Develop Reference

get my instagram follower list with selenium

I'm beginner on programming. I trying get my Instagram follower list but i have just 12 follower. I tried firstly click to box and scroll down but it didn't work.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
import time
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
url= "https://www.instagram.com/"
driver.get(url)
time.sleep(1)
kullaniciAdiGir = driver.find_element(By.XPATH, "//*[#id='loginForm']/div/div[1]/div/label/input"")
kullaniciAdiGir.send_keys("USERNAME")
sifreGir = driver.find_element(By.XPATH, "//input[#name='password']")
sifreGir.send_keys("PASS")
girisButonu = driver.find_element(By.XPATH, "//*[#id='loginForm']/div/div[3]/button/div").click()
time.sleep(5)
driver.get(url="https://www.instagram.com/USERNAME/")
time.sleep(3)
kutucuk= driver.get(url="https://www.instagram.com/USERNAME/followers/")
time.sleep(5)
box =driver.find_element(By.XPATH, "//div[#class='xs83m0k xl56j7k x1iy3rx x1n2onr6 x1sy10c2 x1h5jrl4 xieb3on xmn8rco x1hfn5x7 x13wlyjk x1v7wizp x1l0w46t xa3vuyk xw8ag78']")
box.click()
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
time.sleep(5)
takipciler = driver.find_elements(By.CSS_SELECTOR, "._ab8y._ab94._ab97._ab9f._ab9k._ab9p._abcm")
for takipci in takipciler:
print(takipci.text)
time.sleep(10)
How can i fix it? How can scroll down in box? Thanks

You can select multiple elements with this.
#get all followers
followers = driver.find_elements(By.CSS_SELECTOR, "._ab8y._ab94._ab97._ab9f._ab9k._ab9p._abcm")
# loop each follower
for user in followers:
#do something here.
Using css selectors, in my opinion, is much easier.
Also note I used find_elemets not find_element, as the latter only returns a single result.
As the data is loaded dynamically, you will, infact have to scroll to make the site load more results. Then compare what you have agaisnt whats loaded. Probably execute some javascrtipt like scroll into view on the last element in that container etc.
or take a look here for an alternative solution
https://www.folkstalk.com/2022/10/how-to-get-a-list-of-followers-on-instagram-python-with-code-examples.html
or look at instragrams API, probably something in there for getting your followers.

Handling "Accept all cookie" popup with selenium when selector is unknown

I have a python script, It look like this.
from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.select import Select
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from os import path
import time
# Tried this code
chrome_options = webdriver.ChromeOptions()
prefs = {"profile.default_content_setting_values.notifications" : 2}
chrome_options.add_experimental_option("prefs",prefs)
browser = webdriver.Chrome(ChromeDriverManager().install(), chrome_options=chrome_options)
links = ["https://www.henleyglobal.com/", "https://markets.ft.com/data"]
for link in links:
browser.get(link)
#WebDriverWait(browser, 20).until(EC.url_changes(link))
#How do I disable/Ignore/remove/escape this "Accept all cookie" popup and then access the website to scrape data?
browser.quit()
So each website in the links array displays an "Accept all cookie" popup after navigating to the site. check the below image.
I have tried many ways nothing works, Check the one after imports
How do I exit/pass/escape this popup and then access the website to scrape data?

If you open your page in a new browser you'll note the page fully loads, then, a moment later your popup appears. The default wait strategy in selenium is just that the page is loaded.
One way to handle this is to simply inspect the page and find the xpath of the popup window. The below code should work for that.
browser.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS)
if link == 'https://www.henleyglobal.com/':
browser.findElement(By.XPATH("/html/body/div[7]/div/div/div/div[2]/div/div[2]/button[2]")).click()
else:
browser.findElement(By.XPATH("/html/body/div[4]/div/div/div[2]/div[2]/a")).click()
The code is waiting until the element of the pop-up is clickable and then clicking it.
For unknown sites you could try:
chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("--disable-notifications")
webdriver.Chrome(os.path.join(path, 'chromedriver'), chrome_options=chrome_options)

generally, you can not use some universal locator that will match the "Accept cookies" buttons for each and every web site in the world.
Even here, you have 2 different sites and the elements you need to click are totally different on these sites.
For https://www.henleyglobal.com/ site the correct locator may be something like this CSS Selector .confirmation button.primary-btn while for https://markets.ft.com/data site I'd advise to use CSS Selector .o-cookie-message__actions a.o-cookie-message__button.
These 2 elements are totally different: the first one is button while the second is a, they have totally different class names and all other attributes.
You may thing about the Accept text. It seems to be common, so you could use this XPath //*[contains(text(),'Accept')] but even this will not work since on the first page it matches 2 elements while the accept cookies element is the second between them...
So, there is no General locators, you will have to define separate locators for each page.
Again, for https://www.henleyglobal.com/ I would prefer
driver.find_element(By.CSS_SELECTOR, ".confirmation button.primary-btn").click()
While for the second page https://markets.ft.com/data I would prefer this
driver.find_element(By.CSS_SELECTOR, ".o-cookie-message__actions a.o-cookie-message__button").click()
Also, generally we always use WebDriverWait expected_conditions explicit waits, so the code will be as following:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 10)
# for the first page
wait.until(EC.element_to_be_clickable((By.XPATH, ".confirmation button.primary-btn"))).click()
# for the second page
wait.until(EC.element_to_be_clickable((By.XPATH, ".o-cookie-message__actions a.o-cookie-message__button"))).click()

Can you help me to get Selenium to click image in Chromedriver?

