when i was trying to overlay one image over the other one image had a transparent rounded rectangle filling and the other was just a normal image it looked either like this ( just putting the yellow over the pink without taking into account the rounded corners at all) or like this (looks just like the rounded rectangle without adding anything even kept the transparency)
this is how it should look like:
here are the 2 example images: (pink.png) and (yellow.png)
here is the code used for this :
import cv2
import numpy as np
layer0 = cv2.imread(r'yellow.png', cv2.IMREAD_UNCHANGED)
h0, w0 = layer0.shape[:2]
layer4 = cv2.imread(r"pink.png", cv2.IMREAD_UNCHANGED)
#just a way to help the image look more transparent in the opencv imshow because imshow always ignores
# the transparency and pretends that the image has no alpha channel
for y in range(layer4.shape[0]):
for x in range(layer4.shape[1]):
if layer4[y,x][3]<255:
layer4[y,x][:] =0,0,0,0
# Create a new np array
shapes = np.zeros_like(layer4, np.uint8)
shapes = cv2.cvtColor(shapes, cv2.COLOR_BGR2BGRA)
#the start position of the yellow image on the pink
gridpos = (497,419)
shapes[gridpos[1]:gridpos[1]+h0, gridpos[0]:gridpos[0]+w0] = layer0
# Change this into bool to use it as mask
mask = shapes.astype(bool)
# We'll create a loop to change the alpha
# value i.e transparency of the overlay
for alpha in np.arange(0, 1.1, 0.1)[::-1]:
# Create a copy of the image to work with
bg_img = layer4.copy()
# Create the overlay
bg_img[mask] = cv2.addWeighted( bg_img,1-alpha, shapes, alpha, 0)[mask]
# print the alpha value on the image
cv2.putText(bg_img, f'Alpha: {round(alpha,1)}', (50, 200),
cv2.FONT_HERSHEY_PLAIN, 8, (200, 200, 200), 7)
# resize the image before displaying
bg_img = cv2.resize(bg_img, (700, 600))
cv2.imwrite("out.png", bg_img)
cv2.imshow('Final Overlay', bg_img)
cv2.waitKey(0)
you can test different alpha combinations by pressing a key on the keyboard
OpenCV Version
Took me some time, but basically you have to mask both images and then combine them. The code bellow is commented and should be self explenatory. I think the hardest part to grasp is, that your pink image actually represents the foreground and the yellow image is your background. The trickiest part is to not let anything through from your background, which is why you have to mask both images.
import cv2
import numpy as np
pink = cv2.imread("pink.png", cv2.IMREAD_UNCHANGED)
# We now have to use an image that has the same size as the pink "foreground"
# and create a black image wiht numpy's zeros_like (gives same size as input)
background = np.zeros_like(pink)
# We then split the pink image into 4 channels:
# b, g, r and alpha, we only need the alpha as mask
_, _, _, mask = cv2.split(pink)
yellow = cv2.imread("yellow.png", cv2.IMREAD_UNCHANGED)
# we need the x and y dimensions for pasting the image later
h_yellow, w_yellow = yellow.shape[:2]
# Assuming format is (x, y)
gridpos = (497, 419)
# We paste the yellow image onto our black background
# IMPORTANT: if any of the dimensions of yellow plus the gridpos is
# larger than the background width or height, this will give you an
# error! Also, this only works with the same number of input channels.
# If you are loading a jpg image without alpha channel, you can adjust
# the number of channels, the last input param, e.g. with :3 to only use
# the first 3 channels
background[gridpos[1]:gridpos[1] + h_yellow, gridpos[0]:gridpos[0] + w_yellow, :] = yellow
# This step was not intuitive for me in the first run, since the
# pink img should aready be masked, but for some reason, it is not
pink_masked = cv2.bitwise_and(pink, pink, mask=mask)
# In this step, we mask the positioned yellow image with the inverse
# mask from the pink image, achieved by bitwise_not
background = cv2.bitwise_and(background, background, mask=cv2.bitwise_not(mask))
# We combine the pink masked image with the background
img = cv2.convertScaleAbs(pink_masked + background)
cv2.imshow("img", img), cv2.waitKey(0), cv2.destroyAllWindows()
Cheers!
