the cookie pop-Up. Check the below code, hope it will help
#Disable the notifications window which is displayed on the page
option = Options()
option.add_argument("--disable-notifications")
driver = webdriver.Chrome(r"Driver_Path",chrome_options=option)
driver.get("https://www.madeiramadeira.com.br/")
assert "Madeira" in driver.title
elem = driver.find_element_by_id("input-autocomplete")
elem.clear()
elem.send_keys("525119")
elem.send_keys(Keys.RETURN)
#Clicked on the cookie popup button
accept= driver.find_element_by_xpath("//button[#id='lgpd-button-agree']")
accept.click()
OR with explicitWait
accept=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//button[#id='lgpd-button-agree']")))
accept.click()
#Here uses the XPath with the index like [1][2] to click on the specific element
product_link = driver.find_element_by_xpath("((//a[#id='variant-url'])[1])")
product_link.click()
OR with explicitWait
product_link=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"((//a[#id='variant-url'])[1])")))
product_link.click()
I used to get this error all the time when starting. The problem is that there are probably multiple elements with the same ID "variant-url". There are two ways you can fix this
By using "driver.find_elementS_by_id"
product_links = driver.find_elements_by_id('variant-url')
product_links[2].click()
This will create an index off all the elements with id 'variant-url' then click the index of 2. This works but it is annoying to find the correct index of the button you want to click and also takes a long time if there are many elements with the same ID.
By using Xpaths or CSS selectors
This way is a lot easier as each element has a specific Xpath of Selector. It will look like this.
product_link = driver.get_element_by_xpath("XPATH GOES HERE").click()
To get an Xpath or selector 1. go into developer mode on your browser by inspecting the element 2. right click the element in the F12 menu 3. hover over copy 4. move to copy Xpath and click on it.
Hope this helps you :D
I'm trying to click a Javascript link, but I can't get it to work.
First I'm getting list of Links using this code:
links = driver.find_elements_by_xpath("(//div[#class='market-box-wp collapse in'])[1]//a[#class='truncate']")
then trying to click some of them
links[3].click() #Doesn't work
I found this solution online for Javascript links, but it's using xPath, not sure how to pass links[3] to it:
WebDriverWait(browser, 20).until(EC.element_to_be_clickable((By.XPATH,"Xpath of Element"))).click()
You can use xpath indexing :-
see this is the xpath
(//div[#class='market-box-wp collapse in'])[1]//a[#class='truncate']
Now to locate the 3rd item, you could do this :
((//div[#class='market-box-wp collapse in'])[1]//a[#class='truncate'])[3]
and use it like this :
WebDriverWait(browser, 20).until(EC.element_to_be_clickable((By.XPATH,"((//div[#class='market-box-wp collapse in'])[1]//a[#class='truncate'])[3]"))).click()
I am very new to web scraping, so I still have lots of trouble. Currently, I am trying to web scrape from https://www.enterprisetrucks.com/truckrental/en_US.html by setting the pickup time by running this code:
pickupTime = d.find_element_by_id('fldPickuptime_msdd')
pickupTime.click();
select = Select(d.find_element_by_id('fldPickuptime'))
select.select_by_value('20:00')
But I get the error saying that the element is not currently visible and may not be manipulated.
The dropdown which is present is not of the Select type, so you cannot use the Select method here. You need to click on the time using the xpath of that element directly.
You can use the xpath:
pickupTime = d.find_element_by_id("fldPickuptime_msdd")
pickupTime.click();
selectTime = d.find_element_by_xpath("//*[#id='fldPickuptime_msdd']//span[text()='8:00 PM']")
selectTime.click();
Code for JavaScriptExecutor Click:
element = driver.find_element_by_xpath("Enter the xpath here")
driver.execute_script("arguments[0].click();", element)
[Please click here to view the Tags][1]
The following is one of the tables of the website I am scraping. Here, under 'tbody' I wish to click on the 'MS' button tag under both odd and even class which provides me a different table for further parsing it.
I am using Selenium and Python 3 to perform Web scraping.
The current code only clicks on the 'MS' button in the first row. How can I create a for loop so that I can iterate through all the rows and click on 'MD' element in all the rows?
Thank you.
Following is the code:
table_0=table.find_element_by_tag_name('tbody')
for buttons in table_0.find_elements_by_tag_name("tr"):
buttons.find_elements_by_xpath('//tr[#class="odd"]')
buttons.find_element_by_xpath('//button[text()="MS"]').click()
for buttons in table_0.find_elements_by_tag_name("tr"):
buttons.find_elements_by_xpath('//tr[#class="even"]')
buttons.find_element_by_xpath('//button[text()="MS"]').click()
You should be able to use a CSS selector to gather those for clicking
.btn-group.btn-group-xs button:first-child
The selector certainly works:
Not sure whether you need waits but maybe something like:
elements = driver.find_elements_by_css_selector(".btn-group.btn-group-xs button:first-child")
for element in elements:
element.click()
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Chrome()
driver.get("https://ibl.mdanderson.org/fasmic/#!/")
driver.find_element_by_css_selector("input[type='text']").send_keys("AKT1 (3 mutations)")
driver.find_element_by_css_selector("input[type='text']").send_keys(Keys.RETURN)
elements = driver.find_elements_by_css_selector(".btn-group.btn-group-xs button:first-child")
for element in elements:
element.click()
I am trying to retrieve all possible lists from this website
Model will only open when year is selected. Similarly Make will only open when Model is selected. I want to store all combination of Year, Model and Make for learning purpose.
However I am not able to click year field only. It seems it is hidden and without this I can't go ahead with rest of code.
from selenium import webdriver
import time
from selenium.webdriver.support.ui import Select
from bs4 import BeautifulSoup
driver = webdriver.Chrome()
driver.get("https://www.osram-americas.com/en-us/applications/automotive-lighting-systems/Pages/lrgmain.aspx")
# Switch to new window opened
driver.switch_to.window(driver.window_handles[-1])
# Close the new window
driver.close()
# Switch back to original browser (first window)
driver.switch_to.window(driver.window_handles[0])
el = driver.find_element_by_id('sbToggle_27562807')
el.click()
It gives error :-
Message: no such element: Unable to locate element: {"method":"id","selector":"sbToggle_27562807"}
Message: no such element: Unable to locate element: {"method":"id","selector":"sbToggle_27562807"}
year element is not hidden, actually your locator to locate element using find_element_by_id('sbToggle_27562807') is not correct. In this element id attribute value is dynamically changing that's why you're unable to locate this element.
Instead of id locator you should try using some different locator. I would suggest, for better way try using find_element_by_css_selector() as below :-
el = driver.find_element_by_css_selector("div#fldYear a.sbToggle")
el.click()
Use this CSS selector to get to the arrow pointing downwards on the select year dropdown
"div[id='fldYear'] > div[class='sbHolder'] > a[class='sbToggle']"
or this xpath
"//div[#id='fldYear']/div[#class='sbHolder']/a[#class='sbToggle']"
Click on this to webelement to get the options
The element IDs change on each reload of the page, you'll have to find a different way to find the dropdown.
You can always find the <a> link with the "-- Select Year --" text, for example.