Python Selenium - find item in a list - python

I have the following:
Aliases
NAT
Rules
I can't seem to be able to locate the element with text Aliases. Is it possible to do?
Can anyone help me out?


You can use like:
//*[text()="Aliases"]
another way is
//a[#href="/firewall_aliases.php" and (text()="Aliases")]


You can use the following XPath locator:
//a[text()="Aliases"]
For more uniqueness you can use
//a[#href="/firewall_aliases.php" and (text()="Aliases")]
Or even
//a[#href="/firewall_aliases.php" and (#class="navlnk") and (text()="Aliases")]


To locate the element with text as Aliases you can use either of the following Locator Strategies:
Using link_text:
element = driver.find_element(By.LINK_TEXT, "Aliases")
Using css_selector:
element = driver.find_element(By.CSS_SELECTOR, "a.navlnk[href*='firewall_aliases']")
Using xpath:
element = driver.find_element(By.XPATH, "//a[text()='Aliases' and contains(#href, 'firewall_aliases')]")
Ideally, to locate the element you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:
Using LINK_TEXT:
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.LINK_TEXT, "Aliases")))
Using CSS_SELECTOR:
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a.navlnk[href*='firewall_aliases']")))
Using XPATH:
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[text()='Aliases' and contains(#href, 'firewall_aliases')]")))
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Related

How to click on the first matching element having a specific background-url using Selenium Python

HTML:
<div class="__section-image" style="background-image: url("/img/all/05_element/continentImg/1.png");"></div>
The website have a lot of this html. I want to click the first of them.

To click on the first matching element you can use either of the following locator strategies:
Using css_selector:
driver.find_elements(By.CSS_SELECTOR, "div[class='__section-image']")[0].click()
Using xpath:
driver.find_elements(By.XPATH, "//div[#class='__section-image']")[0].click()
Ideally to click on the first matching element you need to induce WebDriverWait for the visibility_of_all_elements_located() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "div[class='__section-image']")))[0].click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[#class='__section-image']")))[0].click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

No such element error but the element can be located in the DOM through xpath expression

I have a python script logging into our company website to then get each row of data. It logs me in, locates the iframe where the table with row values is located, from there I try to locate a row in the iframe table and attached is a picture:
Highlighting the correct xpath expression but I need all 31 values.
All my code works properly except this:
elem5 = browser.find_element_by_xpath("//td/label[contains(#id, 'driver')][1]")

find_element_by_* returns a single webelement, where as you are looking for all the 31 elements. So you need find_elements* and you can use either of the following Locator Strategies:
Using css_selector:
elements = driver.find_elements(By.CSS_SELECTOR, "td > label[id^='driver']")
Using xpath:
elements = driver.find_elements(By.XPATH, "//td/label[starts-with(#id, 'driver')]")
To find all the desired elements ideally you need to induce WebDriverWait for visibility_of_all_elements_located() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "td > label[id^='driver']")))
Using XPATH:
elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//td/label[starts-with(#id, 'driver')]")))
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to click on an element by title with Selenium Python

I'm trying to check a checkbox with selenium and the only available info is the title.
Is a dynamic element, so I need to select by the title.
I tried all the methods without success (contains #title, etc).
Can someone please help? I'm beginning to code.
The xpath is:
/html/body/div[7]/div[2]/div/div[2]/div/div[2]/div/div/div[1]/form/div/span[1]/input
The CSS Selector is:
#selectCommon > span:nth-child(1) > input:nth-child(1)
The HTML looks like:
<input type="checkbox" title="AM - AMERICAS">

To click() on the element with title as AM - AMERICAS you can use either of the following locator strategies:
Using css_selector:
driver.find_element(By.CSS_SELECTOR, "input[title^='AM'][title$='AMERICAS']").click()
Using xpath:
driver.find_element(By.XPATH, "//input[starts-with(#title, 'AM') and contains(#title, 'AMERICAS')]").click()
Ideally to click() on the clickable element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input[title^='AM'][title$='AMERICAS']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[starts-with(#title, 'AM') and contains(#title, 'AMERICAS')]"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Selenium trying to get elements

I'd like to get the elements by Selenium as the attached pic:
ess-cell class="data-numeric"
However, the following code didn't work even though:
find_element_by_tag_name('div')
part works correctly. Does anyone know why?
row.find_element_by_tag_name('div').find_element_by_tag_name('div').find_elements_by_tag_name('ess-cell')

To get the elements <ess-cell class="data-numeric"...> you can use either of the following Locator Strategies:
Using css_selector:
elements = row.find_elements(By.CSS_SELECTOR, "div > div ess-cell.data-numeric")
Using xpath:
elements = row.find_elements(By.XPATH, "./div/div//ess-cell[contains(#class, 'data-numeric')]")
Ideally you have to induce WebDriverWait for presence_of_all_elements_located() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
elements = WebDriverWait(row, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "div > div ess-cell.data-numeric")))
Using XPATH:
elements = WebDriverWait(row, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "./div/div//ess-cell[contains(#class, 'data-numeric')]")))
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to click an element using Selenium Python

So I have this element in HTML...
<span style="font-size:11pt">Security</span>
... and I want to click it using Selenium in python. How can I do it? (Maybe I can identify it using onclick, but how?)
Also, here is what I've tried:
security = driver.find_element_by_xpath("//button[#onclick=\"on_catolog(2);\"]")
security.click()

You used wrong tag name in your XPath "//button[#onclick=\"on_catolog(2);\"]". It's not a button, but anchor tag. Try
"//a[#onclick='on_catolog(2);']"
Or click by link text:
security = driver.find_element_by_link_text("Security")
security.click()

To click on the element with text as Security you can use either of the following Locator Strategies:
Using css_selector:
driver.find_element_by_css_selector("a[onclick^='on_catolog'] > span[style='font-size:11pt']").click()
Using xpath:
driver.find_element_by_xpath("//a[starts-with(#onclick, 'on_catolog')]/span[text()='Security']").click()
Ideally, to click on the element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a[onclick^='on_catolog'] > span[style='font-size:11pt']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[starts-with(#onclick, 'on_catolog')]/span[text()='Security']"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

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