Old Answer:
It looks like you are setting the whole image as a mask, this is why the rounded corners have no effect at all from your pink background. I myself was struggling a lot with this task aswell and ended up using pillow instead of OpenCV. I don't know if it is more performant, but I got it running.
Here the code that works for your example:
from PIL import Image
# load images
background = Image.open(r"pink.png")
# load image and scale it to the same size as the background
foreground = Image.open(r"yellow.png").resize(background.size)
# split gives you the r, g, b and alpha channel of the image.
# For the mask we only need alpha channel, indexed at 3
mask = background.split()[3]
# we combine the two images and provide the mask that is applied to the foreground.
im = Image.composite(background, foreground, mask)
im.show()
If your background is not monochrome as in your example, and you want to use the version, where you paste your original image, you have to create an empty image with the same size as the background, then paste your foreground to the position (your gridpos), e.g. like this:
canvas = Image.new('RGBA', background.size)
canvas.paste(foreground, gridpos)
foreground = canvas
Hope this helps!
I am having an issue where I'm using Pillow to recolor an image that has a lot of soft gradients but it seems to not completely color the most translucent part of these gradients, with the recolored image having a gradient that is not as smooth. Is there a way to fix this issue? Example Images and current code below.
enter image description here
Original Gradient: 1: https://i.stack.imgur.com/VFi75.png
enter image description here
Recolored Gradient: 1: https://i.stack.imgur.com/e5iNa.png
Here is the Original transparent PNG of the image
import random
import Owl_Attributes
from PIL import Image, ImageColor
# I create the image here and convert the color code to RGBA
RGB_im = image_base_accent3.convert("RGBA")
datas = RGB_im.getdata()
newData = []
for item in datas:
if item[0] == 208 and item[1] == 231 and item[2] == 161:
newData.append((255, 0, 0, item[3]))
else:
newData.append(item)
RGB_im.putdata(newData)
RGB_im.save('Owl_project_pictures\_final_RGB.png')
First, a couple of things to consider:
Inspect your images before you start work. Yours has an alpha channel that is pretty much pointless and irrelevant so I would discard that to save space and processing time.
Using for loops over Python lists of pixels is slow, inefficient, and error-prone in Python. Try to use built-in functions based on C code, or to use vectorised functions like Numpy.
On to your image. There are a whole load of shades and gradations of tone in your image and dealing with one separately through if statements is going to be difficult. I would suggest you want to use HSV colourspace instead.
I think you want the basic result to be a very saturated red with the lightness dictated by the lightness of the original image.
So, I would make an image with:
Hue=0 (see lower part of this diagram), and
Saturation=255 (i.e. fully saturated), and
Value (i.e. brightness) of the original image.
In code that might look like this:
#!/usr/bin/env python3
# ImageMagick command-line "equivalent"
# magick -size 599x452 xc:black xc:white \( VFi75.png -colorspace gray +level 0,60% \) +combine HSL result.png
from PIL import Image
# Load image and create HSV version
im = Image.open('VFi75.png')
HSV = im.convert('HSV')
# Split into separate channels for processing, discarding Hue and Saturation
_, _, V = HSV.split()
# Synthesize Hue channel, same size as input image, filled with 0, to make Red
H = Image.new('L', (im.width, im.height), 0)
# Synthesize Saturation channel, same size as input image, filled with 255, to make fully saturated
S = Image.new('L', (im.width, im.height), 255)
# Recombine synthesized H, S and V (based on original image brightness) back into a recombined image
RGB = Image.merge('HSV', (H,S,V)).convert('RGB')
# Save processed result
RGB.save('result.png')
If you wanted to make it lime green, you would change the Hue angle like this:
# Synthesize Hue channel, same size as input image, filled with 120, to make Lime Green
H = Image.new('L', (im.width, im.height), 120)
If you wanted to make it less saturated, you would change the saturation like this:
# Synthesize Saturation channel, same size as input image, filled with 64, to make less saturated
S = Image.new('L', (im.width, im.height), 64)
I have 2 images - one of the images is binarized i.e. each pixel is either black or white, and the other image is a standard RGB image. Both images are of the same size. For all the white pixels in the first image, I would like to take the corresponding pixels in the RGB image and attach them in place of the white pixels. How can I do this in Python?
