i was trying to parse a image link from a website.
When i inspect the link on the website, it is this one :https://static.nike.com/a/images/c_limit,w_592,f_auto/t_product_v1/df7c2668-f714-4ced-9f8f-1f0024f945a9/chaussure-de-basketball-zoom-freak-3-MZpJZF.png but when i parse it with my code the output is data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7.
from bs4 import BeautifulSoup
import requests
source = requests.get('https://www.nike.com/fr/w/hommes-chaussures-nik1zy7ok').text
soup = BeautifulSoup(source, 'lxml')
pair = soup.find('div', class_='product-card__body')
image_scr = pair.find('img', class_='css-1fxh5tw product-card__hero-image')['src']
print(image_scr)
I think the code isn't the issue but i don't know what's causing the link to come out in base64 format. So how could i set the code to render the link as .png ?
What happens?
First at all, take a look into your soup - There is the truth. Website provides not all information static, there are a lot things provided dynamically and also done by the browser -> So requests wont get this info this way.
Workaround
Take a look at the <noscript> next to your selection, it holds a smaller version of the image and is providing the src
Example
from bs4 import BeautifulSoup
import requests
source = requests.get('https://www.nike.com/fr/w/hommes-chaussures-nik1zy7ok').content
soup = BeautifulSoup(source, 'lxml')
pair = soup.find('div', class_='product-card__body')
image_scr = pair.select_one('noscript img.css-1fxh5tw.product-card__hero-image')['src']
print(image_scr)
Output
https://static.nike.com/a/images/c_limit,w_318,f_auto/t_product_v1/df7c2668-f714-4ced-9f8f-1f0024f945a9/chaussure-de-basketball-zoom-freak-3-MZpJZF.png
If you like a "big picture" just replace parameter w_318 with w_1000...
Edit
Concerning your comment - There are a lot more solutions, but still depending on what you like to do with the information and what you gonna work with.
Following approache uses selenium that is unlike requests rendering the website and give you the "right page source" back but also needs more resources then requests:
from bs4 import BeautifulSoup
from selenium import webdriver
driver = webdriver.Chrome('C:\Program Files\ChromeDriver\chromedriver.exe')
driver.get('https://www.nike.com/fr/w/hommes-chaussures-nik1zy7ok')
soup=BeautifulSoup(driver.page_source, 'html.parser')
pair = soup.find('div', class_='product-card__body')
image_scr = pair.select_one('img.css-1fxh5tw.product-card__hero-image')['src']
print(image_scr)
Output
https://static.nike.com/a/images/c_limit,w_592,f_auto/t_product_v1/df7c2668-f714-4ced-9f8f-1f0024f945a9/chaussure-de-basketball-zoom-freak-3-MZpJZF.png
As you want to grab src meaning image data, so downloading data from server using requests, you need to use .content format as follows:
source = requests.get('https://www.nike.com/fr/w/hommes-chaussures-nik1zy7ok').content
Related
I am using both selenium and BeautifulSoup in order to do some web scraping. I have managed myself to obtain the next piece of code:
from selenium.webdriver import Chrome
from bs4 import BeautifulSoup
url = 'https://www.renfe.com/content/renfe/es/es/cercanias/cercanias-valencia/lineas/jcr:content/root/responsivegrid/rftabdetailline/item_1591014181985.html'
driver.get(url)
soup = BeautifulSoup(driver.page_source, 'lxml')
The output soup produces has the following structure:
<html>
<head>
</head>
<body>
<rf-list-detail line-color="245,150,40" line-number="C2" line-text="Línea C2"
list="[{... ;direction":"Place1"}
,... ,
;direction":"Place2"}...
Recall both text and output style have been modified for reading reasons. I attach an image of the actual output just in case it is more convinient.
Does anyone know how could I obtain every PlaceN (in the image, Moixent would be Place1) in a list? Something like
places = [Place1,...,PlaceN]
I have tried parsing it, but as it has no tags (or at least my html knowledge, which is barely none, says so) I obtain nothing. I have also tried using a regular expression, which I have just found out where a thing, but I am not sure how to do it properly.