I am trying to do a tutorial and learn Selenium in python however i cant seem to get Selenium to click the "Checkout" button using "element_to_be_clickable((By.XPATH".
I am using:
Python v3.9
Chrome v87
This is the URL i am practicing on:
https://www.aria.co.uk/myAria/ShoppingBasket
And this is my current code for the clicking:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
import time
# Open Chromedriver
driver = webdriver.Chrome(r"C:\Users\Ste1337\Desktop\chromedriver\chromedriver.exe")
# Open webpage
driver.get("https://www.aria.co.uk/SuperSpecials/Other+products/ASUS+ROG+Pugio+2+Wireless+Optical+RGB+Gaming+Mouse?productId=72427")
#https://www.aria.co.uk/Products/Components/Graphics+Cards/NVIDIA+GeForce/GeForce+RTX+3060+Ti/Palit+GeForce+RTX+3060+Ti+Dual+8GB+GPU?productId=73054
# Click "Add to Basket" or refresh page if out of stock
try:
element = WebDriverWait(driver, 1).until(EC.presence_of_element_located((By.XPATH, "Out of Stock!")))
time.sleep(5)
browser.refresh()
except:
button = driver.find_element_by_id("addQuantityButton")
button.click()
basket = WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.ID, "basketContent")))
basket.click()
checkout = WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH("//img[contains(#src,'/static/images/checkoutv2.png.png')]"))).click()

I can see your xpath is not correct.
Your Xpath should be.
//img[contains(#src,'/static/images/checkoutv2.png')]
Your code should be.
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//img[contains(#src,'/static/images/checkoutv2.png')]"))).click()

The link you provided contains hCaptcha, which is actually responsible to check whether you are a human being or a bot. I guess that it's also the reason, why you can't click any of the items on the page, because Selenium actually is nothing less than a bot.
You first have to pass the test by clicking on the images, which are asked for.

Unable to use "explicit wait" in the right way

I've written a script using python with selenium to click on some links listed in the sidebar of google maps. When any of the items get clicked, the related information attached to each lead shows up in the right sided area. The script is doing fine. However, I've used hardcoded delay to do the job. How can I get rid of hardcoded delay by achieving the same with explicit wait. Thanks in advance.
Link to the site: website
The script I'm trying with:
import time
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
link = "replace_with_above_link"
driver = webdriver.Chrome()
driver.get(link)
wait = WebDriverWait(driver, 10)
for item in wait.until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "[id^='rlimg0_']"))):
item.location
time.sleep(3) #wish to try with explicit wait but can't find any idea
item.click()
driver.quit()
I tried with wait.until(EC.staleness_of(item)) instead of hardcoded delay but no luck.

If you want to wait until new data displayed after each clcik you may try below:
for item in wait.until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "[id^='rlimg0_']"))):
div = driver.find_element_by_xpath("//div[#class='xpdopen']")
item.location
item.click()
wait.until(EC.staleness_of(div))

Selenium: Dynamically loaded page causes automatic scrolling to fail

I'm using Selenium for Python to navigate a dynamic webpage (link).
I would like to automatically scroll down to a y-point on the page. I have tried various ways to code this, which seem to work on other pages, but not on this particular webpage.
Some examples of my efforts that don't seem to work for Firefox with Selenium:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get("http://en.boerse-frankfurt.de/etp/Deka-Oekom-Euro-Nachhaltigkeit-UCITS-ETF-DE000ETFL474")
By scrolling to a y-position:
driver.execute_script("window.scrollTo(0, 1400);")
Or by finding an element:
try:
find_scrollpoint = driver.find_element_by_xpath("//*[#id='main-wrapper']/div[10]/div/div[1]/div[1]")
except:
pass
else:
scrollpoint = find_scrollpoint.location["y"]
driver.execute_script("window.scrollTo(0, scrollpoint);")
Questions:
What could be some unusual circumstances on webpages such as this, where this very typical scrollTo code may fail?
What can possibly be done to mitigate it? Perhaps keypresses to scroll down – but it would still have to know when to stop pressing down.

It is just quite a dynamic page. I would wait for this specific element to be visible and then scroll into it's view. This works for me:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver = webdriver.Firefox()
driver.get("http://en.boerse-frankfurt.de/etp/Deka-Oekom-Euro-Nachhaltigkeit-UCITS-ETF-DE000ETFL474")
wait = WebDriverWait(driver, 10)
elm = wait.until(EC.visibility_of_element_located((By.XPATH, "//*[#id='main-wrapper']/div[10]/div/div[1]/div[1]")))
driver.execute_script("arguments[0].scrollIntoView();", elm)