Use the binarized image as a binary index for the pixel coordinates:
import numpy as np
my_source_image = np.random.randint(0, 255, (480,640,3), np.uint8) # defined somewhere, assumed to have shape [H,W,3]
my_binarized_image = np.random.randint(0, 2, (480,640), np.uint8) # defined somewhere, assumed to have shape [H,W]
pixel_idx = my_binarized_image.astype(bool)
my_dest_image = np.zeros_like(my_source_image)
my_dest_image[pixel_idx,:] = my_source_image[pixel_idx]
Note that I define the destination image as all-zeroes (if you want a different background color, simply initialize to the color value instead) and then fill in the relevant pixels instead of reusing my_binarized_image as you see to require in your question, because the destination image needs three channels, while the binarized image only has one.
Alternatively, as long as the "background" color is black, you can avoid preallocating a second image and simply zero-out the pixels in the first image instead:
my_dest_image = my_source_image * pixel_idx[...,None]
(The [...,None] adds an extra dimension at the end of pixel_idx to make the pixel-wise multiplication possible)
I am trying to use the Pillow (python-imaging-library) Python library in order to create an outline/stroke/border (with any color and width chosen) around my .png image. You can see here the original image and my wanted result (create by a phone app):
https://i.stack.imgur.com/4x4qh.png
You can download the png file of the original image here: https://pixabay.com/illustrations/brain-character-organ-smart-eyes-1773885/
I have done it in the medium size(1280x1138) but maybe it is better to do it with the smallest size (640x569).
I tried to solve the problem with two methods.
METHOD ONE
The first method is to create a fully blacked image of the brain.png image, enlarge it, and paste the original colored brain image on top of it. Here is my code:
brain_black = Image.open("brain.png") #load brain image
width = brain_black.width #in order not to type a lot
height = brain_black.height #in order not to type a lot
rectangle = Image.new("RGBA", (width, height), "black") #creating a black rectangle in the size of the brain image
brain_black.paste(rectangle, mask=brain_black) #pasting on the brain image the black rectangle, and masking it with the brain picture
#now brain_black is the brain.png image, but all its pixels are black. Let's continue:
brain_black = brain_black.resize((width+180, height+180)) #resizing the brain_black by some factor
brain_regular = Image.open("brain.png") #load the brain image in order to paste later on
brain_black.paste(brain_regular,(90,90), mask=brain_regular) #paste the regular (colored) brain on top of the enlarged black brain (in x=90, y=90, the middle of the black brain)
brain_black.save("brain_method_resize.png") #saving the image
This method doesn't work, as you can see in the image link above. It might have worked for simple geometric shapes, but not for a complicated shape like this.
METHOD TWO
The second method is to load the brain image pixels data into a 2-dimensional array, and loop over all of the pixels. Check the color of every pixel, and in every pixel which is not transparent (means A(or Alpha) is not 0 in the rgbA form) to draw a black pixel in the pixel above, below, right, left, main diagonal down, main diagonal up, secondary diagonal (/) down and secondary diagonal (/) up. Then to draw a pixel in the second pixel above, the second pixel below and etc. this was done with a "for loop" where the number of repetitions is the wanted stroke width (in this example is 30). Here is my code:
brain=Image.open("brain.png") #load brain image
background=Image.new("RGBA", (brain.size[0]+400, brain.size[1]+400), (0, 0, 0, 0)) #crate a background transparent image to create the stroke in it
background.paste(brain, (200,200), brain) #paste the brain image in the middle of the background
pixelsBrain = brain.load() #load the pixels array of brain
pixelsBack=background.load() #load the pixels array of background
for i in range(brain.size[0]):
for j in range(brain.size[1]):
r, c = i+200, j+200 #height and width offset
if(pixelsBrain[i,j][3]!=0): #checking if the opacity is not 0, if the alpha is not 0.
