I have an e-commerce page and there are multiple products on a page. I need to click the link of a product then return on the main page and click the link of the next product, but when I return, the elements can't be found anymore.
Path = "C:\Program Files (x86)\chromedriver.exe"
driver = webdriver.Chrome(Path)
driver.get("https://www.emag.ro/")
search_bar = driver.find_element_by_id("searchboxTrigger")
search_bar.send_keys("laptopuri")
search_bar.send_keys(Keys.RETURN)
main = None
try:
main = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.ID, "main-container"))
)
print("Page loaded,main retrived succesfully")
print(" ")
except:
driver.quit()
products = main.find_elements_by_css_selector("div.card-item.js-product-data")
for product in products:
raw_name = product.text
raw_price = product.find_element_by_css_selector("p.product-new-price").text
link = product.find_element_by_tag_name("a")
#clicking the link
link.click()
spec_page = None
try:
spec_page = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.CLASS_NAME, "col-md-12"))
)
except:
driver.quit()
print(spec_page)
driver.back()
After the first iteration, I get the following error :
selenium.common.exceptions.StaleElementReferenceException: Message: stale element reference: element is not attached to the page document on line raw_name = product.text,basically at the beginning of the loop.
I assume the page is not loading properly or something like that, I tried using time.sleep before going through the loop but nothing
When you are writing driver.back(), it will go back to previous page and by the time it will reach to original page all the defined elements will become stale. You need to redefined them like below :-
This should handle the exception.
products = len(main.find_elements_by_css_selector("div.card-item.js-product-data"))
j = 0
for product in range(products):
elements = main.find_elements_by_css_selector("div.card-item.js-product-data")
raw_name = elements[j].text
raw_price = elements[j].find_element_by_css_selector("p.product-new-price").text
link = elements[j].find_element_by_tag_name("a")
# clicking the link
link.click()
spec_page = None
try:
spec_page = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.CLASS_NAME, "col-md-12"))
)
except:
driver.quit()
print(spec_page)
j = j + 1
driver.back()
Related
driver = webdriver.Chrome(path)
driver.get("https://techwithtim.net")
#print(driver.title)
#ID, name, class
#ID is unique, but is often missing
#name is not unique, but always exists
#class is not unique
search = driver.find_element(By.NAME, "s")
search.send_keys("test")
search.send_keys(Keys.RETURN) #return means enter
#wait for a specific thing to exist on the page before we start looking for it
#let our driver to wait for 10 sec until EC.xxx is reached
try:
main = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.ID, "main")) #By.name, By.class_name, By.tag_name
)
articles = main.find_elements(By.TAG_NAME, "article")
for article in articles:
header = article.find_elements(By.CLASS_NAME, "entry-summary")
print(header.text)
finally:
driver.quit()
I cannot run this code to get the summary of each search result for the search key "test". I have changed find_elements* to find_elements(By*, "string"). The error just shows:
'list' object has no attribute 'text'
I am new to selenium.
You could try something like below:
driver = webdriver.Chrome(path)
driver.get("https://techwithtim.net")
search = driver.find_element(By.NAME, "s")
search.send_keys("test")
search.send_keys(Keys.RETURN) #return means enter
#wait for a specific thing to exist on the page before we start looking for it
#let our driver to wait for 10 sec until EC.xxx is reached
try:
main = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.ID, "main")) #By.name, By.class_name, By.tag_name
)
articles = main.find_elements(By.TAG_NAME, "article")
for article in articles:
header = article.find_elements(By.CLASS_NAME, "entry-summary")
# find_elements will produce a list - So we need to iterate over each item in that list
for eachItem in header:
print(eachItem.text)
finally:
driver.quit()
As some of the comments mention, find_elements will produce a list - So we need to iterate over each item in that list to print the .text value
I'm trying to click on a div to get to the next page of a table (the url does not change when the page changes). The go to the next page div has the same class as the go to the previous page's.
