gone = []
turn = 0
def play(XO,player):
while 0 == 0:
num = input("\n"+player+" enter an available number where you want to put an '"+XO+"'.\n > ")
while ((str(num).isdigit() == False) or ((int(num) <= 9 and int(num) >= 1) == False)) or (num in gone):
num = input("\nValue was not an available number.\n"+player+" enter an available number where you want to put an '"+XO+"'.\n > ")
So, in the second while loop I'm having a problem. You see the (num in gone) part? I'm trying to make it so if num is found in the gone list then it will be true, but it isn't working. Instead it passes through it.
I've tested to see if (not num in gone) applies the opposite effect, and it does!
If you need to see my entire code I can post it... btw this is for a Tic-Tac-Toe program I am making.
You're putting too much logic in one condition. Splitting it up will help you a lot.
Try something like this:
gone = []
turn = 0
def play(XO, player):
while True:
num = input(
f"\n{player} enter an available number "
f"where you want to put an '{XO}'.\n > "
)
try:
num = int(num)
except ValueError:
print("Not a valid number, try again")
continue
if num < 1 or num > 9:
print("Number not in correct range, try again")
continue
if num in gone:
print("Number already gone, try again")
continue
gone.append(num)
turn += 1
Related
I don't understand why is not working on my code
def random_calculation(num):
return((num*77 + (90+2-9+3)))
while random_calculation:
num = int(input("Pleace enter number: "))
if num == "0":
break
else:
print(random_calculation(num))
Can you guide me what is wrong here, i really dont understand
You have several errors in your code:
You cannot do while random_calculation like this. You need to call the function, but since inside the loop you are already checking for a break condition, use while True instead.
Also, you are converting the input to int, but then comparing agains the string "0" instead of the int 0
Here's the corrected code:
def random_calculation(num):
# 90+2-9+3 is a bit strange, but not incorrect.
return((num*77 + (90+2-9+3)))
while True:
num = int(input("Please enter number: "))
if num == 0:
break
# you don't need an else, since the conditional would
# break if triggered, so you can save an indentation level
print(random_calculation(num))
so,when you start the loop it ask you what number you want to enter and then the code checks if the number is == to 0. IF the number is equal to 0: break the loop. IF the number is equal to any other number it prints the "random_calculation" function
The program ask the user for an even integer. If he asks for it 6 times, the program ends. If the number is even, it returns it. My code so far:
i = 0
for i in range(6):
num = int(input("Num: "))
if num % 2 == 0:
print(num)
else:
num = int(input("Num: "))
i+=1
if i == 6:
break
My program doesn't end after user gives 6 not even numbers, how can i fix this?
You don't need to check for i == 6 yourself, this is done automatically by the for loop.
But you need to break out of the loop when an even number is entered.
for i in range(6):
num = int(input("Num: "))
if num % 2 == 0:
print("Success!")
break
else:
print("Failure")
The else: block of a loop is executed if the loop reaches its normal conclusion instead of exiting due to break.
for i in range(6):
num = int(input("Num: "))
if num % 2 == 0:
print(liczba)
break
This will do what you want, without all the extra lines you had.
I'm very new to programming and I've encountered a problem with a basic guessing game I've been writing.
x is a random number generated by the computer. The program is supposed to compare the absolute value of (previous_guess - x) and the new guess minus x and tell the user if their new guess is closer or further away.
But the variable previous_guess isn't updating with the new value.
Any help would be appreciated.
Here is the code so far:
###Guessing Game
import random
n = 100
x = random.randint(1,n)
print("I'm thinking of a number between 1 and ", n)
##print(x) ## testing/cheating.
count = 0
while True:
previous_guess = 0 # Should update with old guess to be compared with new guess
guess = int(input("Guess the number, or enter number greater that %d to quit." % n))
count += 1
print(previous_guess)
print("Guesses: ", count)
if guess > n:
print("Goodbye.")
break
elif count < 2 and guess != x:
print("Unlucky.")
previous_guess = guess #####
elif count >= 2 and guess != x:
if abs(guess - x) < abs(previous_guess - x):
previous_guess = guess #####
print("Getting warmer...")
else:
previous_guess = guess #####
print("Getting colder...")
elif guess == x:
print("You win! %d is correct! Guessed in %d attempt(s)." % (x,count))
break
Your previous guess is being reinitialized every time you loop. This is a very common error in programming so it's not just you!
