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n = int(input())
num = n
cnt = 0
while True:
a = num // 10
b = num % 10
c = (a + b) % 10
num = (b * 10) + c
cnt += 1
if num == n:
print(cnt)
break
C:/Users/ADMIN/AppData/Local/Programs/Python/Python310/python.exe c:/Users/ADMIN/loc-git/Study_CodingTest/baekjoon/Bronze/1110번.py
Traceback (most recent call last):
File "c:\Users\ADMIN\loc-git\Study_CodingTest\baekjoon\Bronze\1110번.py", line 2, in <module>
n = int(input())
ValueError: invalid literal for int() with base 10: '& C:/Users/ADMIN/AppData/Local/Programs/Python/Python310/python.exe c:/Users/ADMIN/loc-git/Study_CodingTest/baekjoon/Bronze/1110번.py'
python version = 3.10.0
I Dont't understand what you need. but chack this code don't come any error:-
n = int(input("enter number"))
num = n
cnt = 0
while True:
a = num // 10
b = num % 10
c = (a + b) % 10
num = (b * 10) + c
cnt += 1
if num == n:
print(cnt)
break
Related
This question already has answers here:
Why does the expression 0 < 0 == 0 return False in Python?
(9 answers)
Why does this not work as an array membership test? [duplicate]
(1 answer)
Closed 4 years ago.
I have a code like below
a=25
b=20
#number=0
if a < b == True:
number = 1
elif a >b == True:
number = 2
print(number)
When i execute this i get the following error
NameError: name 'number' is not defined
When i initialize the number = 0 like below
a=25
b=20
number=0
if a < b == True:
number = 1
elif a >b == True:
number = 2
print(number)
then i am not getting the output as 2, i am getting 0 instead, what am i missing here
Put a parenthesis around the condition.
Ex:
a=25
b=20
#number=0
if (a < b) == True:
number = 1
elif (a > b) == True:
number = 2
print(number)
or:
if a < b:
number = 1
elif a > b:
number = 2
print(number)
You are currently doing (a < b) and (b == True) & (a > b) and (b == 20)
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Write a program that estimates the value of the mathematical constant e by using the formula
[Note: Your program can stop after summing 10 terms.]
e = 1 + 1/1! + 1/2! + 1/3! + ...
I am new to programming languages and trying to learn python by myself. This question has been asked and answered before but I am seeking a solution without any function or module and I want to use only while or for loop.
Edit: This is the code that I wrote for calculating a factorial:
n = 0
factorial = 1
n = raw_input( "Enter a positive integer: ")
n = int(n)
while n < 0:
print "Enter a POSITIVE integer: "
backup = n
backup = int(backup)
while n != 0:
factorial *= n
n -= 1
print "%d!= %d" % (backup, factorial)
And this could be funny to most of you but this is the code that I wrote for the question but it ended up with a syntax error:
accuracy = 1
factorial = 1
counter = 1
e = 1.0
accuracy = raw_input( "Enter desired accuracy of e: ")
accuracy = int (accuracy)
while (counter <= (accuracy - 1))
factorial = factorial * counter
e = e + ( 1 / float(factorial))
counter += 1
print "Constant e is: ", e
Your first step is writing a factorial function. This can be done recursively or with a for-loop:
def factorial(n):
return 1 if n < 2 else n * factorial(n-1)
or:
def factorial(n):
x = 1
for i in range(2, n+1):
x *= i
return x
and then for calculating e we can again use recursion or a for-loop. This function takes a parameter which indicates how many terms in the formula it should evaluate (so you should call with 10 in your case).
def calc_e(t):
if not t:
return 0
else:
return 1 / factorial(t-1) + calc_e(t-1)
or:
def calc_e(t):
s = 0
for i in range(t):
s += 1 / factorial(i)
return s
and they both work:
>>> calc_e(1)
1.0
>>> calc_e(2)
2.0
>>> calc_e(3)
2.5
>>> calc_e(4)
2.6666666666666665
>>> calc_e(5)
2.708333333333333
>>> calc_e(10)
2.7182815255731922
>>> calc_e(20)
2.7182818284590455
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Closed 5 years ago.
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The following python coding is written to generate the triangle numbers between 1 to 55. But the coding is not working why ?
num = 1
sum = 0
while (num <= 10)
sum = sum + num
num = num + 1
print (sum, end=' ')
Missing colon :
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print (sum, end=' ')
or
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print (sum, end=' ')
Output
1 3 6 10 15 21 28 36 45 55
For 2.7
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print sum,
Your error is an error that is not followed by a while statement, followed by a () wrap and end of print that are not supported by default in Python 2.x.
The Corrected Code is:
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print sum
This question already has answers here:
Else Syntax Error Python
(7 answers)
Closed 6 years ago.
A = int(input()) #recom. sleep time
B = int(input()) #unrecom. sleep time
H = int(input()) #fact. slept
if (A <= H < B ):
print('Fine')
elif (A < H >= B):
print('too much')
else (A > H < B):
print('not much')
Error:
File "<ipython-input-9-12133f4a4c3d>", line 8
else(A > H < B):
^
SyntaxError: invalid syntax
Guys don't be rude, I'm financial and start learning programming :)
I can't see the difference between code who passed errors check and this one.
You are using else to make a test. You should use elif
A = int(input()) #recom. sleep time
B = int(input()) #unrecom. sleep time
H = int(input()) #fact. slept
if A <= H < B :
print('Fine')
elif (A < H >= B):
print('too much')
elif A > H < B:
print('not much')
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Closed 9 years ago.
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I have a question about multiples in python. Does anyone know how I can get the program to print multiples of a certain number? Like if I had them in put "10", it should print "1,10,2,5" or something along those lines
Thanks
Very naively you can test every number up to n(10)
n = 10
results = []
for i in range(1,n+1):
if n % i == 0:
results.append(i)
print(results)
Or as a list comprehension:
n = 10
print([x for x in range(1,n+1) if n % x == 0])
But in reality you only need to test up to the sqrt of n. Using a simple generator:
def divisor(n):
a = 1
l = n ** 0.5
while a <= l:
if n % a == 0:
if a == n//a:
yield a,
else:
yield a, n//a
a += 1
print([x for a in divisor(10) for x in a])
print(sorted(x for a in divisor(10) for x in a)) # Sorted
Here you go:
from collections import defaultdict
from math import sqrt
def factor(n):
i = 2
limit = sqrt(n)
while i <= limit:
if n % i == 0:
yield i
n = n / i
limit = sqrt(n)
else:
i += 1
if n > 1:
yield n
def factorGenerator(n):
d=defaultdict(int)
for f in factor(n):
d[f]+=1
return [(e,d[e]) for e in sorted(d.keys())]
def divisorGen(n):
factors = factorGenerator(n)
nfactors = len(factors)
f = [0] * nfactors
while True:
yield reduce(lambda x, y: x*y, [factors[x][0]**f[x] for x in range(nfactors)], 1)
i = 0
while True:
f[i] += 1
if f[i] <= factors[i][1]:
break
f[i] = 0
i += 1
if i >= nfactors:
return
print list(divisorGen(10))
Prints:
[1, 2, 5, 10]