Develop Reference

Change css element style with Python Selenium

I want to change the css element style using Python Selenium while doing automation to increase the height of the page. The html of the element is as follows:
<div style="overflow-y:scroll;overflow-x:hidden;height:150px;">
I know that I can use something like the code below to do this:
driver.execute_script("document.getElementById('id name').style.height = '2000px';")
or
driver.execute_script("document.getElementByClassName('class name').style.height = '2000px';")
But there is no id or class in the HTML (there's only style).

If no ID or class is present then please use CSS
driver.execute_script("document.getElementByCss('div[style='overflow-y:scroll']').style.height = '2000px';")
But you should check in HTML DOM for the mentioned CSS :
Please check in the dev tools (Google chrome) if we have unique entry in HTML DOM or not.
Steps to check:
Press F12 in Chrome -> go to element section -> do a CTRL + F -> then paste the CSS and see, if your desired element is getting highlighted with 1/1 matching node.
CSS you should check :
div[style='overflow-y:scroll']
or
div[style='overflow-y:scroll'][sytle$='height:150px;']
or
div[style='overflow-y:scroll;overflow-x:hidden;height:150px;']
Whichever has the unique entry put that in execute_script and you should be good to go after that.
Alternate way to do
element = driver.find_element_by_css_selector("div[style='overflow-y:scroll;overflow-x:hidden;height:150px;']")
driver.execute_script("arguments[0].setAttribute('style','overflow-y:scroll;overflow-x:hidden;height:2000px;')", element)

Selenium Python - Finding Elements by Class Name With dynamic parameters

I was wondering if there is any way to find element by class name if the class name have a static param and dynamic param, I'll explain:
I got
< class="**dataset-selection-dialog-actions** *ng-tns-c139-19*" >
the 'dataset-selection-dialog-actions' is static but 'ng-tns-c139-19' can be change of any reload page.
can I locate this element without the dynamic param ?
thanks.

yes why not.
Please use find_element_by_class_name('dataset-selection-dialog-actions')
but make sure that it is unique element in HTMLDOM.
to check if it is unique or not, use this css selector, .dataset-selection-dialog-actions
PS : Please check in the dev tools (Google chrome) if we have unique entry in HTML DOM or not.
Steps to check:
Press F12 in Chrome -> go to element section -> do a CTRL + F -> then paste the css selector .dataset-selection-dialog-actions and see, if your desired element is getting highlighted with 1/1 matching node.

Xpath clicking not working at all

Quick info: I'm using Mac OS, Python 3.
I have like 800 links that need to be clicked on a page (and many more pages to go so need automation).
They were hidden because you only see those links when you hover over.
I fixed that by injecting CSS rule (just saying in case its the reason it's not working).
When I try to find elements by xpath it does not want to click the links afterwards and it also doesn't find all of them always just 4 (even when more are displayed in view).
HTML:
Display
When i click ok copy xpath in inspect it gives me:
//*[#id="tiles"]/li[3]/div[2]/ul/li[2]/a
But it doesn't work when I use it like this:
driver.find_elements_by_xpath('//*[#id="tiles"]/li[3]/div[2]/ul/li[2]/a')
So two questions:
How do I get them all?
How do I get it to click on each of them?
The pattern in the XPath is the same, with the /li[3] being the only number that changes, for this I created a for loop to create them all based on the count on page which I did successfully.
So if it can be done with the XPaths generated by myself that are corresponding to when I copy XPath in inspector then I only need question 2 answered.
PS.: this is HTML of parent of that first HTML:
<li onclick="openPopup(event, 'collect', {item_id: 165214})" class="collect" data-item-id="165214">Display</li>

This XPath,
//a[.="Display"]
will select all a links with anchor text equal to "Display".