Change it to:
previous_guess = 0
while True:
#Rest of code follows
Things you should be thinking about when stuff like this shows up.
Where is your variable declared?
Where is your variable initialized?
Where is your variable being used?
If you are unfamiliar with those terms it's okay! Look em up! As a programmer you HAVE to get good at googling or searching documentation (or asking things on stack overflow, which it would appear you have figured out).
Something else that is critical to coding things that work is learning how to debug.
Google "python debug tutorial", find one that makes sense (make sure that you can actually follow the tutorial) and off you go.
You're resetting previous_guess to 0 every time the loop begins again, hence throwing away the actual previous guess. Instead, you want:
previous_guess = 0
while True:
guess = ....
You need to initialize previous guess before while loop. Otherwise it will be initialized again and again.
You have updated previous guess in multiple places. You can make it simpler:
import random
n = 100
x = random.randint(1,n)
print("I'm thinking of a number between 1 and ", n)
##print(x) ## testing/cheating.
count = 0
previous_guess = 0 # Should update with old guess to be compared with new guess
while True:
guess = int(input("Guess the number, or enter number greater that %d to quit." % n))
count += 1
print(previous_guess)
print("Guesses: ", count)
if guess > n:
print("Goodbye.")
break
elif count < 2 and guess != x:
print("Unlucky.")
elif count >= 2 and guess != x:
if abs(guess - x) < abs(previous_guess - x):
print("Getting warmer...")
else:
print("Getting colder...")
elif guess == x:
print("You win! %d is correct! Guessed in %d attempt(s)." % (x,count))
break
previous_guess = guess #####
You need to initialize previous guess before while loop Otherwise it will be initialized again and again. You have to set the value of previous guess to x the computer generator and when you move on after loop you have to update the previous guess to next simply like this:
Add before while { previous_guess = x }
Add After While { previous_guess += x }
###Guessing Game
import random
n = 100
x = random.randint(1,n)
print("I'm thinking of a number between 1 and ", n)
##print(x) ## testing/cheating.
count = 0
previous_guess = x
while True:
# Should update with old guess to be compared with new guess
previous_guess += x
guess = int(input("Guess the number, or enter number greater that %d to quit." % n))
count += 1
print(previous_guess)
print("Guesses: ", count)
if guess > n:
print("Goodbye.")
break
elif count < 2 and guess != x:
print("Unlucky.")
previous_guess = guess #####
elif count >= 2 and guess != x:
if abs(guess - x) < abs(previous_guess - x):
previous_guess = guess #####
print("Getting warmer...")
else:
previous_guess = guess #####
print("Getting colder...")
elif guess == x:
print("You win! %d is correct! Guessed in %d attempt(s)." % (x,count))
break
Picture When u win
Picture When u loose
import random
print("Pick a number from 1-50")
randomNumber = random.randint(1,50)
correct = False
while not correct:
try:
userInput = int(input("Insert your number here. "))
except ValueError:
print("That is not a Number!")
continue
if userInput > randomNumber:
print("Guess lower.")
elif userInput < randomNumber:
print("Guess Higher.")
else:
print("You got it!")
break
So this code currently takes the user input and says whether the user guessed the random integer, or if they should guess higher/lower. I want to edit the code to now say whether the user input is within 5,10,15, etc of the random integer.
So if the random integer was 30, and the user inputs 20, the program would say something like "You are within 10; guess higher."
Any advice? I'm extremely new to python, so please respond with more simple methods if possible.
Thanks.
PS: Oh, preferably without the use of modules, mainly because I'm still learning.
