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I have an array like:
arr=[[1,2,3,4,'a,b,c,d'],[5,6,7,8,'e,f,g,h']]
I want to be:
arr=[[1,2,3,4,'a'],[1,2,3,4,'b'],[1,2,3,4,'c'],[1,2,3,4,'d'],[5,6,7,8,'e'],[5,6,7,8,'f'],[5,6,7,8,'g'],[5,6,7,8,'h']]
can somebody helps to gives me a suggestion? Many thanks.
you can iterate through the string (last element in list) and append the answer onto everything but the last element
new_arr = [[li[:-1]+[letter] for letter in li[-1].split(',')] for li in arr]
# Flatten
out = [item for sublist in new_arr for item in sublist]
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I have a list of strings L.
I need to check, whether a string is either directly an element of L or is in this format: "foo-element_of_L"
Is there a better way to do this in python than adding "foo-X" to L for all X in L?
I would do two lookups:
if x in L or f'foo-{x}' in L:
which may be significantly faster than
if any(x == y or f'foo-{x}' == y for x in L):
which is essentially what you were proposing.
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I have a list a[i,j,k]. Out of this, I need to iterate through list 'a' and declare each of the list items as a list separately.
i[]
j[]
k[]
Is there a way to do this in python?
loop through and create
for item in a:
item = []
or you can use list comprehension
a = [[] for item in a]
if your intended output is [[i], [j], [k]] then use
a = [[item] for item in a]
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I have a list in python of the following form:
myList = ['r0x94', 'r0x21', 'r0x51']
I want to sort it based on the last number in each string entry of the list such that:
sorted_myList = ['r0x21', 'r0x51', 'r0x94']
The last number is not hex, rather it is decimal. How to do it?
>>> my_list = ['r0x94', 'r0x21', 'r0x51']
>>> sorted(my_list, key=lambda x: int(x.rpartition('x')[-1]))
['r0x21', 'r0x51', 'r0x94']
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If I have a list like:
['15', 'A:B', 'B:C', 'D:C', 'F:A']
I want to change the values like:
['1515', 'A:B15', 'B:C15', 'D:C15', 'F:A15']
(add first one to other values in a list)
Is it possible?
Assuming ["15", "A:B", "B:C", "D:C", "F:A"] is your input list, a simple list comprehension would do the job:
>>> l = ["15", "A:B", "B:C", "D:C", "F:A"]
>>> value_to_add = l[0]
>>> [item + value_to_add for item in l]
['1515', 'A:B15', 'B:C15', 'D:C15', 'F:A15']
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I have a list of lists of strings such that:
decipher = [['###>>?', '######', '*&*...', '##&#&#'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######']]
I need to concatenate items with the same indeces from each list to print on the same line, each subsequent set of identically indexed items have to print on a new line:
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###&#&###&#&###&#&#
How can I accomplish that? Thanks!
A simple one line solution would be:
>>> print '\n'.join(''.join(i) for i in zip(*decipher))
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################
Here is another solution:
for col in range(len(decipher[0])):
out = ''
for row in range(len(decipher)):
out += decipher[row][col]
print(out)
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################