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Inherited FPDF class (python) just gets the first page of two correct, second goes all white

I am constructing a class to produce automated pdf reports. (Using FPDF) In my class I have so far defined two functions. One that renders the first page(front) and one that renders a second page(page_two). These two functions produces each what I want. But when I try to combine the two in the function join the second page gets all white.
I don't understand why. Any help would be much appreciated.
from fpdf import FPDF
class MY_PDF(FPDF):
def _init_(self, **kwargs):
super(MY_PDF, self)-__init__(**kwargs)
pdf.add_font('Arial', '', r"c:\WINDOWS\Fonts\ARIAL.ttf", uni=True)
pdf.add_font('Arial_Bold', '', r"c:\WINDOWS\Fonts\ARIALBD.ttf", uni=True)
pdf.add_font('Georgia', '', r"c:\WINDOWS\Fonts\GEORGIA.ttf", uni=True)
pdf.add_font('Calibri', '', r"c:\WINDOWS\Fonts\CALIBRI.ttf", uni=True)
# A4.
WIDTH = 210
HEIGHT = 297
def front(self, title, second_title):
self.set_fill_color(0,0,90)
self.rect(0.5, 50, WIDTH-1, 75, 'F')
self.set_fill_color(149,194,61)
pdf.rect(14, 12, 5, 280, 'F')
self.set_font('Arial', 'B', 38)
self.set_text_color(255, 255, 255)
self.cell(15)
self.cell(150, 135, txt=f'{title}')
self.ln(10)
self.set_font('Arial', '', 28)
self.set_text_color(255, 255, 255)
self.cell(15)
self.cell(150, 150, txt=f'{second_title}')
#self.image('logga.png', 25, 12, 50)
self.ln()
def page_two(self, name, date, nr):
self.set_font('Arial', '', 9)
self.ln(250)
self.cell(20)
self.cell(0, 0, txt="©", align='L', ln=0)
self.cell(-160)
self.cell(0, 0, txt='Company name', align='L', ln=2)
self.ln(4)
self.cell(30)
self.cell(0, 0, txt=f'Author: {name}', align='L', ln=2)
self.ln(4)
self.cell(30)
self.cell(0, 0, txt=f'Date: {date}', align='L', ln=2)
self.ln(4)
self.cell(30)
self.cell(0, 0, txt=f'Number: {nr}', align='L', ln=2)
self.ln()
def join(self, title, second_title, name, date, nr):
self.add_page()
self.front(title, second_title)
self.add_page()
self.page_two(name, date, nr)
pdf= MY_PDF()
pdf.join('TITLE!', 'some other title', 'Name Name', '2021-11-30', '21262')
pdf.output('output.pdf')

How to use a loop to create radiobuttons in Python

I have to create multiple radio buttons. Each has its own name and location on grid. There are also several variables involved.
I stored all the data to create these radio buttons in a tuple
(I know that FONTS does not cause a problem, its stored above this but isn't shown here):
self.unitType = IntVar()
self.matPropSel = IntVar()
self.secProfSel = IntVar()
self.endSupSel = IntVar()
self.loadTypeSel = IntVar()
self.RADIOLABELS = ( # Text, Font, Variable, Value, Row, Column
('English', self.FONTS[3], self.unitType, 1, 3, 1),
('metric', self.FONTS[3], self.unitType, 2, 4, 1),
('select preset', self.FONTS[3], self.matPropSel, 1, 6, 1),
('manual entry', self.FONTS[3], self.matPropSel, 2, 7, 1),
('select preset', self.FONTS[3], self.secProfSel, 1, 10, 1),
('manual entry', self.FONTS[3], self.secProfSel, 2, 11, 1),
('one end', self.FONTS[3], self.endSupSel, 1, 15, 1),
('both ends', self.FONTS[3], self.endSupSel, 2, 16, 1),
('point', self.FONTS[3], self.loadTypeSel, 1, 18, 1),
('uniform distribution', self.FONTS[3], self.loadTypeSel, 2, 19, 1),
('uniform variation', self.FONTS[3], self.loadTypeSel, 3, 20, 1)
)
So, how would I use a for loop to go through this tuple and generate a radio button from each line? Do all of the variables have to be the same? I am having problems with them.
Here is my attempt at a loop:
outerIndexer = 0
for labels in self.RADIOLABELS:
Radiobutton(self, text=self.RADIOLABELS[outerIndexer][0], font=self.RADIOLABELS[outerIndexer][1],
variable=self.RADIOLABELS[outerIndexer][2], value=self.RADIOLABELS[outerIndexer][3])\
.grid(row=self.RADIOLABELS[outerIndexer][4], column=self.RADIOLABELS[outerIndexer][5])
outerIndexer += 1

