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How to merge predicted values to original pandas test data frame where X_test has been converted using CountVectorizer before splitting

I want to merge my predicted results of my test data to my X_test. I was able to merge it with y_test but since my X_test is a corpus I'm not sure how I can identify the indexes to merge.
My codes are as below
def lr_model(df):
from sklearn.feature_extraction.text import CountVectorizer
from sklearn.model_selection import train_test_split
from sklearn.linear_model import LogisticRegression
import pandas as pd
# Create corpus as a list
corpus = df['text'].tolist()
cv = CountVectorizer()
X = cv.fit_transform(corpus).toarray()
y = df.iloc[:, -1].values
# Splitting to testing and training
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.2, random_state = 0)
# Train Logistic Regression on Training set
classifier = LogisticRegression(random_state = 0)
classifier.fit(X_train, y_train)
# Predicting the Test set results
y_pred = classifier.predict(X_test)
# Merge true vs predicted labels
true_vs_pred = pd.DataFrame(np.concatenate((y_pred.reshape(len(y_pred),1), y_test.reshape(len(y_test),1)),1))
return true_vs_pred
This gives me the y_test and y_pred but I'm not sure how I can add the X_test as an original data frame (the ids of the X_test) to this.
Any guidance is much appreciated. Thanks

Using a pipeline can help you link the original X_test with the prediction:
def lr_model(df):
from sklearn.feature_extraction.text import CountVectorizer
from sklearn.model_selection import train_test_split
from sklearn.linear_model import LogisticRegression
import pandas as pd
from sklearn.pipeline import Pipeline
# Defining X and y
cv = CountVectorizer()
X = df['text']
y = df.iloc[:, -1].values
# Splitting to testing and training
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.2, random_state = 0)
# Create a pipeline
pipeline = Pipeline([
('CountVectorizer', cv),
('LogisticRegression', LogisticRegression(random_state = 0)),
])
# Train pipeline on Training set
pipeline.fit(X_train, y_train)
# Predicting the Test set results
y_pred = pipeline.predict(X_test)
return X_test, y_test, y_pred

Why Score from LinearRegression is giving different result than r2_score from sklearn.metrics

Ideally I should get same result as score is nothing but R-Square. But not sure why results are coming different.
from sklearn.datasets import california_housing
data = california_housing.fetch_california_housing()
data.data.shape
data.feature_names
data.target_names
import pandas as pd
house_data = pd.DataFrame(data.data, columns=data.feature_names)
house_data.describe()
house_data['Price'] = data.target
X = house_data.iloc[:, 0:8].values
y = house_data.iloc[:, -1].values
# Splitting the dataset into the Training set and Test set
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.33, random_state = 0)
# Fitting Simple Linear Regression to the Training set
from sklearn.linear_model import LinearRegression
linear_model = LinearRegression()
linear_model.fit(X_train, y_train)
#Check R-square on training data
from sklearn.metrics import mean_squared_error, r2_score
y_pred = linear_model.predict(X_test)
print(linear_model.score(X_test, y_test))
print(r2_score(y_pred, y_test))
Output
0.5957643114594776
0.34460597952465033

from the docs: https://scikit-learn.org/stable/modules/generated/sklearn.metrics.r2_score.html
sklearn.metrics.r2_score(y_true, y_pred,...)
You are passing y_true and y_pred the wrong way around. If you switch them you get the correct result.
print(linear_model.score(X_test, y_test))
print(r2_score(y_test, y_pred))
0.5957643114594777
0.5957643114594777

Standardized data of SVM - Scikit-learn/ Python

This is for an assignment where the SVM methods has to be used for model accuracy.
There were 3 parts, wrote the below code
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
digits = datasets.load_digits();
X = digits.data
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=30, stratify=y)
print(X_train.shape)
print(X_test.shape)
from sklearn.svm import SVC
svm_clf = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))
But after this, the question is as below
Perform Standardization of digits.data and store the transformed data
in variable digits_standardized.
Hint : Use required utility from sklearn.preprocessing. Once again,
split digits_standardized into two sets names X_train and X_test.
Also, split digits.target into two sets Y_train and Y_test.
Hint: Use train_test_split method from sklearn.model_selection; set
random_state to 30; and perform stratified sampling. Build another SVM
classifier from X_train set and Y_train labels, with default
parameters. Name the model as svm_clf2.
Evaluate the model accuracy on testing data set and print it's score.
On top of the above code, tried writing this, but seems to be failing. Can anyone help on how the data can be standardized.
std_scale = preprocessing.StandardScaler().fit(X_train)
X_train_std = std_scale.transform(X_train)
X_test_std = std_scale.transform(X_test)
svm_clf2 = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))

Tried the below. Seems to be working.
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import StandardScaler
digits = datasets.load_digits();
X = digits.data
scaler = StandardScaler()
scaler.fit(X)
digits_standardized = scaler.transform(X)
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(digits_standardized, y, random_state=30, stratify=y)
#print(X_train.shape)
#print(X_test.shape)
from sklearn.svm import SVC
svm_clf2 = SVC().fit(X_train, y_train)
print("Accuracy ",svm_clf2.score(X_test,y_test))