ive used:
elem = driver.find_element_by_class_name('cXQSjq')
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text
most = most.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text
last = last.replace(',','')
last7day.append(last)
#loop for the other pages:
for i in range(6):
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text.replace(',','')
most = most.text.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text.replace(',','')
last7day.append(last)
and it worked to get me to page 2, but after page 2 it gives me the error:
selenium.common.exceptions.ElementClickInterceptedException: Message: element click
intercepted: Element <div class="styles__Chevron-sc-1buchb9-1 cXQSjq">...</div> is
not clickable at point (702, 656). Other element would receive the click: <div
id="hs-eu-cookie-confirmation-inner">...</div>
(Session info: chrome=92.0.4515.107)
Do you know if there is an issue that i am able to call elem.click() after using selenium to find other parts of the page. I'm scraping data from
https://nonfungible.com/market/history
I guess the issue here is that the next page button appears on the bottom of the page, so to click on it you should first scroll this element into the view.
See if this will work now:
from selenium.webdriver.common.action_chains import ActionChains
actions = ActionChains(driver)
elem = driver.find_element_by_class_name('cXQSjq')
actions.move_to_element(elem).perform()
time.sleep(0.3)
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text
most = most.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text
last = last.replace(',','')
last7day.append(last)
#loop for the other pages:
for i in range(6):
actions.move_to_element(elem).perform()
time.sleep(0.3)
elem.click()
timeout = 30
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.CLASS_NAME, "gxzFwa")))
except TimeoutException:
driver.quit()
names = driver.find_elements_by_class_name('iBSZGH')
for company in names[1:]:
name.append(company.text)
mostdata = driver.find_elements_by_class_name('gvgMSe.gJYnHB')
for most in mostdata:
most = most.text.replace(',','')
most = most.text.replace(',','')
data.append(most)
last7dsales = driver.find_elements_by_class_name('fGpHsy.kpsxyE')
for last in last7dsales:
last = last.text.replace(',','')
last7day.append(last)
I didn't check correctness of the rest of your code, but clicking the next button should work now
With Python3 and selenium I want to automate the search on a public information site. In this site it is necessary to enter the name of a person, then select the spelling chosen for that name (without or with accents or name variations), access a page with the list of lawsuits found and in this list you can access the page of each case.
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException, NoSuchElementException
from selenium.webdriver.common.keys import Keys
import time
import re
Name that will be searched
name = 'JOSE ROBERTO ARRUDA'
Create path, search start link, and empty list to store information
firefoxPath="/home/abraji/Documentos/Code/geckodriver"
link = 'https://ww2.stj.jus.br/processo/pesquisa/?aplicacao=processos.ea'
processos = []
Call driver and go to first search page
driver = webdriver.Firefox(executable_path=firefoxPath)
driver.get(link)
Position cursor, fill and click
WebDriverWait(driver, 5).until(EC.element_to_be_clickable((By.CSS_SELECTOR, '#idParteNome'))).click()
time.sleep(1)
driver.find_element_by_xpath('//*[#id="idParteNome"]').send_keys(name)
time.sleep(6)
WebDriverWait(driver, 5).until(EC.element_to_be_clickable((By.CSS_SELECTOR, '#idBotaoPesquisarFormularioExtendido'))).click()
Mark all spelling possibilities for searching
WebDriverWait(driver, 5).until(EC.element_to_be_clickable((By.CSS_SELECTOR, '#idBotaoMarcarTodos'))).click()
WebDriverWait(driver, 5).until(EC.element_to_be_clickable((By.CSS_SELECTOR, '#idBotaoPesquisarMarcados'))).click()
time.sleep(1)
Check how many pages of data there are - to be used in "for range"
capta = driver.find_element_by_xpath('//*[#id="idDivBlocoPaginacaoTopo"]/div/span/span[2]').text
print(capta)
paginas = int(re.search(r'\d+', capta).group(0))
paginas = int(paginas) + 1