I think this does what you want, and it cuts down on the if chains a little:
import random
print("Pick a number from 1-50")
randomNumber = random.randint(1,50)
correct = False
while not correct:
try:
userInput = int(input("Insert your number here. "))
except ValueError:
print("That is not a Number!")
continue
if randomNumber == userInput: # Let's check this first!
print ("YOU WIN!!!")
break # We use break b/c changing correct would still run rest of loop
acceptable_ranges = [5, 10, 15, 20, 25, 30, 25, 40, 45, 50]
guess_error = userInput - randomNumber
i = 0
while abs(guess_error) > acceptable_ranges[i]: # see how close they are
i += 1
if guess_error < 0: # let's figure out where they need to go
next_guess_direction = "higher"
else:
next_guess_direction = "lower"
print (("You are within %i: Please guess %s")
%(acceptable_ranges[i], next_guess_direction))
Let's look. at the last if statement a little further and the final print line. We are checking to see if guess_error, defined above (line 15) guess_error = userInput - randomNumber is less than 0 (negative). If it is less than zero, then we make the variable next_guess_direction equal to the string "higher," because the next guess needs to be larger than the last one (randomNumber was larger than userInput. If guess_error is not negative, then it is positive, because we already eliminated the we eliminate the possibility of 0 using:
if randomNumber == userInput: # Let's check this first!
print ("YOU WIN!!!")
So, if guess_error is positive, we know that userInput was larger than randomNumber and we set next_guess_direction equal to the string "lower." Finally, we print out everything that we have found:
print (("You are within %i: Please guess %s")
%(acceptable_ranges[i], next_guess_direction))
I am using an older version of formatting where %i and %s are placeholders for integer and string, respectively. I then define what should be formatted there using %(acceptable_ranges[i], next_guess_direction), which simply means to put acceptable_ranges[i] in for the integer and next_guess_direction in for the string. Keep in mind, we found i in acceptable_ranges[i] right above the if statement.
I know that is all long, but I did not know how much detail you needed!
Update: I see you ask to do it without modules. Here's a solution:
def ceil(xx):
if int(xx) < xx:
return int(xx) + 1
else:
return int(xx)
def generate_response(actual, guess, interval=5):
diff_interval_units = (guess - actual) / float(interval)
within = ceil(abs(diff_interval_units)) * interval
response = "You are within %d" % within
if diff_interval_units > 0:
response += "; guess lower"
elif diff_interval_units < 0:
response += "; guess higher"
return response
-- original answer:
You can do this with numpy's ceil function.
For instance:
import numpy as np
def generate_response(actual, guess, interval=5):
diff_interval_units = (guess - actual) / np.float(interval)
within = np.ceil(np.abs(diff_interval_units)) * interval
response = "You are within %d" % within
if diff_interval_units > 0:
response += "; guess lower"
elif diff_interval_units < 0:
response += "; guess higher"
return response
A solution using the modulo operator:
import random
randomNumber = random.randint(0,100)
def guess(divisor = 5):
while 1:
try:
print("Pick a number from 0-100")
userInput = int(input("Insert your number here: "))
except ValueError:
print("That is not a Number!")
continue
delta = randomNumber - userInput
if delta == 0:
print("You got it!")
return
remainder = delta % divisor
# this takes advantage of python truncating non-floating point numbers
rounded_delta = (abs(delta) / divisor) * divisor + divisor * bool(remainder)
high_or_low = 'higher' if delta > 0 else 'lower'
print("You are within %s. Guess %s." % (rounded_delta, high_or_low))
nums = []
num = 0
valid_list = []
while num != '':
num = input('Enter numbers :')
nums.append(num)
nums2 = [(nums[i]) for i in range(0,len(nums))]
for i in range(len(nums2)):
if int(nums2[i]) < 101 and int(nums2[i]) > 0:
valid_list.append(nums2[i])
print(valid_list)
Sorry dont really know how to ask question corectly, but i hope those who get my idea will help, Thanks. So i am tryed to make program wich fills list with integers entered by user, than chech if they fit 1-101 and if they fit put those number in valid_list, The problem is while num != '': (BTW inters must be entered one by one, and it must stop when return is hited)
Without having actually tested it, I think this is what you want:
nums = []
num = 0
valid_list = []
while true:
num = input('Enter numbers :')
if not num:
break
nums.append(num)
nums2 = [(nums[i]) for i in range(0,len(nums))]
for i in range(len(nums2)):
if int(nums2[i]) < 101 and int(nums2[i]) > 0:
valid_list.append(nums2[i])
print(valid_list)
From Python 'If not' syntax the if not num syntax is explained as executing if num is any kind of zero or empty container, or False.