As per your question, the HTML you have shared and your code attempts there is no necessity to get the <li> tags. Instead we will get the <a> tags in a list. So to answer your first question How do I get them all you can use the following line of code :
all_Display = driver.find_elements_by_xpath("//*[#id='tiles']//li/div[2]/ul/li[#class='collect']/a[#title='Display']")
Next to click on each of them you have to create a loop to iterate through all the <a> tag as follows :
all_Display = driver.find_elements_by_xpath("//*[#id='tiles']//li/div[2]/ul/li[#class='collect']/a[#title='Display']")
for each_Display in all_Display :
each_Display.click()

Using an XPath with elements by position is not ideal. Instead use a CSS selector to match the attributes for the targeted elements.
Something like:
all_Display = driver.find_elements_by_css_selector("#tiles li[onclick][data-item-id] a[title]")
You can then click them in a loop if none of them is loading a new page:
for element in all_Display:
element.click()

Python - Salesforce: How to find an object with no definitive class name and verify the text?

So, currently I'm using Python 3 and the selenium webdriver with Salesforce to automate admin verifications.
I've been pretty successful (even though I'm not that proficient with programming). However, I've run into an issue... I can't seem to figure out how to find an element on the page so that I can verify the text contained within is accurately being displayed.
This is what it looks like on the user's end:
The highlighted element displays as this
But whenever I search for "GlobalHeaderCommunitySwitcher", it spits back an error that it can't find it.
So I try searching for the other elements in the block of code:
<b class="zen-selectArrow"></b>PVT GBI Internal
<b class="zen-selectArrow"></b>
"PVT GBI Internal"
I've come up empty each time by searching by:
browser.find_element_by_id("globalHeaderCommunitySwitcher")
browser.find_element_by_class_name & used "zen-trigger" and "zen-selectArrow"
browser.find_element_by_xpath("//div[#class='zen-trigger'and text()='PVT GBI Internal']")
This also results in nothing being returned..
Essentially, how do I locate the element in the screenshot via the above code and then have the script verify that the text within that element ("PVT GBI INTERNAL") is present and correct?

you can use //tag[text()="value"] or //tag[contains(attribute,‘value’)]
example : browser.find_element_by_xpath("//a[#class='zen-trigger']//*[‌​text()='PVT GBI Internal']")
//a[#class='zen-trigger']//*[contains(text(),'PVT GBI Internal')]
//a[#class='zen-trigger']//*[contains(#class="zen-selectArrow")and
contains(text(),'PVT GBI Internal')]

Open the page using the google chrome browser
Move the mouse over the element that you want to find and right-click it
Left click Inspect (at the bottom of the selection list)
Your element will be hi-lighted in the Developers tools
Right click the hi-lighted element and select Copy
Click either copy Selector or XPath depending on your preference
Paste that into your selenium find_element_by_xpath() or find_element_by_css_selector() statement as appropriate.
Say xpath
element = browser.find_element_by_xpath("your pasted xpath")
assert element.text == 'Your expected text'

How to send keys to a difficult element in selenium (Python)

I am trying to click a small button, which has no "ID" or "Name", on a website. The only unique identifier is onclick, which is as follows:
onclick="submitForm('DefaultFormName',1,{'param1':'HXCTIMECARDACTIVITIESPAGEXgm7J5oT','serverValidate':'1uCdqvhJe','param2':'',event:'details|1'});return false;"
However, another button on the page has the following onclick:
onclick="submitForm('DefaultFormName',1,{'param1':'HXCTIMECARDACTIVITIESPAGEXgm7J5oT','serverValidate':'1uCdqvhJe','param2':'',event:'details|2'});return false;"
The only difference is a 1 vs. a 2 in the middle of the code. I tried to use a "find_element_by_css_selector" with the following code but it didn't work:
driver.find_element_by_css_selector(".x1p[onclick*='details|1']").click()
Another option would be selecting the preceding element, with the following code:
precedingbutton = driver.find_element_by_name('B22_1_6')
And then sending tab and then enter. However, after I send Tab, I don't know of a way to send Enter without assigning the Send_Keys command back to the preceding box, which deselects the button I want.
Let me know if you can help!

If you can locate the parent, you can locate the child, either with xpath or the nth-child css selector, relative to it.
Edit in response to comments:
Assuming by "2 elements away" you mean it is a sibling preceding the target, try something like td[name="B22_1_6"] + td + td. This is the sibling selector.

You can do it easily by
driver.find_element(By.XPATH, 'your xpath').click()
For finding the xpath , just inspect the button with firebug, and in html tab right click on selected element and click on Copy XPath.
Hope it will help you.