print(paginas)
Capture routine
for acumula in range(1, paginas):
# Fill the field with the page number and press enter
driver.find_element_by_xpath('//*[#id="idDivBlocoPaginacaoTopo"]/div/span/span[2]/input').send_keys(acumula)
driver.find_element_by_xpath('//*[#id="idDivBlocoPaginacaoTopo"]/div/span/span[2]/input').send_keys(Keys.RETURN)
time.sleep(2)
# Captures the number of processes found on the current page - qt
qt = driver.find_element_by_xpath('//*[#id="idDivBlocoMensagem"]/div/b').text
qt = int(qt) + 2
print(qt)
# Iterate from found number of processes
for item in range(2, qt):
# Find the XPATH of each process link - start at number 2
vez = '//*[#id="idBlocoInternoLinhasProcesso"]/div[' + str(item) + ']/span[1]/span[1]/span[1]/span[2]/a'
print(vez)
# Access the direct link and click
element = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, vez)))
element.click()
# Run tests to get data
try:
num_unico = driver.find_element_by_xpath('//*[#id="idProcessoDetalhesBloco1"]/div[6]/span[2]/a').text
except NoSuchElementException:
num_unico = "sem_numero_unico"
try:
nome_proc = driver.find_element_by_xpath('//*[#id="idSpanClasseDescricao"]').text
except NoSuchElementException:
nome_proc = "sem_nome_encontrado"
try:
data_autu = driver.find_element_by_xpath('//*[#id="idProcessoDetalhesBloco1"]/div[5]/span[2]').text
except NoSuchElementException:
data_autu = "sem_data_encontrada"
# Fills dictionary and list
dicionario = {"num_unico": num_unico,
"nome_proc": nome_proc,
"data_autu": data_autu
}
processos.append(dicionario)
# Return a page to click on next process
driver.execute_script("window.history.go(-1)")
# Close driver
driver.quit()
In this case I captured the number of link pages (3) and the total number of links (84). So my initial idea was to do the "for" three times and within them split the 84 links
The direct address of each link is in XPATH (//*[#id="idBlocoInternoLinhasProcesso"]/div[41]/span[1]/span[1]/span[1]/span[2]/a) which I replace with the "item" to click
For example, when it arrives at number 42 I have an error because the first page only goes up to 41
My problem is how to go to the second page and then restart only "for" secondary
I think the ideal would be to know the exact number of links on each of the three pages
Anyone have any ideas?
Code below is "Capture routine":
wait = WebDriverWait(driver, 20)
#...
while True:
links = wait.until(EC.presence_of_all_elements_located((By.XPATH, "//span[contains(#class,'classSpanNumeroRegistro')]")))
print("links len", len(links))
for i in range(1, len(links) + 1):
# Access the direct link and click
.until(EC.element_to_be_clickable((By.XPATH, f"(//span[contains(#class,'classSpanNumeroRegistro')])[{i}]//a"))).click()
# Run tests to get data
try:
num_unico = driver.find_element_by_xpath('//*[#id="idProcessoDetalhesBloco1"]/div[6]/span[2]/a').text
except NoSuchElementException:
num_unico = "sem_numero_unico"
try:
nome_proc = driver.find_element_by_xpath('//*[#id="idSpanClasseDescricao"]').text
except NoSuchElementException:
nome_proc = "sem_nome_encontrado"
try:
data_autu = driver.find_element_by_xpath('//*[#id="idProcessoDetalhesBloco1"]/div[5]/span[2]').text
except NoSuchElementException:
data_autu = "sem_data_encontrada"
# Fills dictionary and list
dicionario = {"num_unico": num_unico,
"nome_proc": nome_proc,
"data_autu": data_autu
}
processos.append(dicionario)
# Return a page to click on next process
driver.execute_script("window.history.go(-1)")
# wait.until(EC.presence_of_element_located((By.CLASS_NAME, "classSpanPaginacaoImagensDireita")))
next_page = driver.find_elements_by_css_selector(".classSpanPaginacaoProximaPagina")
if len(next_page) == 0:
break
next_page[0].click()
You can try run the loop until next button is present on the screen. the logic will look like this,
try:
next_page = driver.find_element_by_class_name('classSpanPaginacaoProximaPagina')
if(next_page.is_displayed()):
next_page.click()
except NoSuchElementException:
print('next page does not exists')
]1I am trying to automate viewing stories on a popular social media site. What's the easiest way to click on every follower's story?