for k in range(30): #the loop
pixelsBack[r, c + k] = (0, 0, 0, 255)
pixelsBack[r, c - k] = (0, 0, 0, 255)
pixelsBack[r + k, c] = (0, 0, 0, 255)
pixelsBack[r - k, c] = (0, 0, 0, 255)
pixelsBack[r + k, c + k] = (0, 0, 0, 255)
pixelsBack[r - k, c - k] = (0, 0, 0, 255)
pixelsBack[r + k, c - k] =(0, 0, 0, 255)
pixelsBack[r - k, c + k] = (0, 0, 0, 255)
background.paste(brain, (200,200), brain) #pasting the colored brain onto the background, because the loop "destroyed" the picture.
background.save("brain_method_loop.png")
This method did work, but it is very time-consuming (takes about 30 seconds just for one picture and 30 pixels stroke). I want to do it for many pictures so this method is not good for me.
Is there an easier and better way to reach my wanted result using Python Pillow library. How can I do it?
And also, how can I fasten my loop code (I understood something about Numpy and OpenCV, which is better for this purpose?)
I know that if a phone app could do it in a matter of milliseconds, also python can, but I didn't find any way to do it.
Thank you.
I tried some solution similar with photoshop stroke effect using OpenCV (It is not perfect and I still finding better solution)
This algorithm is based on euclidean distance transform. I also tried dilation algorithm with ellipse kernel structure, it is bit different with photoshop, and there are some information that distance transform is the way that photoshop using.
def stroke(origin_image, threshold, stroke_size, colors):
img = np.array(origin_image)
h, w, _ = img.shape
padding = stroke_size + 50
alpha = img[:,:,3]
rgb_img = img[:,:,0:3]
bigger_img = cv2.copyMakeBorder(rgb_img, padding, padding, padding, padding,
cv2.BORDER_CONSTANT, value=(0, 0, 0, 0))
alpha = cv2.copyMakeBorder(alpha, padding, padding, padding, padding, cv2.BORDER_CONSTANT, value=0)
bigger_img = cv2.merge((bigger_img, alpha))
h, w, _ = bigger_img.shape
_, alpha_without_shadow = cv2.threshold(alpha, threshold, 255, cv2.THRESH_BINARY) # threshold=0 in photoshop
alpha_without_shadow = 255 - alpha_without_shadow
dist = cv2.distanceTransform(alpha_without_shadow, cv2.DIST_L2, cv2.DIST_MASK_3) # dist l1 : L1 , dist l2 : l2
stroked = change_matrix(dist, stroke_size)
stroke_alpha = (stroked * 255).astype(np.uint8)
stroke_b = np.full((h, w), colors[0][2], np.uint8)
stroke_g = np.full((h, w), colors[0][1], np.uint8)
stroke_r = np.full((h, w), colors[0][0], np.uint8)
stroke = cv2.merge((stroke_b, stroke_g, stroke_r, stroke_alpha))
stroke = cv2pil(stroke)
bigger_img = cv2pil(bigger_img)
result = Image.alpha_composite(stroke, bigger_img)
return result
def change_matrix(input_mat, stroke_size):
stroke_size = stroke_size - 1
mat = np.ones(input_mat.shape)
check_size = stroke_size + 1.0
mat[input_mat > check_size] = 0
border = (input_mat > stroke_size) & (input_mat <= check_size)
mat[border] = 1.0 - (input_mat[border] - stroke_size)
return mat
def cv2pil(cv_img):
cv_img = cv2.cvtColor(cv_img, cv2.COLOR_BGRA2RGBA)
pil_img = Image.fromarray(cv_img.astype("uint8"))
return pil_img
output = stroke(test_image, threshold=0, stroke_size=10, colors=((0,0,0),))
I can't do a fully tested Python solution for you at the moment as I have other commitments, but I can certainly show you how to do it in a few milliseconds and give you some pointers.