Try this as final code includes all Tasks
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import StandardScaler
from sklearn.svm import SVC
digits = datasets.load_digits()
X = digits.data
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=30, stratify=y)
print(X_train.shape)
print(X_test.shape)
svm_clf = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))
scaler = StandardScaler()
scaler.fit(X)
digits_standardized = scaler.transform(X)
X_train, X_test, y_train, y_test = train_test_split(digits_standardized, y, random_state=30, stratify=y)
svm_clf2 = SVC().fit(X_train, y_train)
print(svm_clf2.score(X_test,y_test))

How to change from normal machine learning technique to cross validation?

from sklearn.svm import LinearSVC
from sklearn.feature_extraction.text import CountVectorizer
from sklearn.feature_extraction.text import TfidfTransformer
from sklearn.metrics import accuracy_score
X = data['Review']
y = data['Category']
tfidf = TfidfVectorizer(ngram_range=(1,1))
classifier = LinearSVC()
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.3)
clf = Pipeline([
('tfidf', tfidf),
('clf', classifier)
])
clf.fit(X_train, y_train)
y_pred = clf.predict(X_test)
print(classification_report(y_test, y_pred))
accuracy_score(y_test, y_pred)
This is the code to train a model and prediction. I need to know my model performance. so where should I change to become cross_val_score?

use this:(it is an example from my previous project)
import numpy as np
from sklearn.model_selection import KFold, cross_val_score
kfolds = KFold(n_splits=5, shuffle=True, random_state=42)
def cv_f1(model, X, y):
score = np.mean(cross_val_score(model, X, y,
scoring="f1",
cv=kfolds))
return (score)
model = ....
score_f1 = cv_f1(model, X_train, y_train)
you can have multiple scoring. you should just change scoring="f1".
if you want to see score for each fold just remove np.mean

from sklearn documentation
The simplest way to use cross-validation is to call the cross_val_score helper function on the estimator and the dataset.
In your case it will be
from sklearn.model_selection import cross_val_score
scores = cross_val_score(clf, X_train, y_train, cv=5)
print(scores)

How to perform SMOTE with cross validation in sklearn in python

I have a highly imbalanced dataset and would like to perform SMOTE to balance the dataset and perfrom cross validation to measure the accuracy. However, most of the existing tutorials make use of only single training and testing iteration to perfrom SMOTE.
Therefore, I would like to know the correct procedure to perfrom SMOTE using cross-validation.
My current code is as follows. However, as mentioned above it only uses single iteration.
from imblearn.over_sampling import SMOTE
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.3, random_state=0)
sm = SMOTE(random_state=2)
X_train_res, y_train_res = sm.fit_sample(X_train, y_train.ravel())
clf_rf = RandomForestClassifier(n_estimators=25, random_state=12)
clf_rf.fit(x_train_res, y_train_res)
I am happy to provide more details if needed.

You need to perform SMOTE within each fold. Accordingly, you need to avoid train_test_split in favour of KFold:
from sklearn.model_selection import KFold
from imblearn.over_sampling import SMOTE
from sklearn.metrics import f1_score
kf = KFold(n_splits=5)
for fold, (train_index, test_index) in enumerate(kf.split(X), 1):
X_train = X[train_index]
y_train = y[train_index] # Based on your code, you might need a ravel call here, but I would look into how you're generating your y
X_test = X[test_index]
y_test = y[test_index] # See comment on ravel and y_train
sm = SMOTE()
X_train_oversampled, y_train_oversampled = sm.fit_sample(X_train, y_train)
model = ... # Choose a model here
model.fit(X_train_oversampled, y_train_oversampled )
y_pred = model.predict(X_test)
print(f'For fold {fold}:')
print(f'Accuracy: {model.score(X_test, y_test)}')
print(f'f-score: {f1_score(y_test, y_pred)}')
You can also, for example, append the scores to a list defined outside.

from sklearn.model_selection import StratifiedKFold
from imblearn.over_sampling import SMOTE
cv = StratifiedKFold(n_splits=5)
for train_idx, test_idx, in cv.split(X, y):
X_train, y_train = X[train_idx], y[train_idx]
X_test, y_test = X[test_idx], y[test_idx]
X_train, y_train = SMOTE().fit_sample(X_train, y_train)
....

I think you can also solve this with a pipeline from the imbalanced-learn library.
I saw this solution in a blog called Machine Learning Mastery https://machinelearningmastery.com/smote-oversampling-for-imbalanced-classification/
The idea is to use a pipeline from imblearn to do the cross-validation. Please, let me know if that works. The example below is with a decision tree, but the logic is the same.
#decision tree evaluated on imbalanced dataset with SMOTE oversampling
from numpy import mean
from sklearn.datasets import make_classification
from sklearn.model_selection import cross_val_score
from sklearn.model_selection import RepeatedStratifiedKFold
from sklearn.tree import DecisionTreeClassifier
from imblearn.pipeline import Pipeline
from imblearn.over_sampling import SMOTE
# define dataset
X, y = make_classification(n_samples=10000, n_features=2, n_redundant=0,
n_clusters_per_class=1, weights=[0.99], flip_y=0, random_state=1)
# define pipeline
steps = [('over', SMOTE()), ('model', DecisionTreeClassifier())]
pipeline = Pipeline(steps=steps)
# evaluate pipeline
cv = RepeatedStratifiedKFold(n_splits=10, n_repeats=3, random_state=1)
scores = cross_val_score(pipeline, X, y, scoring='roc_auc', cv=cv, n_jobs=-1)
score = mean(scores))