while True:
time.sleep(3)
WebDriverWait(driver, AWAIT_PRESENCE).until(EC.presence_of_element_located((By.XPATH, TARGET_FOLLOWERS_STORIES)))
stories = driver.find_elements_by_xpath(TARGET_FOLLOWERS_STORIES)
for story in stories:
time.sleep(3)
driver.execute_script("arguments[0].scrollIntoView();", story )
driver.execute_script("arguments[0].click()", story)
time.sleep(2)
while True:
try:
next_btn = WebDriverWait(driver, 3).until(EC.presence_of_element_located((By.XPATH, TARGET_STORIES_NEXT)))
driver.execute_script("arguments[0].click()", next_btn)
time.sleep(1)
except:
break
As and when you click on any element in the list, the elements reference will be refreshed and selenium can not find the elements from the old list. That's the reason why you get staleElementException. You just need little tweak to the code, to handle this issue. Always get the number of stories and iterate through stories using the xpath with index [index].
while True:
time.sleep(3)
WebDriverWait(driver, AWAIT_PRESENCE).until(EC.presence_of_element_located((By.XPATH, TARGET_FOLLOWERS_STORIES)))
stories = driver.find_elements_by_xpath(TARGET_FOLLOWERS_STORIES)
for storyNumber in range(len(stories)): #<== updated this line
time.sleep(3)
story = driver.find_element_by_xpath(TARGET_FOLLOWERS_STORIES + "[" +str(storyNumber+1) + "]") #<== updated this line
driver.execute_script("arguments[0].scrollIntoView();", story )
driver.execute_script("arguments[0].click()", story)
time.sleep(2)
while True:
try:
next_btn = WebDriverWait(driver, 3).until(EC.presence_of_element_located((By.XPATH, TARGET_STORIES_NEXT)))
driver.execute_script("arguments[0].click()", next_btn)
time.sleep(1)
except:
break
I am trying to move to page 2 and beyond of this page (pagination) with python selenium and spent a few hours on this. I am getting this error, and would be thankful of any help..Error from chromedriver
is not clickable at point(). Other element would receive the click
My code so far:
class Chezacash:
t1 = time.time()
driver = webdriver.Chrome(chromedriver)
def controller(self):
self.driver.get("https://www.chezacash.com/#/home/")
element = WebDriverWait(self.driver, 10).until(
EC.presence_of_element_located((By.CSS_SELECTOR, "div.panel-heading")))
soup = BeautifulSoup(self.driver.page_source.encode('utf-8'),"html.parser")
self.parser(soup)
self.driver.find_element(By.XPATH, "//li[#class='paginate_button active']/following-sibling::li").click()
time.sleep(2)
soup = BeautifulSoup(self.driver.page_source.encode('utf-8'),"html.parser")
self.parser(soup)
def parser(self, soup):
for i in soup.find("table", {"id":"DataTables_Table_1"}).tbody.contents:
date = i.findAll("td")[0].get_text().strip()
time = i.findAll("td")[1].get_text().strip()
home = i.findAll("td")[4].div.span.get_text().strip().encode("utf-8")
home_odds = i.findAll("td")[4].div.findAll("span")[1].get_text().strip()
draw_odds = i.findAll("td")[5].div.findAll("span")[1].get_text().strip()
away = i.findAll("td")[6].div.span.get_text().strip().encode("utf-8")
away_odds = i.findAll("td")[6].div.findAll("span")[1].get_text().strip()
print home
cheza = Chezacash()
try:
cheza.controller()
except:
cheza.driver.service.process.send_signal(signal.SIGTERM) # kill the specific phantomjs child proc # quit the node proc
cheza.driver.quit()
traceback.print_exc()
What if instead you would locate the "Next" button by link text, scroll into it's view and then click:
next_button = self.driver.find_element_by_link_text("Next")
self.driver.execute_script("arguments[0].scrollIntoView();", next_button)
next_button.click()
I would also maximize the browser window before navigating to the page:
self.driver.maximize_window()
self.driver.get("https://www.chezacash.com/#/home/")