I just used ImageMagick at the command line. It runs on Linux and macOS (use brew install imagemagick) and Windows. So, I extract the alpha/transparency channel and discard all the colour info. Then use a morphological "edge out" operation to generate a fat line around the edges of the shape in the alpha channel. I then invert the white edges so they become black and make all the white pixels transparent. Then overlay on top of the original image.
Here's the full command:
magick baby.png \( +clone -alpha extract -morphology edgeout octagon:9 -threshold 10% -negate -transparent white \) -flatten result.png
So that basically opens the image, messes about with a cloned copy of the alpha layer inside the parentheses and then flattens the black outline that results back onto the original image and saves it. Let's do the steps one at a time:
Extract the alpha layer as alpha.png:
magick baby.png -alpha extract alpha.png
Now fatten the edges, invert and make everything not black become transparent and save as overlay.png:
magick alpha.png -morphology edgeout octagon:9 -threshold 10% -negate -transparent white overlay.png
Here's the final result, change the octagon:9 to octagon:19 for fatter lines:
So, with PIL... you need to open the image and convert to RGBA, then split the channels. You don't need to touch the RGB channels just the A channel.
im = Image.open('baby.png').convert('RGBA')
R, G, B, A = im.split()
Some morphology needed here - see here.
Merge the original RGB channels with the new A channel and save:
result = Image.merge((R,G,B,modifiedA))
result.save('result.png')
Note that there are Python bindings to ImageMagick called wand and you may find it easier to translate my command-line stuff using that... wand. Also, scikit-image has an easy-to-use morphology suite too.
I've written this function which is based on morphological dilation and lets you set the stroke size and color. But it's EXTREMELY slow and it seems to not work great with small elements.
If anyone can help me speed it up it would be extremely helpful.
def addStroke(image,strokeSize=1,color=(0,0,0)):
#Create a disc kernel
kernel=[]
kernelSize=math.ceil(strokeSize)*2+1 #Should always be odd
kernelRadius=strokeSize+0.5
kernelCenter=kernelSize/2-1
pixelRadius=1/math.sqrt(math.pi)
for x in range(kernelSize):
kernel.append([])
for y in range(kernelSize):
distanceToCenter=math.sqrt((kernelCenter-x+0.5)**2+(kernelCenter-y+0.5)**2)
if(distanceToCenter<=kernelRadius-pixelRadius):
value=1 #This pixel is fully inside the circle
elif(distanceToCenter<=kernelRadius):
value=min(1,(kernelRadius-distanceToCenter+pixelRadius)/(pixelRadius*2)) #Mostly inside
elif(distanceToCenter<=kernelRadius+pixelRadius):
value=min(1,(pixelRadius-(distanceToCenter-kernelRadius))/(pixelRadius*2)) #Mostly outside
else:
value=0 #This pixel is fully outside the circle
kernel[x].append(value)
kernelExtent=int(len(kernel)/2)
imageWidth,imageHeight=image.size
outline=image.copy()
outline.paste((0,0,0,0),[0,0,imageWidth,imageHeight])
imagePixels=image.load()
outlinePixels=outline.load()
#Morphological grayscale dilation
for x in range(imageWidth):
for y in range(imageHeight):
highestValue=0
for kx in range(-kernelExtent,kernelExtent+1):
for ky in range(-kernelExtent,kernelExtent+1):
kernelValue=kernel[kx+kernelExtent][ky+kernelExtent]
if(x+kx>=0 and y+ky>=0 and x+kx<imageWidth and y+ky<imageHeight and kernelValue>0):
highestValue=max(highestValue,min(255,int(round(imagePixels[x+kx,y+ky][3]*kernelValue))))
outlinePixels[x,y]=(color[0],color[1],color[2],highestValue)
outline.paste(image,(0,0),image)
return outline
Very simple and primitive solution: use PIL.ImageFilter.FIND_EDGES to find edge of drawing, it is about 1px thick, and draw a circle in every point of the edge. It is quite fast and require few libs, but has a disadvantage of no smoothing.