You can do it like this by looping through the RADIOLABELS. Note: it is also recommended to save the button to a list so it doesn't get lost.
self.RADIOLABELS = ( # Text, Font, Variable, Value, Row, Column
('English', self.FONTS[3], self.unitType, 1, 3, 1),
('metric', self.FONTS[3], self.unitType, 2, 4, 1),
('select preset', self.FONTS[3], self.matPropSel, 1, 6, 1),
('manual entry', self.FONTS[3], self.matPropSel, 2, 7, 1),
('select preset', self.FONTS[3], self.secProfSel, 1, 10, 1),
('manual entry', self.FONTS[3], self.secProfSel, 2, 11, 1),
('one end', self.FONTS[3], self.endSupSel, 1, 15, 1),
('both ends', self.FONTS[3], self.endSupSel, 2, 16, 1),
('point', self.FONTS[3], self.loadTypeSel, 1, 18, 1),
('uniform distribution', self.FONTS[3], self.loadTypeSel, 2, 19, 1),
('uniform variation', self.FONTS[3], self.loadTypeSel, 3, 20, 1)
)
radiobuttons = []
for _Text, _Font, _Variable, _Value, _Row, _Column in self.RADIOLABELS: # it will unpack the values during each iteration
_Radio = tk.Radiobutton(root, text = _Text, font = _Font, variable = _Variable, value = _Value)
# ^ root should be the frame/Tk you're trying to place it on, it will be self if this is a direct subclass of a Frame or Tk
# ^ or Radiobutton(.....) if you did from tkinter import *
_Radio.grid(row = _Row, column = _Column)
radiobuttons.append(_Radio)