Any thoughts?
Thank you in advance!!
output of soup
This site responds with non-html structure. So, you need no html-parser like BeautifulSoup or lxml for this task.
Here example using requests library. You can install it like this
pip install requests
import requests
import html
import json
url = 'https://www.renfe.com/content/renfe/es/es/cercanias/cercanias-valencia/lineas/jcr:content/root/responsivegrid/rftabdetailline/item_1591014181985.html'
response = requests.get(url)
data = response.text # get data from site
raw_list = data.split("'")[1] # extract rf-list-detail.list attribute
json_list = html.unescape(raw_list) # decode html symbols
parsed_list = json.loads(json_list) # parse json
print(parsed_list) # printing result
directions = []
for item in parsed_list:
directions.append(item["direction"])
print(directions) # extracting directions
# ['Moixent', 'Vallada', 'Montesa', "L'Alcudia de Crespins", 'Xàtiva', "L'Enova-Manuel", 'La Pobla Llarga', 'Carcaixent', 'Alzira', 'Algemesí', 'Benifaió-Almussafes', 'Silla', 'Catarroja', 'Massanassa', 'Alfafar-Benetússer', 'València Nord']
This question follows this previous question. I want to scrape data from a betting site using Python. I first tried to follow this tutorial, but the problem is that the site tipico is not available from Switzerland. I thus chose another betting site: Winamax. In the tutorial, the webpage tipico is first inspected, in order to find where the betting rates are located in the html file. In the tipico webpage, they were stored in buttons of class “c_but_base c_but". By writing the following lines, the rates could therefore be saved and printed using the Beautiful soup module:
from bs4 import BeautifulSoup
import urllib.request
import re
url = "https://www.tipico.de/de/live-wetten/"
try:
page = urllib.request.urlopen(url)
except:
print(“An error occured.”)
soup = BeautifulSoup(page, ‘html.parser’)
regex = re.compile(‘c_but_base c_but’)
content_lis = soup.find_all(‘button’, attrs={‘class’: regex})
print(content_lis)
I thus tried to do the same with the webpage Winamax. I inspected the page and found that the betting rates were stored in buttons of class "ui-touchlink-needsclick price odd-price". See the code below:
from bs4 import BeautifulSoup
import urllib.request
import re
url = "https://www.winamax.fr/paris-sportifs/sports/1/7/4"
try:
page = urllib.request.urlopen(url)
except Exception as e:
print(f"An error occurred: {e}")
soup = BeautifulSoup(page, 'html.parser')
regex = re.compile('ui-touchlink-needsclick price odd-price')
content_lis = soup.find_all('button', attrs={'class': regex})
print(content_lis)
The problem is that it prints nothing: Python does not find elements of such class (right?). I thus tried to print the soup object in order to see what the BeautifulSoup function was exactly doing. I added this line
print(soup)
When printing it (I do not show it the print of soup because it is too long), I notice that this is not the same text as what appears when I do a right click "inspect" of the Winamax webpage. So what is the BeautifulSoup function exactly doing? How can I store the betting rates from the Winamax website using BeautifulSoup?
EDIT: I have never coded in html and I'm a beginner in Python, so some terminology might be wrong, that's why some parts are in italics.
That's because the website is using JavaScript to display these details and BeautifulSoup does not interact with JS on it's own.
First try to find out if the element you want to scrape is present in the page source, if so you can scrape, pretty much everything! In your case the button/span tag's were not in the page source(meaning hidden or it's pulled through a script)
No <button> tag in the page source :
So I suggest using Selenium as the solution, and I tried a basic scrape of the website.
Here is the code I used :
from selenium import webdriver
option = webdriver.ChromeOptions()
option.add_argument('--headless')
option.binary_location = r'Your chrome.exe file path'
browser = webdriver.Chrome(executable_path=r'Your chromedriver.exe file path', options=option)
browser.get(r"https://www.winamax.fr/paris-sportifs/sports/1/7/4")
span_tags = browser.find_elements_by_tag_name('span')
for span_tag in span_tags:
print(span_tag.text)
browser.quit()
This is the output:
There are some junk data present in this output, but that's for you to figure out what you need and what you don't!