from PIL import Image, ImageFilter, ImageDraw
from pathlib import Path
def mystroke(filename: Path, size: int, color: str = 'black'):
outf = filename.parent/'mystroke'
if not outf.exists():
outf.mkdir()
img = Image.open(filename)
X, Y = img.size
edge = img.filter(ImageFilter.FIND_EDGES).load()
stroke = Image.new(img.mode, img.size, (0,0,0,0))
draw = ImageDraw.Draw(stroke)
for x in range(X):
for y in range(Y):
if edge[x,y][3] > 0:
draw.ellipse((x-size,y-size,x+size,y+size),fill=color)
stroke.paste(img, (0, 0), img )
# stroke.show()
stroke.save(outf/filename.name)
if __name__ == '__main__':
folder = Path.cwd()/'images'
for img in folder.iterdir():
if img.is_file(): mystroke(img, 10)
Solution using PIL
I was facing the same need: outlining a PNG image.
Here is the input image:
Input image
I see that some solution have been found, but in case some of you want another alternative, here is mine:
Basically, my solution workflow is as follow:
Read and fill the non-alpha chanel of the PNG image with the border
color
Resize the unicolor image to make it bigger
Merge the original image to the bigger unicolor image
Here you go! You have an outlined PNG image with the width and color of your choice.
Here is the code implementing the workflow:
from PIL import Image
# Set the border and color
borderSize = 20
color = (255, 0, 0)
imgPath = "<YOUR_IMAGE_PATH>"
# Open original image and extract the alpha channel
im = Image.open(imgPath)
alpha = im.getchannel('A')
# Create red image the same size and copy alpha channel across
background = Image.new('RGBA', im.size, color=color)
background.putalpha(alpha)
# Make the background bigger
background=background.resize((background.size[0]+borderSize, background.size[1]+borderSize))
# Merge the targeted image (foreground) with the background
foreground = Image.open(imgPath)
background.paste(foreground, (int(borderSize/2), int(borderSize/2)), foreground.convert("RGBA"))
imageWithBorder = background
imageWithBorder.show()
And here is the outputimage:
Output image
Hope it helps!
I found a way to do this using the ImageFilter module, it is much faster than any custom implementation that I've seen here and doesn't rely on resizing which doesn't work for convex hulls
from PIL import Image, ImageFilter
stroke_radius = 5
img = Image.open("img.png") # RGBA image
stroke_image = Image.new("RGBA", img.size, (255, 255, 255, 255))
img_alpha = img.getchannel(3).point(lambda x: 255 if x>0 else 0)
stroke_alpha = img_alpha.filter(ImageFilter.MaxFilter(stroke_radius))
# optionally, smooth the result
stroke_alpha = stroke_alpha.filter(ImageFilter.SMOOTH)
stroke_image.putalpha(stroke_alpha)
output = Image.alpha_composite(stroke_image, img)
output.save("output.png")
I was trying to change pixel of an image in python using this question. If mode is 0, it changes first pixel in top right corner of image to grey(#C8C8C8). But it doesn't change. There is not enough documentation about draw.point(). What is the problem with this code?
import random
from PIL import Image, ImageDraw
mode = 0
image = Image.open("dom.jpg")
draw = ImageDraw.Draw(image)
width = image.size[0]
height = image.size[1]
pix = image.load()
string = "kod"
n = 0
if (mode == 0):
draw.point((0, 0), (200, 200, 200))
if(mode == 1):
print(pix[0,0][0])
image.save("dom.jpg", "JPEG")
del draw
Is using PIL a must in your case? If not then consider using OpenCV (cv2) for altering particular pixels of image.
Code which alter (0,0) pixel to (200,200,200) looks following way in opencv:
import cv2
img = cv2.imread('yourimage.jpg')
height = img.shape[0]
width = img.shape[1]
img[0][0] = [200,200,200]
cv2.imwrite('newimage.bmp',img)
Note that this code saves image in .bmp format - cv2 can also write .jpg images, but as jpg is generally lossy format, some small details might be lost. Keep in mind that in cv2 [0][0] is left upper corner and first value is y-coordinate of pixel, while second is x-coordinate, additionally color are three values from 0 to 255 (inclusive) in BGR order rather than RGB.
For OpenCV tutorials, including installation see this.