reportlab dynamic data-driven header outputs wrong subtitle

I have created some fictitious, though representative, clinical trial type data using Pandas, and now come to some test reporting in ReportLab.
The data has a block (~50 rows) where the treatment column is 'Placebo' and the same amount where the treatment is 'Active'. I simply want to list the data using a sub-heading of 'Treatment Group: Placebo' for the first set and 'Treatment Group: Active' for the second.
There are some hits on a similar topic, and, indeed I've used one of the suggested techniques, namely to extend the arguments of a header functions using partial from functools.
title1 = "ACME Corp CONFIDENTIAL"
title2 = "XYZ123 / Anti-Hypertensive Draft"
title3 = "Protocol XYZ123"
title4 = "Study XYZ123"
title5 = "Listing of Demographic Data by Treatment Arm"
title6 = "All subjects"
def title(canvas, doc, bytext):
canvas.saveState()
canvas.setFont(styleN.fontName, styleN.fontSize)
canvas.drawString(DOCMARGIN, PAGE_HEIGHT*.975, title1)
canvas.drawString(DOCMARGIN, PAGE_HEIGHT*.950, title2)
canvas.drawString(DOCMARGIN, PAGE_HEIGHT*.925, title3)
canvas.drawCentredString(PAGE_WIDTH/2.0, PAGE_HEIGHT*.900, title4)
canvas.drawCentredString(PAGE_WIDTH/2.0, PAGE_HEIGHT*.875, title5)
canvas.drawCentredString(PAGE_WIDTH/2.0, PAGE_HEIGHT*.850, title6)
canvas.drawString(DOCMARGIN, PAGE_HEIGHT*.825, "Treatment Group:" + bytext)
canvas.restoreState()
This is then called as follows. n_groups has the value of 2 from a summary query and 0 maps to 'Placebo' and 1 maps to active.
def build_pdf(doc):
ptemplates = []
for armcd in range(n_groups):
ptemplates.append(PageTemplate(id = 'PT' + str(armcd), frames = [dataFrame,],
onPage = partial(title, bytext=t_dict[armcd]),
onPageEnd = foot))
doc.addPageTemplates(ptemplates)
elements = []
for armcd in range(n_groups):
elements.append(NextPageTemplate('PT' + str(armcd)))
sublist = [t for t in lista if t[0] == (armcd+1)]
sublist.insert(0,colheads)
data_table = Table(sublist, 6*[40*mm], len(sublist)*[DATA_CELL_HEIGHT], repeatRows=1)
data_table.setStyle(styleC)
elements.append(data_table)
elements.append(PageBreak())
doc.build(elements)
The report produces 6 pages. The first 3 pages of placebo data are correct, pages 5 & 6 of active data are correct, but page 4 - which should be the first page of the second 'active' group has the sub-title 'Treatment Group: Placebo'.
I have re-organized the order of the statements multiple times, but can't get Page 4 to sub-title correctly. Any help, suggestions or magic would be much appreciated.
[Edit 1: sample data structure]
The 'top' of the data starts as:
[
[1, 'Placebo', '000001-000015', '1976-09-20', 33, 'F', 'Black'],
[1, 'Placebo', '000001-000030', '1959-04-26', 50, 'M', 'Asian'],
[1, 'Placebo', '000001-000031', '1946-02-07', 64, 'F', 'Asian'],
[1, 'Placebo', '000001-000046', '1947-11-08', 62, 'M', 'Asian'],
etc for 50 rows, then continues with
[2, 'Active', '000001-000002', '1962-02-28', 48, 'F', 'Black'],
[2, 'Active', '000001-000008', '1975-10-20', 34, 'M', 'Black'],
[2, 'Active', '000001-000013', '1959-01-19', 51, 'M', 'White'],
[2, 'Active', '000001-000022', '1962-01-12', 48, 'F', 'Black'],
[2, 'Active', '000001-000036', '1976-10-17', 33, 'F', 'Asian'],
[2, 'Active', '000001-000045', '1980-12-31', 29, 'F', 'White'],
for another 50.
The column header inserted is:
['Treatment Arm Code',
'Treatment Arm',
'Site ID - Subject ID',
'Date of Birth',
'Age (Years)',
'Gender',
'Ethnicity'],
[Edit 2: A solution - move the PageBreak() and make it conditional:]
def build_pdf(doc):
ptemplates = []
for armcd in range(n_groups):
ptemplates.append(PageTemplate(id = 'PT' + str(armcd), frames = [dataFrame,],
onPage = partial(title, bytext=t_dict[armcd]),
onPageEnd = foot))
doc.addPageTemplates(ptemplates)
elements = []
for armcd in range(n_groups):
elements.append(NextPageTemplate('PT' + str(armcd)))
if armcd > 0:
elements.append(PageBreak())
sublist = [t for t in lista if t[0] == (armcd+1)]
sublist.insert(0,colheads)
data_table = Table(sublist, 6*[40*mm], len(sublist)*[DATA_CELL_HEIGHT], repeatRows=1)
data_table.setStyle(styleC)
elements.append(data_table)
doc.build(elements)

How to search for the dictionary keys in a list

Say I have a dictionary of:
lst = {'adore': 10, 'hate': 10, 'hello': 10, 'pigeon': 1, 'would': 5, 'elections': 5}
And I have a list of:
mylist = [['a new', 'party'], ['to', 'lol'], ['compete'], ['in', 'adore', 'the 2013'], ['federal', 'elections'], ['The Free', 'Voters'], ['leadership', 'declined to'], ['join forces', 'according to', 'a leaked'], ['email from', 'Bernd Lucke'], ['Advocating', 'adore'] ]
I want to be able to search the list for the keys in the dictionary. If a word in the list is a key, then to take the value of that key and add it to a counter. In the end, to have a total sum of all the values.
Is there a way to do this?