I'm new to Python and I'm struggling to find a solution or a way to do the following thing. I need 2 things from a website that I can get from inspect element: the link to the .m3u8 file which can be found in the html (Elements tab) of the website and a link to a .ts file (it doesn't matter which one) from the Network tab. Does anybody know how to do this? Thanks in advance!
Use BS4 and requests:
import requests
from bs4 import BeautifulSoup
URL = 'https://stackoverflow.com/questions/64828046/'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
results = soup.find(id='question-header')
print(results)
from urllib.request import urlopen
import lxml.html
connection = urlopen('http://yourwebsite')
dom = lxml.html.fromstring(connection.read())
for link in dom.xpath('//a/#href'):
if link.endswith(".m3u8") or link.endwith(".ts"):
print(link)
you can use other if conditions to check whether something is in the link, like:
if "m3u8" in link:
print(link)
Hi, I want to get the text(number 18) from em tag as shown in the picture above.
When I ran my code, it did not work and gave me only empty list. Can anyone help me? Thank you~
here is my code.
from urllib.request import urlopen
from bs4 import BeautifulSoup
url = 'https://blog.naver.com/kwoohyun761/221945923725'
html = urlopen(url)
soup = BeautifulSoup(html, 'lxml')
likes = soup.find_all('em', class_='u_cnt _count')
print(likes)
When you disable javascript you'll see that the like count is loaded dynamically, so you have to use a service that renders the website and then you can parse the content.
You can use an API: https://www.scraperapi.com/
Or run your own for example: https://github.com/scrapinghub/splash
EDIT:
First of all, I missed that you were using urlopen incorrectly the correct way is described here: https://docs.python.org/3/howto/urllib2.html . Assuming you are using python3, which seems to be the case judging by the print statement.
Furthermore: looking at the issue again it is a bit more complicated. When you look at the source code of the page it actually loads an iframe and in that iframe you have the actual content: Hit ctrl + u to see the source code of the original url, since the side seems to block the browser context menu.
So in order to achieve your crawling objective you have to first grab the initial page and then grab the page you are interested in:
from urllib.request import urlopen
from bs4 import BeautifulSoup
# original url
url = "https://blog.naver.com/kwoohyun761/221945923725"
with urlopen(url) as response:
html = response.read()
soup = BeautifulSoup(html, 'lxml')
iframe = soup.find('iframe')
# iframe grabbed, construct real url
print(iframe['src'])
real_url = "https://blog.naver.com" + iframe['src']
# do your crawling
with urlopen(real_url) as response:
html = response.read()
soup = BeautifulSoup(html, 'lxml')
likes = soup.find_all('em', class_='u_cnt _count')
print(likes)
You might be able to avoid one round trip by analyzing the original url and the URL in the iframe. At first glance it looked like the iframe url can be constructed from the original url.
You'll still need a rendered version of the iframe url to grab your desired value.
I don't know what this site is about, but it seems they do not want to get crawled maybe you respect that.
I am learning BeautifulSoup and i tried to extract all the "a" tags from a website. I am getting lot of "a" tags but few of them are ignored and i am confused why that is happening any help will be highly appreciated.
Link i used is : https://www.w3schools.com/python/
img : https://ibb.co/mmEKTK
red box in the image is a section that has been totally ignored by the bs4. It does contains "a" tags.
Code:
import requests
import bs4
import re
import html5lib
res = requests.get('https://www.w3schools.com/python/')
soup = bs4.BeautifulSoup(res.text,'html5lib')
try:
links_with_text = []
for a in soup.find_all('a', href=True):
print(a['href'])
except:
print ('none')
sorry for the code indentation i am new here.
The links which are being ignored by bs4 are dynamically rendered i.e Advertisements etc were not present in the HTML code but have been called by scripts based on your browser habits. requests package will only fetch static HTML content, you need to simulate browser to get the dynamic content.
Selenium can be used with any browser like Chrome, Firefox etc. If you want to achieve the same results on server (without UI), use headless browsers like Phatomjs.