Like this?
lst = {'adore': 10, 'hate': 10, 'hello': 10, 'pigeon': 1, 'would': 5, 'elections': 5}
mylist = [['a new', 'party'], ['to', 'lol'], ['compete'], ['in', 'adore', 'the 2013'], ['federal', 'elections'], ['The Free', 'Voters'], ['leadership', 'declined to'], ['join forces', 'according to', 'a leaked'], ['email from', 'Bernd Lucke'], ['Advocating', 'adore']]
print([lst.get(i) for j in mylist for i in j if lst.get(i) != None])
print(sum([lst.get(i) for j in mylist for i in j if lst.get(i) != None]))
Output:
[10, 5, 10]
25
If you don't like them in one line:
total = []
for i in mylist:
for j in i:
if lst.get(i) != None:
total.append(lst.get(i))
print(sum(total))

Probably you can do this in a more pythonic way.
lst = {'adore': 10, 'hate': 10, 'hello': 10, 'pigeon': 1, 'would': 5}
counter = {'adore': 0, 'hate': 0, 'hello': 0, 'pigeon': 0, 'would': 0}
mylist = [['a new', 'party'], ['to', 'lol'], ['compete'], ['in', 'adore', 'the 2013'], ['federal', 'elections'], ['The Free', 'Voters'], ['leadership', 'declined to'], ['join forces', 'according to', 'a leaked'], ['email from', 'Bernd Lucke'], ['Advocating', 'adore'] ]
def func():
for key in lst.keys():
for item in mylist:
if key in item:
counter[key] = counter[key] + lst[key]
func()
print sum(counter.values())

Write a List Into Excel File with Python

I have a list to be exported to an Excel file keeping the appropriate format, I resorted to a library named xlsxwriter,
here is an example :
xlsxwriter
and here is my list :
{'FirstName': u'Forence','LastName': u'Bidorst', 'Salary': -6775000.0, 'BirthDate': datetime.datetime(2013, 6, 20, 0, 0)}
{'FirstName': u'Oliver','LastName': u'Bidorst', 'Salary': -6775000.0, 'BirthDate': datetime.datetime(2013, 6, 20, 0, 0)}
{'FirstName': u'Mathew','LastName': u'Stark', 'Salary': -6775000.0, 'BirthDate': datetime.datetime(2013, 6, 20, 0, 0)}
{'FirstName': u'Sphed','LastName': u'liomst', 'Salary': -6775000.0, 'BirthDate': datetime.datetime(2013, 6, 20, 0, 0)}
I modified the code to browse a list and insert it into the file,
def export_result_XL():
list=get_list()
...
# Write some data headers.
worksheet.write('A1', 'First Name', bold)
worksheet.write('B1', 'Last Name', bold)
worksheet.write('C1', 'Salary', bold)
worksheet.write('D1', 'Birth Date', bold)
# Some data we want to write to the worksheet.
for entry in list:
x = str(entry['FirstName'])
y = str(entry['LastName'])
z = str(entry['Salary'])
e = str(entry['BirthDate'])
v = BirthDate[:10] # because the date format is like yyyy-mm-dd 00:00:00
expenses = (
[x,y ,z ,v]
)
# Start from the first cell below the headers.
row = 1
col = 0
for item ,str1,str2,str3,date_str in (expenses):
# Convert the date string into a datetime object.
date = datetime.strptime(date_str, "%Y-%m-%d")
worksheet.write_string (row, col, str1 )
worksheet.write_string (row, col + 1, str2 )
worksheet.write_string(row, col + 2, str3 )
worksheet.write_datetime(row, col + 3, date, date_format )
row += 1
# Write a total using a formula.
#worksheet.write(row, 0, 'Total', bold)
#worksheet.write(row, 2, '=SUM(C2:C5)', money_format)
workbook.close()
return ''
I had two problems here :
1 -
for item, date_str in (frais)
ValueError: too many values ​​to unpack
2-
if I avoid to convert to date format the file will be genreated but columns and rows are flipped
Is there any Idea how to do it , I hope I was clear in the description

Finally I found a Solution :
row = 1
col = 0
for entry in list:
print entry
strdate=str(entry['BirthDate'])
formatdate=strdate[:10]
date = datetime.strptime(str(formatdate), "%Y-%m-%d")
worksheet.write_string (row, col, entry['FirstName'] )
worksheet.write_string (row, col+1, entry['LastName'] )
worksheet.write_number (row, col+6, entry['Salary'],number_format )
worksheet.write_datetime(row, col+10, date, date_format )
row += 1
workbook.close()